Analytical using FULL outer join

Question

Hi,
Please execute the below script and check the output for the given select query the output gives rnum alias value as null which should not be the case. I am just wondering what is wrong in this case
CREATE TABLE A
ID INTEGER,
RD INTEGER,
SD DATE
CREATE TABLE B
ID INTEGER,
RD INTEGER,
SD DATE
INSERT INTO A VALUES (
30001, 200, TO_Date( '01/01/2007 12:00:00 AM', 'MM/DD/YYYY HH:MI:SS AM'));
INSERT INTO A VALUES (
30001, 200, TO_Date( '01/02/2007 12:00:00 AM', 'MM/DD/YYYY HH:MI:SS AM'));
INSERT INTO A VALUES (
30001, 250, TO_Date( '01/01/2007 12:00:00 AM', 'MM/DD/YYYY HH:MI:SS AM'));
INSERT INTO B VALUES (
30001, 300, TO_Date( '01/01/2007 12:00:00 AM', 'MM/DD/YYYY HH:MI:SS AM'));
INSERT INTO B VALUES (
30001, 300, TO_Date( '01/02/2007 12:00:00 AM', 'MM/DD/YYYY HH:MI:SS AM'));
INSERT INTO B VALUES (
30001, 250, TO_Date( '01/02/2007 12:00:00 AM', 'MM/DD/YYYY HH:MI:SS AM'));
INSERT INTO B VALUES (
30001, 200, TO_Date( '01/01/2007 12:00:00 AM', 'MM/DD/YYYY HH:MI:SS AM'));
COMMIT;
SELECT NVL(aa.id, ba.id) , aa.rd,aa.sd, ba.rd,ba.sd,aa.rnum,ba.rnum
FROM
(SELECT a.id, a.rd, a.sd , row_number() OVER(PARTITION BY a.id, a.rd ORDER BY a.rd) AS rnum
FROM A) a FULL OUTER JOIN
(SELECT b.id, b.rd, b.sd , row_number() OVER(PARTITION BY b.id, b.rd ORDER BY b.rd) AS rnum
FROM B) b
ON
a.rd = b.rd
AND
a.id = b.id
AND
a.rnum = b.rnum
Message was edited by:
vsugur
Message was edited by:
vsugur

Answer 1

Which version are you using? Maybe is a bug.
Try this:with aa as ( SELECT a.id, a.rd, a.sd ,
                  row_number() OVER ( PARTITION BY a.id, a.rd ORDER BY a.rd ) AS rnum
                  FROM a ),
bb as ( SELECT b.id, b.rd, b.sd ,
           row_number() OVER(PARTITION BY b.id, b.rd ORDER BY b.rd) AS rnum
           FROM b)
SELECT NVL(aa.id, bb.id) id, aa.rd ard, aa.sd asd, bb.rd brd, bb.sd bsd,
             aa.rnum arum, bb.rnum brum
FROM aa FULL OUTER JOIN bb
ON aa.rd = bb.rd AND
      aa.id = bb.id AND
      aa.rnum = bb.rnum;