Anybody can help me go back to iphone main screen?
I am a novice for iphone, just activated last night. I got problem to go back to main screen after going to set up mail, which was not successful neither, it says my yahoo mail can't be verified.
Pressing the "Home" button does not return the iPhone to the main or Home screen?
Similar Messages
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My screen on the touch is frozen. the screen shows a usb cable and the itunes logo above it. How can I get it back to the main screen
The screen is telling you to connect the iPod to a computer with iTunes via the USB cable. iTunes should open and give you instructions. If not, open iTunes and retore the iPod via iTunes.
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my iphone 4's backlight turns off ocassionally.,some say update it and it will be ok..,anybody can help me?
yes the phone is already on..,autolock is set to 1 min..,what i mean is that whenever im using my iphone the backlight turns off and i got a black sceen but i can see the icons on my iphone if i put it on a bright light..,even if i press the wake up botton the backlight just lit at little and it turns off again,,,and after about 30 mins on sleep mode and press the wake up button it will function as a normal again,few minutes after backlights turns off again..thanks!
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i have a iphone 8g and the lock button doesnt work and i forgot my password and i was wondering if anybody can help me??
You will need to restore your iPhone, take a look at this link, http://support.apple.com/kb/HT1212
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I saw a message "cannot get mail. The connection to the server failed". Anybody can help pls?
I saw a message "cannot get mail. The connection to the server failed". Anybody can help pls? I did try to delete the account and add back. Also tried to reset/ reboot the iPad but still effortless.
Hi all, I finally solved the issue. Here I wish to share with you all. First, I delete my hotmail account from mail account. Secondly I reboot my ipad2 with holding sleep and home button at once untill the apple logo is appeared. Then I add back the hotmail account. Done. Hope it helps. Thank you.
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the speakers of my brand new mac book pro are not working and I cannot plug in the earphones, the hole looks smaller than the pin or with an obstruction. anybody can help? thanks
Hi talero,
Contact AppleCare or bring it into an Apple Store or AASP. -
Can Apple make an app or an update that makes you insert your password to turn your phone off? This can help deal with theft of iPhones because people take or find a iPhone, the first thing they do is turn the phone off.
They probably can do such s thing if they choose to do so.
Let them know that you would like this:
http://www.apple.com/feedback
Not sure this is a very useful thing. It would run down the battery. All a thief has to do is remove them SIM and restore the iphone to stop it from being tracked. -
Anybody can help me? I'm trying to start my computer and it shows this question mark. Then i restart it holding the option key and it shows a padlock with a password field. What password should i put? I would appreciate any help
Contact Apple, or if you bought the computer secondhand, the previous owner.
(118258) -
anybody can help me understand if the Ipads becomes ready to be used in all world regions with 3G and or 4G infrastructure? I mean, are all of them released or when I buy one in the US to be used in Argentina I need to ask for a released one, with add costs?
There are two versions of the current iPad, the WiFi only (which will work anywhere in the world, but only connect to WiFi networks) and the 3G/4G model. The latter will connect to 3G networks worldwide, as I understand it, but the only 4G networks it can connect to are in the US and Canada.
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Anybody can help with this SQL?
The table is simple, only 2 columns:
create table personpay(
id integer primary key,
pay number(8,2) not null);
So the original talbe looks like this:
ID PAY
1 800
2 400
3 1200
4 500
5 600
6 1900
The requirement is to use one single query(no pl/sql) to show something lile the following, in other words, for each ID, the pay is the sum of all before itself and itself. So the query result looks like this:
ID PAY
1 800
2 1200
3 2400
4 2900
5 3500
6 5400
Again, just use one sql. No pl/sql. Anybody can help with this? I really appreciate that.
thanks,Eh, people are so "analytically minded" that can't even notice a simple join?
Counting Ordered Rows
Let’s start with a basic counting problem. Suppose we are given a list of integers, for example:
x
2
3
4
6
9
and want to enumerate all of them sequentially like this:
x #
2 1
3 2
4 3
6 4
9 5
Enumerating rows in the increasing order is the same as counting how many rows precede a given row.
SQL enjoys success unparalleled by any rival query language. Not the last reason for such popularity might be credited to its proximity to English . Let examine the informal idea
Enumerating rows in increasing order is counting how many rows precede a given row.
carefully. Perhaps the most important is that we referred to the rows in the source table twice: first, to a given row, second, to a preceding row. Therefore, we need to join our number list with itself (fig 1.1).
Cartesian Product
Surprisingly, not many basic SQL tutorials, which are so abundant on the web today, mention Cartesian product. Cartesian product is a join operator with no join condition
select A.*, B.* from A, B
Figure 1.1: Cartesian product of the set A = {2,3,4,6,9} by itself. Counting all the elements x that are no greater than y produces the sequence number of y in the set A.
Carrying over this idea into formal SQL query is straightforward. As it is our first query in this book, let’s do it step by step. The Cartesian product itself is
select t.x x, tt.x y
from T t, T tt
Next, the triangle area below the main diagonal is
select t.x x, tt.x y
from T t, T tt
where tt.x <= t.x
Finally, we need only one column – t.x – which we group the previous result by and count
select t.x, count(*) seqNum
from T t, T tt
where tt.x <= t.x
group by t.x
What if we modify the problem slightly and ask for a list of pairs where each number is coupled with its predecessor?
x predecessor
2
3 2
4 3
6 4
9 6
Let me provide a typical mathematician’s answer, first -- it is remarkable in a certain way. Given that we already know how to number list elements successively, it might be tempted to reduce the current problem to the previous one:
Enumerate all the numbers in the increasing order and match each sequence number seq# with predecessor seq#-1. Next!
This attitude is, undoubtedly, the most economical way of thinking, although not necessarily producing the most efficient SQL. Therefore, let’s revisit our original approach, as illustrated on fig 1.2.
Figure 1.2: Cartesian product of the set A = {2,3,4,6,9} by itself. The predecessor of y is the maximal number in a set of x that are less than y. There is no predecessor for y = 2.
This translates into the following SQL query
select t.x, max(tt.x) predecessor
from T t, T tt
where tt.x < t.x
group by t.x
Both solutions are expressed in standard SQL leveraging join and grouping with aggregation. Alternatively, instead of joining and grouping why don’t we calculate the count or max just in place as a correlated scalar subquery:
select t.x,
(select count(*) from T tt where tt.x <= t.x) seq#
from T t
group by t.x
The subquery always returns a single value; this is why it is called scalar. The tt.x <= t.x predicate connects it to the outer query; this is why it is called correlated. Arguably, leveraging correlated scalar subqueries is one the most intuitive techniques to write SQL queries.
How about counting rows that are not necessarily distinct? This is where our method breaks. It is challenging to distinguish duplicate rows by purely logical means, so that various less “pure” counting methods were devised. They all, however, require extending the SQL syntactically, which was the beginning of slipping along the ever increasing language complexity slope.
Here is how analytic SQL extension counts rows
select x, rank() over(order by x) seq# from T; -- first problem
select x, lag() over(order by x) seq# from T; -- second problem
Many people suggest that it’s not only more efficient, but more intuitive. The idea that “analytics rocks” can be challenged in many ways. The syntactic clarity has its cost: SQL programmer has to remember (or, at least, lookup) the list of analytic functions. The performance argument is not evident, since non-analytical queries are simpler construction from optimizer perspective. A shorter list of physical execution operators implies fewer query transformation rules, and less dramatic combinatorial explosion of the optimizer search space.
It might even be argued that the syntax could be better. The partition by and order by clauses have similar functionality to the group by and order by clauses in the main query block. Yet one name was reused, and the other had been chosen to have a new name. Unlike other scalar expressions, which can be placed anywhere in SQL query where scalar values are accepted, the analytics clause lives in the scope of the select clause only. I have never been able to suppress an impression that analytic extension could be designed in more natural way. -
Hello, I can't open the FluidTunes. Anybody can help me?
Hello, I can't open the FluidTunes. Anybody can help me?
You didn't give any information other than you have have some kind of iMac. You should probably contact the maker of the software http://majicjungle.com/about.html and click on the email for support.
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Anybody can help me for RTF conversion?
Anybody can help me for RTF conversion for selected text frames only in Indesign by script
ID has no built-in way to export a story as RTF with style labeling in a column next to the text, similar to what you would see in Story Editor view, but there is a remote possibility that this could be scripted (ask in InDesign Scripting) or perhaps you can make InDesign Tagged Text work for you. Try exporting a few paragraphs to tagged text and see if it would be useful.
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Hi..i just finish installed OS x maverick, it seems that my ITunes having problem..an error occured (-45054)...is there anybody can help me on this..thanks
Hi plugking,
Welcome to the Support Communities!
Repairing disk permissions is the first step in resolving this error message:
Troubleshooting permissions issues in Mac OS X
http://support.apple.com/kb/HT2963
Open Disk Utility (/Applications/Utilities/). Select your Mac OS X startup volume in the column on the left of the Disk Utility window, then click the First Aid tab. Click the Repair Disk Permissions
Also, make sure you have the latest version of iTunes installed:
Apple - iTunes - Download iTunes Now
http://www.apple.com/itunes/download/
Cheers,
- Judy -
Hi
I call you from Iran.
Today I encountered a problem I hope you can help me.
I have iPhone 5 with version 6.1.4. Jailbreak I would rather not unlock.
My problem is that the Operator name (top left) searching ... The appearance of!
And no matter how I turn off and I remove the SIM card Sarchyng not stop.
Even when I'm not on the phone's SIM card No SIM card Does not appear.
I appreciate your help.
Thank you for your attention.ilove.perspolis wrote:
Hi
I call you from Iran.
Today I encountered a problem I hope you can help me.
I have iPhone 5 with version 6.1.4. Jailbreak I would rather not unlock.
My problem is that the Operator name (top left) searching ... The appearance of!
And no matter how I turn off and I remove the SIM card Sarchyng not stop.
Even when I'm not on the phone's SIM card No SIM card Does not appear.
I appreciate your help.
Thank you for your attention.
I read this to say that the phone is not jailbroken and the OP does not want to jailbreak it.
The only way to unlock it is to contact the carrier it is locked to, and ask them to unlock it.
You are also in the unfortunate position that the iPhone is not supported in Iran due to the international embargo. -
i cannot download or updates any apps after upgrading the newest ios .. it show offers In-Apps Purchase... anybody can help me ?
This is happening to me too. I'm looking for anyway to fix this its getting very annoying not being able to update apps.
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