Apache 2.2.2 Jrun 4 WinXP --- Apache connector problem.

I configured External Web Server using Web Server
Configuration tool. I have cross-checked all the artifacts like
httpd.conf, etc. Everything looks fine. I started JRun and Apache
multiple times. "C:/JRun4/lib/wsconfig/1/mod_jrun20.so" is present.
I cannot get rid of following error.
Apache Server Start Console
Log.-------------------------------------
C:\Program Files\Apache Software
Foundation\Apache2.2\bin>httpd.exe -w -n Apache2.2 -k start
httpd.exe: Syntax error on line 486 of C:/Program
Files/Apache Software Foundation/Apache2.2/conf/httpd.conf: Cannot
load C:/JRun4/lib/wsconfig/1/mod_jrun20.so into server: The
specified procedure could not be found.
httpd.conf lines ---------------------------------
# JRun Settings
LoadModule jrun_module
"C:/JRun4/lib/wsconfig/1/mod_jrun20.so"
<IfModule mod_jrun20.c>
JRunConfig Verbose true
JRunConfig Apialloc false
JRunConfig Ssl false
JRunConfig Ignoresuffixmap false
JRunConfig Serverstore
"C:/JRun4/lib/wsconfig/1/jrunserver.store"
JRunConfig Bootstrap 127.0.0.1:51000
#JRunConfig Errorurl <optionally redirect to this URL on
errors>
AddHandler jrun-handler .jsp .jws
</IfModule>
BTW , Which procedure it is trying to find?
Can somebody help me.
Thanks in advance.
Suyog

And what happens on Apache 1.3?
Thanks in advance,
Lopato

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    j
    o
    e
    b
    e
    a
    c
    o
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