Applet server problem

Question

I have an applet that tries to call a servlet which is located back to the server (the same it came from). The result is:
java.security.AccessControlException: access denied
(java.net.SocketPermission localhost:80 connect,resolve)
at java.security.AccessControlContext.checkPermission(Unknown Source)
at java.security.AccessController.checkPermission(Unknown Source)
at java.lang.SecurityManager.checkPermission(Unknown Source)
at java.lang.SecurityManager.checkConnect(Unknown Source)
at sun.net.www.http.HttpClient.openServer(Unknown Source)
at sun.net.www.http.HttpClient.<init>(Unknown Source)
at sun.net.www.http.HttpClient.New(Unknown Source)
at sun.net.www.http.HttpClient.New(Unknown Source)
at
sun.net.www.protocol.http.HttpURLConnection.getNewHttpClient(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.plainConnect(Unknown
Source)
at sun.net.www.protocol.http.HttpURLConnection.connect(Unknown Source)
at
sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)
at java.net.URL.openStream(Unknown Source)
at
com.acer.applets.PackageVisualizationApplet.doEverythingElse(PackageVisualizationApplet.java:61)
at
com.acer.applets.PackageVisualizationApplet.init(PackageVisualizationApplet.java:45)
at sun.applet.AppletPanel.run(Unknown Source)
at java.lang.Thread.run(Unknown Source)
As i found to the web, an applet is permitted to open(only) a client socket without the need to be certified.
An other point is that, as i remember, an applet can communicate freely, only with the server it came from(without certification).
Is there any idea why is this happening?

Answer 1

Hi igorm3
Never tried such way but very successfull to communicate with scripts in server side using simple URL connection:
    final String
      USER_URL = "http://yourDomain/",
      SCRIPT_PATH = "scripPath/",
      SCRIPT = "yourScriptOrServlet";
    StringBuffer
      buff = new StringBuffer(USER_URL).append(SCRIPT_PATH).append(SCRIPT);
      buff.append("someQueryString");
    String result = null; // script response storage
    BufferedReader inp = null;
    try {
      URL url = new URL(buff.toString());
      URLConnection conn = url.openConnection();
      conn.setDoInput(true);
      conn.connect();
      inp = new BufferedReader(
              new InputStreamReader(conn.getInputStream()));
      result = inp.readLine();
      inp.close();
      inp = null;
    catch (MalformedURLException ue) {}
    catch (Exception e) {}
    finally {
      try { if (inp != null) inp.close(); } catch(IOException e) {}
    }Regards.