[ask]cpu time and disk i/o in tkprof

Question

this is result of tkprof
1     call     count       cpu    elapsed       disk      query    current        rows
2     ------- ------  -------- ---------- ---------- ---------- ----------  ----------
3     Parse        1      0.00       0.00          0          0          0           0
4     Execute      1      0.00       0.00          0          0          0           0
5     Fetch     1001      2.55       5.46      49517      39884          0      100000
6     ------- ------  -------- ---------- ---------- ---------- ----------  ----------
7     total     1003      2.55       5.47      49517      39884          0      100000what is the relationship between the cpu time with the disk??

Answer 1

I mean, what effect the disk to cpu time?What is the effect of barometric pressure to water depth?
When all else fails, Read The Fine Manual
http://download.oracle.com/docs/cd/B19306_01/server.102/b14211/sqltrace.htm#PFGRF01040
code]
count = number of times OCI procedure was executed
cpu = cpu time in seconds executing
elapsed = elapsed time in seconds executing
disk = number of physical reads of buffers from disk
query = number of buffers gotten for consistent read
current = number of buffers gotten in current mode (usually for update)
rows = number of rows processed by the fetch or execute call
There is minimal relationship between "cpu time in seconds executing" for most SQL and "number of physical reads of buffers from disk".
CPU Times includes CPU activity other than working to complete physical reads of buffers from disk
Each measures in its own units based upon activity two different subsystem components.