"Attention required | cloudfare.... one more step," what is it???

In the past few days, when I try to open some pages from google search, it leads me to the correct url but it first shows a page that says ATTENTION REQUIRED | CLOUDFARE
One more Step
Please complete the security check to access www.athriftymrs.com ... which was the website i was trying to visit.
and then it asks me to fill the captcha and something with a yield icon that says what can i do to prevent this in the future and it gives me a tip that I should use a malware scanner.
This is the link i tried to visit http://www.athriftymrs.com/2013/11/how-to-make-your-towels-fluffy-again.html
I never proceeded to enter the captcha but I really want to know what is going on. Because on windows, it supposedly means that you have malware and you should delete or change some host files.... but Im not really sure with the mac os X 10.7.5 tho.
HELP!  btw, this happened on a couple of other websites too...

Well! I am not a tech guy. I am just a tech enthusiast and an end user of Apple products. I am a doctor but I do like to play with software, hardware and networking stuff that I get exposed to.
When I replied to for the first time, as above, I'd suggested you guys to use safari extensions to detect whether any website is a problematic one or not. After that (or maybe even before that reply), I personally have encountered cloudflare.com for many times. I think until now, I didn't realize what you guys were actually wanted to ask, in regards to cloudflare.com.
Before today, this thing didn't flash in my mind because of the following 2 reasons.
1. Even though, I've encountered cloudflare.com for at least 20/30 times in the past 2 months, I've never seen it as a problem (as you guys did). The reason behind me encountering that site (asking me to verify if I was human through a captcha) was too obvious to me after my 1st or 2nd encounter with cloudflare. Why? ... I am going to explain that below.
2. The cloudflare.com link that somebody have posted above, leads to the homepage of the cloudflare.com. And it is not the same page that we encounter while going to some other websites, e.g. athriftymrs.com link posted by @mh2khin above.
These 2 mistakes above, kept me away from understanding you guys' real concern.
SOLUTION to your problem (I've discovered this though my own encounters and don't know if this is posted elsewhere).
This website is not a threat to your security. It is not a malicious software or a survey loop or a website that wants to sell you something.
Actually, the website sees you guys as threat to the security and services of its own and its clients. And that's the reason behind cloudflare.com asking you to enter captcha solution to confirm that you are a human and not a bot.
Just google cloudflare.com and you will know what it is and what services it provides.
I really don't know the proper tech terms but, what I've understood by myself from the first/second encounter with the website is that coludflare.com is a web hosting service. It is a cloud based server or something of that sort. So, when you want to visit a website that is hosted on cloudflare.com servers, it is cloudflar.com's responsibility to protect the data and service of cloudflare and its clients. Also, by asking the captcha thingy, cloudflare.com security is trying to avoid automated traffic attack though bots.
Ok, now I understood that the website is just trying to protect itself.
But, BIG QUESTION:            WHY ME ?          (in you guys' cases ME = you)???
Well, I have a sure-hot answer for "WHY ME" (ME= TimbukTrue)?  And most likely, it is also the case when ME= mh2khin or dipakcg, etc.
It is because I was experimenting with VPNs or  Proxy server bypasses  or a TOR Browser,  when I encountered the problem.
As I've tried to explain above, the cloudflare.com is a web hosting service. It is trying to protect itself and its clients.
Even though, VPN / Proxy server / TOR are highly secure services that protect my identity, their exit IPs are limited in numbers. While the number of subscribers they carry could be any number. It is most certain that the IP address that cloudflare.com getting signals from (via VPN/Proxy/TOR) is used by thousands of people around the world everyday. Thus, cloudflare.com's safety mechanism sees it as a threat and wants you to prove yourself as an alive human before letting you in and increasing incoming and outgoing traffic as well as accessing data stored on their servers.
Sorry for this big essay, but, as I've mentioned earlier, I am not a tech guy. So, I couldn't keep it short and sweet.
Anyways.
I can say for sure that cloudflare.com is safe and good website. In my above post, I have mentioned a safari extension named 'WOT' (Web Of Trust). I have attached a picture of WOT rating of cloudflare.com to support my belief that cloudflare.com is safe to visit.
Check the reputation of cloudflare.com at https://www.mywot.com/en/scorecard/cloudflare.com
If you still don't want to see cloudflare.com on your way to your desired website, try to go thru a unique end user IP (e.g. home broadband connection) and not through a professional bypass service (e.g. VPN, Proxy, TOR etc.).
I hope this helps you guys.
✌️

Similar Messages

  • I bought a photoshop CS5(for two users). If I add one more user, what can I do?

    I bought a photoshop CS5, and it indicated for two users only. If I want to add one more user, then what can I do?

    Buy another license.
    You can only activate two copies of the software and they're supposed to be for the same person and not used simultaneously.

  • Tunning Required! One more one for the Challengers!

    Hi all,
    This is one more to challenge!
    SELECT COUNT(1) FROM WHSE_LOC WHERE ((AREA_C,WKSTN_C) IN (SELECT AREA_C, WKSTN_C FROM WHSE_LOC WHERE AISLE_I = :B3 AND BIN_I = :B2 AND LVL_I = :B1 ) ) AND (AISLE_I,BIN_I,LVL_I) NOT IN (SELECT AISLE_I, BIN_I, LVL_I FROM WHSE_LOC WHERE AISLE_I = :B3 AND BIN_I = :B2 AND LVL_I = :B1 );
    I have the above query in one among the packages. My DBA reports that this query is the longest running in our database from : 7.22PM to 8.15PM IST.
    The record size currently is around 38500. This works when the records size is less than 5000 but when gone beyond that this fails. Can anybody help in this reg.?
    The following is the description of the table:
    desc whse_loc
    Name Null? Type
    AISLE_I NOT NULL NUMBER(3)
    BIN_I NOT NULL NUMBER(3)
    LVL_I NOT NULL NUMBER(2)
    AREA_C NOT NULL CHAR(4)
    WKSTN_C NOT NULL CHAR(4)
    STRG_ZONE_I NOT NULL NUMBER(2)
    SIZE_C NOT NULL CHAR(2)
    PULL_SEQ_I NOT NULL NUMBER(6)
    PUTAWAY_SEQ_I NOT NULL NUMBER(5)
    STRG_LOC_STAT_C NOT NULL CHAR(3)
    PALT_ID_CT_Q NOT NULL NUMBER(3)
    PULL_PALT_ID_CT_Q NOT NULL NUMBER(3)
    FLR_AIR_C NOT NULL CHAR(1)
    PALT_PULL_ALLOW_F NOT NULL CHAR(1)
    CTN_PULL_ALLOW_F NOT NULL CHAR(1)
    SSP_PULL_ALLOW_F NOT NULL CHAR(1)
    HOLD_STAT_C NOT NULL VARCHAR2(4)
    HOLD_REAS_T VARCHAR2(32)
    STRG_LOC_HOLD_TS DATE
    HOLD_USER_ID CHAR(7)
    MODF_USER_ID NOT NULL CHAR(7)
    MODF_PGM_N NOT NULL CHAR(8)
    MODF_TS NOT NULL DATE
    DPT_Q NUMBER(1)
    Pls. help me reg. optimizing the same!

    You are accessing the table three times, and you can reduce that to one:
    SQL> create table whse_loc (aisle_i, bin_i, lvl_i, area_c, wkstn_c)
      2  as
      3  select 1, 1, 1, 'A', 'A' from dual union all
      4  select 1, 1, 1, 'A', 'B' from dual union all
      5  select 1, 1, 2, 'A', 'A' from dual union all
      6  select 1, 1, 2, 'A', 'B' from dual union all
      7  select 1, 1, 2, 'A', 'C' from dual union all
      8  select 1, 1, 3, 'A', 'A' from dual union all
      9  select 1, 1, 3, 'A', 'B' from dual union all
    10  select 1, 1, 3, 'A', 'C' from dual union all
    11  select 1, 1, 3, 'A', 'D' from dual
    12  /
    Table created.
    SQL> var B1 number
    SQL> var B2 number
    SQL> var B3 number
    SQL> exec :B1 := 1; :B2 := 1; :B3 := 1
    PL/SQL procedure successfully completed.
    SQL> SELECT COUNT(1)
      2    FROM WHSE_LOC
      3   WHERE ( (AREA_C,WKSTN_C) IN
      4           ( SELECT AREA_C
      5                  , WKSTN_C
      6               FROM WHSE_LOC
      7              WHERE AISLE_I = :B3
      8                AND BIN_I = :B2
      9                AND LVL_I = :B1
    10           )
    11         )
    12     AND (AISLE_I,BIN_I,LVL_I) NOT IN
    13         (SELECT AISLE_I
    14               , BIN_I
    15               , LVL_I
    16            FROM WHSE_LOC
    17           WHERE AISLE_I = :B3
    18             AND BIN_I = :B2
    19             AND LVL_I = :B1
    20         )
    21  /
      COUNT(1)
             4
    1 row selected.That is your current query. The last predicate can be simplified like this:
    SQL> SELECT COUNT(1)
      2    FROM WHSE_LOC
      3   WHERE (AREA_C,WKSTN_C) IN
      4         ( SELECT AREA_C
      5                , WKSTN_C
      6             FROM WHSE_LOC
      7            WHERE AISLE_I = :B3
      8              AND BIN_I = :B2
      9              AND LVL_I = :B1
    10         )
    11     AND (  aisle_i != :B3
    12         OR bin_i != :B2
    13         OR lvl_i != :B1
    14         )
    15  /
      COUNT(1)
             4
    1 row selected.Note that the query below doesn't give the right result:
    SQL> SELECT COUNT(*)
      2  FROM  (SELECT DISTINCT AREA_C, WKSTN_C
      3         FROM   WHSE_LOC
      4         WHERE  AISLE_I = :B3 AND
      5                BIN_I   = :B2 AND
      6                LVL_I   = :B1)
      7  /
      COUNT(*)
             2
    1 row selected.By using an analytic function, the table scans are reduced to one:
    SQL> select sum(count_area_wkstn-1)
      2    from ( select whse_loc.*
      3                , count(*) over (partition by area_c, wkstn_c) count_area_wkstn
      4             from whse_loc
      5         )
      6   where aisle_i = :b3
      7     and bin_i = :b2
      8     and lvl_i = :b1
      9  /
    SUM(COUNT_AREA_WKSTN-1)
                          4
    1 row selected.Doing the same with other parameters:
    SQL> exec :B1 := 2; :B2 := 1; :B3 := 1
    PL/SQL procedure successfully completed.
    SQL> SELECT COUNT(1)
      2    FROM WHSE_LOC
      3   WHERE ( (AREA_C,WKSTN_C) IN
      4           ( SELECT AREA_C
      5                  , WKSTN_C
      6               FROM WHSE_LOC
      7              WHERE AISLE_I = :B3
      8                AND BIN_I = :B2
      9                AND LVL_I = :B1
    10           )
    11         )
    12     AND (AISLE_I,BIN_I,LVL_I) NOT IN
    13         (SELECT AISLE_I
    14               , BIN_I
    15               , LVL_I
    16            FROM WHSE_LOC
    17           WHERE AISLE_I = :B3
    18             AND BIN_I = :B2
    19             AND LVL_I = :B1
    20         )
    21  /
      COUNT(1)
             5
    1 row selected.
    SQL> SELECT COUNT(1)
      2    FROM WHSE_LOC
      3   WHERE (AREA_C,WKSTN_C) IN
      4         ( SELECT AREA_C
      5                , WKSTN_C
      6             FROM WHSE_LOC
      7            WHERE AISLE_I = :B3
      8              AND BIN_I = :B2
      9              AND LVL_I = :B1
    10         )
    11     AND (  aisle_i != :B3
    12         OR bin_i != :B2
    13         OR lvl_i != :B1
    14         )
    15  /
      COUNT(1)
             5
    1 row selected.
    SQL> select sum(count_area_wkstn-1)
      2    from ( select whse_loc.*
      3                , count(*) over (partition by area_c, wkstn_c) count_area_wkstn
      4             from whse_loc
      5         )
      6   where aisle_i = :b3
      7     and bin_i = :b2
      8     and lvl_i = :b1
      9  /
    SUM(COUNT_AREA_WKSTN-1)
                          5
    1 row selected.And yet another combination, with the explain plans so you can see the number of table scans.
    SQL> exec :B1 := 3; :B2 := 1; :B3 := 1
    PL/SQL procedure successfully completed.
    SQL> set autotrace on explain
    SQL> SELECT COUNT(1)
      2    FROM WHSE_LOC
      3   WHERE ( (AREA_C,WKSTN_C) IN
      4           ( SELECT AREA_C
      5                  , WKSTN_C
      6               FROM WHSE_LOC
      7              WHERE AISLE_I = :B3
      8                AND BIN_I = :B2
      9                AND LVL_I = :B1
    10           )
    11         )
    12     AND (AISLE_I,BIN_I,LVL_I) NOT IN
    13         (SELECT AISLE_I
    14               , BIN_I
    15               , LVL_I
    16            FROM WHSE_LOC
    17           WHERE AISLE_I = :B3
    18             AND BIN_I = :B2
    19             AND LVL_I = :B1
    20         )
    21  /
      COUNT(1)
             5
    1 row selected.
    Execution Plan
    Plan hash value: 2315582378
    | Id  | Operation            | Name     | Rows  | Bytes | Cost (%CPU)| Time     |
    |   0 | SELECT STATEMENT     |          |     1 |    90 |    13   (8)| 00:00:01 |
    |   1 |  SORT AGGREGATE      |          |     1 |    90 |            |          |
    |*  2 |   FILTER             |          |       |       |            |          |
    |*  3 |    HASH JOIN SEMI    |          |     1 |    90 |     9  (12)| 00:00:01 |
    |   4 |     TABLE ACCESS FULL| WHSE_LOC |     9 |   405 |     4   (0)| 00:00:01 |
    |*  5 |     TABLE ACCESS FULL| WHSE_LOC |     1 |    45 |     4   (0)| 00:00:01 |
    |*  6 |    TABLE ACCESS FULL | WHSE_LOC |     1 |    39 |     4   (0)| 00:00:01 |
    Predicate Information (identified by operation id):
       2 - filter( NOT EXISTS (SELECT /*+ */ 0 FROM "WHSE_LOC" "WHSE_LOC"
                  WHERE "AISLE_I"=TO_NUMBER(:B3) AND "BIN_I"=TO_NUMBER(:B2) AND
                  "LVL_I"=TO_NUMBER(:B1) AND LNNVL("AISLE_I"<>:B1) AND LNNVL("BIN_I"<>:B2)
                  AND LNNVL("LVL_I"<>:B3)))
       3 - access("AREA_C"="AREA_C" AND "WKSTN_C"="WKSTN_C")
       5 - filter("AISLE_I"=TO_NUMBER(:B3) AND "BIN_I"=TO_NUMBER(:B2) AND
                  "LVL_I"=TO_NUMBER(:B1))
       6 - filter("AISLE_I"=TO_NUMBER(:B3) AND "BIN_I"=TO_NUMBER(:B2) AND
                  "LVL_I"=TO_NUMBER(:B1) AND LNNVL("AISLE_I"<>:B1) AND LNNVL("BIN_I"<>:B2)
                  AND LNNVL("LVL_I"<>:B3))
    Note
       - dynamic sampling used for this statement
    SQL> SELECT COUNT(1)
      2    FROM WHSE_LOC
      3   WHERE (AREA_C,WKSTN_C) IN
      4         ( SELECT AREA_C
      5                , WKSTN_C
      6             FROM WHSE_LOC
      7            WHERE AISLE_I = :B3
      8              AND BIN_I = :B2
      9              AND LVL_I = :B1
    10         )
    11     AND (  aisle_i != :B3
    12         OR bin_i != :B2
    13         OR lvl_i != :B1
    14         )
    15  /
      COUNT(1)
             5
    1 row selected.
    Execution Plan
    Plan hash value: 3820410662
    | Id  | Operation           | Name     | Rows  | Bytes | Cost (%CPU)| Time     |
    |   0 | SELECT STATEMENT    |          |     1 |    90 |     9  (12)| 00:00:01 |
    |   1 |  SORT AGGREGATE     |          |     1 |    90 |            |          |
    |*  2 |   HASH JOIN SEMI    |          |     1 |    90 |     9  (12)| 00:00:01 |
    |*  3 |    TABLE ACCESS FULL| WHSE_LOC |     1 |    45 |     4   (0)| 00:00:01 |
    |*  4 |    TABLE ACCESS FULL| WHSE_LOC |     1 |    45 |     4   (0)| 00:00:01 |
    Predicate Information (identified by operation id):
       2 - access("AREA_C"="AREA_C" AND "WKSTN_C"="WKSTN_C")
       3 - filter("AISLE_I"<>TO_NUMBER(:B3) OR "BIN_I"<>TO_NUMBER(:B2) OR
                  "LVL_I"<>TO_NUMBER(:B1))
       4 - filter("AISLE_I"=TO_NUMBER(:B3) AND "BIN_I"=TO_NUMBER(:B2) AND
                  "LVL_I"=TO_NUMBER(:B1))
    Note
       - dynamic sampling used for this statement
    SQL> select sum(count_area_wkstn-1)
      2    from ( select whse_loc.*
      3                , count(*) over (partition by area_c, wkstn_c) count_area_wkstn
      4             from whse_loc
      5         )
      6   where aisle_i = :b3
      7     and bin_i = :b2
      8     and lvl_i = :b1
      9  /
    SUM(COUNT_AREA_WKSTN-1)
                          5
    1 row selected.
    Execution Plan
    Plan hash value: 1194892149
    | Id  | Operation            | Name     | Rows  | Bytes | Cost (%CPU)| Time     |
    |   0 | SELECT STATEMENT     |          |     1 |    52 |     5  (20)| 00:00:01 |
    |   1 |  SORT AGGREGATE      |          |     1 |    52 |            |          |
    |*  2 |   VIEW               |          |     9 |   468 |     5  (20)| 00:00:01 |
    |   3 |    WINDOW SORT       |          |     9 |   405 |     5  (20)| 00:00:01 |
    |   4 |     TABLE ACCESS FULL| WHSE_LOC |     9 |   405 |     4   (0)| 00:00:01 |
    Predicate Information (identified by operation id):
       2 - filter("AISLE_I"=TO_NUMBER(:B3) AND "BIN_I"=TO_NUMBER(:B2) AND
                  "LVL_I"=TO_NUMBER(:B1))
    Note
       - dynamic sampling used for this statementRegards,
    Rob.

  • Append one more page in old spool number

    Hi friend's,
    I'm having a script for pick list, now my problem is, if igive the production order for 2nd time, the first spool number has append one more page. what is the solution?
    Thanks in Advance.
    Vallamuthu.M

    Hi,
    I guess your application uses a Smartform or a Sapscript form to create spools.
    For sapscripts, when the application call the function module you can useparameters ITCPO-TDNEWID and ITCPO-TDFINAL. For smartforms when you call the function module of the Smartform, you can set  'OUTPUT_OPTIONS-TDDEST' and 'OUTPUT_OPTIONS-TDNEWID'.
    regards,
    Aidan

  • I am trying to copy more or less 30G from my MacbookPro to an external hard drive and it is stuck in the "preparing to copy" step. But that for more than one hour. What should I do to make it faster? Thanks a lot in advance!

    I am trying to copy more or less 30G from my MacbookPro to an external hard drive and it is stuck in the "preparing to copy" step. But that for more than one hour. What should I do to make it faster? Thanks a lot in advance!

    Thanks Shootist007, by blockd files I mean files that I have changed to blocked and when I tried to move then for the first time, I had to unblock again. I am trying to backup my pictures, my songs and other files like word documents and excel tables. First I put all of them as blocked, what caused the first problems on trying to move them. Then, I've unchecked the block option and if I try to move one by one, there is no problem. The issue is to move all together, because it gets stuck in the preparing to copy files step. Anyway, if I cannot do all by once, I'll do it one by one, event though that was not suposed to happen if we are talking about technology, right? Anyway, I thank you again for trying to help me!

  • HT201628 I tried following the steps in this article. When I attempt to delete iTunes,  it says "iTunes" can't be modified or deleted because it's required by Mac OS X. What other steps could I take to get my MacBook Air to recognize my iphone again?

    I tried following the steps in this article. When I attempt to delete iTunes,  it says “iTunes” can’t be modified or deleted because it’s required by Mac OS X. What other steps could I take to get my MacBook Air to recognize my iphone again? Neither iTunes nor iPhoto recognize my phone any longer.

    iTunes can't be deleted because it comes with OS X. In order to delete it, open Terminal and copy:
    sudo rm /Applications/iTunes.app
    This will remove iTunes, so then you can reinstall iTunes

  • DCP in Adobe does it require more steps after export ?

    DCP in Adobe does it require more steps after export ?

    Provide the name of the program you are using so a Moderator may move this message to the correct program forum
    The Cloud is not a program, it is a delivery process... a program would be Photoshop or Lighroom or Muse or ???

  • How send video more than one minute via what's up

    How send video more than one minute via what's up

    Hi,
    I haven't tried but u can follow the below approach.
    popupBean1.setParameters("pItemID={@ItemID}&deptNo={@Deptno}")
    Regards,
    Gyan

  • For some reason my i pod doesn't have an app store.  I went to reset it and it asked for my restriction code.  I forgot what my restriction code was and now it's saying that I only have one more chance to try

    for some reason my i pod doesn't have an app store.  I went to reset it and it asked for my restriction code.  I forgot what my restriction code was and now it's saying that I only have one more chance to try?

    To restore see:
    iTunes: Backing up, updating, and restoring iOS software
    Restoring will not mess up your other iDevices

  • Evry time after sync. my iphone 4 ios 4.3.3 with itunes 10.3.1.55 the time change up one more hour ,, please tell me what can i do to solve this problem

    evry time after sync. my iphone 4 ios 4.3.3 with itunes 10.3.1.55 the time change up one more hour ,, please tell me what can i do to solve this problem

    This year, the government has canceled the daylight saving time , that's why happening this problem to me so I changed the time zone in iPhone from Cairo,Egypt (GMT+2 with daylight saving) to Harare,Zimbabwe (GMT+2 without daylight saving , no change in time from summer & winter) & now working good, no change in time after sync. , But it's very stupid thing from apple that they didn't add an option in time setting to enable or disable the daylight saving time like any other mobile.

  • I cannot get on to my Apple TV.  I know that they are now requiring a one time security code?  What is it How do I find it?

    I know that they are now requiring a one time security code.  How do I find it?  Does anyone know what it is?

    There is no such code required to use the Apple TV. A user can setup a passcode to be required for airplay, and Apple ID is required for use of the iTunes store (or any other subscriptions associated with it).

  • Credit card number change, your company can not charge , so , what can I do ?because I buy one year plan , but the plan stop already  ,I can not change the credit card details.So, I need to buy one more year or can continous the paln with changing the cre

    credit card number change, your company can not charge , so , what can I do ?because I buy one year plan ,
    but the plan stop already  ,I can not change the credit card details.
    So, I need to buy one more year or can continous the paln with changing the credit number?

    Hello pen pang,
    if your Photoshop is a part of Creative Cloud you can use "Manage your membership and payments|Creative Cloud" at
    http://helpx.adobe.com/x-productkb/policy-pricing/membership-subscription-troubleshooting- creative-cloud.html >>>
    Payment & credit card >>> Help changing the credit card on your account >>> from there see what hints are listed.
    On the other hand I'm sure that you can use the recommended procedure with a "normal" PS too.
    If necessary and for further questions click through http://helpx.adobe.com/contact.html and if "open" please use the chat, I had the best experiences. I quote from Adobe's employee Preran: The chat button is activated as soon as there is an agent available to help.
    If you need these explanations in another language, please use "Change" at the end/bottom of the website from above
    Good luck!
    Hans-Günter

  • One more person who can't send mail but can receive

    I sent mail last night and woke up this morning not being able to send mail.
    I can receive, but can't send. I can send to my self, but can't reply to others or create new.
    The email time out message say's the authentication is on. How that changed over night? Not sure.
    Under Mail preferences, Account information, outgoing server settings-
    I've been using 2525 with no authentication for over a year. I noticed someone suggesting 465 and 587... didn't work.
    I went into advanced and saw where it IS asking for authentication (using password) but in the drop down list it doesn't give the word 'none' just like the account option had to select.
    I used the connection Doctor and I have connection...
    what else can I do?
    Thank you for the help
    Chelle

    The standard TCP-port for SMTP is 25. If this doesn't work, try to authenticate to the SMTP-server with the credentials of your POP3-login. Maybe your ISP reconfigured his SMTP-servers to use aSMTP.
    Some other ISP use a method called "SMTP-after-POP3". This means, that you must fetch your mail using POP3 first. After doing this, you have a specific period of time (at most ISPs 5 to 15 minutes) to send mail from the same IP-address as you have POPed before. This is for additional security.
    One more reason could be that your configured SMTP-server is simply "dead" or offline for system maintenance. To check if the machine is alive, go to terminal and
    ping nameofyourserver
    and see if it responds. If so, try connecting on the SMTP port by typing
    telnet nameofyourserver 25
    These steps can provide additional information to find the cause for your problem.

  • Count of windows in Safari returns one more than actual

    First of all I'm completely new to Applescript.
    What I do at the moment is to search for scripts that might do something similar to want I want and then modify them to suit my particular requirements.
    I have been trying to use a script that searches for a particular URL in Safari.
    Here is an excerpt from the script:-
    tell application "System Events"
         tell application "Safari"
              set windowCount to count of windows
              repeat ...
         end tell
    end tell
    The problem is that the value returned by "set windowCount to count of windows" returns a value which is one more than the actual number of Windows that are open.
    Can anyone tell me why it is going wrong?
    Many Thanks
    I'm using Script Editor 2.7(176), AppleScript 2.4 on a late 2008 MacBook running Yosemite 10.10.2 and Safari Version 8.0.3 (10600.3.18)

    Hi,
    Try this (don't use this script in the 'tell application "System Events"' block) :
    set tUrls to {}
    tell application "Safari"
        repeat with thisWind in (get windows whose its document is not missing value)
            repeat with thisTab in (get tabs of thisWind)
                set t to URL of thisTab
                if t contains "search string" then set end of tUrls to t
            end repeat
        end repeat
    end tell
    tUrls

  • One more generics question

    One more dumbshit generics question...
    Is there a way to do this without the warnings or the @SuppressWarnings({"unchecked"})
       * Returns the index of the last occurrence of the specified element in this
       * list, or -1 if this list does not contain the element.
      //@SuppressWarnings({"unchecked"})
      public int lastIndexOf(Object object) {
        int i = 0;
        int last = -1;
        for(Node<E> node=this.head.next; node!=null; node=node.next) {
          if (node.item.equals((E) object)) {
            last = i;
          i++;
        return(last);
    produces the warning
    C:\Java\home\src\linkedlist\LinkedList.java:313: warning: [unchecked] unchecked cast
    found   : java.lang.Object
    required: E
          if (node.item.equals((E) object)) {
                                   ^... remembering that List specifies +public int lastIndexOf(Object object);+ as taking a raw Object, not E element, as I would have expected.
    Thanx all. Keith.
    PS: Crossposted from the tail of http://forum.java.sun.com/thread.jspa?messageID=10225418&#10225418
    which nobody has answered, I presume because the thread is marked as "answered".

    I'm not sure you understood or if I made myself clear. Or perhaps I'm missing a vital detail in your implementation.
    I'm talking about the cast to E in this line:if (node.item.equals((E) object)) {Object.equals() takes a parameter of type Object. So the cast to E is superfluous. That cast is what's causing the warning. You remove the cast => no more warning => you can remove the SuppressWarnings annotation.
    Unless your E's have an overloaded equals() that takes an argument of type E. In that case you'll have to live with it.

Maybe you are looking for

  • Cannot Sign in to Ebay ONLY problems, cache, cookies, firewall, what happened???

    Hi and thanks in advance for anyone who can help with any suggestions. I downloaded the new version of firefox a few weeks back. The next day I noticed I could not sign in to my Ebay account. I can go anywhere else on the internet and all my sign in/

  • Output for EDI

    hiall, here i have a scenario where i have to give Advance shipment Notification to the customer ,now i have made the basic setting of EDI and the output cond type i'm using is LAVA.which is in the delivery. now when i do issue output i could see the

  • With iOS5 and Cloud - it *appears* the iPad2 is the right choice for me...

    Like many people, Ive been hemming and hawing over whether to go with an iPad2 or an Android device.  Ive read the reviews, watched the product demos, and analyzed what each device can and cannot do.  Im not an Apple "guy" per say but Im not a PC-die

  • KeyListener implementation

    I am trying to implement a key listener for the first time, and having trouble. Can you please look at the following code snippet and tell me what's wrong? void meth1()throws Exception{ this.addKeyListener(new KeyListener (){ public void keyPressed(K

  • Can not get iso7.0.3 update to download gives a error message

    No problem except on this 1 ipad