Beginner question! Calling servlet from a browser

Hello,
Does anyone know how to set up the JSDK server to run
servlets class files from a different directory to the default? (the default being, I think, webpages/web-inf/servlets)
Can't find info in the documentation that I can understand ... is it
the default.cfg file? If so I can't figure out what needs to
be put in there.
Help appreciated!

Try downloading Apache Tomcat 4.0. It is a great free Servlet/JSP container. Very easy to install and you can easily configure where you are going to place your servlets.

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Calling servlet from a java program

Hi
I need to call a servlet's doPost() method from a java program. I have a specific situation, where I need to call servlet from a java program. DUring this call I need to pass a file and two string to the servlet. Servelt after receiving the file and string uploads the file to the server at a specified location. I am stuck up as how to call servlet from a java program instead of a HTML or JSP.
Can anyone help me to start with this.
any suggestion is welcome.

You have to establish a URLConnection with servlet from your java program.
URL servletURL = new URL("http://localhost:8080/Myservlet?str1=abc&str2=def");
URLConnection servletConnection = servletURL.openConnection();you can get the objectOutputStream
ObjectOutputStream oos = new ObjectOutputStream (servletConnection.getOutputStream());
oos.writeObject(your file object);-------------------------------------------------
In the servlet u can get the strings using request.getParameter("str1");
In the servlet u can get the strings using request.getParameter("str2");
file = new ObjectInputStream (request.getInputStream()).readObject()a lot of resources are available on this ...
hope this helps :)

Calling Servlet from a java prog?

Hi all,
I am calling servlet from a java prog (Java Agent in Lotus Notes) by using URL and URLConnection object. how can i trigger the Servlet By using doPost method .I have to send some parameter also.
Thanx
Muthu

you need to open a connection to the servlet. Then you must call getInputStream() and getOutputStream() and use them in any way you see fit. I was trying this before and could not get POST to work unless I openned the input stream from the servlet. Strange... but doGet worked without openning the input stream???
// open a connection....
// write to the servlet
servletConnection.getOutputStream().write("whatever");
servletConnection.getOutputStream().flush();
servletConnection.getOutputStream().close();
// grab what the servlet sends back, required to do a post.
byte [] in = new byte[100];
servletConnection.getInputStream().read(in);
servletConnection.getInputStream().close();

Wot all ways are there to call servlet from jsp

hi all
i want to know wot all methods are available
so that i can call servlet from jsp
the one which i know is using RequestDispatcher
wot are others ?
thanx

hi all
i want to know wot all methods are available
so that i can call servlet from jsp
the one which i know is using RequestDispatcher
wot are others ?
thanxhi here are few ways... to call servlet from jsp...
these are just generic syntax.
Form:
<form action="ServletPath">
Link:
Directives & Action tags :
<%@ page import="ServletPath" %>
     <%@ taglib uri="ServletPth" %>
     <jsp:include page="ServletPath">
     <jsp:forward page="ServletPath">
     <jsp:useBean class="ServletPath"> (Not sure about this useBean)
hope you got your answer.
regards,
immu

How to call Servlet from jsp page and how to run this app using tomcat..?

Hi ,
I wanted to call servlet from jsp action i.e. on submit button of JSP call LoginServlet.Java file.
Please tell me how to do this into jsp page..?
Also i wanted to execute this application using tomcat.
Please tell me how to do this...? what setting are required for this...? what will be url ..??
Thanks.

well....my problem is as follows:
whenever i type...... http://localhost:8080/appName/
i am getting 404 error.....it is not calling to login.jsp (default jsp)
but when i type......http://localhost:8080/appName/login.do........it executes servlet properly.
Basically this 'login.do' is form action (form action='/login.do').....and i wanted to execute this from login jsp only.(from submit button)
In short can anyone please tell me how to diaplay jsp page using tomcat 5.5
plz help me.

Calling servlets from main()?

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I would like to know that while calling servlets from another class having main(), how can we set the type of request i.e. put, post or get?
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use the method - setRequestMethod( "POST") of HttpURLConnection for setting the method to POST.Similarly for other methods..
You could find [url http://java.sun.com/developer/JDCTechTips/2004/tt0210.html#2]this useful

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I need to call servelt class from the <netui:anchor ..> tag of my jpf.
i have mapped this servlet class in the web.xml.
please tell us how to invoke servlet from the netui:anchor tag from the jpf action
method.
thanks
shashi

I am calling a Servlet from JAVA Class as I am using IDE: Eclipse. The Problem is below
URL url = new URL(ServletPath);
URLConnection connet = url.openConnection();Why should the Servlet running in different Runtime print on your Eclipse Runtime. Please be more clear about the question.

Calling servlet from Java

Hello!
I need to send XML file to servlet from Java. I generate XML in general java class.
Is there any way how to call servlet directly from Java without using a page with form? I need to send it by post method. I need some java alternative to Microsoft.XMLHTTP object.
Thanks

Try this part of the Networking tutorial:
http://java.sun.com/docs/books/tutorial/networking/urls/index.html
It might be the answer to your question.

Calling Servlet from Java Class in eclipse

Hi ,
I am calling a Servlet from JAVA Class as I am using IDE: Eclipse. The Problem is below
URL url = new URL(ServletPath);
URLConnection connet = url.openConnection();
I am using the above code in JAVA to Connect to Servlet I have given Print statement in Servlet such that whenever it calls it prints on Console but when I try to run the code the Statement is not printed in the Console of eclipse I think URL connection is not able to establish any connection ..... if any has solution for this please reply
Thanks & Regards,
Arvind

I am calling a Servlet from JAVA Class as I am using IDE: Eclipse. The Problem is below
URL url = new URL(ServletPath);
URLConnection connet = url.openConnection();Why should the Servlet running in different Runtime print on your Eclipse Runtime. Please be more clear about the question.

How to call servlet from applet residing in Oracle9i forms bean area.

Dear Members
I have an applet which is calls a servlet for database operations. If access this from a browser it works fine as the applet is signed. But When i place this applet in a bean area of Forms in Oracle 9i. It gives access control exception. Can anyone help me, as i feel this problem is with oracle9i forms.

Dear Members
I have an applet which is calls a servlet for database
operations. If access this from a browser it works
fine as the applet is signed. But When i place this
applet in a bean area of Forms in Oracle 9i. It gives
access control exception. Can anyone help me, as i
feel this problem is with oracle9i forms.As far as I recall - Oracle 9i forms is operating on a top of another special/internal servlet. I can't really recall, since I've been working with Oracle 9i forms 2 yrs ago. So total procedure looks like following:
applet -> Oracle 9i Forms servlet -> my servlet
instead of
applet -> my servlet
I think this is an actual reason why your signed applet can't work with your servlet.
Oracle 9i servlet has a number configuration files, I think among them you should change smth to get your construction working. Another approach would be to use servlet filtering before calling Oracle 9i servlet
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Paul

About calling servlet from an applet

In one of my jsp, I have an applet which is to call a servlet. When I run it, I get an error in the status bar of IE. It says 'Exception: java.lang.runtimeException: java.security.AccessControlException: access denied (java.net.SocketPermission localhost:8080....)'
Does anybody have similar experience?
Thanks,
Joe

hi;
to call a servlet from applet i give you a link:http://www.j-nine.com/pubs/applet2servlet/Applet2Servlet.html.
read cearfuly, and if you have any question you can post it to me?
goodluck

How to call servlet from jsp

i m trying to call it from jsp using
<a href="../purchaseP?orderno=<%=pno%>"><%=pno%></a>
but its giving error..
type Status report
message HTTP method GET is not supported by this URL
description The specified HTTP method is not allowed for the requested resource (HTTP method GET is not supported by this URL).

i m trying to call it from jsp using
<a href="../purchaseP?orderno=<%=pno%>"><%=pno%></a>
but its giving error..
type Status report
message HTTP method GET is not supported by this URL
description The specified HTTP method is not allowed
for the requested resource (HTTP method GET is not
supported by this URL).Are you implementing the doGet or doPost method in your servlet? If you are calling from a hyperlink then it needs to be implementing the GET method. To access the POST method use a html form.

Problem while calling servlet from java bean

I am trying to call a servlet from java bean in cep.
My java bean:
package com.bea.wlevs.example.algotrading;
import com.bea.wlevs.ede.api.StreamSink;
import com.bea.wlevs.example.algotrading.event.MarketEvent;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.Unmarshaller;
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.StringReader;
import java.net.MalformedURLException;
import java.net.URL;
import java.net.URLConnection;
public class MarketEventBean implements StreamSink {
     String s=null;
     public void onInsertEvent(Object event) {
          if (event instanceof MarketEvent) {
               MarketEvent marketEvent = (MarketEvent) event;
               try {
                    JAXBContext cxt = JAXBContext.newInstance(MarketEvent.class);
                    Unmarshaller unmarsh = cxt.createUnmarshaller();
                    StringReader strReader = new StringReader(marketEvent.getString_1());
                    MarketEvent obj = (MarketEvent) unmarsh.unmarshal(strReader);
                    s=obj.getSymbol();
                    System.out.println("data: " + s);
               } catch(Exception e) {
                    e.printStackTrace();
               try {
                    System.out.println("test1");
     URL url = new URL("http://172.18.21.94:7001/AppServletrecv-Model-context-root/ReceiveServlet");
     URLConnection conn = url.openConnection();
          System.out.println("test2");
     conn.setDoOutput(true);
          System.out.println("test3");
     BufferedWriter out =
     new BufferedWriter( new OutputStreamWriter( conn.getOutputStream() ) );
     out.write("symbol="+s);
          System.out.println("test4");
     out.flush();
     System.out.println("test5");
     out.close();
     System.out.println("test6");
     BufferedReader in =
     new BufferedReader( new InputStreamReader( conn.getInputStream() ) );
          System.out.println("test7");
     String response;
     while ( (response = in.readLine()) != null ) {
     System.out.println( response );
     in.close();
     catch ( MalformedURLException ex ) {
     // a real program would need to handle this exception
     catch ( IOException ex ) {
     // a real program would need to handle this exception
My servlet code:
package model;
import javax.servlet.http.HttpServlet;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class ReceiveServlet extends HttpServlet {
private final static String _SYMBOL = "symbol";
public void doPost(HttpServletRequest request, HttpServletResponse response) {
* Get the value of form parameter
// private final static String USERNAME = "username";
String symbol = request.getParameter( _SYMBOL );
* Set the content type(MIME Type) of the response.
response.setContentType("text/html");
* Write the HTML to the response
try {
PrintWriter out = response.getWriter();
out.println("<html>");
out.println("<head>");
out.println("<title> A very simple servlet example</title>");
out.println("</head>");
out.println("<body>");
out.println("<h1>Hello " + symbol +"</h1>");
out.println("</body>");
out.println("</html>");
out.close();
} catch (IOException e) {
Web.xml:
<?xml version = '1.0' encoding = 'windows-1252'?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
version="2.5" xmlns="http://java.sun.com/xml/ns/javaee">
<servlet>
<servlet-name>ReceiveServlet</servlet-name>
<servlet-class>model.ReceiveServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>ReceiveServlet</servlet-name>
<url-pattern>/ReceiveServlet</url-pattern>
</servlet-mapping>
</web-app>
My servlet is running in weblogic server.
But when I am running this program in weblogic server side there is no log.
Edited by: 856272 on Jun 23, 2011 6:43 AM

I would run both sides in a debugger and see what code is getting invoked

Very urgent: call servlet from JSP

Hello,
I'm facing a problem in invoking a servlet from a JSP having the JSF components.
The application has a text field to implement ajax for search functionality in the database .I have written a servlet to make the database connection and fire the querry.
Ajax implementation in a js file is called on every keyup event in the jsp file,and
a call is given to the servlet from the ajax methode.
The function in the js file is as follows:-
function getPersonByFirstNameXML( firstName ) {
    if (!firstName) {
        clearPersonByFirstNameXML();
    } else {
        var url = BASE_URL + "/servlet/get_PersonsXML";
        alert(url);
        return new AJAXRequest("post", url, "firstName=" + encode(firstName), processGetPersonByFirstNameXML);
}Im getting the myAJAX.status value as 500.
I think I'm not able to access the servlet properly.
what changes do i need to make in the we.xml file ?
and what should be the url to be passed.
Please provide me a sloution to the above problem as it is very urgent else if anybody is aware of a readymade JSF componet with search functionality freely available please let me know.
PS:
The sample application named RedirectionExample which makes use of a servlet and would be of help to you. You can find the tutorial on the following page:
http://developers.sun.com/prodtech/javatools/jscreator/reference/codesamples/sampleapps.html
is not available as stated in some of the suggestions by Author: mayagiri
Thanks for any help.
Abhi

the status 500 generally means either HTTP server internal error or that execution of CGI script or servlet aborted with error.
It can be reasonably supposed that the request reaches the servlet, ie. that "url" value points to some existing servlet, otherwise most probably the status value would be 404.
To test that the servlet is working i'd try to access it using some simple html page with form like this (with {BASE_URL} replaced by real value):
<form method=post action={BASE_URL}/servlet/get_PersonsXML>
<input type=text name=firstName>
<input type=Submit>
</form>

Beginner question! Calling servlet from a browser

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