Best way to outer join a table that is doing a sub query
RDBMS : 11.1.0.7.0
Hello,
What is the best way to outer join a table that is doing a sub query? This is a common scenario in EBS for the date tracked tables.
SELECT papf.full_name, fu.description
FROM fnd_user fu
,per_all_people_f papf
WHERE fu.user_id = 1772
AND fu.employee_id = papf.person_id(+)
AND papf.effective_start_date = (SELECT MAX( per1.effective_start_date )
FROM per_all_people_f per1
WHERE per1.person_id = papf.person_id)Output:
No output produced because the outer join cannot be done on the sub queryIn this case I did a query in the FROM clause. Is this my best option?
SELECT papf.full_name, fu.description
FROM fnd_user fu
,(SELECT full_name, person_id
FROM per_all_people_f papf
WHERE papf.effective_start_date = (SELECT MAX( per1.effective_start_date )
FROM per_all_people_f per1
WHERE per1.person_id = papf.person_id)) papf
WHERE fu.user_id = 1772
AND fu.employee_id = papf.person_id(+)Output:
FULL_NAME DESCRIPTION
{null} John DoeThanks,
--Johnnie
Hi,
BrendanP wrote:
... See the adjacent thread for the other with Row_Number().Do you mean {message:id=10564772} ? Which threads are adjacent is always changing. Post a link.
I think RANK suits the requirements better than ROW_NUMBER:
WITH all_matches AS
SELECT papf.full_name
, fu.description
, RANK () OVER ( PARTITION BY papf.person_id
ORDER BY papf.effective_start_date DESC
) AS r_num
FROM fnd_user fu
LEFT OUTER JOIN per_all_people_f papf ON fu.employee_id = papf.person_id
WHERE fu.user_id = 1772
SELECT full_name
, description
FROM all_matches
WHERE r_num = 1
Johnnie: I hope this answers your question.
If not, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) for all tables involved, and also post the results you want from that data.
See the forum FAQ {message:id=9360002}
Similar Messages
-
Hi
Let's say I have three tables ORDERS, PRODUCT and CLIENT. I want a query that will give me all PRODUCT and CLIENT combinations and the total sum of orders if it has one. If I try to do this:
select P.NAME, C.NAME, SUM(O.AMOUNT)
from PRODUCT P, CLIENT C, ORDER O
where P.ID = O.PRODUCT_ID(+) and
C.ID = O.CLIENT_ID(+)
I get an error where I cannot double outer join a table.
Any ideas?3360 wrote:
BluShadow wrote:
and ANSI allows a little more in those terms than regular oracle syntax.It is different, but it cannot do anything that regular equi-joins cannot do. In most cases the optimizer converts ANSI joins to regular joins for execution, and this additional conversion has been subject to numerous bugs.ANSI does allow for doing things that regular Oracle syntax cannot do.
Here's an ANSI way to do it if you only want to see those client/product combinations that exist in orders table:
SQL> with product as (
2 select 101 id, 'Product 1' name from dual union all
3 select 102 id, 'Product 2' name from dual union all
4 select 103 id, 'Product 3' name from dual
5 ), client as (
6 select 11 id, 'Client 1' name from dual union all
7 select 12 id, 'Client 2' name from dual
8 ), orders as (
9 select 11 client_id, 101 product_id, 10 amount from dual union all
10 select 11 client_id, 103 product_id, 30 amount from dual union all
11 select 12 client_id, 102 product_id, 20 amount from dual union all
12 select 12 client_id, 102 product_id, 20 amount from dual
13 )
14 --
15 -- end-of-test-data
16 --
17 select p.name
18 , c.name
19 , sum(o.amount)
20 from orders o
21 left outer join product p
22 on p.id = o.product_id
23 left outer join client c
24 on c.id = o.client_id
25 group by
26 p.name
27 , c.name
28 order by
29 p.name
30 , c.name
31 /
NAME NAME SUM(O.AMOUNT)
Product 1 Client 1 10
Product 2 Client 2 40
Product 3 Client 1 30(If the datamodel is good with product_id being a foreign key of product.id and the same with client, then outer join is not really necessary, I know. But for the sake of argument assume bad datamodel that needs outer join ;-) )
The above ANSI can be written in regular Oracle syntax as well:
SQL> with product as (
2 select 101 id, 'Product 1' name from dual union all
3 select 102 id, 'Product 2' name from dual union all
4 select 103 id, 'Product 3' name from dual
5 ), client as (
6 select 11 id, 'Client 1' name from dual union all
7 select 12 id, 'Client 2' name from dual
8 ), orders as (
9 select 11 client_id, 101 product_id, 10 amount from dual union all
10 select 11 client_id, 103 product_id, 30 amount from dual union all
11 select 12 client_id, 102 product_id, 20 amount from dual union all
12 select 12 client_id, 102 product_id, 20 amount from dual
13 )
14 --
15 -- end-of-test-data
16 --
17 select p.name
18 , c.name
19 , sum(o.amount)
20 from orders o, product p, client c
21 where p.id(+) = o.product_id
22 and c.id(+) = o.client_id
23 group by
24 p.name
25 , c.name
26 order by
27 p.name
28 , c.name
29 /
NAME NAME SUM(O.AMOUNT)
Product 1 Client 1 10
Product 2 Client 2 40
Product 3 Client 1 30Many old Oracle coders will probably state that this syntax is much easier. For a simple case like this I find both ways easy. But I have complex cases where I much prefer ANSI where I can easily distinguish join predicates from filter predicates. It is a matter of opinion, I know ;-)
But if we then take the original post as a literal specification, that we want all combinations of products and clients and then the sum of order amount if it exists, null otherwise.
This can be written easily in ANSI notation:
SQL> with product as (
2 select 101 id, 'Product 1' name from dual union all
3 select 102 id, 'Product 2' name from dual union all
4 select 103 id, 'Product 3' name from dual
5 ), client as (
6 select 11 id, 'Client 1' name from dual union all
7 select 12 id, 'Client 2' name from dual
8 ), orders as (
9 select 11 client_id, 101 product_id, 10 amount from dual union all
10 select 11 client_id, 103 product_id, 30 amount from dual union all
11 select 12 client_id, 102 product_id, 20 amount from dual union all
12 select 12 client_id, 102 product_id, 20 amount from dual
13 )
14 --
15 -- end-of-test-data
16 --
17 select p.name
18 , c.name
19 , sum(o.amount)
20 from product p
21 cross join client c
22 left outer join orders o
23 on o.product_id = p.id
24 and o.client_id = c.id
25 group by
26 p.name
27 , c.name
28 order by
29 p.name
30 , c.name
31 /
NAME NAME SUM(O.AMOUNT)
Product 1 Client 1 10
Product 1 Client 2
Product 2 Client 1
Product 2 Client 2 40
Product 3 Client 1 30
Product 3 Client 2
6 rows selected.ANSI notation allows outer join with more than one table.
Regular Oracle syntax could only do this by creating an inline view of the cartesian join and then outer joining orders with the inline view. Doable, but not as nice (IMHO) as the ANSI method for a case like this ;-) -
Best way to deal with Mutating table exception with Row Level Triggers
Hello,
It seems to be that the best way to deal with Mutating Table exception(s) is to have to put all the trigger code in a package & use it in conjunction with a Statement level trigger .
This sounds quite cumbersome to me . I wonder is there any alternative to dealing with Mutating table exceptions ?
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Left outer join 3 tables with where-statement
Hi folks,
I hope you can understand (and maybe solve) my problem.
Generally I try to left outer join three tables. The third table is used for a WHERE-statement.
The three table structures are the following:
table 1 (user)
user1 | key
table 2 (detail)
key | ID
table 3 (header)
ID | user2
...and I want to achieve the following structure (as example filled with data):
user | key | ID
|-----|----
xy | a | 001
xy | b | #
z | b | #
The clue ist the usage of the third table. I need the table to set user1 and user2 equal (WHERE) but there are two problems:
1) Obviously I can't left outer join two tables with each other. In this case I already used the 'key' of table 1 to join it with the 'key' of table 2. So I can't left outer join the 'ID' of table 2 with the 'ID' of table 3. Error message that I can only left outer join a table once. Any proposals?
2) I have to include a WHERE to equal user1 with user2. But I am not allowed to use the user2 from table 3 because of the left outer join.
I tried this coding:
SELECT auser1 akey b~id INTO TABLE itab FROM ( table1 AS a
LEFT OUTER JOIN table2 AS b ON akey = bkey )
LEFT OUTER JOIN table3 AS c ON bID = cID )
WHERE auser1 = cuser2.
I would really appreciate your help.
Regards
MrclSpdlIF you want to join a DB table with an internal table, you need to use the 'FOR ALL ENTRIES' statement.
select dbfields
into table itab2
from dbtab
for all entries in itab
where dbfield1 = itab-field1.
This will get you a second internal table with all the corresponding data for the first selection. You can then join them with a loop through the first table and a read table on the second table (for 1 - 1 relation) or a nested loop statement on both tables (for 1 - N relation). Make itab a hashed table when using read table with key, use a sorted table if you need to loop without key access.
Regards,
Freek -
JOIN 2 tables that have same column ?
I need to learn how to join two tables that both have the same column name:
tbl1 - idskey
tbl2 - idskey
the idskey column holds a id_number
When I do the JOIN I would like to make sure that only Distinct records are joined from both tables and that any duplicates are removed in the final join. So if:
Tbl1 has a idskey of: 12345
and
Tbl2 has a idskey of: 12345
In the final JOIN I want to remove one of those duplicates.
I actually need to join 3 tables that have the same linking column names for the join, but if I learn how to do this correctly on 2, that will be a start.
10g for db, thanks!Hi,
SELECT DISTINCT and GROUP BY are the most common ways to get unique results from non-unique keys. Exactly how you use them depends on exactly what you want to do.
SELECT DISTINCT guarantees that no two rows in the result set, conisdering all columns, will be identical.
GROUP BY produces one row from a set of rows that have a common feature. The values on that row may be a composite of values from various rows in that set (e.g., an average).
Please post a small, specific example. For instance:
"I have two rows in tbl1 ...
and these fhtee rows in tbl2 ...
Notice how there is one row with idskey=12345 in tbl1 but two such rows in tbl2.
How can I get theses results ...
where only one row has idskey=12345?" -
Join columns of outer join with table have no uniqueness cons
Hi! I'm getting noizy error in alert log from time to time:
Join columns of outer join with table <table_name> have no uniqueness constraints
I've collected all the queries (v$sql, all_source) with montioned table, but non of them produces that error if executed.
Any hints how to reproduce this error or where else to search that buggy sql join?
Edited by: user545083 on 25.10.2010 6:21Hi
I think this error is output via an materialized view refresh - check for mviews against the given table which fulfil the issue given in the error text.
Thanks
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Outer join two tables with two keys
Hi,
I have a question regard outer join,
I have table A (Aid, ADesc), Table B(Bid, Bdesc), and Table C (Aid, Bid, Cdesc)
There is data in Table A and B, but Table C is empty
I want to outer join C with A and B with below query
select ADesc,Bdesc, Cdest
from A, B, C
where A.Aid=C.Aid(+) and B.Bid(+)=C.Bid
and A.Aid='XXX' and B.Bid(+)='ZZZ'
The query result show only data in column Adesc , but column BDesc is empty even though there are some data in table B.
How should the query been modified to correctly show ADESC and Bdesc.
Thanks
VincentGuess the below should work:
Case when records are available in Table C:
with a as
(select 'XXX' aid, 'adesc' adesc from dual),
b as
(select 'ZZZ' bid, 'bdesc' bdesc from dual),
c as
(select 'XXX' aid, 'ZZZ' bid, 'cdest' cdest from dual where 1 = 1)
select ADesc,Bdesc, C1.Cdest
from
A LEFT OUTER JOIN C c1 ON (A.AID = C1.AID AND A.AID = 'XXX'),
B LEFT OUTER JOIN C C2 ON (B.BID = C2.BID AND B.BID = 'ZZZ');
Output:
"ADESC" "BDESC" "CDEST"
"adesc" "bdesc" "cdest"Case when table C is empty:
with a as
(select 'XXX' aid, 'adesc' adesc from dual),
b as
(select 'ZZZ' bid, 'bdesc' bdesc from dual),
c as
(select 'XXX' aid, 'ZZZ' bid, 'cdest' cdest from dual where 1 = 2)
select ADesc,Bdesc, C1.Cdest
from
A LEFT OUTER JOIN C c1 ON (A.AID = C1.AID AND A.AID = 'XXX'),
B LEFT OUTER JOIN C C2 ON (B.BID = C2.BID AND B.BID = 'ZZZ');
"ADESC" "BDESC" "CDEST"
"adesc" "bdesc" "" -
Left Outer Joining multiple tables to one source table FAILS with VLD-1511
Hi all,
Is it me, or is OWB unable to handle left outer joining 1 source table to multiple other tables?
I want to load a fact table so I have 1 source table with measures. This table must be outer joined to some dimensions that have their FK in the fact table.
The SQL statement would look like this (and is perfectly valid):
select ...
from input, dim1, dim2
where input.c1 = dim1.c1(+)
and input.c2 = dim2.c2(+);
I put the where clause in the joiner operator and validate, but that gives me message VLD-1511: A table may be outer joined to at most one other table.
Even splitting this up into one outer join per joiner still gives this message.
A search and look around on the forum and on metalink shows there are related issues (like bug 3334035). Seemingly creating a view is the work-around to use.....? (ie downgrading owb to a simple gui tool) }-;
Have other people experienced this problem of not being able to outer join one input table to multiple other tables?
Thanks,
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<---------- START QUOTE ---------->
RESEARCH
=========
Bug 3437036 KEY LOOKUP DOES NOT DETECT ORA-1417 IN VALIDATE/GENERATE STEP
Unpublished Bug 4211684 FORWARD PORT OF BUG 3437036
shows:
Some more development has been completed when this bug is fixed in Paris.
The following are the details:
1. If the join condition contains a full outer join such as
tab1.c (+) = tab2.c (+) and tab2.c (+) = tab3.c
then the new validations implemented for this bug do not apply since
in OWB, full outer join triggers generation of joins in ANSI syntax.
ANSI syntax does not have the original problem the base bug of this
bug reported.
2. If the join condition does not contain any full outer join condition,
then the join is generated in Oracle join syntax, which is subject two
several restrictions. The fix to this bug check two of the restrictions.
3. The first restriction in Oracle syntax is that the outer join operator
"(+)" can only directly be attached to a column name. If you attach it
to an expression, such as the following:
(tab1.c + 1) (+) = tab2.c
Then there will be an ORA-936 error at the time of mapping deployment.
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this situation.
4. The second restriction in Oracle syntax is that a table can only be
outer joined to exactly one other table.
For example, this is an invalid join in Oracle syntax:
tab1.c (+) = tab2.c and tab1.d (+) = tab3.d
because tab1 is left outer joined to tab2 and tab3.
But note that the following is still valid in Oracle syntax:
tab1.c (+) = tab2.c and tab1.d = tab3.d (+)
because tab1 is left outer joined to tab2 and right outer joined to tab3.
So this latter case does not violate the restriction that "same oj" to
more than 1 table is not allowed.
If same oj to more than 1 table is specified in a join condition,
VLD-1511 will be issued, and the map is made invalid.
<---------- END QUOTE ---------->
OWB does a partial validation, ie not all access paths are (can be) checked. A full check is only done by the database itself. So some scenarios (like checking whether multiple tables are outer joined the correct way) are not checked, and in this case are flagged with an error (even though it is actually a correct scenario).
Seemingly this was not flagged with an error in earlier versions of OWB, so beware, OWB behaviour may change when upgrading...
Alternative solutions are (1) using key lookups, (2) using a view with all outer joins in there, (3) using intermediate result tables between the joins.
Hope this info helps some people prevent spending too much time on a false error message,
Ed -
Create a library which joins 2 tables that report painter can use.
Hi,
Please help in resolving following issue:
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ZFKHALIX: SAP->Khalix Interface --- Custom Mapping Table <b><u><i>(Developned)</i></u></b>
GLPCT : EC-PCA: Totals Table <b><u><i>(Standard Table)</i></u></b>
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Best way to insert in a table througth a database link
Hi all,
i have two databases (oracle 10g, windows 2003 server)
Database A and Database B
i need to insert data in a table (Table_A) that lives in database A
The data i have to insert is in a table that lives a database B
I have a database link from database B to database A
so, connected to database B, i'm trying the following :
insert into table_a@database_link_to_A
select col1
from table_b
where col1 is not null
This query is taking forever, and i have to cancel it.
I'd like to hear from your experience. Wich is the best way to accomplish this task ?
Best Regards
Rui Madaleno
NOTE: I forgot to mencion that Table_A does not have any trigger or indexes.
Edited by: ruival on Jan 20, 2010 3:51 PMTry this:
insert /*+ append */ into table_a@database_link_to_A select col1 from table_b where col1 is not nullOr
Sqlplus COPY another option.
[http://www.praetoriate.com/oracle_tips_dm_sqlplus_copy.htm]
HTH
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I've always written my queries using the (+) operator for outer joins. I want to start using the new ANSI standard available in 9i. I can do it when I'm joining two tables in a simple query, but how does it work when I am joining multiple tables?
Here is an example of some SQL that works with the (+) outer join syntax. How can I convert this to use the LEFT OUTER JOIN syntax?
SELECT *
FROM audit_entry aue,
audit_table aut,
audit_statement aus,
audit_row aur,
audit_row_pkey aup1,
audit_row_pkey aup2
WHERE aue.audit_entry_id = aus.audit_entry_id
AND aut.table_name = 'TEST_AUDITING'
AND aut.table_owner = 'CLA_JOURNAL'
AND aus.audit_table_id = aut.audit_table_id
AND aur.audit_statement_id (+) = aus.audit_statement_id
AND aup1.audit_row_id (+) = aur.audit_row_id
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AND aup2.pk_column_name (+) = 'TEST_AUDITING_PK_2'
I can join audit_statement to audit_entry easy enough, but then I want to join audit_table to audit_statement, how do I do that, do I start nesting the join statements?
Thanks
RichardThanks for getting back so quickly, I have tried the suggested SQL with mixed results:
SELECT COUNT(*)
FROM audit_entry aue
JOIN audit_statement aus ON aue.audit_entry_id = aus.audit_entry_id
JOIN audit_table aut ON aus.audit_table_id = aut.audit_table_id
RIGHT OUTER JOIN audit_row aur ON aur.audit_statement_id = aus.audit_statement_id
RIGHT OUTER JOIN audit_row_pkey aup1 ON aup1.audit_row_id = aur.audit_row_id
RIGHT OUTER JOIN audit_row_pkey aup2 ON aup2.audit_row_id = aur.audit_row_id
WHERE aut.table_name = 'TEST_AUDITING_TWO'
AND aut.table_owner = 'CLA_JOURNAL'
AND aup1.pk_column_name = 'TEST_AUDTING_PK_1'
AND aup2.pk_column_name = 'TEST_AUDITING_PK_2'
I had to change the order slightly, between the first two JOINs but otherwise it executed OK. My problem is, it should only return 175 rows but its returning 30625 rows. If I comment out the second reference to audit_row_pkey I get the expected result:
SELECT COUNT(*)
FROM audit_entry aue
JOIN audit_statement aus ON aue.audit_entry_id = aus.audit_entry_id
JOIN audit_table aut ON aus.audit_table_id = aut.audit_table_id
RIGHT OUTER JOIN audit_row aur ON aur.audit_statement_id = aus.audit_statement_id
RIGHT OUTER JOIN audit_row_pkey aup1 ON aup1.audit_row_id = aur.audit_row_id
--RIGHT OUTER JOIN audit_row_pkey aup2 ON aup2.audit_row_id = aur.audit_row_id
WHERE aut.table_name = 'TEST_AUDITING_TWO'
AND aut.table_owner = 'CLA_JOURNAL'
AND aup1.pk_column_name = 'TEST_AUDTING_PK_1'
--AND aup2.pk_column_name = 'TEST_AUDITING_PK_2'
It looks the same condition is being used in each case but why do I suddenly get so many rows - its joining differently somehow. It must be to do with the order, do I need to bracket the query?
Thanks again
Richard -
Outer join two tables with query search record attached to both tables
When I create a query with two tables that have query search records attached with outer join, PS seems to do a natural join (cartesian). We are on PT8.48.
Is there a workaround for this issue. I do not want to remove query search record on either of the tables.
I am trying to create an Emergency contact report. I am using two tables PS_EMPLOYEES and PS_EMERGENCY_CNTCT. Here is the sql PeopleSoft query generated when I did Left outer Join.
Query SQL:
SELECT A.EMPLID, A.NAME, A.ADDRESS1, A.CITY, B.PRIMARY_CONTACT, B.ADDRESS1, B.CITY, B.STATE, B.POSTAL, B.RELATIONSHIP, A.DEPTID, A.JOBCODE, A.COMPANY, A.EMPL_TYPE
FROM (PS_EMPLOYEES A LEFT OUTER JOIN PS_EMERGENCY_CNTCT B ON A.EMPLID = B.EMPLID ), PS_EMPLMT_SRCH_QRY A1, PS_PERS_SRCH_QRY B1
WHERE A.EMPLID = A1.EMPLID
AND A.EMPL_RCD = A1.EMPL_RCD
AND A1.OPRID = 'SREESR'
AND (B.EMPLID = B1.EMPLID OR B.EMPLID IS NULL )
AND B1.OPRID = 'PS'
Appreciate any help.I think there are fixes for this issue in later tools releases (Report ID 1544345000). I'm not sure about 8.48, but you might try the workaround documented in
E-QR: Left Outer Joins with Security Records are returning unexpected results [ID 651252.1]
on Oracle Support.
Regards,
Bob -
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I'm working on performance optimization where I have to find the temporary tablespaces that are created or read during runtime? Is there any way to find it?
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