Binary file pop up problem. what do i do?

when i try to open a new page, a little window opens up telling me "You have chosen to open Firefox Setup 3.6.12.exe which is a: Binary File from: http://ftp.halifax.rwth-aachen.de Would you like to save this file?" Ive tried uninstalling firefox and reinstalling it, but nothing works. what do i do? also, when i looked up the given url in the window, it led me to a linux site. i dont even use linux, i use windows xp

http://www.mozilla.org/community/mirrors.html <br />
That is an official Mozilla download mirror at the RWTH Aachen University.
Have you tried a new Firefox Profile? <br />
http://kb.mozillazine.org/Creating_a_new_Firefox_profile_on_Windows

Similar Messages

Binary File IO DLL Problem

Hiii
I have developed one Binary file Read/Write Vi.. and then i have convert that vi in to DLL......
Now i tested that DLL Vi it is showing an error No 74. Actually for Binary write i will convert the Input cluster to Flattern to String and for Binary Read i will convert the output to unflattern to string.. I have attached the TEST.vi for reference
Attachments:
Binary Read#Write DLL.vi ‏18 KB
Binary File Read#Write.vi ‏24 KB
TEST.vi.vi ‏31 KB

hi there
if you want to read the size of the string you have to enable the "append array or string size" at the write file function. or you do not append the size and simply read all bytes.
in any case you should replace existing files to avoid remaining bytes of larger strings written in prior calls.
See attachment for details.
Best regards
chris
CL(A)Dly bending G-Force with LabVIEW
famous last words: "oh my god, it is full of stars!"
Attachments:
IO.JPG ‏66 KB
IO_8.5.vi ‏27 KB

Binary file open .. problem with formatting

dear all,
probably it is too much time I am not using any more Labview, but I have a problem in opening the attached data file.
it is supposed to be a matrix of 1000x316, with integer values up to 16 bit (65k levels).
In matlab i open it with fopen command, and assigning the format as "uint16"..
now I want to create a quick viewer in labview, but I can not go beyond the classic binary string...
may you help me with this stupid problem?
regards,
Edo
Solved!
Go to Solution.
Attachments:
image_P10.0_slit_P2.00.zip ‏261 KB

Is this what you need? It results in a 1000x316 array of U16s.
Message Edited by jcarmody on 01-08-2009 12:07 PM
Message Edited by jcarmody on 01-08-2009 12:08 PM
Jim
You're entirely bonkers. But I'll tell you a secret. All the best people are. ~ Alice
Attachments:
binfile.vi ‏8 KB
binfile.gif ‏3 KB

Blob for binary file, read/write problems

Hi,
I am relatively new to this type of development so apologies if this question is a bit basic.
I am trying to write a binary document (.doc) to a blob and read it back again, constructing the original word file. I have the following code for reading and writing the file:
private void save_addagreement_Click(object sender, EventArgs e)
// Save the agreement to the database
int test_setting = 0;
// create an OracleConnection object to connect to the
// database and open the connection
string constr;
if (test_setting == 0)
constr = "User Id=royalty;Password=royalty;data source=xe";
else
constr = "User ID=lob_user;Password=lob_password;data source=xe";
OracleConnection myOracleConnection = new OracleConnection(constr);
myOracleConnection.Open();
// create an OracleCommand object to hold a SQL statement
OracleCommand myOracleCommand = myOracleConnection.CreateCommand();
myOracleCommand.CommandText = "insert into blob_content(id, blob_column) values 2, empty_blob())";
OracleDataReader myOracleDataReader = myOracleCommand.ExecuteReader();
// step 2: read the row
OracleTransaction myOracleTransaction = myOracleConnection.BeginTransaction();
myOracleCommand.CommandText =
"SELECT id, blob_column FROM blob_content WHERE id = 2";
myOracleDataReader = myOracleCommand.ExecuteReader();
myOracleDataReader.Read();
Console.WriteLine("myOracleDataReadre[\"id\"] = " + myOracleDataReader["id"]);
OracleBlob myOracleBlob = myOracleDataReader.GetOracleBlobForUpdate(1);
Console.WriteLine("OracleBlob = " + myOracleBlob.Length);
myOracleBlob.Erase();
FileStream fs = new FileStream(agreement_filename.Text, FileMode.Open, FileAccess.Read);
Console.WriteLine("Opened " + agreement_filename.Text + " for reading");
int numBytesRead;
byte[] byteArray = new byte[fs.Length];
numBytesRead = fs.Read(byteArray, 0, (Int32)fs.Length);
Console.WriteLine(numBytesRead + " read from file");
myOracleBlob.Write(byteArray, 0, byteArray.Length);
Console.WriteLine(byteArray.Length + " written to blob object");
Console.WriteLine("Blob Length = " + myOracleBlob.Length);
fs.Close();
myOracleDataReader.Close();
myOracleConnection.Close();
This gives the following console output:
myOracleDataReadre["id"] = 2
OracleBlob = 0
Opened D:\sample_files\oly_in.doc for reading
56832 read from file
56832 written to blob object
Blob Length = 56832
My write to file code is:
private void save_agreement_to_disk_Click(object sender, EventArgs e)
string filename;
SaveFileDialog savedoc = new SaveFileDialog();
if (savedoc.ShowDialog() == DialogResult.OK)
filename = savedoc.FileName;
// create an OracleConnection object to connect to the
// database and open the connection
OracleConnection myOracleConnection = new OracleConnection("User ID=royalty;Password=royalty");
myOracleConnection.Open();
// create an OracleCommand object to hold a SQL statement
OracleCommand myOracleCommand = myOracleConnection.CreateCommand();
myOracleCommand.CommandText =
"SELECT id, blob_column " +
"FROM blob_content " +
"WHERE id = 2";
OracleDataReader myOracleDataReader = myOracleCommand.ExecuteReader();
myOracleDataReader.Read();
Console.WriteLine("myOracleDataReader[id] = " + myOracleDataReader["id"]);
//Step 2: Get the LOB locator
OracleBlob myOracleBlob = myOracleDataReader.GetOracleBlobForUpdate(1);
Console.WriteLine("Blob size = " + myOracleBlob.Length);
//Step 3: get the BLOB data using the read() method
byte[] byteArray = new byte[500];
int numBytesRead;
int totalBytes = 0;
FileStream fs = new FileStream(filename, FileMode.OpenOrCreate, FileAccess.Write);
while ((numBytesRead = myOracleBlob.Read(byteArray, 0, 500)) > 0)
totalBytes += numBytesRead;
fs.Write(byteArray, 0, byteArray.Length);
Console.WriteLine("numBytes = " + numBytesRead + " totalBytes = " + totalBytes);
Console.WriteLine((int)fs.Length + " bytes written to file");
fs.Close();
myOracleDataReader.Close();
myOracleConnection.Close();
This gives the following console output:
myOracleDataReader[id] = 2
Blob size = 0
0 bytes written to file
If I manually add the blob file using the following:
DECLARE
my_blob BLOB;
BEGIN
-- load the BLOB
my_bfile := BFILENAME('SAMPLE_FILES_DIR', 'binaryContent.doc');
SELECT blob_column
INTO my_blob
FROM blob_content
WHERE id = 1 FOR UPDATE;
DBMS_LOB.FILEOPEN(my_bfile, dbms_lob.file_readonly);
DBMS_LOB.LOADFROMFILE(my_blob, my_bfile, DBMS_LOB.GETLENGTH(my_bfile), 1, 1);
DBMS_LOB.FILECLOSEALL();
COMMIT;
END;
COMMIT;
The write to file works perfectly. This tells me that there must be something wrong with my code that is writing the blob to the database. I tried where possible to following the Oracle article using large objects in .NET but that (along with most things on the internet) focus on uploading text files.
Thanks in advance.
Chris.

myOracleCommand.CommandText = "insert into blob_content(id, blob_column) values 2, empty_blob())";
OracleDataReader myOracleDataReader = myOracleCommand.ExecuteReader();
This looks wrong, you shouldn't be using ExecuteReader unless you expect to get a result back. Try using ExecuteNonQuery to do the insert.

When I do a download, it is saved to a Binary File. Where are these files stored & how do you uninstall a program you don't want to keep ?

I use firefox, when I download a file from another website, there is a pop-up that shows the name of the download, which shows it is saved to a binary file, (don't know what a binary file is) but my question is where are the binary files stored on my computer & if I can uninstall it if I don't want to keep it.

read basic about svchost:
[http://support.microsoft.com/kb/314056/en-us A description of Svchost.exe in Windows XP Professional Edition]
find svchost services:
[http://webcache.googleusercontent.com/search?q=cache:pa9PdGlHr0sJ:www.bleepingcomputer.com/tutorials/list-services-running-under-svchost.exe-process/+what+is+svchost.exe&cd=12&hl=el&ct=clnk&gl=gr a way how to determine what services are running under a SVCHOST.EXE process]
One Temporary Solution is to disable the Windows Automatic Update service:
http://ask-leo.com/how_do_i_fix_this_high_cpu_usage_svchost_virus_or_whatever_it_is.html
(no '''it is not''' a virus)
(works for me)
thank you
Please mark "Solved" the answer that really solve the problem, to help others with a similar problem.

Writing a binary file

Hi,
I have trouble when writing a binary file. Here is what I do:
I have some VI's collecting various data for a fixed period of time. I put all the data into 1D arrays at a fixed frequency (they all have the same size). Once it is done I merge all the arrays into one 2D array and I write that to a binary file. If I wait about 10 seconds after writing the file and I repeat the whole thing, everything is fine and the timing is correct. If I wait for a shorter period of time (say a sec, and this is the maximum I can wait to have a usable application) then the timing is wrong in the first part of the loop (the time-critical data-acquisition one). Of course, if I don't write the file, everything is fine (I have to wait about 250 msec between two runs, but that's ok). Any advice ?
I also tried several things like streaming the data to disk during the time-critical period and this works fine only if the file allready exists. If not I experience jitters again. I don't really want to stream the data in real time, but it could work if I can get rid of the jitters. Again, any advice ?
I'm using LV7.1 and the real time module running on a PC (ETS).
Another, sort of related, topic: I noticed that when using 2D arrays within time critical loops all the process are slowdown whereas if I use several 1D arrays everything is fine... Any idea why ?
Thanks,
Laurent

Hello,
File I/O transfer rates during streaming to disk depends on several factors: CPU speed and load, hard drive technology (IDA / Serial ATA / SCSI ...), quality of programming. High jitter is always due to bad programming. File I/O operations are not deterministic. So, file I/O VI's must not be called in the critical task. Data must be saved in the normal priority VI's in order to keep jitter as low as possible. This is the reason why an application in RT is based on RT FIFO to transfer data from the critical loop and the normal priority VI.
You will find a lot of tutorials detailing the key concepts for RT programming at the link below:
* Real-Time Module
http://zone.ni.com/devzone/devzone.nsf/webcategories/C25F8C664230613A862567DF006ABB06
Moreover, memory allocation in LabVIEW is implicit. You must use large set of data carefully because some function reallocate new buffers for their outputs instead of reusing the input buffers (like the function "build an array"). You will find an example of how we can decrease the memory use with array in LabVIEW in the tutorials linked above.
If you need more specific advices, you can post a sample code that reproduce the behavior that you does not understand. I will try to look at this and give you my feedback.
Sincerely.
Matthieu Gourssies, NIF.

Binary File Reader to a Chart

Hello All,
Newbie having some trouble with reading a chart from a binary file. My problem may be with trying to use a binary file, I am not sure. The x axis time is not the same length as the actual test time. I have acquired a rms voltage from a VCR RF envelope. I'm using a 6009 DAQ with LV 7.1 on Win2K. I have attached the recording vi and the reading vi and a sample file. I have tried different things including the examples that came with lab view. I need to write a small sized file because this test will last for 4 hours. I have another application that will run for 5 days. I appreciate any help or ideas.
Thanks,
bh3560
Attachments:
Chart write_Read.zip ‏140 KB

Hi,
The program you have attached acquires, saves and reads data in ASCII ( floating numbers) and not binary.
To get an idea on how to write and read data in binary format, look at attached examples( taken from examples shipped with labview)
Hope this helps
Regards
Dev
Attachments:
Cont Acq&Graph Voltage-To File(Binary).vi ‏88 KB
Graph Acquired Binary Data.llb ‏72 KB

Unable to execute a binary file

I'm trying to run a server following the official instructions (http://www.ventrilo.com/setup.php#Server_Installing), but when I try to execute the binary i get this:
[srv@srv ventsrv]$ ./ventrilo_srv
bash: ./ventrilo_srv: No such file or directory
[srv@srv ventsrv]$
The permissions seem to be in order
[srv@srv ventsrv]$ ls -al
total 596
drwxr-xr-x 2 srv users 40 Nov 19 2008 .
drwx------ 3 srv users 4096 Apr 4 17:54 ..
-rw-r--r-- 1 srv users 14388 Nov 12 2007 LICENSE
-rwxr-x--x 1 srv users 468420 Nov 19 2008 ventrilo_srv
-rw-r--r-- 1 srv users 47244 Nov 12 2007 ventrilo_srv.htm
-rw-r----- 1 srv users 312 Nov 12 2007 ventrilo_srv.ini
-rwxr-x--- 1 srv users 55032 Nov 19 2008 ventrilo_status
[srv@srv ventsrv]$
I also tried using ". ventrilo_srv" instead, where I get:
[srv@srv ventsrv]$ . ventrilo_srv
bash: .: ventrilo_srv: cannot execute binary file
[srv@srv ventsrv]$
What's wrong?

error17 wrote:
Alright, thanks for the help all.
If ". <executable>" is wrong though, why did it say "cannot execute" and not just "command not found" as it usually does when one tries to use a non existent command?
is builtin bash command. Here is copypaste from man bash:
. filename [arguments]
source filename [arguments]
Read and execute commands from filename in the current shell environment and return the exit status of the last command executed from filename. If filename does not contain a slash, file names in PATH are used to find the directory containing filename. The file searched for in PATH need not be executable. When bash is not in posix mode, the current directory is searched if no file is found in PATH. If the sourcepath option to the shopt builtin command is turned off, the PATH is not searched. If any arguments are supplied, they become the positional parameters when filename is executed. Otherwise the positional parameters are unchanged. The return status is the status of the last command exited within the script (0 if no commands are executed), and false if filename is not found or cannot be read.

How to transfer a binary file through the socket?

hi,
i have a problem when I want to transfer a binary file through the socket. On the server side we write a program with C. On the client side with use java. The socket worked fine when we transfer some asci files. But failed when transfer the binary file. How to solve the problem? Can someone give me some advice? Thanks a lot.
sincerely,
zheng chuanbo

i use streams to read the binary file. The problem is I don't know when the transfered stream finished. With text file I can recognize the end of the transfer by a special string, but how to deal with the end of a stream? should the server send an "EOF" or something else to the client to notify the end?

What's the best way for reading this binary file?

I've written a program that acquires data from a DAQmx card and writes it on a binary file (attached file and picture). The data that I'm acquiring comes from 8 channels, at 2.5MS/s for, at least, 5 seconds. What's the best way of reading this binary file, knowing that:
-I'll need it also on graphics (only after acquiring)
-I also need to see these values and use them later in Matlab.
I've tried the "Array to Spreadsheet String", but LabView goes out of memory (even if I don't use all of the 8 channels, but only 1).
LabView 8.6
Solved!
Go to Solution.
Attachments:
AcquireWrite02.vi ‏15 KB
myvi.jpg ‏55 KB

But my real problem, at least now, is how can I divide the information to get not only one graphic but eight?
I can read the file, but I get this (with only two channels):
So what I tried was, using a for loop, saving 250 elements in different arrays and then writing it to the .txt file. But it doesn't come right... I used 250 because that's what I got from the graphic: at each 250 points it plots the other channel.
Am I missing something here? How should I treat the information coming from the binary file, if not the way I'm doing?
(attached are the .vi files I'm using to save in the .txt format)
(EDITED. I just saw that I was dividing my graph's data in 4 just before plotting it... so It isn't 250 but 1000 elements for each channel... Still, the problem has not been solved)
Message Edited by Danigno on 11-17-2008 08:47 AM
Attachments:
mygraph.jpg ‏280 KB
Read Binary File and Save as txt - 2 channels - with SetFilePosition.vi ‏14 KB
Read Binary File and Save as txt - with SetFilePosition_b_save2files_with_array.vi ‏14 KB

Problem when streaming out a binary file

Hi,
I am trying to stream out a binary file to an output stream (not a file, but a socket). My file is a gzip file, and I was initially simply trying to open the
file, read it to a a byte array, and writing it out to my output stream. However, I got corrupted data at my other end and it took me quite a bit of
debugging hours to find out why.
I tried writing to a file the same information I was writing to my output stream but, although my file was correct, my output stream still contained
corrupted data.
I think I have finally narrowed down my problem to the fact that when I try to write a 0x00 value to my output stream, everything gets ignored from this
point until I write a 0x0a byte to my output stream. Obviously this produces corrupted data, since I need all the bytes of my binary file.
If somebody can direct me as to how to write a 0x00 value to a socket output stream, I would really appreciate your input.
This is a sample of my code (Right now I am writing byte by byte: not very efficient, but was the only way I found where I was getting a problem):
// out is of type OutputStream
if (Zipped){
     // In this case we just have to stream the file out
File myFile = new File(fileName);
     FileInputStream inputFile = new FileInputStream(myFile);
     FileOutputStream fos = new FileOutputStream(new File("/tmp/zip.gz")); //zip.gz results in a good (not corrupted) file.
     ByteArrayOutputStream out1 = new ByteArrayOutputStream(1024);
     int bytes = (int)myFile.length();
     byte[] buffer = new byte[bytes];
     bytes = inputFile.read(buffer);
     while (bytes != -1) {
          out1.write(buffer,0,bytes);
          bytes = inputFile.read(buffer);
     inputFile.close();
     try {
          int count=0;
          bytes=out1.size();
          while (count<bytes){
               fos.write(buffer,count,1);
out.write(buffer,count,1); // when buffer[count] == 0x00, everything after it gets ignored until a 0x0a byte is written.
               count++;
     } catch (IOException ioe) {
          SysLog.event("IOEXCEPTION: "+ioe);
     } catch (Exception e) {
          SysLog.event("EXCEPTION: "+e);
     fos.flush();
     fos.close();
     out.flush();
out.close();
     return;
}

Actually, I had thought about that and for some time I tried getting rid of some of the header information in the gzipped file, and then I stopped doing that when I realized that part of the gzipped file is a CRC value which I believe is computed taking into account both the data of the file and the header information. If this is the case, then getting rid of part of the header would produce a corrupted file ... but then, I might be wrong in this issue.
Anyway, to make my application more clear, what I am doing is writing the code for a cgi command which is suppossed to access information from a database, create an xml file, gzip it, and then send it to the client who requested the information.
Therefore, what I am sending is an xml file (Content-Type: text/xml) in compressed format (Content-Encoding: gzip). Note that if I don't gzip the file and then send it uncompressed to the client, I have no problems. However, for me it is very important to gzip it because the size of the file can get very large and that would just take bandwidth unnecessarily.
On the other hand, if I try to gunzip the file locally, I have no problem either (the file is not corrupt at the server's end). Therefore, my problem is when I stream it out.
Any further help would be really appreciated!

How to get rid of a binary file with firefox that pop up allthe time?

each time that i open moxilla firefox a box asking if I want to save or cancel the binary file. I have tried to ignore ti however it has become a bother. How do I stop the box from popping up ?

Hi
if you mean http://db.tidbits.com/ - I didn't get any popups in a few minutes of browsing there, this without any blocking software. If you're seeing the very same ad popup window from differing sites, then it'd sure be worth looking at whether or not your mac or router or isp is using some rogue dns server.
DNS - Domain Name System
it translates domain names meaningful to humans into the numerical (binary) identifiers associated with networking equipment for the purpose of locating and addressing these devices worldwide. An often-used analogy to explain the Domain Name System is that it serves as the "phone book" for the Internet by translating human-friendly computer hostnames into IP addresses. For example, www.example.com translates to 192.0.32.10.
to borrow from wiki.
DNS servers can be chosen in your router or in your mac at System Preferences-Network-Advanced-DNS tab, If no special dns servers are selected, your router will usually accept the isp's suggestion, so you'll be using theirs, for better or for worse.
The most common place for any 'rogue' dns to be set, is in System Preferences-Network-Advanced-DNS tab... look there on your mac, and see if any numbers are visible. Copy them & paste here, then we'll know what's going on.

Problem working with binary file

Hi,
I have two seperate programs.
The first one:
*Reads a PDF file from disk via InputStreamReader.read(char[])
*converts it to s String [String.valueOf(char[])]
connects to other program using Socket and writes the string's bytes to the OutputStream of the Socket (socket.getOutputStream().write(string.getBytes);)
Second one:
*Reads the file from socket via BufferedReader.read(char[])
*converts it to a string via String.valueOf()
*writes it to a file using FileOutputStream.write(content.getBytes())
The problem is:
If the secong program is running on Win2K,the PDF file is opened with no errors but the pages are all blank.But everything is OK if it is running on Unix(IBM AIX java ver 1.3.1)
First program is always on Win2K.
I compared the win2k and unix PDF files,some nonprintable chars are displayed as ? in the win2K one,
what can be the reason? why does the same problem not occur on Unix?
Some problems are mentioned on web/forums but these are related with browsers or servlets which I am not using in this case.
Thanks in advance,

PDF is a binary file.
You're doing 1 of 2 possible things wrong....
1) trying to read a binary file as a text file ( string )
You can't "just read" a binary file as a text file to extra the strings.
You need to get the binary format, and parse it's format properly to extract the
string data.
2) trying to send a binary file across a socket as a string
You need to read the PDF file as an array of bytes and send them across
the socket as such. Trying to convert binary data to characters / strings
is wrong. characters get converted to and from native encoding schemes to
unicode.... among other problems.
regards,
Owen

Binary file problem (Read a specific Stream)

Hi Guys ,
I have a problem , I want to read a binary files but not the whole binary file. I only want to read one stream.
Forexample , I have a binar files which has 5 streams. If I only want to read one of the stream what should i do ? How do i get the position of each stream starting and end ?
The binary file is attached.
Please note that the file was 5.7mb where as labview message system allows 5.2mb. therfore i uploaded the file on a file host
http://uploading.com/files/55524a3d/10211001_.raw/
Thankyou in advance
Rgs
M Omar Tariq

As far as I can understand. You are able to read and decode the file in Labview. But have problems with big files. In such cases. Read the data file in chunked and discard data not needed. You can also make a tool that splits the multi-channel data into separate files in a binary format easy to read from Labview. It is also not needed to have all the data in memory then analyzing the data. Analysis may in many cases be done in chunks.
Besides which, my opinion is that Express VIs Carthage must be destroyed deleted
(Sorry no Labview "brag list" so far)

Urgent - pls help - Problem while inserting binary file into Oracle DB

Hi,
I am trying to insert binary files into a Blob column in a Oracle 10G table.
The binary files would be uploaded by the web users and hence come as multipart request. I use apache commons upload streaming API to handle it. Finally i am getting a input stream of the uploaded file.
The JDBC code is
PreparedStatement ps=conn.prepareStatement("insert into bincontent_table values(?)");
ps.setBinaryStream(1,inStream,length);
My problem starts when i try to find the length of the stream. available() method of inputstream does not return the full length of the stream. so i put a loop to read thru the stream and find the length as shown below
int length=0;
while((v=inStream.read())!=-1)
length++;
Now, though i got the length, my stream pointer has reached the end and i cant reset it(it throws an error if i try).
So i copied the stream content to a byte array and created an ByteArrayInputStream like this.
tempByteArray=new byte[length];
stream.read(tempByteArray,0,length);
ByteArrayInputStream bais=new ByteArrayInputStream(tempByteArray);
Now if i pass this bytearray input stream instead of the normal input stream to the prepared statement's setBinaryStream() method it throws an error as
"ORA-01460: unimplemented or unreasonable conversion requested".
Now how to solve this?
My doubts are ,
1) preparedStatement.setBinaryStream(int parameterIndex, InputStream x, int length) expects an inputstream and its length. if i have the stream how to find its length with out reading the stream?
2) Also as the length parameter is a integer, what if i have a large binary file whose length runs more than the capacity of integer
3) Alternatively there is a setBlob(int i, Blob x) in prepared statement. But how to instantiate a Blob object and set it here
4) Is there any better way to do this.
Thanks in advance

"ORA-01460: unimplemented or unreasonable conversion
requested".When the setBinaryStream method is used, the driver may have to do extra work to determine whether the parameter data should be sent to the server as a LONGVARBINARY or a BLOB (reference: javadoc)
1) preparedStatement.setBinaryStream(int parameterIndex,
InputStream x, int length) expects an inputstream and its length. if i
have the stream how to find its length with out reading the stream?no. stream may have no specified length. i think you have wrong understanding about stream.
2) Also as the length parameter is a integer, what if i have a large
binary file whose length runs more than the capacity of integer
3) Alternatively there is a setBlob(int i, Blob x) in prepared statement.
But how to instantiate a Blob object and set it here
4) Is there any better way to do this.use ps.setBlob(1, instream) instead

Binary file pop up problem. what do i do?

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