Bind custom object in weblogic server start

Question

I want to bind my custom object to jndi when weblogic server start. how can i do?

Answer 1

Bonjour Yiwen,
That could easily done by registering a startup class in weblogic server that will do the binding of the object in the JNDI tree (it can also create all the subcontexts you need).
Below is some code that works fine on WLS 5.1:
a.. a custom object
package StartupJNDI;
public class CustomObject extends Object
protected String name;
public CustomObject ( String aszName )
name = aszName;
public String getName()
return name;
public void setName(String newName)
name = newName;
a.. a startup class
package StartupJNDI;
import javax.naming.*;
public class Registration
public Registration()
InitialContext initCtx = null;
try
initCtx = new InitialContext ();
initCtx.bind ( "Startup Registered Object" , new CustomObject ( "This is a void object" ) );
catch ( Exception ex )
ex.printStackTrace ( System.err );
public static void main(String[] args)
new Registration();
a.. a startup class in weblogic.properties:
weblogic.system.startupClass.JNDIStartupRegistration=StartupJNDI.Registration
Please, be sure that the path to these classes is also registered in the WEBLOGIC_CLASSPATH system property (e.g. : in your startweblogic.cmd file on Windows NT).
You can check that the object is bound in the JNDI tree through the console.
Hope this helps,
Cordialement,
Etienne
Yiwen Tian <[email protected]> a écrit dans le message : [email protected]..
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I want to bind my custom object to jndi when weblogic server start. how can i do?
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