Build index on olap's table

Hi,
I am on an OLAP application which has a table having millions of records, and the table doesn't have any index. When checking the data found one particular column has total less than 50 distinct values which likely to be a good candidate for building index against. Another column on the same table is composed of [fixed_character_string]_[random_value], e.g. BLABLABLA_000000001, BLABLABLA_000000002, etc. what kind of index should I build, normal index for the first one, and bitmap index for the second?
Last, This is a partitioned table.
Regards

rac100g wrote:
When checking the data found one particular column has total less than 50 distinct values which likely to be a good candidate for building index against. Not true.
rac100g wrote:
Another column on the same table is composed of [fixed_character_string]_[random_value], e.g. BLABLABLA_000000001, BLABLABLA_000000002, Sounds like you should have 2 columns and not one.
In general, we're not going to be able to help you much with the level of detail you have given us.
If you want to share DDL's for the tables, data volumes / distributions as well as the types of queries your application is going to be issuing then we may be able to get somewhere. You may also want to look at using enterprise manager / tuning pack (if your licensed for it), check the documentation for your version (which you should always mention when posting a question).

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    http://stackoverflow.com/questions/7359702/how-do-i-obtain-a-query-execution-plan
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    You can use the statistics for building indexes:
    http://www.mssqltips.com/sqlservertip/2979/querying-sql-server-index-statistics/
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    CompTIA A+ ,Microsoft MCP, MCTS, MCSA, MCITP |
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    Hello,
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    Jonathan Lewis
    http://jonathanlewis.wordpress.com
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    "For every expert there is an equal and opposite expert."
    Arthur C. Clarke

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    Jozsef wrote:
    Hi there,
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    http://www.jlcomp.demon.co.uk
    "For every expert there is an equal and opposite expert."
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    -Yasser
    Edited by: YasserRACDBA on Mar 5, 2009 11:45 PM

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    Also if we create index as :(create index i_name on t_name(c_name)) By default it will create Global index. Please correct me......
    Above staement will create non-partitioned index
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    Message was edited by:
            Rk Pasupuleti

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