Bus V Aux

Hello everyone.
Okay, I know this question may perhaps have been addressed prior in the forum (if so, please point me in the proper direction), but although I myself have asked a slew of Aux/Bus questions on here (the vast majority of which have been adequately - if not exhaustively - answered) here's what may be a very, very simple Bus/Aux question that I HAVEN'T asked:
WHAT'S THE DIFFERENCE??
I never asked this question before because I think I was led to believe (or potentially just assumed) that they were the same thing. They do, afterall, seem to be interchangable, as I've been using Auxes the past few long months to route various channels into. However, and after going through the macpro video tutorials on Logic, I realize that there IS a difference - although I'm not completely sure exactly what it is.
I know/can see that Auxes have both ins and outs, while Buses only have outs - no ins . . .
Can someone give me a brief (or not so brief) explanation of the differences? Have I been horribly erred this entire time routing my tracks/channels into Auxes instead of Buses??
Thank you everyone, as always. Everyone on here has always been very helpful.
Javier Calderon

This is all very interesting. I rarely use busses, so the distinction between a buss and a buss object isn't something that crossed my mind before. Now I get it, and I'd like to elaborate a bit on this conversation...
It'san important thing to remember the concept of the "objects" in Logic. For example, if you see an output in the environment's audio layer, what you're really seeing is an audio object assigned to an output object. Since anything you see in the audio layer that has a fader and a pan pot is going to be an audio object, we can forget about the term "audio object" for now and concentrate on what kind of object it's assigned to. So when we see an output object in the environment/audio layer, we're seeing the visual representation of an output object. If we see a buss object, we see the visual representation of a buss object.
And as I've come to understand, it's important to distinguish between the buss and the buss object. They are not the same thing. Right. Forums. Cool!
The buss itself is just a pathway, a wire as jord put it. Funny thing is you can have no buss objects in the environment but the busses -- these pathways, or wires -- still exist. Of course, it doesn't make sense to send signal down a buss wire and not have that bussed signal show up anywhere. But it's entirely possible, and I think even educational towards explaining the distinction between buss and buss object. So... a lil' tutorial thingee...
Try this out:  Add an audio track to the arrange on channel 1 (track 1), output 1/2.
Open the environment audio layer and arrange your objects so that you can see all of the following all the same time:
track 1 (channel 1)
buss 1
output 1
aux 1
Now, delete bus 1 from the environment. This is only temporary. (Oh and try not to do any other kind of editing in the meantime. This will make it easy to hit UNDO and get your bus back later).
Play your track. You'll see the meter on channel 1 and output 1/2. Simple enough.
Next, on channel 1, change the output to bus 1. The meters on output 1/2 will now go dead, as expected, because you've diverted the signal from output 1/2 to buss 1 (the wire, not the object). Notice also that even though you deleted the bus 1 object from your environment, the choice for bus 1 was not grayed out (unavailable). This proves the point that the buss -- the pathway/wire itself -- exists independent of the buss object. To prove the point, go to your aux object and assign its input to bus 1 and you'll now see level coming into this aux because you've now connected buss 1 to the input of that aux.
Switch the Aux's input back to "no input". And UNDO to get your buss back.

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