Butterwort​h Filter

I want to build a Butterworth filter with the formula node. what should I do?
Let's do it step by step and if you can correct me.
I saw the formula for the Butterworth is:
H(jw)=1/sqrt([1+(f/fc)^2n]) 
now I know that the cutoff freq. is fc=1/(2*pi*R*C) where R & C  are variable and choosen by the user (this is what the teacher asked). 
So if i write in the formula node this statments:
Tau=R*C;
Fc=1/(2*pi*Tau);
FdT=abs(1/sqrt([1+(f/Fc)**2*n]));
i got error. why? 
Solved!
Go to Solution.
Attachments:
Exercise6.vi ‏7 KB

You were close.  But your little loop inside the formula should look like this.  Notice the perithesis around the 2*n.  You were only squaring.  You should raise to a power of 2*n.  I added an input for the number of poles.
for ( f=0; f<1000;f++)
H[f]=1/sqrt(1+(f/Fc)**(2*n));
 Also, there's an Absolute Value in the Numeric palette.  Use that instead of the square and square root.
There are only two ways to tell somebody thanks: Kudos and Marked Solutions
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Attachments:
Exercise6.png ‏49 KB

Similar Messages

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    Attachments:
    butterworth-filter-differences.png ‏285 KB

    Hello Lynn,
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    Attachments:
    IIR Filtering and Response_CH.vi ‏55 KB
    butterworth2nd_order_bandpass_0p1to10Hz_mag_response.PNG ‏18 KB

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