Calculate the difference between two dates

I would like to calculate the difference between two dates in PL/SQL and return the result as a number of days expressed as an integer value.

Denes,
A fair point, I should really have posted this on the SQL forum (I'm new to the forum as well as PL/SQL) but thanks for responding anyway. It does raise a question as to how to implement this in ApEx though.
I have created the function and am calling it as shown below from the source window of a form. The source type is 'PL/SQL expression or function' and the expression in the source window of the form is:
calc_date_difference (:p26_c_payment, :p26_c_rec)
The two parameters being passed are of type date but I'm not sure how to handle the ruturned number and populate the form in ApEx with this value.
Is it possible to do it this way or am I taking completely the wrong approach?
Regards
Sandy
This is not ApEx related but SQL related:
CREATE OR REPLACE FUNCTION calc_date_difference (
p_date_1   VARCHAR2,
p_date_2   VARCHAR2
RETURN NUMBER
v_difference   NUMBER;
v_sql_err      VARCHAR2 (4000);
BEGIN
v_difference := TRUNC (TO_DATE (p_date_1)) - TRUNC
(TO_DATE (p_date_2));
RETURN v_difference;
CEPTION
WHEN OTHERS
THEN
v_sql_err := SQLERRM || CHR (10) || CHR (10) ||
SQLCODE;
ND calc_date_difference;and
SQL> SELECT calc_date_difference ('23.01.2007',
'20.01.2007') diff
2    FROM DUAL;
DIFF
3
Denes Kubicek

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Edited by: user10441472 on Nov 22, 2010 3:14 PM

You already asked this question and I answered it...
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Something like this should work:
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regards,
Prashanth

Hi,
have a look at those two:
(How do I calculate the difference between two dates?)
http://joda-time.sourceforge.net/faq.html
Calculating the Difference Between Two Datetime Stamps
http://www.xmission.com/~goodhill/dates/deltaDates.html
Get difference in days
http://javaalmanac.com/egs/java.util/CompDates.html
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michal

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Hi:
Question 1:
We have same problem, and what we did is to create:
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Hello,
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oracle.jbo.domain.Date
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hi,
try this.....
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Calendar cal = Calendar.getInstance();
cal.setTime(date);
Calendar calto = Calendar.getInstance();
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Hi Grame...
For the days calculation ..
I suggest you to use replacement path ..
I have the reference that you can see the sample. The case of samples is also about day calculation.
http://www.sd-solutions.com/documents/SDS_BW_Replacement%20Path%20Variables.html
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Calculate the Difference between 2 dates

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Find the difference between two dates for the specific month and year

Hi,
I have two dates, start date is 30/12/2012 and end date is 04/01/2013. Using datediff I found the difference of days between two dates. But I find the no of days in January 2013. ie output is 4 instead of 6. I input month and year to find the no of days
for that date. In this case I input Jan 2013. How can I sql this ?

I don't understand how most of the answers provided here not analytically solving the problem with many cases possible.
First let me understand you:
You have 2 dates range and you want to calculate day range for specific month and year between the original date range.
declare @for_month int = 1 --January
declare @for_year int = 2013
declare @StartDate date = '2012-12-20'
declare @EndDate date = '2013-01-04'
SELECT
CASE
WHEN (DATEPART(MONTH, @StartDate) = @for_month and DATEPART(MONTH, @EndDate) = @for_month) and ((DATEPART(YEAR, @StartDate) = @for_year or DATEPART(YEAR, @EndDate) = @for_year)) THEN
DATEDIFF(DAY, @StartDate,@EndDate)
WHEN (@StartDate < cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (@EndDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
DATEDIFF(DAY, DATEADD(MONTH, DATEDIFF(MONTH, -1, @EndDate)-1, 0),@EndDate)
WHEN (@EndDate > cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) and (@StartDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
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WHEN ((DATEDIFF(DAY, @StartDate, cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) >= 0) and (DATEDIFF(DAY, cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date), @EndDate) >= 0)) THEN
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ELSE
0
END as [DD]
I don't know how you calculate day range between 01/01/2013 and 04/01/2013
is 4, it is actually is 3 but if that is the case, you can add 1 from the condition.

How do I calculate the difference between two times?

I am so embarrassed by the fact that I can't figure this out.
Cell B2- 8:00 am
Cell C2- 10:50 am
Cell D2- (How do I get this cell to calculate the difference and say 2:50?)
I know this is probably one of the most basic operations, but for the life of me I can't figure it out. Cells B2 & C2 are formatted for 24 hour clock. But if I tell the system to just subtract the two, I get "0.118". Everything I find on the forum search goes beyond what I need. Can anyone help me?
Thank you.

KOENIG Yvan wrote:
Numbers states clearly in the Help and the PDF Users Guide that it doesn't know a "duration" object but a time one which is restricted to the range 00:00:0 to 23:59:59.
When I search the U.S. language Numbers User Guide for the word "duration," it is not found.
What may be more clear: _duration is not available but time is_?
Once again your response resemble to a rant againt the Help and the User Guide.
In the Help:
+date-time Any Numbers date/time value. _While you can choose to display only date or time in a cell, all Numbers date or time values contain both the date and time._+
Which wording would be more clear and precise?
TIMEVALUE
+The TIMEVALUE function converts a date, a time, or a text string to _a decimal fraction of a 24-hour day._+
Which wording would be more clear and precise?
TIME
+The TIME function converts hours, minutes, and seconds into a time format.+
+TIME(hours, minutes, seconds)+
+hours: The number of hours _(using a 24-hour clock)._+
+minutes: The number of minutes.+
+seconds: The number of seconds.+
Notes
+You can specify hour, minute, and second values greater than 23, 59, and 59, respectively. _If the hours, minutes, and seconds add up to more than 24 hours, Numbers subtracts 24 hours repeatedly until the sum is less than 24 hours._+
Which wording would be more clear and precise?
In the User Guide:
page 190
+date-time Any Numbers date/time value. _While you can choose to display_+
+_only date or time in a cell, all Numbers date or time values contain_+
+_both the date and time._+
+TIME (page 277) Converts a time to a decimal fraction of a 24-hour day.+
+TIMEVALUE (page 278) Converts a time in a string to a decimal fraction of a 24-hour day.+
TIME
+The TIME function converts the specified time to a decimal fraction of a 24-hour day.+
+TIME(hours, minutes, seconds)+
+• hours: The number of hours _(using a 24-hour clock)_.+
+• minutes: The number of minutes.+
+• seconds: The number of seconds.+
Notes
+You can specify hour, minute, and second values greater than 23, 59, and 59,+
+respectively. _If the hours, minutes, and seconds add up to more than 24 hours,_+
+_Numbers subtracts 24 hours repeatedly until the sum is less than 24 hours._+
+You can also specify fractional values for hours, minutes, or seconds.+
TIMEVALUE
+The TIMEVALUE function converts a time in a string to a decimal fraction of a 24-hour+
day.
TIMEVALUE(date-time)
+• date-time: A date, a time, or a string in any of the Numbers date and time formats.+
As you may check, the infos are exactly the same in the Help and in the Guide.
And I really don't understand how you may find them unclear.
Yvan KOENIG (from FRANCE lundi 4 août 2008 14:57:36)

How to get the difference between two dates???

HI I have two dates and I want to test if there is an hour between them.
Is there a way to compare two dates like mySQL can with dateDiff(date1,date2);
Thanks alot.
Graham

This link is now out of date as they have revamped the structure. Yep. Here it is again: http://forum.java.sun.com/thread.jsp?forum=31&thread=502686
I've also noticed that my comment regarding daylight saving was misleading. The demonstrated method for calculating difference between Dates is reliable. However, one needs to be careful when interpreting Dates in a daylight saving timezone.

How to find the difference between two date?

Hi,
I currently writing a date comparision program. Below is the idea analogy,
Currently i need to find how many day differences between 30 July 2003 and 22 June 2004. How can i use java to code it?
Thanks.

there doesn't seem to be a direct way but try this:int daysBetween = 0;
Calendar c = new GregorianCalendar(2004, Calendar.JULY, 30);
Calendar d = new GregorianCalendar(2003, Calendar.JUNE, 22);
while (c.get(Calendar.YEAR) != d.get(Calendar.YEAR)) {
daysBetween += 360;
d.add(Calendar.DAY_OF_YEAR, 360);
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Function Module to get the difference between two times.

Hi All,
I want to know if there is any function module that gives me the difference between two specified times.
For Ex: Time 1: 12/01/2007 00:01 A.M
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Hi, You can use the following function module to calculate the diffrence between to dates in the unit that you want.
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Parameters:
EXPORTING
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     I_START_TIME "The start time of the time interval
     I_END_DATE   "The end date of the time interval
     I_END_TIME   "The end time of the time interval
     I_UNIT_OF_DURATION "Time unit of the duration if not to be calculated in days.
     Value     =====     Meaning
     ' '     =====     Day (default)
     D     =====     Days
     H     =====     Hours
     MIN     =====     Minutes
     MON     =====     Months
     S     =====     Seconds
     WK     =====     Weeks
     YR     =====     Years
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IMPORTING
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Message was edited by:
        Rajesh Soman

Calculate the difference between two dates

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