Call a servlet in webdynpro

Hi Colleagues,
We have developed a servlet where there is a method which returns an arraylist, we have a requirement where we have to call this method(which is inside the servlet) in a webdynpro project and bind the arraylist output to the context of webdynpro.
Could anyone please let me know how to achieve this?
ManyThanks in advance
Swetha

Hi swetha,
Find the thread,may give some inputs.
Webdynpro VS. Java Servlet
Regards,
Sri

Similar Messages

How to call a servlet from Webdynpro application

Hi All,
I am new to SAP . I have requirement to call a SERVLET which is on a different application server from my webdynpro application , the servlet will return a file .. i need to display that file to the user .. can some one tell me how this can be done .. If possibel please provide some sample code.
Regards,
Tarun.

Hi
Check this
1. How to access Servlet information from a webdynpro application ?
Regards
Abhijith YS

How to call IAC Iview from WebDynpro java code

Hi Team,
I am tring to call IAC Iview from WebDynpro Java code. we are passing value but blank page displayed and there is no error show on error log.
Below is Java Code which i am calling.
public void wdDoInit()
      try {
            String strURL = "portal_content/TestSRM/iView/TestSRM";                           //WDProtocolAdapter.getProtocolAdapter().getRequestParameter("application");
             String random = WDProtocolAdapter.getProtocolAdapter().getRequestObject().getParameter("random_code");
             //wdContext.currentContextElement().setRandomNumber(random);
//below we are call URL
WDPortalNavigation.navigateAbsolute("ROLES://portal_content/TestSRM/iView/TestSRM?VAL="+random,WDPortalNavigationMode.SHOW_INPLACE,(String)null, (String)null,
                   WDPortalNavigationHistoryMode.NO_DUPLICATIONS,(String)null,(String)null, " ");
        } catch (Exception e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
I am passing value from URL.
http://<host Name>:<port>/webdynpro/resources/local/staruser/StarUser?random_code=111111111
when we call above URL we getting blank screen.
Regards
Pankaj Kamble

Hi Vinod,
read this document (from pages 7 ).
<a href="https://www.sdn.sap.comhttp://www.sdn.sap.comhttp://www.sdn.sap.com/irj/servlet/prt/portal/prtroot/docs/library/uuid/b5380089-0c01-0010-22ae-bd9fa40ddc62">https://www.sdn.sap.comhttp://www.sdn.sap.comhttp://www.sdn.sap.com/irj/servlet/prt/portal/prtroot/docs/library/uuid/b5380089-0c01-0010-22ae-bd9fa40ddc62</a>
In addition lok at these links: (Navigation Between Web Dynpro Applications in the Portal)
<a href="http://help.sap.com/saphelp_erp2005/helpdata/en/ae/36d93f130f9115e10000000a155106/frameset.htm">http://help.sap.com/saphelp_erp2005/helpdata/en/ae/36d93f130f9115e10000000a155106/frameset.htm</a>
<a href="http://help.sap.com/saphelp_erp2004/helpdata/en/b5/424f9c88970f48ba918ad68af9a656/frameset.htm">http://help.sap.com/saphelp_erp2004/helpdata/en/b5/424f9c88970f48ba918ad68af9a656/frameset.htm</a>
It may be helpful for you.
Best regards,
Gianluca Barile

How to call a servlet in new window without toolbar from OA page

How to call a servlet in new window without toolbar from a OA page?Please provide sample code

I have tried with the way suggested in Mukul's blog using javascript in Destination URI property.
I tried to open a OA Page and from which forwarded it to a servlet..
It is showing the error:
Error Page
Exception Details.
oracle.apps.fnd.framework.OAException: The application id or shortname () you entered does not exist.
     at oracle.apps.fnd.framework.webui.OAPageErrorHandler.prepareException(OAPageErrorHandler.java:1223)
     at oracle.apps.fnd.framework.webui.OAPageBean.preparePage(OAPageBean.java:1969)
     at oracle.apps.fnd.framework.webui.OAPageBean.preparePage(OAPageBean.java:502)
     at oracle.apps.fnd.framework.webui.OAPageBean.preparePage(OAPageBean.java:423)
     at oa_html._OA._jspService(_OA.java:86)
     at oracle.jsp.runtime.HttpJsp.service(HttpJsp.java:119)
     at oracle.jsp.app.JspApplication.dispatchRequest(JspApplication.java:385)
     at oracle.jsp.JspServlet.doDispatch(JspServlet.java:259)
     at oracle.jsp.JspServlet.internalService(JspServlet.java:178)
     at oracle.jsp.JspServlet.service(JspServlet.java:148)
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:588)
     at oracle.jsp.provider.Jsp20RequestDispatcher.forward(Jsp20RequestDispatcher.java:162)
     at oracle.jsp.runtime.OraclePageContext.forward(OraclePageContext.java:175)
     at oa_html._OA._jspService(_OA.java:96)
     at oracle.jsp.runtime.HttpJsp.service(HttpJsp.java:119)
     at oracle.jsp.app.JspApplication.dispatchRequest(JspApplication.java:385)
     at oracle.jsp.JspServlet.doDispatch(JspServlet.java:259)
     at oracle.jsp.JspServlet.internalService(JspServlet.java:178)
     at oracle.jsp.JspServlet.service(JspServlet.java:148)
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:588)
     at org.apache.jserv.JServConnection.processRequest(JServConnection.java:456)
     at org.apache.jserv.JServConnection.run(JServConnection.java:294)
     at java.lang.Thread.run(Thread.java:534)
## Detail 0 ##
oracle.apps.fnd.framework.OAException: The application id or shortname () you entered does not exist.
     at oracle.apps.fnd.framework.webui.OAWebBeanFactoryImpl.getAppId(OAWebBeanFactoryImpl.java:5391)
     at oracle.apps.fnd.framework.webui.OAPageBean.preparePage(OAPageBean.java:969)
     at oracle.apps.fnd.framework.webui.OAPageBean.preparePage(OAPageBean.java:502)
     at oracle.apps.fnd.framework.webui.OAPageBean.preparePage(OAPageBean.java:423)
     at oa_html._OA._jspService(_OA.java:86)
     at oracle.jsp.runtime.HttpJsp.service(HttpJsp.java:119)
     at oracle.jsp.app.JspApplication.dispatchRequest(JspApplication.java:385)
     at oracle.jsp.JspServlet.doDispatch(JspServlet.java:259)
     at oracle.jsp.JspServlet.internalService(JspServlet.java:178)
     at oracle.jsp.JspServlet.service(JspServlet.java:148)
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:588)
     at oracle.jsp.provider.Jsp20RequestDispatcher.forward(Jsp20RequestDispatcher.java:162)
     at oracle.jsp.runtime.OraclePageContext.forward(OraclePageContext.java:175)
     at oa_html._OA._jspService(_OA.java:96)
     at oracle.jsp.runtime.HttpJsp.service(HttpJsp.java:119)
     at oracle.jsp.app.JspApplication.dispatchRequest(JspApplication.java:385)
     at oracle.jsp.JspServlet.doDispatch(JspServlet.java:259)
     at oracle.jsp.JspServlet.internalService(JspServlet.java:178)
     at oracle.jsp.JspServlet.service(JspServlet.java:148)
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:588)
     at org.apache.jserv.JServConnection.processRequest(JServConnection.java:456)
     at org.apache.jserv.JServConnection.run(JServConnection.java:294)
     at java.lang.Thread.run(Thread.java:534)
oracle.apps.fnd.framework.OAException: The application id or shortname () you entered does not exist.
     at oracle.apps.fnd.framework.webui.OAWebBeanFactoryImpl.getAppId(OAWebBeanFactoryImpl.java:5391)
     at oracle.apps.fnd.framework.webui.OAPageBean.preparePage(OAPageBean.java:969)
     at oracle.apps.fnd.framework.webui.OAPageBean.preparePage(OAPageBean.java:502)
     at oracle.apps.fnd.framework.webui.OAPageBean.preparePage(OAPageBean.java:423)
     at oa_html._OA._jspService(_OA.java:86)
     at oracle.jsp.runtime.HttpJsp.service(HttpJsp.java:119)
     at oracle.jsp.app.JspApplication.dispatchRequest(JspApplication.java:385)
     at oracle.jsp.JspServlet.doDispatch(JspServlet.java:259)
     at oracle.jsp.JspServlet.internalService(JspServlet.java:178)
     at oracle.jsp.JspServlet.service(JspServlet.java:148)
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:588)
     at oracle.jsp.provider.Jsp20RequestDispatcher.forward(Jsp20RequestDispatcher.java:162)
     at oracle.jsp.runtime.OraclePageContext.forward(OraclePageContext.java:175)
     at oa_html._OA._jspService(_OA.java:96)
     at oracle.jsp.runtime.HttpJsp.service(HttpJsp.java:119)
     at oracle.jsp.app.JspApplication.dispatchRequest(JspApplication.java:385)
     at oracle.jsp.JspServlet.doDispatch(JspServlet.java:259)
     at oracle.jsp.JspServlet.internalService(JspServlet.java:178)
     at oracle.jsp.JspServlet.service(JspServlet.java:148)
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:588)
     at org.apache.jserv.JServConnection.processRequest(JServConnection.java:456)
     at org.apache.jserv.JServConnection.run(JServConnection.java:294)
     at java.lang.Thread.run(Thread.java:534)

How to call a servlet from another servlet

hi everybody,
i have a problem, i have to call one servlet from another one.
Everything works on my pc, but when i install the application on the customer's server i got an error about an Uknown URL followed by the name of the machine.
Wjat i do is the folloqing :
String urlString = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+"/"+servletName;
URL url = new URL(urlString);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
the variable servletName is the name of the servlet i have to call.
Is there another way to call the servlet ?
All the servlet are installed in the same server.
Any suggestion ?
Cheers.
Stefano

Sweep is correct about requestDispatcher being another approach for inter-servlet delegation; the only issue that i recall with this approach is that it defaults the method of the destination servlet to the one it was called from...for example, calling servlet2 from within servlet1.post() resulted in the dispatcher attempting to utilize servlet2.post() - i believe that i searched for a parameterize solution to no avail :( (ended up handling the request by placing a "fake" doPost() in servlet2 that simply called servlet2.doGet())
however, if your application is functioning correctly on your pc/webserver then the problem may be external to servlet communication (e.g. client webserver's ports not configured or blocked, missing runtime classes, etc.)
my suggestion would be to set aside the programmatic concerns for the moment - what is the response if you open a browser on a client's machine and access the URL in question (i.e. http://clientserver:port/stefanoServlet)? If it will not respond to access in this manner then it certainly won't when your application calls for it.
It's possible that there is a coding error but, given the info supplied, i'd start examining the environment, first. Let us know if you have any luck with the test i recommended or not (please provide abundant detail). Or, if you've found the solution then you may want to post back with a quick blub so the next person knows how to escape the trap.
D

How can i call a servlet from a servlet ?

Hello,
Can i call a Servlet from within a Servlet ?
and is it "right thing" to Do ?
Thanks

JMO, but I wouldn't do it like this.
Don't have a remote object like a servlet doing database queries for your app. That will mean TWO network hops for every query if the database resides on another machine. The network is the biggest bottleneck you've got.
Write a JavaBean that does the database stuff for you and just have the first servlet instantiate it when it needs it. A Bean has a better chance of being reused, too. Write a TableGateway or DAO for your object.
Or write an EJB to do it.
The only time I've done a servlet-to-servlet connection like that was for one servlet running in a DMZ that would authenticate a user and then forward the request to another servlet running inside the second firewall.
I wouldn't encapsulate database query logic in a servlet like that. JMO - MOD

Calling a webservice from webdynpro ABAP.

Hi,
Anybody have doc/material with screenshots on calling a webservice from webdynpro ABAP (In WAS 7.0 version using service calls ) with clear steps ?
Thanks in advance. Ponts will not be a constraint for right answers
Praveen
Edited by: Praveen kumar Kadi on Feb 23, 2009 11:19 AM

Hi Praveen,
1st Step : configure Logical Port
http://help.sap.com/saphelp_nw70/helpdata/EN/16/285d32996b25428dc2eedf2b0eadd8/frameset.htm
2nd Step : Generate Proxy Object
http://help.sap.com/saphelp_nw70/helpdata/EN/16/285d32996b25428dc2eedf2b0eadd8/frameset.htm
3rd Step : Instantiating the proxy object & calling the methods exposed by webservice
data: sys_exception type ref to cx_ai_system_fault,
      sys_exception2 type ref to cx_ai_application_fault,
      client_proxy type ref to zco_myesa, "MY PROXY CLASS
      lv_ret_code type int4,
      lv_input type zsend_email_input,
      lv_response type zsend_email_response.
data: lv_from type string,
      lv_from_address type string,
      lv_to type string,
      lv_to_address type string,
      lv_subject type string,
      lv_msg type string.
lv_input-from = 'MYSAPTEST'.
lv_input-from_address = '<someAddress>'.
lv_input-to = 'Prashant'.
lv_input-to_address = '<someAddress>'.
lv_input-subject = ' TEST'.
lv_input-msg_body = ' Hi this is wonderfull to see it work'.
try.
create object client_proxy
exporting
logical_port_name = 'BASIC'. " Basic is a TYPE G RFC Destination
call method client_proxy->send_email
   exporting
     input = lv_input
   importing
     output = lv_response    .
catch cx_ai_system_fault into sys_exception .
    data lv_err type string.
     lv_err = sys_exception->if_message~get_text( ).
     write: / lv_err.
catch cx_ai_application_fault into sys_exception2 .
     lv_err = sys_exception->if_message~get_text( ).
     write: / lv_err.
endtry.
if lv_response is initial.
   write: /'Not Executed'.
else.
   write: /'Did Execute'.
endif.
Greetings
Prashant

Reg calling Transaction code in Webdynpro ABAP

Hi All,
Can I call Transaction code in Webdynpro ABAP Portal Application. If so, how can this be possible? Can anybody give me a lead?
Thanks.
Kumar Saurav.

Hi,
The most easy Way is here:
1) Test any Webdynpro Application from SE80 when the webdynpro Browser opens to display output
Copy its HTTP link, Suppose we get the below link
http://r3d01web1.Siemens.dk:8001/sap/bc/webdynpro/sap/z_dynamic_view?sap-client=002&sap-language=EN
2) Now replace some part of the above link ( webdynpro/sap/z_dynamic_view?sap-client=002&sap-language=EN ) with the new link part ( gui/sap/its/webgui?~transaction=PA30 )
So that the newly generated link is such that the below one:
http://r3d01web1.Siemens.dk:8001/sap/bc/gui/sap/its/webgui?~transaction=PA30
Note in place of PA30 you can put any of your desired tcode.
3) Now Just Make a webdynpro component and in its View layout put a LINK TO URL ui element
and in its property REFERENCE just past the http link ( http://r3d01web1.Siemens.dk:8001/sap/bc/gui/sap/its/webgui?~transaction=PA30 )
4) Activate and test your webdynpro Application.

I want to send a response from the servlet and then call another servlet.

Hi,
I want to send a response from the servlet and then call another servlet. can this happen. Here is my scenario.
1. Capture all the information from a form including an Email address and submit it to a servlet.
2. Now send a message to the browser that the request will be processed and mailed.
3. Now execute the request and give a mail to the mentioned Email.
Can this be done in any way even by calling another servlet from within a servlet or any other way.
Can any one Please help me out.
Thanks,
Ramesh

Maybe that will help you (This is registration sample):
1.You have Registration.html;
2.You have Registration servlet;
3.You have CheckUser servlet;
4.And last you have Dispatcher between all.
See the code:
Registration.html
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<HTML>
<HEAD>
    <TITLE>Hello registration</TITLE>
</HEAD>
<BODY>
<H1>Entry</H1>
<FORM ACTION="helloservlet" METHOD="POST">
<LEFT>
User: <INPUT TYPE="TEXT" NAME="login" SIZE=10><BR>
Password: <INPUT TYPE="PASSWORD" NAME="password" SIZE=10><BR>
<P>
<TABLE CELLSPACING=1>
<TR>
<TH><SMALL>
<INPUT TYPE="SUBMIT" NAME="logon" VALUE="Entry">
</SMALL>
<TH><SMALL>
<INPUT TYPE="SUBMIT" NAME="registration" VALUE="Registration">
</SMALL>
</TABLE>
</LEFT>
</FORM>
<BR>
</BODY>
</HTML>
Dispatcher.java
package mybeans;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.ServletException;
import java.io.IOException;
import javax.servlet.RequestDispatcher;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class Dispatcher extends HttpServlet {
    protected void forward(String address, HttpServletRequest request,
                           HttpServletResponse response)
                           throws ServletException, IOException {
                               RequestDispatcher dispatcher = getServletContext().
                               getRequestDispatcher(address);
                               dispatcher.forward(request, response);
Registration.java
package mybeans;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class Registration extends Dispatcher {
    public String getServletInfo() {
        return "Registration servlet";
    public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        ServletContext ctx = getServletContext();
        if(request.getParameter("logon") != null) {
            this.forward("/CheckUser", request, response);
        else if (request.getParameter("registration") != null) {
            this.forward("/registration.html", request, response);
CheckUser.java
package mybeans;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import java.sql.*;
public class CheckUser extends Dispatcher {
    Connection conn;
    Statement stat;
    ResultSet rs;
      String cur_UserName;
    public static String cur_UserSurname;;
    String cur_UserOtchestvo;
    public String getServletInfo() {
        return "Registration servlet";
    public void service(HttpServletRequest request, HttpServletResponse response)
    throws ServletException, IOException {
        try{
            ServletContext ctx = getServletContext();
            Class.forName("oracle.jdbc.driver.OracleDriver");
            conn = DriverManager.getConnection("jdbc:oracle:oci:@eugenz","SYSTEM", "manager");
            stat = conn.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE, ResultSet.CONCUR_UPDATABLE);
           String queryDB = "SELECT ID, Login, Password FROM TLogon WHERE Login = ? AND Password = ?";
            PreparedStatement ps = conn.prepareStatement(queryDB);
           User user = new User();
        user.setLogin(request.getParameter("login"));
        String cur_Login = user.getLogin();
        ps.setString(1, cur_Login);
        user.setPassword(request.getParameter("password"));
        String cur_Password = user.getPassword();
        ps.setString(2, cur_Password);
     Password = admin");
        rs = ps.executeQuery();
             String sn = "Zatoka";
        String n = "Eugen";
        String queryPeople = "SELECT ID, Surname FROM People WHERE ID = ?";
       PreparedStatement psPeople = conn.prepareStatement(queryPeople);
                  if(rs.next()) {
            int logonID = rs.getInt("ID");
            psPeople.setInt(1, logonID);
            rs = psPeople.executeQuery();
            rs.next();
                   user.setSurname(rs.getString("Surname"));
          FROM TLogon, People WHERE TLogon.ID = People.ID";
                   ctx.setAttribute("user", user);
            this.forward("/successLogin.jsp", request, response);
        this.forward("/registration.html", request, response);
        catch(Exception exception) {
}CheckUser.java maybe incorrect, but it's not serious, because see the principe (conception).
Main is Dispatcher.java. This class is dispatcher between all servlets.

Calling a servlet in java class

Hello,
I try to call a servlet from java class
but is dose not work
what should be the problem
   public void callServlet()
          try
                        // xxservlet is the servlet name
               URL url = new URL("http://www.mydomain.com/xxservlet");
               URLConnection hpCon = url.openConnection();
               hpCon.setDoOutput(true);
               OutputStreamWriter out = new OutputStreamWriter(hpCon.getOutputStream());
               out.write("This Is a Test");
               out.flush();
               out.close();
          }catch(Exception ex){ex.printStackTrace();}
// My Servlet is in package servlets
public class XXServlet extends HttpServlet
    public void service(HttpServletRequest req, HttpServletResponse resp) {
        try {
             ServletInputStream sin = req.getInputStream();
             int len = req.getContentLength();
                byte[] input = new byte[len];
                ServletInputStream sin = req.getInputStream();
               int c, count = 0 ;
               while ((c = sin.read(input, count, input.length-count)) != -1) {
                   count +=c;
              sin.close();
              String inString = new String(input);
              System.out.println("Servlet is running ...."+inString);
        } catch (IOException e) {
            try{
                resp.setStatus(HttpServletResponse.SC_BAD_REQUEST);
                resp.getWriter().print(e.getMessage());
                resp.getWriter().close();
            } catch (IOException ioe) {
// web.xml
<servlet>
       <servlet-name>xxservlet</servlet-name>
       <servlet-class>servlets.XXServlet</servlet-class>
    </servlet>
   <servlet-mapping>
    <servlet-name>xxservlet</servlet-name>
    <url-pattern>/xxservlet</url-pattern>
</servlet-mapping>
}regards
Edited by: the_Orient on Mar 30, 2009 3:16 AM

I have start servlet from brwoser only to test that servlet works fine
A gain what I need
I want to call a servlet from a javs class
URL url = new URL("http://www.mydomain.com/myservlet");
URLConnection hpCon = url.openConnection();
hpCon.setDoOutput(true);
OutputStreamWriter out = new OutputStreamWriter(hpCon.getOutputStream());
out.write("Hello Woprld");
out.flush();
out.close();// Servlet
public void doGet(HttpServletRequest req, HttpServletResponse resp) {
        try {
              String xp =req.getSession().getServletContext().getRealPath("/");
              File f = new File(xp+"/students/info.txt");
              f.createNewFile();
        } catch (IOException e) {
            try{
                resp.setStatus(HttpServletResponse.SC_BAD_REQUEST);
                resp.getWriter().print(e.getMessage());
                resp.getWriter().close();
            } catch (IOException ioe) {
problem file can not be created
    public void doPost(HttpServletRequest req, HttpServletResponse resp)
}I hope that is clear

Help needed to call a servlet from an applet

Hi,
can someone help me with the way to call a servlet from an applet.
actually on click of a button i wanna call my servlet and save some data in DB.
i am not able to call my servlet. see the sample code which i am trying..
public void actionPerformed(ActionEvent event) {
if (event.getActionCommand().equals("Upload")) {
try {
System.out.println("Upload button has been clicked -----------");
URL url = new URL("http://localhost:8084/uploadApp/TestServlet");
URLConnection urlConnection = url.openConnection();
urlConnection.setDoInput(true);
urlConnection.setDoOutput(true);
urlConnection.setUseCaches(false);
ObjectOutputStream objOut = new ObjectOutputStream (urlConnection.getOutputStream());
objOut.writeBytes(userId); // pass parameter to servlet
objOut.flush();
objOut.close();
} catch (MalformedURLException ex) {
Logger.getLogger(ButtonListener.class.getName()).log(Level.SEVERE, null, ex);
} catch (IOException ex) {
Logger.getLogger(ButtonListener.class.getName()).log(Level.SEVERE, null, ex);
is there any problem with the code? please suggest.

hii,
checkout my add from, HTH
[http://forums.sun.com/thread.jspa?threadID=5419921&messageID=10885709#10885709]
... kopik

Calling a servlet from a servlet?

Is it possible to call one servlet from another servlet?

You should use servlets to process requests. If what you're asking for is to execute a piece of logic within a servlet before its finished processing the request, then you should consider using a regular java class instead of a servlet. If you just want to send the request information to another servlet you can use getRequestDipatcher().forward(..) method. Keep in mind that by doing so you'll interupt the current servlet.
Regards,
D.

Calling a servlet from another servlet?

Hi
I would like to know that how can I call one Servlet from another Servlet. I have tried getServlet() method of ServletContext but it has been deprecated. I want to call a specific method of the other Servlet, is there any other way?
Thanks

I should have seen it from your previous post :(
Code of Servlet 1:
public void doGet(HttpServletRequest request,
HttpServletResponse response) throws
ServletException, IOException
RequestDispatcher rDispatch = null ;
rDispatch = getServletConfig
().getServletContext().getRequestDispatcher
("/Servlet2") ;
rDispatch.forward(request, response) ;
System.out.println("Back in 1");
I assume Servlets 1and 2 are in same web app and you've mapped your servlet2 to /Servlet2 in your web.xml
make it as
rDispatch = request.getRequestDispatcher("/Servlet2");
rDispatch.forward(request,response);
Nothin's wrong with yer servlet2

Calling a servlet from XSQL

Has anyone successfully called a servlet from xsql? If you have, have you called one from the href in the xsl:stylesheet?
null

Can you post a sample of what you're trying to do? Not sure what you mean by having the XSQL "call a servlet"? Call a servlet when? to serve/use what?
Are you trying to using a servlet to return a dynamically-constructed stylesheet in the role of:
<?xml-stylesheet type="text/xsl" href="http://foo/servlets/myservlet"?>
If not, can you expound on what you're trying to achieve/accomplish?
Thanks.

Servlets calls another servlet

servlets calls another servlet ...how to do it ? whats the efficient way ?
class myservlet extends HttpServlet
// i want to call a servlet situated at another machine in the LAN whose, IP // 123.123.45.66 (say)
the servlet which is situated in another machine
remoteservlet extends HttpServlet
doPost(...)
how do i call ?
few of the way i found by searching the forum.
but i would like to know the good way in my situation.

res.sendRedirect("LoginServlet?="+req.getRequestURI())
i tested this. it does not work.
my servlet wants to call another servlet which is
active on IP xxx.ddd.ffff.zzz in the LAN .
whats the way ?
res.sendRedirect("http://xxx.ddd.ffff.zzz:<portnumber>/<context_name>/<servlet_regd_name">);The request and response objects are generated anew for that Servlet. There's no two ways about it, IMO.
cheers,
ram.

Call a servlet in webdynpro

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