Calling Java function XSL

Question

Hi,
I am trying to call a small java function in XSL but while performing transformation I get following error
"Function not in namespaceError in XPath expression, Function not in namespace"
I am performing following steps:
1. Java class file placed in class path and classpath is set. Java class is a simple file with no main() function. There is only one function called calculate()
2. Defined a namespace in XSL
3. Calling a function from class file in XSL
My XSL looks like this:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:fib="java:FibonacciNumber" extension-element-prefixes="fib" >
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/" >
<xsl:value-of select="fib:calculate(number(.))"/>
</xsl:template>
</xsl:stylesheet>
Can someone please point out what I am missing out here?
Regards,
Nitin

Answer 1

Looks like you are using the Xalan convention for java protocol in namespaces.
In Oracle XDK you need to use:
xmlns:fib="http://www.oracle.com/XSL/Transform/java/FibonacciNumber"
Assuming your class is in the default package.
If it is in a package you need the fully qualified name:
xmlns:fib="http://www.oracle.com/XSL/Transform/java/com.foo.FibonacciNumber"
See for example http://www.devx.com/Java/Article/31675/0/page/1
or http://download-east.oracle.com/docs/cd/B14099_11/web.1012/b14033/adx04xsj.htm#i1023310
For more discussion on how hard it is to craft portable functions with Oracle,
see Re: EXSLT implementation
Mik