Can a tree control express a heirarchical query?

Hi,
Are any of the tree controls data aware?
null

The tree controls are not data aware. Creating a data model for a
tree control is highly dependent on the data so it is best left
to the developer to design.
Regards,
JDeveloper Team
Sotiri Bonanos (guest) wrote:
: Hi,
: Are any of the tree controls data aware?
null

Similar Messages

How can I display and change built-in symbols of a tree control programmatically?

I want to set the built-in symbols of a tree control during runtime.
I only found an example to assign custom pictures but not how to select one of the 40 built-in symbol.
Many Thanks
Solved!
Go to Solution.

The ActiveItem.SymbolIndex will allow you to select the symbol for the active item. You can use the ListBox Symbol Ring Constant (Dialog and User Interface palette) to select a symbol (or you can just enter the number directly if you know what it is).
Message Edited by smercurio_fc on 07-10-2008 09:36 AM
Attachments:
Example_VI_BD6.png ‏2 KB

How can I save the all the values of a tree control ?

I have a problem, in run time, I adds new items on a tree control, but i don´t know how I can save the values of the child text of each item in a file.
Thanks.

I'm no expert on the tree control, but I made a small example to save all items to a textfile, including item tag, item string, and indent level. One drawback of this method is that it fully expands the tree regardless how the user left it. To go the other direction, you'd have to write a routine to go through the text file and programmatically build the tree.
To master the tree control, I think you have to resort to creating a control reference for it and using the Invoke Node to do some operations. For another approach to traversing and operating on a tree, check out the "Traversing Tree Controls and Setting Custom Symbols" (search the NI Developer Zone site).
Best of luck,
John
Attachments:
Save Tree Structure to Textfile.vi ‏32 KB

How can I drag and drop an item from one Tree control to another in LabVIEW 7.1?

You can use the mouse up and down event on the two tree controls but the problem is making the correct selection in the second tree control. I want to be able to switch over to the selection bar of the second tree control so that I can place my item in the correct position. I know all possible workarounds with double-clicks and so on... but I really want a windows drag and drop.
This is what I have for the moment. Please check the library below. I need to activate the selection bar of the second tree control somehow to get the position in the control. The VI below is written in LV 7.1
Attachments:
Drag&Drop.llb ‏65 KB

Hi Jones,
As far as I know this feature is currently not supported by the Tree control. A workaround, would be to use the vertical position of the mouse in the button up event to determine what line you�re dropping the item.
If you would like the Tree control to include the drag and drop feature, please submit this as a Product Suggestion under the feedback at www.ni.com/contact.
Good luck!
Best regards,
Philip C.
Applications Engineer
National Instruments
www.ni.com/ask
- Philip Courtois, Thinkbot Solutions

Can we handle exceptions for the expressions in select query?

Hi all,
Can we handle exceptions for the expressions in select query.
I created a view, there I am extracting a substring from a character data and expected that as a number.
For example consider the following query.
SQL> select to_number( substr('r01',2,2) ) from dual;
TO_NUMBER(SUBSTR('R01',2,2))
1
Here we got the value as "1".
Consider the following query.
SQL> select to_number( substr('rr1',2,2) ) from dual;
select to_number( substr('rr1',2,2) ) from dual
ORA-01722: invalid number
For this I got error. Because the substr returns "r1" which is expected to be as number. So it returns "Invalid number".
So, without using procedures or functions can we handle these type of exceptions?
I am using Oracle 10 G.
Thanks in advance.
Thank you,
Regards,
Gowtham Sen.

SQL> select decode(ltrim(rtrim(translate(substr('r21', 2, 2), '0123456789', ' ' ), ' '), ' '), null, (substr('r21', 2, 2)), null) from dual;
DE
21
SQL> ed a
SQL> select decode(ltrim(rtrim(translate(substr('rr1', 2, 2), '0123456789', ' ' ), ' '), ' '), null, (substr('rr1', 2, 2)), null) from dual;
D
-

Can I edit the data already displayed in tree control?

I'm using a tree control to display some data in front panel. But after running the program, can I edit the data already displayed in tree control by using input control and let it change and display dynamically? In invoke nodes I can only find add or delete items in tree but can't find edit...

There is no direct editing option available, same can be achieved in two steps by using
--> Add Item Invoke Node
--> Delete Item Invoke Node
I am not allergic to Kudos, in fact I love Kudos.
Make your LabVIEW experience more CONVENIENT.

Can i place controls from the properties dialog of an express vi on the front panel?

I'm using the spectral measurements express vi in my vi and I'd like to put the "window" and "number of averages" controls from the properties dialog on the front panel. However, there are not outputs on the express vi icon for these parameters. Can I place controls for these on the front panel somehow or do I always have to go into the block diagram and open the properties dialog to change the values?

The way to do this is to right click on the express VI and select Open Front Panel. This will convert it to a standard subVI. then go into the subVI and replace the Spectrum Averaging and Spectrum Window constants to front panel controls by right click on them. Right click the icon and select Show Connector. Wire the new controls to a free terminal on the connector. You may have to add additional terminals if there aren't any available to wire to the new controls.

How can we use "tooltip " option in heirarchical tree item in oracle 11g?

how can we use "tooltip " option in heirarchical tree item properties in oracle 11g forms?

hi user11973188
how can we use "tooltip " option in heirarchical tree item properties in oracle 11g forms?isn't it exist in the tree item's property itself... ?!
Regards,
Abdetu...

Can I use control query and Variant?

Can I use control query and Variant?
I tried both but its not working, whats my requirement is in a web template having material, distribution as drop box and I have to create for all countries(Like USA, Canada,China)so what I did , I created a control query as material& distribution and I created variants for countries. After precalculating its not working.
Any help ll be appreciated
Thanks

Yes you can use Control Query AND Variant in your Setting. Maybe you did not setup you Web template correctly?

How to get all items under a parent item in a tree control

Hello,
I have 2 questions regarding a tree control:
1) Is there any way to specify a parent item tag and get an array of ALL its sub item tags? For example, in the attached vi, specify the Parent#2 parent tag and get an array containing Item#P21 and Item#P22
2) Is there a way to specify a range to the ActiveCell property. For example, all items from line#1 to line number#3
Any ideas?
Attachments:
Tree example.vi ‏6 KB

Mentos wrote:
1) Is there any way to specify a parent item tag and get an array of ALL its sub item tags? For example, in the attached vi, specify the Parent#2 parent tag and get an array containing Item#P21 and Item#P22
Did you try a search? There's no direct way of doing this. You have to navigate the tree and build up an array. You can find an example here: http://forums.ni.com/t5/LabVIEW/get-all-children-of-a-parent-in-tree/td-p/729548
2) Is there a way to specify a range to the ActiveCell property. For example, all items from line#1 to line number#3
No. (It's called ActiveCell, not ActiveCells) Presumably you are trying to perform an operation on multiple items. Unfortunately, you need to use a loop. You should defer panel updates if you're doing this a lot.

How to binding incoming xml node list to the tree control as dataProvider

Recently, I faced into one issue: I want to binding incoming xml node (it's not avaliable at start) list to the tree control as a dataProvider.
Since the incoming xml node list is not avaliable at beginning but I needs to bind it to the tree, so I create one virtual one in the xml, and prepare to remove it before the tree is shown. (ready for the actual node adding). But It did not work.
Please see the presudo-code here:
1. Model layer(CsModel.as)
public class CsModel
        [Bindable]
        public var treeXML:XML=<nodes><car label="virtualOne" id="1">
                               </car></nodes>;
        (Here, I want to build binding relationship on the <car/> node,
         one 'virtual/stub' node is set here with lable="virtualOne".
         But this node will be deleted after IdTree
         control is created completely.)
        [Bindable]
        public var treeData:XMLList =new XMLListCollection(treeXML.car);
2. view layer(treePage.mxml)
        private var _model:CsModel = new CsModel();
        private function addNode():void
                var newNode:XML=<car/>;
                newNode.@label="newOne";
                newNode.@id=1;
                _model.treeXML.appendChild(newNode);
                         private function cleanData():void
                                 delete _model.treeXML.car;
        <mx:VBox height="100%" width="100%">
        <mx:Button label="AddNode" click="addNode()" />
        <mx:Tree id="IdTree" labelField="@label"
          creationComplete="cleanData()"
          dataProvider="{_model}"/>
    </mx:VBox>
3. Top view layer (App.Mxml)
<mx:application>
    <treePage />
</mx:application>
For method: cleanData()，It's expected that when the treePage is shown, we first delete the virutalOne to provide one 'clear' tree since we don't want show virtualOne to the user. The virutalOne node just for building the relationship between treeData and treeXML at beginning. But the side effect of this method, I found, is that the relationship between treeXML and treeData was cut off. And this leads to that when I added new node (by click the 'addNode' button) to the xmlXML, the xmlData was not affected at all !
So Is there any other way to solve this issue or bind the incoming xml node list to the xmlListCollection which will be used as Tree control's dataProvider ?

If u want to display the name : value then u can do like this
<xsl:eval>this.selectSingleNode("name").nodeName</xsl:eval> : <xsl:value-of select="name" />

How to use the drop event of the tree control in LabVIEW 8.20?

Hi,
I am using the two tree controls in my application to provide a option for the user to drag and drop item from one tree to the other. I have to validate the user selection. I tried to capture the user drop event using the event structure. The problem I am facing is, I am not able to drop the item even though i have wired a constant true to the filter(Accepted?) in the event case. I have enable the property(Allow droping) in the right menu of the tree control also.
While configuring an event case for (drop, drag entered and some thing like this) only I am getting the problem otherwise it is working fine.
What do i need to do to caprture the drop event ?
Is there any way to avoid the item duplication while droping a new item in the tree control ?
or how can i do this?
Thanks,
Pandiarajan R

Hi Pandiarajan,
I hope you are doing well today! There is a lengthy discussion on the Tree Control Drag & Drop feature at this forums post including contributions from the developer of the Drag & Drop feature:
Tree Control Drag & Drop in LabVIEW 8
By avoiding item duplication, do you mean that you don't want the same item to be in the old tree control or do you not want more than one item in the new tree control?
Adnan Zafar
Certified LabVIEW Architect
Coleman Technologies

How to get position of a ring in a tree control?

Ok, this is probably a stupid question, but how does one get the position of a ring inside of a tree control? I have a tree with two columns, with rings in the second column. I can set the position using SetTreeCellRingValueFromIndex(), but how does one get the position after the user has modified the control? I found the functions GetTreeCellRingIndexFromValue() and GetTreeCellRingValueFromIndex() but I haven't found a way to get either the Index or the Value of the ring (what I'm looking for is the index, but if I can obtain the value I can go from there). Thanks in advance!
Solved!
Go to Solution.

Hi,
You can use GetTableCellVal function to get the value of the ring.
There is not special "ring" function for that. Maybe that's what you were searching for
From the value you can get to the index using the functions you are already aware of.
Hope this helps,
S. Eren BALCI
www.aselsan.com.tr

Ssrs expression to sql query

Hi,
I am unable to convert the below ssrs expression to sql query. can you guys help.
-- IIF(Parameters!parameter1.Value Is Nothing,
-- " 3>2 ",
-- "column1 NOT LIKE
-- Replace(IIF(Left(Parameters!parameter1.Value, 1) = "'",
-- Parameters!parameter1.Value,
-- "'" & Replace(Parameters!parameter1.Value, "'", "''") "'"),
Thanks.

Thank you for your response Carnegie,
I actually have two stored procedures as below. (columns and joined tables are excluded)
I need to change the dates of @DateFrom and @DateTo parameter, I am passing @DateFrom_FD and @DateTo_LD as well.
CREATE ROCEDURE [dbo].[Test]
(@DateFrom
SMALLDATETIME
, @DateTo
SMALLDATETIME
, @program
VARCHAR(MAX))
AS
DECLARE
@DateFrom_FD
SMALLDATETIME
, @DateTo_LD
SMALLDATETIME
SET @DateFrom_FD = DATEADD(MONTH,DATEDIFF(MONTH,0,@DateFrom),0)
SET @DateTo_LD = DATEADD(DAY,-1,DATEADD(MONTH,DATEDIFF(MONTH,0,@DateTo)+1,0))
SELECT
DimDate.[Year]
, DimDate.[Month]
, DimDate.PK_Date
, CustomerID
FROM DimDate
WHERE DimDate.PK_Date BETWEEN @DateFrom_FD AND @DateTo_LD
Now I am using one of the SP as a main report and the other SP as a subreport.
In order to configure the main report and the subreport, I believe that I need to link them with parameters.
However, in the parameters of subreport properties, the option given are only @DateFrom and @DateTo.
No @DateFrom_FD AND @DateTo_LD
Therefore, I am thinking to use expressions to convert @DateFrom and @DateTo the same way I did in SQL.
I am not sure if this works....but this is the only thing that I could think of.
Thank you,
YJB5151

How do I get the tag of a selected line in a tree control ?

I am running LabVIEW 7.1.
I want to be able to add a parent or sibling to a tree to a selected item in a tree.

The tag of the selected item is actually the output of the tree control itself. If you create an indicator from the tree control, you will get a duplicate tree control (indicator), but if you wire the output into a string indicator, the tag of the selected item will show up. You can an item to the tree by wiring the tree reference into an invoke node, calling the method "Edit Tree Items: Add Item", and wiring the output of the tree control (which will be the tag of the selected item) into the "Parent Tag" terminal. This method will only let you add a child to an item, you cannot add a parent or sibling. Items cannot have multiple parents, so it wouldn't make sense to add a parent; and to add a sibling for the selected item, you could call the method "Navigate Tree: Get Parent" and pass the tag of the parent into the "Edit Tree Items: Add Item" method.
Robert Mortensen
Software Engineer
National Instruments

Can a tree control express a heirarchical query?

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