Can somebody please explain how to format and then reinstall Mac lion10.7 without cd

can somebody please explain how to format and then reinstall Mac lion10.7 without cd

You will need either an Ethernet or Wifi Connection to the Internet - USB Mobile device is not supported.
If you already have Lion installed you can boot to Recovery with Command R and use the Disk Utility to erase the Macintosh HD and then reinstall the OS from the Mac OS X Utilities.
You will need the Apple Id used for purchase if the Mac did not ship with Lion installed originally.
If you want to repartition the HDD you can use the Recovery Disk Assistant to make a recovery USB drive
http://support.apple.com/kb/DL1433
http://support.apple.com/kb/HT4848
As Always - Back up the Mac before erasing unless you are confident there is absolutely nothing on the mac that you might possibly need later.
If the machine is a 2011 build or later you might be able to boot to Internet Recovery with Command Option R

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    GROUP BY P2.SAL
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    SQL> select * from psal;
    NAME SAL
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    baker 900
    charles 900
    delta 800
    eddy 700
    fred 700
    george 700
    george 700
    Regards,
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    ... Please help me in understanding the query.
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    If you run it in steps and analyze the output at the end of each step, then you should be able to understand what it does.
    Given below is some brief information on the same:
    test@ora>
    test@ora> --
    test@ora> -- Query 1 - using the non-equi (theta) join
    test@ora> --
    test@ora> with psal as (
      2    select 'able' as name, 1000 as sal from dual union all
      3    select 'baker',   900 from dual union all
      4    select 'charles', 900 from dual union all
      5    select 'delta',   800 from dual union all
      6    select 'eddy',    700 from dual union all
      7    select 'fred',    700 from dual union all
      8    select 'george',  700 from dual union all
      9    select 'george',  700 from dual)
    10  --
    11  SELECT p1.sal AS p1_sal, p1.NAME AS p1_name, p2.sal AS p2_sal,
    12         p2.NAME AS p2_name
    13    FROM psal p1, psal p2
    14   WHERE p1.sal >= p2.sal;
        P1_SAL P1_NAME     P2_SAL P2_NAME
          1000 able          1000 able
          1000 able           900 baker
          1000 able           900 charles
          1000 able           800 delta
          1000 able           700 eddy
          1000 able           700 fred
          1000 able           700 george
          1000 able           700 george
           900 baker          900 baker
           900 baker          900 charles
           900 baker          800 delta
           900 baker          700 eddy
           900 baker          700 fred
           900 baker          700 george
           900 baker          700 george
           900 charles        900 baker
           900 charles        900 charles
           900 charles        800 delta
           900 charles        700 eddy
           900 charles        700 fred
           900 charles        700 george
           900 charles        700 george
           800 delta          800 delta
           800 delta          700 eddy
           800 delta          700 fred
           800 delta          700 george
           800 delta          700 george
           700 eddy           700 eddy
           700 eddy           700 fred
           700 eddy           700 george
           700 eddy           700 george
           700 fred           700 eddy
           700 fred           700 fred
           700 fred           700 george
           700 fred           700 george
           700 george         700 eddy
           700 george         700 fred
           700 george         700 george
           700 george         700 george
           700 george         700 eddy
           700 george         700 fred
           700 george         700 george
           700 george         700 george
    43 rows selected.
    test@ora>
    test@ora>This query joins PSAL with itself using a non equi-join. Take each row of PSAL p1 and see how it compares with PSAL p2. You'll see that:
    - Row 1 with sal 1000 is >= to all sal values of p2, so it occurs 8 times
    - Row 2 with sal 900 is >= to 9 sal values of p2, so it occurs 7 times
    - Row 3: 7 times again... and so on.
    - So, total no. of rows are: 8 + 7 + 7 + 5 + 4 + 4 + 4 + 4 = 43
    test@ora>
    test@ora> --
    test@ora> -- Query 2 - add the GROUP BY
    test@ora> --
    test@ora> with psal as (
      2    select 'able' as name, 1000 as sal from dual union all
      3    select 'baker',   900 from dual union all
      4    select 'charles', 900 from dual union all
      5    select 'delta',   800 from dual union all
      6    select 'eddy',    700 from dual union all
      7    select 'fred',    700 from dual union all
      8    select 'george',  700 from dual union all
      9    select 'george',  700 from dual)
    10  --
    11  SELECT p2.sal AS p2_sal,
    12         COUNT(*) as cnt,
    13         COUNT(p1.sal) as cnt_p1_sal,
    14         COUNT(DISTINCT p1.sal) as cnt_dist_p1_sal,
    15         MIN(p1.sal) as min_p1_sal,
    16         MAX(p1.sal) as max_p1_sal
    17    FROM psal p1, psal p2
    18   WHERE p1.sal >= p2.sal
    19  GROUP BY p2.sal;
        P2_SAL        CNT CNT_P1_SAL CNT_DIST_P1_SAL MIN_P1_SAL MAX_P1_SAL
           700         32         32               4        700       1000
           800          4          4               3        800       1000
           900          6          6               2        900       1000
          1000          1          1               1       1000       1000
    test@ora>
    test@ora>Now, if you group by p2.sal in the output of query 1, and check the number of distinct p1.sal, min of p1.sal etc. you see that for p2.sal values - 800, 900 and 1000, there are 3 or less p1.sal values associated.
    So, the last 3 rows are the ones you are interested in, essentially. As follows:
    test@ora>
    test@ora> --
    test@ora> -- Query 3 - GROUP BY and HAVING
    test@ora> --
    test@ora> with psal as (
      2    select 'able' as name, 1000 as sal from dual union all
      3    select 'baker',   900 from dual union all
      4    select 'charles', 900 from dual union all
      5    select 'delta',   800 from dual union all
      6    select 'eddy',    700 from dual union all
      7    select 'fred',    700 from dual union all
      8    select 'george',  700 from dual union all
      9    select 'george',  700 from dual)
    10  --
    11  SELECT p2.sal AS p2_sal,
    12         COUNT(*) as cnt,
    13         COUNT(p1.sal) as cnt_p1_sal,
    14         COUNT(DISTINCT p1.sal) as cnt_dist_p1_sal,
    15         MIN(p1.sal) as min_p1_sal,
    16         MAX(p1.sal) as max_p1_sal
    17    FROM psal p1, psal p2
    18   WHERE p1.sal >= p2.sal
    19  GROUP BY p2.sal
    20  HAVING COUNT(DISTINCT p1.sal) <= 3;
        P2_SAL        CNT CNT_P1_SAL CNT_DIST_P1_SAL MIN_P1_SAL MAX_P1_SAL
           800          4          4               3        800       1000
           900          6          6               2        900       1000
          1000          1          1               1       1000       1000
    test@ora>
    test@ora>
    test@ora>That's what you are doing in that query.
    The thing is - in order to find out Top-N values, you simply need to scan that one table PSAL. So, joining it to itself is not necessary.
    A much simpler query is as follows:
    test@ora>
    test@ora>
    test@ora> --
    test@ora> -- Top-3 salaries - distinct or not; using ROWNUM on ORDER BY
    test@ora> --
    test@ora> with psal as (
      2    select 'able' as name, 1000 as sal from dual union all
      3    select 'baker',   900 from dual union all
      4    select 'charles', 900 from dual union all
      5    select 'delta',   800 from dual union all
      6    select 'eddy',    700 from dual union all
      7    select 'fred',    700 from dual union all
      8    select 'george',  700 from dual union all
      9    select 'george',  700 from dual)
    10  --
    11  SELECT sal
    12  FROM (
    13    SELECT sal
    14      FROM psal
    15    ORDER BY sal DESC
    16  )
    17  WHERE rownum <= 3;
           SAL
          1000
           900
           900
    test@ora>
    test@ora>
    test@ora>And for Top-3 distinct salaries:
    test@ora>
    test@ora> --
    test@ora> -- Top-3 DISTINCT salaries; using ROWNUM on ORDER BY on DISTINCT
    test@ora> --
    test@ora> with psal as (
      2    select 'able' as name, 1000 as sal from dual union all
      3    select 'baker',   900 from dual union all
      4    select 'charles', 900 from dual union all
      5    select 'delta',   800 from dual union all
      6    select 'eddy',    700 from dual union all
      7    select 'fred',    700 from dual union all
      8    select 'george',  700 from dual union all
      9    select 'george',  700 from dual)
    10  --
    11  SELECT sal
    12  FROM (
    13    SELECT DISTINCT sal
    14      FROM psal
    15    ORDER BY sal DESC
    16  )
    17  WHERE rownum <= 3;
           SAL
          1000
           900
           800
    test@ora>
    test@ora>
    test@ora>You may also want to check out the RANK and DENSE_RANK analytic functions.
    RANK:
    http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions123.htm#SQLRF00690
    DENSE_RANK:
    http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions043.htm#SQLRF00633
    HTH
    isotope

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    Jen

    esaisquoi wrote:
    I have a file that I have rasterized and saved as a PDF, in Illustrator. It's perfect as is, but I want to lower the PPI so the PDF can also be easily sent in an email without it being a large file. (The current file is around 7mb.)
    Rasterizing usually increases the size of Illustrator files. A circle, for example, requires very little data to be drawn. There are a total of twelve points, each with X,Y coordinates, a fill, and a stroke. This circle is stored as a mathematically defined path and will always be drawn sharply at all sizes and print sharply at all resolutions. This is called a vector graphic.
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    In the above example rasterizing has made the file larger, harder to edit, and print poorly. All of these are bad.
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    I used the Effects > Doc Raster Effects Setting to lower the PPI, and the only thing that happened is the file size only became few kb less than the original. I tried again, this time lowering the PPI all the way to a measely 7 (can I even do that?), and the file this time managed to get larger than the original. Not by much, mind you, but it's still baffling.
    This did nothing. Document Raster Effects Settings applies to any effect in the Effects menu that produce a raster image rather than a vector, which only applies to a few commands. Effect > Stylize > Drop Shadow, Inner Glow, Outer Glow, and Feather are some, as are all the effects below Photoshop Effects. The setting has no effects on anything that has already been rasterized.
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    I don't particularly care how I acheive the effect, but I'd like to lower the file size.
    I don’t know what effect you are trying to produce. Use the camera icon at the top of a reply to attach a screen grab of what you have drawn. If this is not exactly what you want, but you can find it somewhere else on the web, post a screen grab of that, too.
    Also, can someone explain to me what I am obviously not understanding about PPI? Freakin' PPI, how does THAT work?
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        So that there will be a higher bandwidth for EF packets.
             910Kbps X .26 = 236.6   approx. 237Kbps

    Hello,
    Please confirm if my presentation is  correct. Thank you very much in advance....
    First, I have called Telstra to ask what is the upload speed of the link in our atm link. They said it is 910Kbps.
    Then I checked also our router and I have executed a show command à sh controller atm0/1/0
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            IDB: 0x30AB0424  Instance: 0x30AC1288  PHY Inst: 0x00000000  us_bwidth: 910  -->  I am assuming that this is Upload Speed = 910Kbps  and this is automatically detected by the router interface.
    Second, I have checked the EF priority value. For my 5 ip phones in this site.
    Class-map: cm-voice-out (match-all)
      653566 packets, 134229712 bytes
      1 minute offered rate 0000 bps, drop rate 0000 bps
      Match: ip dscp ef (46)
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    Third, My question to myself:  Why Priority 26% got the corresponding bandwidth of 133 Kbps???
                 My assessment: I’m  assuming that it depends on what was configured on this command line --> vbr-nrt <SCR> <PCR>  = vbr-nrt 512 512   (In my understanding, This is ATM shaping).
              512Kbps X .26  = 133.12  approx. 133Kbps
    My Conclusion:
          From current configuration vbr-nrt 512 512  .... I’m thinking if we can change it to this new configuration --> vbr-nrt  910 910 , Does it affect the call delay?
        So that there will be a higher bandwidth for EF packets.
             910Kbps X .26 = 236.6   approx. 237Kbps

  • Can somebody please explain me this logic?

    array = [1,2,3,4,5,6,7];
    newArray = array;
    trace ("array: " + array);
    newArray = newArray.splice (0, 5);
    trace ("array: " + array);
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    array: 6,7
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    That helped me out.
    I found my problem also in the Flash Documentation. I couldn't find it before because i didn't know what to look for.
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