Can two RMI Servers talk each other

Can two RMI Servers talk each other ?
For it to happen, does one of them be dependent on another ?

1. Absolutely.
2. No

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    I am trying to transfer files from MacBook Pro to new MacBook air using Migration assistant via WiFi connection - the two computers can't seem to find each other.
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    Try this article - http://support.apple.com/kb/HT4889.
    If it doesn't help, post back in this thread.
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  • I have a new Macbook Pro - trying to migrate files etc from my Macbook Air using a Thunderbolt Cable between the two.  I follow the directions but the two computers never "discover" each other.  WiFi connect works but 70 hours is a rough deal.

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    Are you trying target disk mode?
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    I am trying to transfer files from my MacBook Pro (using Mac OSX 10.6.8) to MacBook Air (Mac OSX 10.7.4) using Migration Assist via WiFi connection.  The two macs cannot find each other.  any suggestions

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  • Two sessions are blocked each other in

    Hi All,
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  • 2 users on imessage with the same apple id but setup so they messages can't be seen by each other

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    This is not an area where I have any expertise, but you may want to consider using separate Apple IDs and using the recently released Family Sharing capabilities which still allow you to share your music and apps.
    http://www.apple.com/ios/whats-new/family-sharing/
    https://www.apple.com/support/icloud/family-sharing/

  • Cant connect two linksys routers to each other.

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  • How to print two tables adjacent to each other?

    Hi,
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    1. Since the body page is 'Flowed' type, the two tables are placed one below the other (Tab1 & Tab2). So I tried to set the Flow direction of the Body page to 'Western text'. But this did not solve the issue as since it is set to 'western text', only after Tab1 is rendered, table Tab2 starts printing itself, which is not desired. Both the tables should be printed at the same time.
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    s@k

    Dear Andres,
    I tried as per you suggestion and it works fine. Thanks a lot.
    Now adding to this, I am trying to print the 'formatted text'. The tables have two columns. the first column is a normal field and the second column is table having the 'formatted text'.
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    I have set the 'Body' row of the table to 'Flowed' with direction as 'Western text' (Top to bottom does not help ).
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    The sample data has around 10 entries in the (final)  table. When I try to print the form, if column2(table) is initial, the data in Column3 and 4 are shifted towards Left hand side.
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  • Delete masterdata from two infoobjects which have each other as attribut

    Hello,
    we have the infoobject 0BPARTNER und 0CUSTOMER which have each other within as an attribut.
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    Can you help me?
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    Hi Stefan:
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    Francisco Milán.
    Edited by: Francisco Milan on Jun 15, 2010 10:48 AM

  • How to restrict two employees from viewing each others' activities in a particular account?

    Dear Experts,
    I have a scenario here and request your kind input to bring a solution to it.
    I have two sales org. in one company. One is SO1 and other one is SO2. I want to restrict the sales employee of SO1 and SO2. Both of them are working in the same national account. I don’t want the SO1 sales employee to see what the SO2 sales employee does in that particular account; and the vice versa. So, it’s just restricting the view of particular account for both of them. Is it possible in CRM? If yes, how do you do that?
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    Hi SMTP,
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  • HT1660 if i create a copy in mp3 format in itunes from the mp4 music i already have in itunes it puts both formats in the same file is there a way of seperating the two formated albums from each other completely but keep them in itunes

    HAVE CONVERTED MY ITUNES MUSIC INTO A SECOND FORMAT OF MP3. WHEN I DID THIS IT COPIES THE MP3 FORMAT DIRECTLY INTO THE SAME FILE. THEN IT SHOWS TWO OF EACH SONG IN THE MUSIC FILE IN MP3 AND MP4. WOULD LOVE TO SEPERATE THEM INTO DIFFERENT FILES LIKE WINDOWS MEDIA PLAYER DOES WITH WMA AND MP4 IT CREATES A SEPERATE FILE FOR THE MP4 FILE DIRECTLY IN THE WMP MUSIC FOLDER THAT YOU CAN CLICK ON. QUESTION IS CAN IT BE DONE IN ITUNES IS THERE SOMETHING I CAN CLICK ON IN ITUNES THAT WILL SEPERATE THESE TWO FORMATS FROM EACH SO IT WILL BE EASIER FOR ME TO PICK WHEN NEEDED WHICH ONE I NEED WITHOUT DOING IT ONE SONG AT A TIME. THANKS PLEASE HELP!!!

    Select the Songs view. Use the Search window to display the tracks from the album. Turn on the Kind column and sort on it. Give each version of the album a distinct title. E.g. Album [AAC] and Album [MP3].
    See Grouping tracks into albums for tips on iTunes organization.
    tt2

  • Acrobat search. Two words close to each other.

    Hello.
    I recently bought Adobe Acrobat XI Pro.
    I am a college student so I frequently need to search large volumes of text for a specific keyword.
    How do I tell my Advanced Search to look for text if the distance between two keywords doesn't exceed some number of symbols or words?
    Lets say I want to find the word "Blood" in the same sentance as the word "Pressure" but not "Blood Pressure". How do I tell my search program to find that?
    In Microsoft Word, there is a feature I am talking about. See micture included.
    Those search commands are called commands, tokens or something of that nature. I forgot.
    This feature existed in some programs since the days of DOS as I remember.
    So how do I use this feature in Adobe Acrobat XI Pro ?
    Where may I find a full list of those search operators?
    Thank you.

    That isn't possible in exactly the way you describe - Acrobat has no regexp-driven search feature.
    Acrobat's Advanced Search feature has a 'proximity' option to match two or more words separated by up to a maximum number of words (which is set on the application preferences) but it will also match adjacent words, and can only be run against multiple files (not against the current document). Neither can you filter the search results using another set of rules.

  • Can two ERP systems  talk to one SCM?

    Hello Experts,
    We have a requirement to connect Two ERP systems to one SCM system?
    Is this option available is available in SCM? CIF processing and optimizer should divide for the two ERP systems in SCM.
    Please advice .
    Thanks
    Ramesh

    Hi Ramesh,
      Yes;  it is possible to integrate multiple R/3 systems with single APO. You need to define multiple business system groups in APO  and assign to different R/3 logical systems to be integrated(transaction /SAPAPO/C1 and /SAPAPO/C2). Also you can use CIF enhancements APOCF001 on APO inbound  to attach (suffix) a unique R/3 identifier along with product and location codes. For this, you have to maintain a Z table containing the required suffixes. You may further refer to application help in the enhancement transaction.
    Regards,
    Raghav
    Edited by: Raghav_Udupa on Jun 17, 2010 4:29 PM

  • How does two ERP systems of two different release communicate each other?

    Dear Experts,
    i have a query regarding the communication method between two ERP Systems of different releases.
    for example ECC6.0 and ECC4.7, how do i do the integration to make the communication happen?
    Regards,
    Binod Sahu

    Hi,
    You can use RFC for communication any version of SAP.
    This is good and easy.
    Regards,
    Anil

  • Assigning two dimensional array to each other

    Hi All,
    I have two two-dimensional arrays and I want to assign one's second dimension's values as the other's second dimension's values in this way:
            int userCounter = 0;
            for (int userID : mostCommonUsers) {
                reducedTrainingVectorForSimilarity[userCounter] = trainingVectorForSimilarity[userID];
                userCounter++;
            }In the above code, I have an *"ArrayList<Integer> mostCommonUsers"*, and iterate through this. I'm using the values inside this array list, as a first dimension's index number of the *"trainingVectorForSimilarity"*, and assigning all the values in the second dimension to the left-hand-side array's second dimension. Both array has fixed length of second dimension. So, am I right by doing this, or I should make a for-loop to iterate over the individual values on the second dimensions of both arrays?
    Another similar question: In the below code, *"trainingVectorForSimilarity"* is an *"float[][]"*, so basically I assign all the second dimensions' values into a newly created array named *"trainingUserRatings"*. Again, I assumed that if the corresponding first dimesion's second dimension values will be assign without any iteration over each values.
    for (int i = 0; i < trainingVectorForSimilarity.length; i++) {
                float[] trainingUserRatings = trainingVectorForSimilarity;
    similarity[i] = calculateCosineSimilarity(testingVectorForSimilarity, trainingUserRatings);
    Am I right for both cases?                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                   

    Here is the output for the code that you sent:
    [[1, 2, 3], [4, 5, 6]]
    [[1, 2, 3], [4, 5, 6]]
    [[1, 2, 3], [4, 5, 6]]
    [[1, 2, 3], [4, 5, 6]]
    [[1, 2, 3], [4, 999999, 6]]
    [[1, 2, 3], [4, 999999, 6]]
    [[1, 2, 3], [4, 999999, 6]]
    [[1, 2, 3], [4, 5, 6]]
    [null, [4, 999999, 6]]
    [null, [4, 999999, 6]]
    [[1, 2, 3], [4, 999999, 6]]
    [[1, 2, 3], [4, 5, 6]]I confused that even making an array copy still refers the same object but not a copy of that object. For example:
    float[][] trainingVectorForSimilarity is defined and initialized.
                float[] trainingUserRatings = new float[trainingVectorForSimilarity.length];
    trainingUserRatings = trainingVectorForSimilarity[i];
    is the same withfloat[] trainingUserRatings = new float[trainingVectorForSimilarity[i].length];
    System.arraycopy(trainingVectorForSimilarity[i], 0, trainingUserRatings, 0, trainingUserRatings.length);

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