Can you dual-boot arch linux with Windows 7 ?

Here is my current dilemna; I have Windows still on my netbook for the only reason that I use it for gaming .
Other than that I have Linux Mint dual-booted with it .
Now my question is, can I just instruct arch to install into the already existing linux partition, formatting it and making it it's home, or do I have to delete it, thus rendering my computer inoperable until I successfully dualboot arch with it ? o_O
Or should I take a different approach altogether, and triple boot my netbook with arch, mint, and windows, and then from there delete the mint partition and allocate the free space accordingly using easeus partition master (another reason I still have windows) ?
Please help . D:
PS. I HATE Windows but only kept it because apparently not everyone shares the Linux view of technology . >.>
Last edited by AstarothMastemaRavenclaw (2011-02-06 16:42:35)

if youre happy with your partition layout u can just install arch ofc.
while installing you will be prompted to select mount points and create filesystems ( you can skip the partition step )
select your current / partition for, well, /
and /home for.. /home.
the installer will then create new filesystems there (formatting those partitions) and set mountpoints

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Hello,
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joshuawagner147 wrote:
hyperreal_logic wrote:
To the original poster:
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Greetings,
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I/O size (minimum/optimal): 512 bytes / 512 bytes
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Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
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/dev/sdb1 * 1 13 104391 83 Linux
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/dev/sdb4 686 974 2321392+ 83 Linux
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grub
kernel26-fallback.img
kernel26.img
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System.map26
vmlinuz26
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Thanks in advance for any help,
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Greetings,
I'm trying to dual boot Arch linux (installed without a bootloader on a USB SSD) and Ubuntu 10.04 (installed on a hdd with GRUB2) but can't get Arch to boot. (Oh and I already have windows dualbooted)
The entry grub autogenerated:
menuentry "Arch Linux [/boot/vmlinuz26] (on /dev/sdb3)" {
insmod ext2
set root='(hd1,1)'
search --no-floppy --fs-uuid --set 95d9208a-44e4-48ba-abd2-a365d1ac25ff
linux /vmlinuz26 root=/dev/sda3 ro
initrd /kernel26.img
Why did it input root=/dev/sda3 as it says (on /dev/sdb3)?
The entry I figured would work:
menuentry "Arch Linux" {
set root=(hd1,0)
linux /boot/vmlinuz26 root=/dev/sdb3 ro
initrd /boot/kernel26.img
Output from fdisk -l:
Disk /dev/sda: 160.0 GB, 160041885696 bytes
255 heads, 63 sectors/track, 19457 cylinders
Units = cylinders of 16065 * 512 = 8225280 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disk identifier: 0xbc4264d9
Device Boot Start End Blocks Id System
/dev/sda1 * 1 13 102400 7 HPFS/NTFS
Partition 1 does not end on cylinder boundary.
/dev/sda2 13 5286 42353664 7 HPFS/NTFS
Partition 2 does not end on cylinder boundary.
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Partition 3 does not end on cylinder boundary.
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/dev/sda6 5286 6502 9764864 83 Linux
/dev/sda7 6502 18971 100155392 83 Linux
Partition table entries are not in disk order
WARNING: GPT (GUID Partition Table) detected on '/dev/sdb'! The util fdisk doesn't support GPT. Use GNU Parted.
Disk /dev/sdb: 8019 MB, 8019509248 bytes
255 heads, 63 sectors/track, 974 cylinders
Units = cylinders of 16065 * 512 = 8225280 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
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/dev/sdb1 * 1 13 104391 83 Linux
/dev/sdb2 14 111 787185 82 Linux swap / Solaris
/dev/sdb3 112 685 4610655 83 Linux
/dev/sdb4 686 974 2321392+ 83 Linux
/dev/sdb3 is the root partition
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grub
kernel26-fallback.img
kernel26.img
lost+found
System.map26
vmlinuz26
- If I try to edit the root=/dev/sda3 to /dev/sdb3 it begins booting but doesnt find /dev/sdb3.
Thanks in advance for any help,
Oskar

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