Can you please cancel my subscription? This program is not working for me. Thank you.
I am not happy with this program. Please cancel my subscription.
Hi shann1473,
I'm sorry that your subscription didn't meet your needs. I just looked at your account, and I'm not able to cancel it myself. Please contact Adobe Customer Support; they'll be able to take care of that quickly for you. Here is the contact information:
Contact Customer Care.
I apologize for the inconvenience.
Best,
Sara
Similar Messages
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what do you recommend?
Start '''[https://support.mozilla.org/en-US/kb/troubleshoot-firefox-issues-using-safe-mode Firefox in Safe Mode]''' {web Link} by holding down the '''<Shift ''(Mac Options)'' >''' key, and then starting Firefox. Is the problem still there?
You can also reset Firefox from here, but try Safe Mode first. -
When I create an event on my mac ical then sync to my iphone, I cannot later edit the event via my iphone. I used to be able to do this before. Can someone please tell me why this option does not exist anymore? I have iphone 3Gs and can't use iCloud due to older running system on my macbook pro.
Lyndsay237 wrote:
This device does not have a sim card in it. Could this be the reason or am I missing something when I am trying to update.
Yes. You can't update or restore any GSM iPhone without a valid sim card installed in the phone. The sim card need not be activated, but it must be valid & present. If you want to update, you need to get a sim card. -
I bought Elements 13 4 days ago through Amazon - so far it has not run for more than 5 minutes before Windows closes it down with the message - this program is not working correctly, windows will close it. I know this is not unusual but has anyone got a solution - apart from returning it
with a very unfavourable review? I have tried all the suggested fixes on the Adobe help site with no result. Elements 10 runs OK on the same machine.
Alternatively, is there any possible way to get support from Adobe?juliana
Do you have any version of Premiere Elements 13 or only Photoshop Elements 13 which comes with Elements Organizer 13?
Let us look at the following for Elements Organizer 13....
1. Deletion of disabling the Elements Organizer 13 setting file which is named psa.prf. In Windows 7, 8, o 8.1 64 bit, it is found in the
path
Local Disk C
Users
Owner
AppData
Roaming
Adobe
Elements Organizer
13.0
Organizer
and in the Organizer Folder is the psa.prf file that you delete or disable by renaming it from psa.prf to psa.prfOLD.
2. If the above gains you successful entry into the Elements Organizer 13, then you can
a. create a new catalog
and/or
b. repair or optimize the current one
See Elements Organizer 13/File Menu/Manage Catalogs/Catalog Manager.
3. There are times that certain formats will bring the Elements Organizer down when you try to import those formats into
it. But, from what you wrote, your current problems do not sound media related.
3. At your earliest opportunity, please update Elements Organizer 13 to 13.1 using its Help Menu/Updates.
Please review and consider and then let us know the outcome.
Thank you.
ATR -
Calendar Issues - "Repitition is not working for the item you tried to access"
I ran into an interesting error when troubleshooting a calendar issue today, wondering if anyone has seen it.
Exchange 2010 SP2 latest RU, Outlook 2010
User changes then start time for a recurring meeting, changes in everybody's calendar but hers 9still shows in her calednar as the original start time)
Logged into OWA to see if her claendar reflected the correct start time there - no, still shows the old start time. So I open the meeting, have a quick look, and the following error pops up:
"Repitition is not working for the item you tried to access. It's possible either the start or end date are not correct"
Has anyone seen this error in OWA before?
TAGHi,
Please double check whether the updated start time and end time are changed properly in attendees’ calendar. Also confirm whether the updating message is in the organizer’s sent items both in OWA and Outlook.
Thanks,
Winnie Liang
TechNet Community Support -
Can you please cancel my subscription
Can you please cancel my subscription
Please cancel my subscription too ... and come up with an easier way for others to do the same than having to complain about it via this forum ... or wait and wait and wait for someone to pick up the chat ...
Bill -
I am trying to use imovie and i have never had this problem before. All of my videos are completly grey and when you try and play them all i get is a black screen but i still hear audio. Can you please help and tell me what i need to do. Thank you
Make sure all of the videos used in the project that is having that problem are from the same event. If they are from multiple events, move them all into one event.
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hi everyone, can you help me, because my ipod touch 5th gen, is not opening since this morning, i am just listening to music last night. And its not working anymore. THANK YOU
If not successful try the ramaining items of
- iOS: Not responding or does not turn on
- Also try DFU mode after try recovery mode
How to put iPod touch / iPhone into DFU mode « Karthik's scribblings
- If not successful and you can't fully turn the iOS device fully off, let the battery fully drain. After charging for an least an hour try the above again.
- Try on another computer
- If still not successful that usually indicates a hardware problem and an appointment at the Genius Bar of an Apple store is in order.
Apple Retail Store - Genius Bar -
I upgraded from iPhone 4 to iPhone 5 and all of my apps EXCEPT one transferred over. Why did this one app not transfer over? Thank you
The app is compatible with iOS6...any other reason why this might have happened? Thank you
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Can you please cancel my subscription plan?
Hi I need to cancel my creative cloud subscription plan and single app photoshop plan?
Can you please do this asap? I'm on the wrong plan and need to cancel them all.
The creative cloud plan is under 30 days so I would like a refund.
Thank you!i am about in the same boat as you. The help is useless so is the tech support, that is if your willing to wait a few hours to reach them if you can that is. If things do not improve at adobe im canceling too.
Here is the good news i have most the abode programs i use regularly installed, they can be hacked so when i cancel i still can use photoshop and other programs. I do have the .dll files needed to do such a hack and its easy to just repace the files so it never will ask subscription information again.
so im loosing nothing but useless tech support and my online storage. Get your **** staight adobe or is hack my computers software time. -
Can you please complie and run this program...
please run this program and tell me why the maths are not working
Thanks in advance:
import java.applet.*;
import java.awt.*;
import java.awt.event.*;
public class calculator2 extends Applet implements ActionListener {
int total;
Label label1, label2,label3,label4, label5, label6;
TextField text1, text2,text3, text4, text5, text6;
Button clicker1;
public void init() {
setLayout(new BorderLayout());
Panel pan=new Panel();
label1 = new Label ("Input Rent");
label2 = new Label ("Input Bills");
label3 = new Label ("Input mobile bills");
label4 = new Label ("Input food bills");
text1 = new TextField (5);
text2 = new TextField (5);
text3 = new TextField (5);
text4 = new TextField (5);
label5 = new Label ("input income");
text5 = new TextField (5);
label6 = new Label ("how much to save each month");
text6 = new TextField (5);
clicker1 = new Button("Calculate");
pan.add(label1);
pan.add(text1);
pan.add(label2);
pan.add(text2);
pan.add(label3);
pan.add(text3);
pan.add(label4);
pan.add(text4);
pan.add(label5);
pan.add(text5);
pan.add(label6);
pan.add(text6);
pan.add(clicker1);
add(pan);
setVisible(true);
clicker1.addActionListener(this);
} // end init
public void actionPerformed (ActionEvent e) {
total=Integer.parseInt(text5.getText()) -Integer.parseInt(text1.getText()) Integer.parseInt(text2.getText()) Integer.parseInt(text3.getText()) +
Integer.parseInt(text4.getText()) +Integer.parseInt(text5.getText());
text6.setText(""+total);
// end actionPerformed
}// end classs
thanxs AnthonyTry this:
import java.applet.*;
import java.awt.*;
import java.awt.event.*;
public class budget extends Applet implements ActionListener {
int total;
Label label1, label2,label3,label4, label5, label6;
TextField text1, text2,text3, text4, text5, text6;
Button clicker1;
int income,rent,bills,mobile,food,save;
public void init() {
setLayout(new BorderLayout());
Panel pan=new Panel();
label1 = new Label ("Input Rent");
label2 = new Label ("Input Bills");
label3 = new Label ("Input mobile bills");
label4 = new Label ("Input food bills");
text1 = new TextField (5);
text2 = new TextField (5);
text3 = new TextField (5);
text4 = new TextField (5);
label5 = new Label ("input income");
text5 = new TextField (5);
label6 = new Label ("how much to save each month");
text6 = new TextField (5);
clicker1 = new Button("Calculate");
pan.add(label1);
pan.add(text1);
pan.add(label2);
pan.add(text2);
pan.add(label3);
pan.add(text3);
pan.add(label4);
pan.add(text4);
pan.add(label5);
pan.add(text5);
pan.add(label6);
pan.add(text6);
pan.add(clicker1);
add(pan);
setVisible(true);
clicker1.addActionListener(this);
} // end init
public void actionPerformed (ActionEvent e) {
income = Integer.parseInt(text5.getText());
rent = Integer.parseInt(text1.getText());
bills = Integer.parseInt(text2.getText());
mobile = Integer.parseInt(text3.getText());
food = Integer.parseInt(text4.getText());
save = Integer.parseInt(text6.getText());
total = (income) - (rent + bills + mobile + food + save);
text6.setText(""+total);
// end actionPerformed
}kent -
MSVS-2010 users: Can you *PLEASE* verify whether the "View Call Hierarchy" feature works for you?
I recently decided to educate myself in the intricacies of plugin development and have been experimenting with the set of Samples provided. Supposedly, Visual Studio 2010 (the official IDE for this development) has a very useful feature named "View Call Hierarchy", as described here:
http://dhondiyals.wordpress.com/2011/07/20/call-hierarchy-a-handy-feature-in-visual-studio -2010/
My problem is that that feature never works for me in C/C++ projects. Regardless of what function name I right-click, I always get this error message:
"A function with the name 'xyz' could not be located"
Note: For C# projects, the feature works perfectly.
I have seen on the net some suggestions, from "remove the SDF (Intellisense) files" to "Reinstall Visual Studio".
I have 5 Visual Studio Pro installations in different computers and the feature does not work ever, in any one of them. I have tried with the Adobe source code, I have tried to create a basic MFC project and the feature does not work. I have tried C and C++ and it does not work. Well, you get the idea.
Can you folks share your experience with this issue?
TIAKarl Heinz Kremer wrote:
Based on the Acrobat XI SDK documentation, MSVS 2010 is NOT supported for
plug-in development:
http://livedocs.adobe.com/acrobat_sdk/11/Acrobat11_HTMLHelp/Plugins_Cr eatingSimplePlug.34.2.html
Karl Heinz Kremer
From your link:
"The project files for the sample applications are created and supported only in the listed compiler versions."
The above is wrong. I have dowloaded the following:
- Acrobat SDK 9.1: Comes with Visual Studio 2008 project files.
- Acrobat SDK X: Comes with Visual Studio 2009 project files.
- Acrobat SDK XI: Comes with Visual Studio 2010 project files. -
I've been trying to set my health app since it came out with IOS 8. But every time I selected my data and everything , nothing happened.
Can you please tell me exactly how to set it ?Maybe:
Use Health on your iPhone or iPod touch with iOS 8 - Apple Support
http://www.cnet.com/how-to/apple-health-app-how-to-set-up-import/
http://blog.human.co/posts/human-ios-health.html
Not that all feature re not available on an iPod.
If you have problem please provide more details of your problem. Like what you did, what you tap and what happened or did not happen -
This program won't work for some reason
I'm having trouble with getting this program to do what I want. It reads in a file and identifies certain parts that follow the rules I've given. The first version below is one that works. It simply prints out the string if it meets the conditions in the if statements. The second one will compile but shows no data. I know it stores the values in the arrays sortstem and sortdg becuase I put the println statement directly after the code for storing them and it worked. However, when I put it where it is now, it will not work. Any suggestions? Also, I get an error after the program runs for both versions: It says exception in thread "main" Java.lang.NullPointerException at tokens.main(tokens.java.69) (this was for the first program).
import java.io.*;
import java.util.*;
class tokens {
public static void main(String args[]) throws IOException {
int i; //int to read in the data from the text file
int count = -1;
int countt = -1;
int countc = 0; //int to put data into a char array
FileInputStream fin; //input stream
char array[] = new char[10000]; //array to hold chars from the text file
String s; //chars are transfered to this String
int index; //index of the names I'm searching for in the string
String tokens[] = new String[10000];
try {
fin = new FileInputStream(args[0]);
} catch (FileNotFoundException e) {
System.out.println("File not Found");
return;
} catch (ArrayIndexOutOfBoundsException e) {
System.out.println("Usage: ShowFile File");
return;
do {
i = fin.read();
if (i != -1) {
if (count==array.length-1) { //this expands the array if more space is needed
char temp[] = new char[array.length+5000];
for (int j = 0; j < array.length; j++) temp[j] = array[j];
array = temp;
array[++count] = (char) i;
else
array[++count] = (char) i;
} while(i != -1);
fin.close();
s = new String(array);
StringTokenizer st = new StringTokenizer(s);
while (st.hasMoreTokens()) {
if (countt==tokens.length-1) { //this expands the array if more space is needed
String temp1[] = new String[tokens.length+5000];
for (int j = 0; j < tokens.length; j++) temp1[j] = tokens[j];
tokens = temp1;
tokens[++countt] = st.nextToken();
else
tokens[++countt] = st.nextToken();
if (tokens[4].startsWith("stem")) {
if (tokens[4].equals(tokens[201])) { //Skip this one
else
if ((tokens[9].equals("32")) && (tokens[15].equals("31"))
&& (tokens[21].equals("30")) && (tokens[27].equals("29"))
&& (tokens[33].equals("28")) && (tokens[39].equals("27"))) {
System.out.println(tokens[4]);
for (int k = 201; k < tokens.length-198; k++) {
if (tokens[k].startsWith("stem")) {
if ((tokens[k].equals(tokens[k+197])) || (tokens[k].equals(tokens[k-197]))) {
//Skip this one
else
if ((tokens[k+5].equals("32")) && (tokens[k+11].equals("31"))
&& (tokens[k+17].equals("30")) && (tokens[k+23].equals("29"))
&& (tokens[k+29].equals("28")) && (tokens[k+35].equals("27"))) {
System.out.println(tokens[k]);
}This one below compiles but doesn't print to the screen.
import java.io.*;
import java.util.*;
class tokenstest {
public static void main(String args[]) throws IOException {
int i; //int to read in the data from the text file
int count = -1;
int countt = -1;
int countc = 0; //int to put data into a char array
FileInputStream fin; //input stream
char array[] = new char[1000000]; //array to hold chars from the text file
String s; //chars are transfered to this String
int index; //index of the names I'm searching for in the string
String tokens[] = new String[200000];
String sortdg[] = new String[500];
String sortstem[] = new String[500];
try {
fin = new FileInputStream(args[0]);
} catch (FileNotFoundException e) {
System.out.println("File not Found");
return;
} catch (ArrayIndexOutOfBoundsException e) {
System.out.println("Usage: ShowFile File");
return;
do {
i = fin.read();
if (i != -1) {
if (count==array.length-1) { //this expands the array if more space is needed
char temp[] = new char[array.length+5000];
for (int j = 0; j < array.length; j++) temp[j] = array[j];
array = temp;
array[++count] = (char) i;
else
array[++count] = (char) i;
} while(i != -1);
fin.close();
s = new String(array);
StringTokenizer st = new StringTokenizer(s);
while (st.hasMoreTokens()) {
if (countt==tokens.length-1) { //this expands the array if more space is needed
String temp1[] = new String[tokens.length+5000];
for (int j = 0; j < tokens.length; j++) temp1[j] = tokens[j];
tokens = temp1;
tokens[++countt] = st.nextToken();
else
tokens[++countt] = st.nextToken();
if (tokens[4].startsWith("stem")) {
if (tokens[4].equals(tokens[201])) { //Skip this one
else
if ((tokens[9].equals("32")) && (tokens[15].equals("31"))
&& (tokens[21].equals("30")) && (tokens[27].equals("29"))
&& (tokens[33].equals("28")) && (tokens[39].equals("27"))) {
sortstem[countc] = tokens[4];
sortdg[countc] = tokens[3];
countc++;
for (int k = 201; k < tokens.length-198; k++) {
if (tokens[k].startsWith("stem")) {
if ((tokens[k].equals(tokens[k+197])) || (tokens[k].equals(tokens[k-197]))) {
//Do nothing
else
if ((tokens[k+5].equals("32")) && (tokens[k+11].equals("31"))
&& (tokens[k+17].equals("30")) && (tokens[k+23].equals("29"))
&& (tokens[k+29].equals("28")) && (tokens[k+35].equals("27"))) {
sortstem[countc] = tokens[k];
sortdg[countc] = tokens[k-1];
countc++;
for (int z = 0; z < countc; z++) {
System.out.println(sortstem[z]);
for (int z = 0; z < countc; z++) {
for (int y = z+1; y < countc; y++) {
if (sortdg[z].compareTo(sortdg[z]) > 0) {
String tdg = sortdg[z];
String tstem = sortstem[z];
sortdg[z] = sortdg[y];
sortstem[z] = sortstem[y];
sortdg[y] = tdg;
sortstem[y] = tstem;
for (int j = 0; j < 20; j++) {
System.out.println(sortstem[j] + ": dG = " + sortdg[j]);
System.out.println("Test");
}I'm still having trouble with the println in this program. For some reason, in this section of the code, if I put System.out.println(sortstem[0]); inside the for loop, it works fine. But if I try to do it ouside of this loop, it will not work. The only thing I can think of is that the variable is only available inside the loop but I just can't figure it out. Can anyone enlighten me?
for (int k = 201; k < tokens.length-198; k++) {
if (tokens[k].startsWith("stem")) {
if ((tokens[k].equals(tokens[k+197])) || (tokens[k].equals(tokens[k-197]))) {
//Do nothing
else
if ((tokens[k+5].equals("32")) && (tokens[k+11].equals("31"))
&& (tokens[k+17].equals("30")) && (tokens[k+23].equals("29"))
&& (tokens[k+29].equals("28")) && (tokens[k+35].equals("27"))) {
sortstem[countc] = tokens[k];
sortdg[countc] = tokens[k-1];
countc++;
[code/] -
Can't use audiobooks AND Genius? And VoiceOver not working for radio?
Anyone know how to resolve this? In order to transfer audiobooks, I have to disable the automatic syncing from my nano. But it seems that this means that I lose the ability to transfer the Genius mixes that are created in iTunes.
Also, after much hassle, finally got VoiceOver to work, but it only works when I"m playing music that I already have stored and it won't work for songs on the radio... any ideas?I'm not sure about the Genius working with audio books, but from what I understand, when you say that you want VoiceOver, iTunes goes through your music list and makes that voiceover prompt for each song thats in their. It can't do that with the radio because the songs aren't preinstalled on the ipod.
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