Capacity pleae help with this please please please !!!!!!!!!!!!!!!!!
when i restored me ipod it gives all the information for example colour, serial number
the problem is my it says.....
capacity 892.0Mb
my ipod isnt 892mb ipod nano!!!!!!!!!!!
that solves why i cant get all my music onto it and i am very confused help me with this someone
need advice!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
The apple knowledge base document shows why you lose around 100mb to 200mb on every ipod
http://docs.info.apple.com/article.html?artnum=60955
In iPod's About menu, the hard disk size is reported as slightly less than the technical specifications for the iPod. The same is true if you connect iPod to your computer in disk mode look at the info or properties window for the disk.
Why the difference? Most hard disk manufacturers measure disk size this way: 1 MB = 1 million bytes (1000 * 1000). A 4 GB disk, therefore, is one that holds 4 billion bytes. Computers, including Windows computers, Macintosh computers and iPod, measure disk size this way: 1 MB = 1 048 576 bytes (1024 * 1024). The difference in these two calculations is what causes the drive to appear as 3.7 GB on a computer, but actually be a 4 billion byte disk.
This difference wont change how many songs you can get onto your ipod. Bear in mind, the song average advertised on the ipod is based on 4 mins per song, encoded at 128kbps in AAC format.
Hope this helps
Similar Messages
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Hi I got an email from itunes saying that my pre order was ready and when I click on the link from my ipad it takes me to the itunes store app and then it doesn't do anything help with this please .
<Link Edited By Host>Thanks for your advice, I went to the apple shop today for a face to face meeting with a tech and he checked everything and could not figure out why I was having this problem so we decided to give up on that account and create a whole new one for me using a different email address.
Now I can download apps on both my iPhone and ipad2.
If anyone is reading this in Brisbane Australia go to the Chermside apple shop and ask for Wade. He was fantastic!
Jan -
Itunes istallation freezes at 'Publishing Product Information'. Can anyone help with this please?
Itunes istallation freezes at 'Publishing Product Information'. Can anyone help with this please?
You need more memory. 4 GB is not enough:
1.12 GB Page-outs
[killed] com.apple.CallHistoryPluginHelper.plist
[killed] com.apple.CallHistorySyncHelper.plist
[killed] com.apple.cmfsyncagent.plist
[killed] com.apple.coreservices.appleid.authentication.plist
[killed] com.apple.sbd.plist
[killed] com.apple.security.cloudkeychainproxy.plist
[killed] com.apple.telephonyutilities.callservicesd.plist
7 processes killed due to memory pressure
Problem System Launch Daemons: ℹ️
[killed] com.apple.ctkd.plist
[killed] com.apple.icloud.findmydeviced.plist
[killed] com.apple.softwareupdate_download_service.plist
[killed] com.apple.wdhelper.plist
4 processes killed due to memory pressure -
When I tap the Apple store, YouTube and the iTunes apps, they don' launch. Any help with this?
1. Double-click the Home button to close all Inactive Apps in Task Bar
2. Hold the Apps in Task Bar down for a second or two until you see the minus sign
3. Tap the minus sign to close App
4. Tap center of screen to return to Home Screen
5. Reset iPad. Hold the Sleep and Home button down for about 10 second until you see the Apple logo. Ignore the red slider -
Just moved to a new city and updated my banking information. Everytime I try to make a purchase it is telling me that I have contact itunes store support to make my purchase. Can someone please help me with this.
Huh?
There is NO telephone support for itunes at all. You cannot call them
You contact them as everyone esle does:
http://www.apple.com/support/contact/ -
javax.servlet.ServletException
at com.evermind.server.http.EvermindPageContext.handlePageThrowable(EvermindPageContext.java:595)
at com.evermind.server.http.EvermindPageContext.handlePageException(EvermindPageContext.java:537)
at jsp.addservice._jspService(addservice.jsp:515)
at com.orionserver.http.OrionHttpJspPage.service(OrionHttpJspPage.java:56)
at oracle.jsp.runtimev2.JspPageTable.service(JspPageTable.java:356)
at oracle.jsp.runtimev2.JspServlet.internalService(JspServlet.java:498)
at oracle.jsp.runtimev2.JspServlet.service(JspServlet.java:402)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
at com.evermind.server.http.ServletRequestDispatcher.invoke(ServletRequestDispatcher.java:847)
at com.evermind.server.http.ServletRequestDispatcher.forwardInternal(ServletRequestDispatcher.java:340)
at com.evermind.server.http.ServletRequestDispatcher.forward(ServletRequestDispatcher.java:229)
at mil.usmc.m4l.servlets.M4LServlet.forward(M4LServlet.java:34)
at mil.usmc.m4l.servlets.EditService.doGet(EditService.java:120)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:740)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
at com.evermind.server.http.ResourceFilterChain.doFilter(ResourceFilterChain.java:65)
at mil.usmc.m4l.filters.M4LCMSFilter.doFilter(M4LCMSFilter.java:150)
at com.evermind.server.http.ServletRequestDispatcher.invoke(ServletRequestDispatcher.java:673)
at com.evermind.server.http.ServletRequestDispatcher.forwardInternal(ServletRequestDispatcher.java:340)
at com.evermind.server.http.HttpRequestHandler.processRequest(HttpRequestHandler.java:830)
at com.evermind.server.http.HttpRequestHandler.run(HttpRequestHandler.java:285)
at com.evermind.server.http.HttpRequestHandler.run(HttpRequestHandler.java:126)
at com.evermind.util.ReleasableResourcePooledExecutor$MyWorker.run(ReleasableResourcePooledExecutor.java:192)
at java.lang.Thread.run(Thread.java:534)
Edited by: user11237193 on Apr 27, 2010 10:58 AM
I am getting error and I ned help with it Thank you for your help.I'd enter the dell service tags in here to find out what OS the pc was designed for.
http://www.dell.com/support/contents/us/en/19/Category/Product-Support/Self-support-Knowledgebase/locate-service-tag?~ck=mn
For windows I'd ask over here.
http://answers.microsoft.com/en-us/windows
Regards, Dave Patrick ....
Microsoft Certified Professional
Microsoft MVP [Windows]
Disclaimer: This posting is provided "AS IS" with no warranties or guarantees , and confers no rights. -
Can I get some help with this please
I got the following error messages from java after running my code.
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 66
at Graph.ChainingHashTable.get(ChainingHashTable.java:76)
at Graph.Vertex.isNeighbor(Vertex.java:123)
at Graph.LinkedGraph.addEdge(LinkedGraph.java:42)
at Graph.Traversals.main(Traversals.java:311)
The following is my code
Traversal.java
package Graph;
public class Traversals implements Callback<Vertex>
public void visit( Vertex data )
System.out.println( data.getName() );
* Perform a breadth first traversal of the vertices in the given graph
* starting at the specified node. The call back object is used to process
* each node as it appears in the traversal.
* @param g the graph to traverse
* @param start the vertex where the traversal will start
* @param cb the object that processes vertices.
public void BFSTraverse( Graph g, Vertex start, Callback<Vertex> cb )
Queue<Vertex> waiting = new LinkedQueue<Vertex>(); // Queue of waiting
// vertices
// Ensure the graph has no marked vertices
List<Vertex> vertices = g.getVertices();
for( vertices.first(); vertices.isOnList(); vertices.next() )
vertices.get().setTag( false );
// Put the start vertex in the work queue
waiting.enqueue( start );
// While there are waiting vertices
while( !waiting.empty() )
// Get the next Vertex
Vertex curVertex = waiting.front();
waiting.dequeue();
// If this Vertex hasn't been processed yet
if( !curVertex.getTag() )
cb.visit( curVertex ); // Process the vertex
curVertex.setTag( true ); // Mark it as visited
// Put its unmarked neighbors into the work queue
List<Vertex> neighbors = curVertex.getNeighbors();
for( neighbors.first(); neighbors.isOnList(); neighbors.next() )
Vertex cur = neighbors.get();
if( !cur.getTag() )
waiting.enqueue( cur );
* Use Kruskal's algorithm to create a minimum spanning tree for the given
* graph. The MST is returned in the form of a graph.
* @param g the graph from which to generate the MST
* @return a graph containing the the vertices of g and the the edges
* nesseary to form a minimum spanning tree.
public Graph kruskalMST( Graph g )
// Where the MST will be stored
Graph mst = new LinkedGraph();
// All the vertices in the graph
List<Vertex> vertices = g.getVertices();
// List of Vertex Sets
List<Set<String>> vertexSets = new LinkedList();
// Add the vertices in the original graph to mst
// and create the vertex sets at the same time
for( vertices.first(); vertices.isOnList(); vertices.next() )
String curName = vertices.get().getName();
Set<String> curSet = null; // new ArrayBasedSet<Vertex>();
// Add the name of the current vertex to its set and then
// add the set to the list that contains the vertex sets
curSet.add( curName );
vertexSets.add( curSet );
// Add the current vertex to the MST graph
mst.addVertex( curName );
// Put the edges into a heap which effectively sorts them
Heap<Edge> edges = new ArrayBasedHeap<Edge>();
List<Edge> allEdges = g.getEdges();
for( allEdges.first(); allEdges.isOnList(); allEdges.next() )
edges.insertHeapNode( allEdges.get() );
// Setup is complete - run the algorithm
// There is more than one set left in the list vertex sets
while( vertexSets.size() > 1 )
// Get the smallest edge
Edge cur = edges.getSmallest();
// Find the sets where these vertices are located
int sourcePos = findSet( vertexSets, cur.getSource().getName() );
int destPos = findSet( vertexSets, cur.getDest().getName() );
// If the vertices are in different sets - add the edge to
// the MST
if( sourcePos != destPos )
Set<String> sourceSet = vertexSets.get( sourcePos );
Set<String> destSet = vertexSets.get( destPos );
// Add the edge to the MST
mst.addEdge( cur.getSource().getName(),
cur.getDest().getName(), cur.getCost() );
// Merge the sets
sourceSet.union( destSet );
vertexSets.remove( destPos );
// The MST can be read from this graph
return mst;
* Return the position of the first set in the list that contains the
* specified name.
* @param vertexSets a list of sets to search.
* @param name the name being searched for.
* @return the position of the first set in the list that contains the name
* or -1 if the name cannot be found.
private int findSet( List<Set<String>> vertexSets, String name )
int retVal = -1;
// Step through the list and examine each set. Stop when you
// find a set with the name or we fall off the list
for( int i = 0; retVal == -1 && i < vertexSets.size(); i = i + 1 )
Set curSet = vertexSets.get( i );
// Does the current set contain the name we are looking for?
if( curSet.contains( name ) )
retVal = i;
// Return the position of the set
return retVal;
* Perform Dijkstra's Shortest Path algorithm on the given graph, starting
* at the given vertex.
* @param g the Graph to traverse.
* @param name the name of the vertex where the traversal starts.
* @return an array containing vertex path costs.
public int[] dijkstraSP( Graph g, String name )
// The names of the vertices for which the shortest
// path is not known
Set<String> u = new ArrayBasedSet<String>();
// The names of the vertices for which the shortest
// path is known
Set<String> s = new ArrayBasedSet<String>();
// Put the vertices in an array to make things easier
List<Vertex> vertices = g.getVertices();
Vertex v[] = new Vertex[ vertices.size() ];
for( int i = 0; i < vertices.size(); i++ )
v[ i ] = vertices.get( i );
// The starting vertex
Vertex start = g.getVertex( name );
// The lowest costs seen so far
int c[] = new int[ v.length ];
// Temporary edge used by the program
Edge curEdge = null;
// Sort the vertices by name so that the costs will
// appear in order by name
Heap<String> names = new ArrayBasedHeap<String>();
// Build the heap
for( int i = 0; i < v.length; i = i + 1 )
names.insertHeapNode( v[ i ].getName() );
// Read out the values
for( int i = 0; !names.empty(); i = i + 1 )
v[ i ] = g.getVertex( names.getSmallest() );
// We "know" the shortest path to the source
s.add( name );
// For each vertex, compute the starting cost
for( int i = 0; i < v.length; i = i + 1 )
// If this isn't the start node
if( !v[ i ].getName().equals( name ) )
// Put it in the unknown set
u.add( v[ i ].getName() );
// Compute the initial cost to reach this Vertex
curEdge = start.getEdge( v[ i ].getName() );
if( curEdge != null )
c[ i ] = curEdge.getCost();
else
// This Vertex is currently unreachable
c[ i ] = Integer.MAX_VALUE;
else
// It costs 0 to get to the start vertex
c[ i ] = 0;
// Set is complete - run the algorithm until all of
// the paths are known
while( !u.isEmpty() )
// Find the position of the lowest-cost unknown node
int min = Integer.MAX_VALUE;
int minPos = -1;
for( int i = 0; minPos == -1 && i < c.length; i = i + 1 )
if( c[ i ] < min && u.contains( v[ i ].getName() ) )
min = c[ i ];
minPos = i;
// We know the shortest path to the vertex
s.add( v[ minPos ].getName() );
u.remove( v[ minPos ].getName() );
// Update the costs based
for( int i = 0; i < c.length; i = i + 1 )
// Get the edge between the new shortest and the
// current node in the array
curEdge = v[ minPos ].getEdge( v[ i ].getName() );
// If there is an edge
if( curEdge != null )
// If going through the new node is better than
// what has been seen update the cost
if( c[ i ] > c[ minPos ] + curEdge.getCost() )
c[ i ] = c[ minPos ] + curEdge.getCost();
return c;
public static void main( String args[] )
Traversals t = new Traversals();
Graph g = new LinkedGraph();
g.addVertex( "A" );
g.addVertex( "B" );
g.addVertex( "C" );
g.addVertex( "D" );
g.addVertex( "E" );
g.addVertex( "F" );
g.addEdge( "A", "B", 5 ); <--------------------------------------------------------------------------------------------Line 311
g.addEdge( "A", "D", 9 );
g.addEdge( "A", "C", 10 );
g.addEdge( "B", "A", 5 );
g.addEdge( "B", "D", 4 );
g.addEdge( "C", "A", 10 );
g.addEdge( "C", "D", 13 );
g.addEdge( "C", "E", 14 );
g.addEdge( "D", "B", 4 );
g.addEdge( "D", "A", 9 );
g.addEdge( "D", "C", 13 );
g.addEdge( "D", "E", 7 );
g.addEdge( "D", "F", 8 );
g.addEdge( "E", "C", 14 );
g.addEdge( "E", "D", 7 );
g.addEdge( "E", "F", 2 );
g.addEdge( "F", "D", 8 );
g.addEdge( "F", "E", 2 );
int costs[] = t.dijkstraSP( g, "A" );
for( int i = 0; i < costs.length; i = i + 1 )
System.out.println( costs[ i ] );
}ChainingHashTable.java
package Graph;
* An implementation of a HashTable using chaining for collision resolution.
* Javadoc comments for methods specified in the Table interface have been
* omitted.
* This code assumes that the preconditions stated in the comments are true when
* a method is invoked and therefore does not check the preconditions.
public class ChainingHashTable<K, V> implements Table<K, V>
private List<Tuple<K, V>> hashTable[]; // The hashtable
int size; // The size of the hash table
* Create a new hash table.
* @param cardinality the number of elements in the domain.
public ChainingHashTable( int cardinality )
// Note that the cast is necessary because you cannot
// create generic arrays in Java. This statement will
// generate a compiler warning.
hashTable = (LinkedList<Tuple<K, V>>[]) new LinkedList[ cardinality ];
size = 0;
public void put( K key, V value )
int bucket = key.hashCode();
// Do we need to create a new list for this bucket?
if( hashTable[ bucket ] == null )
hashTable[ bucket ] = new LinkedList<Tuple<K, V>>();
hashTable[ bucket ].add( new Tuple<K, V>( key, value ) );
size = size + 1;
public void remove( K key )
int bucket = key.hashCode();
List<Tuple<K, V>> chain = hashTable[ bucket ];
boolean found = false;
// Is there a chain to search?
if( chain != null )
// Step through the chain until we fall off the end or
// find the tuple to delete
chain.first();
while( !found && chain.isOnList() )
// If this tuple has the key we are looking for
// delete it and stop the loop
if( chain.get().getKey().equals( key ) )
chain.remove();
found = true;
else
chain.next();
public V get( K key )
int bucket = key.hashCode();
List<Tuple<K, V>> chain = hashTable[ bucket ]; <----------------------------------------------------------------Line 76
V retVal = null;
// Is there a chain to search?
if( chain != null )
// Step through the chain until we find the element or
// run out of list.
for( chain.first(); retVal == null && chain.isOnList(); chain
.next() )
// If this tuple has the key we are looking for,
// extract the value
if( chain.get().getKey().equals( key ) )
retVal = chain.get().getValue();
return retVal;
public boolean isEmpty()
return size == 0;
public int size()
return size;
public int cardinality()
return hashTable.length;
public List<K> getKeys()
List<Tuple<K, V>> chain;
List<K> keys = new LinkedList<K>();
// Go through each chain and create a list that contains all
// of the keys in the table
for( int i = 0; i < hashTable.length; i++ )
if( hashTable[ i ] != null )
chain = hashTable[ i ];
for( chain.first(); chain.isOnList(); chain.next() )
keys.add( chain.get().getKey() );
return keys;
public List<V> getValues()
List<Tuple<K, V>> chain;
List<V> values = new LinkedList<V>();
// Go through each chain and create a list that contains all
// of the keys in the table
for( int i = 0; i < hashTable.length; i++ )
if( hashTable[ i ] != null )
chain = hashTable[ i ];
for( chain.first(); chain.isOnList(); chain.next() )
values.add( chain.get().getValue() );
return values;
* Return a string representation of this hash table.
* @return a string representation of this hash table.
public String toString()
StringBuffer hashAsString = new StringBuffer( "" );
List chain = null;
for( int i = 0; i < hashTable.length; i = i + 1 )
hashAsString.append( "h[" + i + "]==" );
if( hashTable[ i ] != null )
chain = hashTable[ i ];
for( chain.first(); chain.isOnList(); chain.next() )
hashAsString.append( " " + chain.get() );
hashAsString.append( "\n" );
return hashAsString.toString();
} // ChainingHashTable -
CAN SOMEBODY HELP WITH THIS, PLEASE?
I am working on a web application called the Bookstore and deployment is through J2EE1.2.1(old). All the compilation of the servlets I used, it showed no errors at all and deployment Progress window shows that the deployment is complete. But anytime I open the web browser to use this application, it first shows the opening page(index.html) and the next jsp.page and the 3rd page to be displayed does not show on this browser. The error shown on the J2ee command prompt is as below:-
Cannot find principal mapping information for data source with JNDI name jdbc/books
java.lang.NoClassDefFoundError: javax/xml/transform/TransformerExceptionDoes J2EE 1.2.1 include the xml-apis.jar? If not, you need to add it to the classpath.
-
Everytime I go to export a photo, I get an error.
"Export Results: Not enough memory (1)
Using Windows 7 32-bit. Intel i5 4690K CPU 16GB RAM 120 SSD and 1 TB harddrive.Even though you have 16gb of ram installed, 32 bit Windows can only use 4gb of it so 12gb is wasted. This is the reason you are getting not enough memory errors and is a known problem with Lightroom an 32 bit Windows during export. You need to change to 64 bit Windows.
-
I have downloaded an iOS update on my iPad air2 but it has locked the screen and I can only see the iTunes symbol with a white arrow and a padlock below it. I have tried turning the iPad off and on but the same screen reappears. Has anyone had a similar problem?
What that symbol indicates is that your iPad has gone into recovery mode and now it needs to be restored in order for you to be able to use it again. You can reboot from now until the cows come home and it will not do any good.
You do indeed need to plug your iPad into your computer and use iTunes to restore the device.
Use iTunes to restore your iOS device to factory settings - Apple Support
Just in case you need to use recovery mode.....
If you can't update or restore your iPhone, iPad, or iPod touch - Apple Support -
Don't have a product key right now help with this please.
Hi, i was installing XP onto my mac for school. cause we are using visual studio. i realized the computer doesn't have a product key so i don't have one. My Mac is stuck on the product key screen for Windows.
Is there anyway of restarting and going back to the Mac OS X partition without messing up my laptop cause I don't know how long it will take me to find the old computer and get the key from it.
thanks!Hi, Haseeb.
Assuming you tried to install Win on a separate partition from Mac OSX, all you need to do is hold down the power button to force a shut down (if you haven't tried that already). Once the Mac is powered off, just press the power button again to boot normally into Mac OSX.
If the Mac still tries to start into Bootcamp, hold down the option key after pressing the power button, and a screen will show up that will allow you select the Mac OSX startup disc. Select it and you will start up in OSX and be good to go.
Good Luck. -
my ipad 2 says "cannot get mail the username or password for sky is incorrect" but it is correct. My BT mail is fine. HELP
Try deleting and recreating the account on your iPad.
-
SUddenly my music videos won't play on my ipad1. I just get the audio. Can anyone help with this please?
Look in the Videos App and play them in there.
-
Does anybody know how to get help with this one?
Hello there!
I wanted to get an advice on how to get in touch with the appropriate person at BT that could help with my situation.
I have tried telephone help, complaints by email and unfortunately still waiting for somebody from the customer services to help me out.
I have recently moved home. I contacted BT on 26th June to organise the line transfer to the new address. The date was set for 18th July. I also ordered line rental saver and paid for it over the phone. All went smooth, telephone and broadband was working fine at the new place, but on the 23rd July I was sent an email that "BT is sorry that I am leaving".
I thought it was a mistake, but the lady in the on-line chat said somebody stopped my service. Later she rang and left a message saying that I must have requested to move to another provider. Did not manage to speak to her again, but phoned the help line this time.
There a gentleman was trying to convince me that I called BT and cancelled my service on the 18th July and to him I was not a BT customer anymore. The truth is that I did not request to stop my service, anyway - why would I do that after paying for a year in advance. This has no logic, but because computer says so then he thinks I did it.
He also added that my account is a 'mess'. He then promised that somebody would get in touch to sort it out as my line rental was gone and my phone and internet could go off any minute.
I did not get any help. After that I wrote to them 3 email complaints to request assistance. They called and aknowledge they will help, but 3 weeks down the line nothing was done to explain the situation. Left the messages to the person from email complaints to ring me or email me -never happened.
Last week I got 2 emails welcoming me to BT and outlining the call plans that were diferent from each other and the one I agreed to on the 25th June. When I called help line 2 days ago a lady confirmed on which one I am on, but could not sort out the most annoying thing - the 'final' bill.
I was sent a bill for over 200 pounds due to premature termination of phone and broadband service , which I never ordered. They already took the money this week. My line saver is gone as well. So I am 360 pounds short. I aslo have no access to myBT to monitor my phone activity or make orders.They also did not send any confrimation of the call plan I am currently on.
It is a very annoying situation, because somebody at BT made an error and I am unable to get to anybody that could help. Everytime you call the help line you speak to somebody else and despite me thinking the email complaints would be the way forward they are not. Would appreciate some advice on how to tackle these issues: false accusations from them, inappropriate billing, problem with myBT.
Thanks LukaszHi lbadek
I can help with this please send us an email using the contact the mods link in my proifle and we will investigated from there.
Thanks
Stuart
BTCare Community Mod
If we have asked you to email us with your details, please make sure you are logged in to the forum, otherwise you will not be able to see our ‘Contact Us’ link within our profiles.
We are sorry that we are unable to deal with service/account queries via the private message(PM) function so please don't PM your account info, we need to deal with this via our email account :-) -
my itunes keeps crashing every time i open it with my windows 7. im active military and dont have time to be messing with this. please help
Hello there, Staver13.
The following Knowledge Base article provides some assistance in troubleshooting your issue:
Can't connect to the iTunes Store
http://support.apple.com/kb/TS1368
Particularly:
Troubleshoot issues on an iPhone, iPad, or iPod touch
If you haven't been able to connect to the iTunes Store:
Make sure your date, time, and time zone are correct in Settings > General > Date & Time.
Note: Time Zone may list another city in your time zone.
Make sure that your iOS software is up to date by tapping Settings > General > Software Update (iOS 5 or later) or connecting your iOS device to iTunes and clicking Check for Update on your device's Summary page.
Check and verify that you're in range of a Wi-Fi router or base station. If you're on a device with cellular service, make sure that cellular data is turned on from Settings > General > Cellular.
Note: If connected to cellular data, larger items may not download. You may need to connect to Wi-Fi to download apps, videos, and podcasts.
Make sure that you have an active Internet connection. You can check the user guide for your device for help with connecting to the Internet.
Make sure that other devices (portable computers, for example) are able to connect to the Wi-Fi network and access the Internet.
Try resetting (turning off and then on again) your Wi-Fi router.
If the issue persists, try troubleshooting your Wi-Fi networks and connections.
Thanks for reaching out to Apple Support Communities.
Cheers,
Pedro.
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