CASE statement in PL/SQL
Hi PL/SQL experts,
I'm going a bit loopy here, so could someone please point out what I'm doing wrong with this case statement:
Test procedure is:
CREATE OR REPLACE procedure SCOTT.postcode_validate_2 (input_post_code VARCHAR2) as
alphabet_string VARCHAR2(52) := 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvxwyz';
number_string VARCHAR2(10) := '012345789';
last_part_postcode VARCHAR2(3) := NULL;
BEGIN
IF INSTR(input_post_code,' ') = 0
THEN
DBMS_OUTPUT.PUT_LINE('We need a space in the postcode please');
GOTO exit;
ELSIF LENGTH(SUBSTR(input_post_code,instr(input_post_code,' ')+1)) > 3
THEN
DBMS_OUTPUT.PUT_LINE('Last part of postcode can only be 3 characters');
GOTO exit;
ELSE
last_part_postcode := SUBSTR(input_post_code,instr(input_post_code,' ')+1);
END IF;
CASE input_post_code
WHEN (length(substr(input_post_code,1,instr(input_post_code,' ')-1)) = 2
AND instr(alphabet_string,substr(input_post_code,1,1)) != 0
AND instr(number_string,substr(input_post_code,2,1)) != 0)
THEN
DBMS_OUTPUT.PUT_LINE('We have a valid postcode in the format A9')
-- ELSE
-- DBMS_OUTPUT.PUT_LINE('Sorry but that is an incorrect postcode! Format A9');
-- GOTO exit;
-- END IF;
WHEN (length(substr(input_post_code,1,instr(input_post_code,' ')-1)) = 3
AND instr(alphabet_string,substr(input_post_code,1,1)) != 0
AND instr(alphabet_string,substr(input_post_code,2,1)) != 0
AND instr(number_string,substr(input_post_code,3,1)) != 0)
THEN
DBMS_OUTPUT.PUT_LINE('We have a valid postcode in the format AA9')
-- ELSE
-- DBMS_OUTPUT.PUT_LINE('Sorry but that is an incorrect postcode! Format AA9');
-- GOTO exit;
-- END IF;
WHEN (length(substr(input_post_code,1,instr(input_post_code,' ')-1)) = 3
AND instr(alphabet_string,substr(input_post_code,1,1)) != 0
AND instr(number_string,substr(input_post_code,2,1)) != 0
AND instr(number_string,substr(input_post_code,3,1)) != 0)
THEN
DBMS_OUTPUT.PUT_LINE('We have a valid postcode in the format A99')
-- ELSE
-- DBMS_OUTPUT.PUT_LINE('Sorry but that is an incorrect postcode! Format A99');
-- GOTO exit;
-- END IF;
WHEN (length(substr(input_post_code,1,instr(input_post_code,' ')-1)) = 3
AND instr(alphabet_string,substr(input_post_code,1,1)) != 0
AND instr(number_string,substr(input_post_code,2,1)) != 0
AND instr(alphabet_string,substr(input_post_code,3,1)) != 0)
THEN
DBMS_OUTPUT.PUT_LINE('We have a valid postcode in the format A9A')
-- ELSE
-- DBMS_OUTPUT.PUT_LINE('Sorry but that is an incorrect postcode! Format A9A');
-- GOTO exit;
-- END IF;
WHEN (length(substr(input_post_code,1,instr(input_post_code,' ')-1)) = 4
AND instr(alphabet_string,substr(input_post_code,1,1)) != 0
AND instr(alphabet_string,substr(input_post_code,2,1)) != 0
AND instr(number_string,substr(input_post_code,3,1)) != 0
AND instr(number_string,substr(input_post_code,4,1)) != 0)
THEN
DBMS_OUTPUT.PUT_LINE('We have a valid postcode in the format AA99')
-- ELSE
-- DBMS_OUTPUT.PUT_LINE('Sorry but that is an incorrect postcode! Format AA99');
-- GOTO exit;
-- END IF;
WHEN (length(substr(input_post_code,1,instr(input_post_code,' ')-1)) = 4
AND instr(alphabet_string,substr(input_post_code,1,1)) != 0
AND instr(alphabet_string,substr(input_post_code,2,1)) != 0
AND instr(number_string,substr(input_post_code,3,1)) != 0
AND instr(alphabet_string,substr(input_post_code,4,1)) != 0)
THEN
DBMS_OUTPUT.PUT_LINE('We have a valid postcode in the format AA9A')
-- ELSE
-- DBMS_OUTPUT.PUT_LINE('Sorry but that is an incorrect postcode! Format AA9A');
-- GOTO exit;
-- END IF;
END;
-- Check last part of format, should be AA9
IF (instr(number_string,substr(input_post_code,1,1)) != 0
AND instr(alphabet_string,substr(input_post_code,2,1)) != 0
AND instr(alphabet_string,substr(input_post_code,3,1)) != 0)
THEN
DBMS_OUTPUT.PUT_LINE('End part of the postcode is in the correct format, 9AA');
ELSE
DBMS_OUTPUT.PUT_LINE('End part of the postcode is in the wrong format!');
END IF;
<<exit>>
DBMS_OUTPUT.PUT_LINE('Please try again');
END;
However, I'm getting the following error:
LINE/COL ERROR
37/6 PLS-00103: Encountered the symbol "WHEN" when expecting one of
the following:
:= . ( % ;
On a second note, can I not have the ELSE structure embedded within the case (currently commented out)?
Thanks very much in advance.
Dev
Fixed code:
CREATE OR REPLACE procedure postcode_validate_2 (input_post_code VARCHAR2) as
alphabet_string VARCHAR2(52) := 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvxwyz';
number_string VARCHAR2(10) := '012345789';
last_part_postcode VARCHAR2(3) := NULL;
BEGIN
IF INSTR(input_post_code,' ') = 0
THEN
DBMS_OUTPUT.PUT_LINE('We need a space in the postcode please');
GOTO exit;
ELSIF LENGTH(SUBSTR(input_post_code,instr(input_post_code,' ')+1)) > 3
THEN
DBMS_OUTPUT.PUT_LINE('Last part of postcode can only be 3 characters');
GOTO exit;
ELSE
last_part_postcode := SUBSTR(input_post_code,instr(input_post_code,' ')+1);
END IF;
CASE
WHEN (length(substr(input_post_code,1,instr(input_post_code,' ')-1)) = 2
AND instr(alphabet_string,substr(input_post_code,1,1)) != 0
AND instr(number_string,substr(input_post_code,2,1)) != 0)
THEN
DBMS_OUTPUT.PUT_LINE('We have a valid postcode in the format A9');
-- ELSE
-- DBMS_OUTPUT.PUT_LINE('Sorry but that is an incorrect postcode! Format A9');
-- GOTO exit;
-- END IF;
WHEN (length(substr(input_post_code,1,instr(input_post_code,' ')-1)) = 3
AND instr(alphabet_string,substr(input_post_code,1,1)) != 0
AND instr(alphabet_string,substr(input_post_code,2,1)) != 0
AND instr(number_string,substr(input_post_code,3,1)) != 0)
THEN
DBMS_OUTPUT.PUT_LINE('We have a valid postcode in the format AA9');
-- ELSE
-- DBMS_OUTPUT.PUT_LINE('Sorry but that is an incorrect postcode! Format AA9');
-- GOTO exit;
-- END IF;
WHEN (length(substr(input_post_code,1,instr(input_post_code,' ')-1)) = 3
AND instr(alphabet_string,substr(input_post_code,1,1)) != 0
AND instr(number_string,substr(input_post_code,2,1)) != 0
AND instr(number_string,substr(input_post_code,3,1)) != 0)
THEN
DBMS_OUTPUT.PUT_LINE('We have a valid postcode in the format A99');
-- ELSE
-- DBMS_OUTPUT.PUT_LINE('Sorry but that is an incorrect postcode! Format A99');
-- GOTO exit;
-- END IF;
WHEN (length(substr(input_post_code,1,instr(input_post_code,' ')-1)) = 3
AND instr(alphabet_string,substr(input_post_code,1,1)) != 0
AND instr(number_string,substr(input_post_code,2,1)) != 0
AND instr(alphabet_string,substr(input_post_code,3,1)) != 0)
THEN
DBMS_OUTPUT.PUT_LINE('We have a valid postcode in the format A9A');
-- ELSE
-- DBMS_OUTPUT.PUT_LINE('Sorry but that is an incorrect postcode! Format A9A');
-- GOTO exit;
-- END IF;
WHEN (length(substr(input_post_code,1,instr(input_post_code,' ')-1)) = 4
AND instr(alphabet_string,substr(input_post_code,1,1)) != 0
AND instr(alphabet_string,substr(input_post_code,2,1)) != 0
AND instr(number_string,substr(input_post_code,3,1)) != 0
AND instr(number_string,substr(input_post_code,4,1)) != 0)
THEN
DBMS_OUTPUT.PUT_LINE('We have a valid postcode in the format AA99');
-- ELSE
-- DBMS_OUTPUT.PUT_LINE('Sorry but that is an incorrect postcode! Format AA99');
-- GOTO exit;
-- END IF;
WHEN (length(substr(input_post_code,1,instr(input_post_code,' ')-1)) = 4
AND instr(alphabet_string,substr(input_post_code,1,1)) != 0
AND instr(alphabet_string,substr(input_post_code,2,1)) != 0
AND instr(number_string,substr(input_post_code,3,1)) != 0
AND instr(alphabet_string,substr(input_post_code,4,1)) != 0)
THEN
DBMS_OUTPUT.PUT_LINE('We have a valid postcode in the format AA9A');
-- ELSE
-- DBMS_OUTPUT.PUT_LINE('Sorry but that is an incorrect postcode! Format AA9A');
-- GOTO exit;
-- END IF;
END CASE;
-- Check last part of format, should be AA9
IF (instr(number_string,substr(input_post_code,1,1)) != 0
AND instr(alphabet_string,substr(input_post_code,2,1)) != 0
AND instr(alphabet_string,substr(input_post_code,3,1)) != 0)
THEN
DBMS_OUTPUT.PUT_LINE('End part of the postcode is in the correct format, 9AA');
ELSE
DBMS_OUTPUT.PUT_LINE('End part of the postcode is in the wrong format!');
END IF;
<<exit>>
DBMS_OUTPUT.PUT_LINE('Please try again');
END;
/As VG2 pointed out you were missing some semicolons.
Also, CASE input_post_code was replaced with just CASE since you are doing a searched case.
Also, END at the end of the case statement was replaced with END CASE.
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When I execute the following t-sql 2012 statement, the "NO Prod' value is not
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SELECT DISTINCT
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WHEN 'IB' then 'IB Prod'
WHEN 'HR' then 'HR Prod'
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The product_type (not blood_type, not automobile_body_type!) has a constraint that assures it is never NULL and never blank; I invented 'XX' as a default.
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--CELKO-- Books in Celko Series for Morgan-Kaufmann Publishing: Analytics and OLAP in SQL / Data and Databases: Concepts in Practice Data / Measurements and Standards in SQL SQL for Smarties / SQL Programming Style / SQL Puzzles and Answers / Thinking
in Sets / Trees and Hierarchies in SQL -
CASE STATEMENTS AND CASE EXPRESSIONS IN ORACLE9I PL/SQL
제품 : PL/SQL
작성날짜 : 2001-11-13
CASE STATEMENTS AND CASE EXPRESSIONS IN ORACLE9I PL/SQL
=======================================================
PURPOSE
아래의 자료는 Case 문에서 oracle 8.1.7과 Oracle 9i의 New Feature로 8.1.7에서는
sqlplus 에서만 가능했고, 9i 부터는 pl/sql 까지 가능하다.
Explanation
1. Oracle 8.1.7 Feature
Oracle 8.1.7 에서 Case 문은 Decode 문과 유사하지만, 기존의 decode 문을 쓰는 것보다
더 많은 확장성과 Logical Power와 좋은 성능을 제공한다. 주로 나이와 같이 category 별로
나눌때 주로 사용하고 Syntex는 아래와 같다.
CASE WHEN <cond1> THEN <v1> WHEN <cond2> THEN <v2> ... [ELSE <vn+1> ] END
각각의 WHEN...THEN 절의 argument 는 255 까지 가능하고 이 Limit를 해결하려면
Oracle 8i Reference를 참조하면 된다.
The maximum number of arguments in a CASE expression is 255, and each
WHEN ... THEN pair counts as two arguments. To avoid exceeding the limit of 128 choices,
you can nest CASE expressions. That is expr1 can itself be a CASE expression.
Case Example : 한 회사의 모든 종업원의 평균 봉급을 계산하는데 봉급이 $2000보다 작은경우
2000으로 계산을 하는 방법이 pl/sql을 대신하여 case function을 사용할 수 있다.
SELECT AVG(CASE when e.sal > 2000 THEN e.sal ELSE 2000 end) FROM emp e;
Case Example : 나이를 column으로 가지고 있는 customer table을 예로 들어보자.
SQL> SELECT
2 SUM(CASE WHEN age BETWEEN 70 AND 79 THEN 1 ELSE 0 END) as "70-79",
3 SUM(CASE WHEN age BETWEEN 80 AND 89 THEN 1 ELSE 0 END) as "80-89",
4 SUM(CASE WHEN age BETWEEN 90 AND 99 THEN 1 ELSE 0 END) as "90-99",
5 SUM(CASE WHEN age > 99 THEN 1 ELSE 0 END) as "100+"
6 FROM customer;
70-79 80-89 90-99 100+
4 2 3 1
1 SELECT
2 (CASE WHEN age BETWEEN 70 AND 79 THEN '70-79'
3 WHEN age BETWEEN 80 and 89 THEN '80-89'
4 WHEN age BETWEEN 90 and 99 THEN '90-99'
5 WHEN age > 99 THEN '100+' END) as age_group,
6 COUNT(*) as age_count
7 FROM customer
8 GROUP BY
9 (CASE WHEN age BETWEEN 70 AND 79 THEN '70-79'
10 WHEN age BETWEEN 80 and 89 THEN '80-89'
11 WHEN age BETWEEN 90 and 99 THEN '90-99'
12* WHEN age > 99 THEN '100+' END)
SQL> /
AGE_G AGE_COUNT
100+ 1
70-79 4
80-89 2
90-99 3
Example
2. Oracle 9i Feature
Oracle 9i부터는 pl/sql에서도 case문을 사용할 수 있으면 이것은
복잡한 if-else 구문을 없애고, C언어의 switch문과 같은 기능을 한다.
아래의 9i pl/sql Sample 및 제약 사항을 보면 아래와 같다.
Sample 1:
A simple example demonstrating the proper syntax for a case
statement
using a character variable as the selector. See the section entitled
'Restrictions' at the end of this article for details on which PLSQL
datatypes may appear as a selector in a case statement or
expression.
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set serveroutput on
declare
achar char(1) := '&achar';
begin
case achar
when 'A' then dbms_output.put_line('The description was Excellent');
when 'B' then dbms_output.put_line('The description was Very Good');
when 'C' then dbms_output.put_line('The description was Good');
when 'D' then dbms_output.put_line('The description was Fair');
when 'F' then dbms_output.put_line('The description was Poor');
else dbms_output.put_line('The description was No such Grade');
end case;
end;
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Sample 2:
A simple example demonstrating the proper syntax for a case
expression
using a character variable as the selector. See the section entitled
'Restrictions' at the end of this article for details on which PLSQL
datatypes may appear as a selector in a case statement or
expression.
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set serveroutput on
declare
achar char(1) := '&achar';
description varchar2(20);
begin
description :=
case achar
when 'A' then 'Excellent'
when 'B' then 'Very Good'
when 'C' then 'Good'
when 'D' then 'Fair'
when 'F' then 'Poor'
else 'No such grade'
end;
dbms_output.put_line('The description was ' || description);
end;
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NOTE: The above simple samples demonstrate two subtle differences in the
syntax
required for case statements and expressions.
1) A case STATEMENT is terminated using the 'end case' keywords; a
case
EXPRESSION is terminated using only the 'end' keyword.
2) Each item in a case STATEMENT consists of one or more
statements, each
terminated by a semicolon. Each item in a case expression
consists of
exactly one expression, not terminated by a semicolon.
Sample 3:
Sample 1 demonstrates a simple case statement in which the selector
is
compared for equality with each item in the case statement body.
PL/SQL
also provides a 'searched' case statement as an alternative; rather
than
providing a selector and a list of values, each item in the body of
the
case statement provides its own predicate. This predicate can be any
valid boolean expression, but only one case will be selected.
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set serveroutput on
declare
achar char(1) := '&achar';
begin
case
when achar = 'A' then dbms_output.put_line('The description was
Excellent');
when achar = 'B' then dbms_output.put_line('The description was Very
Good');
when achar = 'C' then dbms_output.put_line('The description was
Good');
when achar = 'D' then dbms_output.put_line('The description was
Fair');
when achar = 'F' then dbms_output.put_line('The description was
Poor');
else dbms_output.put_line('The description was No such Grade');
end case;
end;
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Sample 4:
This sample demonstrates the proper syntax for a case expression of
the
type discussed in Sample 3 above.
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set serveroutput on
declare
achar char(1) := '&achar';
description varchar2(20);
begin
description :=
case
when achar = 'A' then 'Excellent'
when achar = 'B' then 'Very Good'
when achar = 'C' then 'Good'
when achar = 'D' then 'Fair'
when achar = 'F' then 'Poor'
else 'No such grade'
end;
dbms_output.put_line('The description was ' || description);
end;
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Sample 5:
This sample demonstrates the use of nested case statements. It is
also
permissable to nest case expressions within a case statement (though
it
is not demonstrated here), but nesting of case statements within a
case
expression is not possible since statements do not return any value.
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set serveroutput on
declare
anum1 number := &anum1;
anum2 number := &anum2;
answer number;
begin
case anum1
when 1 then case anum2
when 1 then answer := 10;
when 2 then answer := 20;
when 3 then answer := 30;
else answer := 999;
end case;
when 2 then case anum2
when 1 then answer := 15;
when 2 then answer := 25;
when 3 then answer := 35;
else answer := 777;
end case;
else answer := 555;
end case;
dbms_output.put_line('The answer is ' || answer);
end;
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Sample 6:
This sample demonstrates nesting of case expressions within another
case
expression. Note again the absence of semicolons to terminate both
the
nested case expression and the individual cases of those
expressions.
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set serveroutput on
declare
anum1 number := &anum1;
anum2 number := &anum2;
answer number;
begin
answer :=
case anum1
when 1 then case anum2
when 1 then 10
when 2 then 20
when 3 then 30
else 999
end
when 2 then case anum2
when 1 then 15
when 2 then 25
when 3 then 35
else 777
end
else 555
end;
dbms_output.put_line('The answer is ' || answer);
end;
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Although PL/SQL anonymous blocks have been used in all of the examples
so far,
case statements and expressions can also be used in procedures,
functions, and
packages with no changes to the syntax.
The following samples are included for completeness and demonstrate the
use of
case statements and/or expressions in each of these scenarios.
Sample 7:
This sample demonstrates use of a case statement in a stored
procedure.
Note that this sample also demonstrates that it is possible for each
of
the items in the case body to consist of more than one statement.
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set serveroutput on
create or replace procedure testcasestmt ( anum IN number ) is
begin
case
when anum = 1 then dbms_output.put_line('The number was One');
dbms_output.put_line('In case 1');
when anum = 2 then dbms_output.put_line('The number was Two');
dbms_output.put_line('In case 2');
when anum = 3 then dbms_output.put_line('The number was Three');
dbms_output.put_line('In case 3');
when anum = 4 then dbms_output.put_line('The number was Four');
dbms_output.put_line('In case 4');
when anum = 5 then dbms_output.put_line('The number was Five');
dbms_output.put_line('In case 5');
else dbms_output.put_line('The description was Invalid input');
dbms_output.put_line('In the else case');
end case;
end;
exec testcasestmt(&anum);
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Sample 8:
This sample demonstrates the use of a case statement in a stored
package.
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set serveroutput on
create or replace package testpkg2 is
procedure testcasestmt ( anum IN number );
function testcasestmt_f ( anum IN number ) return number;
end testpkg2;
create or replace package body testpkg2 is
procedure testcasestmt ( anum IN number ) is
begin
case
when anum = 1 then dbms_output.put_line('The number was One');
dbms_output.put_line('In case 1');
when anum = 2 then dbms_output.put_line('The number was Two');
dbms_output.put_line('In case 2');
when anum = 3 then dbms_output.put_line('The number was Three');
dbms_output.put_line('In case 3');
when anum = 4 then dbms_output.put_line('The number was Four');
dbms_output.put_line('In case 4');
when anum = 5 then dbms_output.put_line('The number was Five');
dbms_output.put_line('In case 5');
else dbms_output.put_line('The description was Invalid input');
dbms_output.put_line('In the else case');
end case;
end;
function testcasestmt_f ( anum IN number ) return number is
begin
case
when anum = 1 then dbms_output.put_line('The number was One');
dbms_output.put_line('In case 1');
when anum = 2 then dbms_output.put_line('The number was Two');
dbms_output.put_line('In case 2');
when anum = 3 then dbms_output.put_line('The number was Three');
dbms_output.put_line('In case 3');
when anum = 4 then dbms_output.put_line('The number was Four');
dbms_output.put_line('In case 4');
when anum = 5 then dbms_output.put_line('The number was Five');
dbms_output.put_line('In case 5');
else dbms_output.put_line('The description was Invalid input');
dbms_output.put_line('In the else case');
end case;
return anum;
end;
end testpkg2;
exec testpkg2.testcasestmt(&anum);
variable numout number
exec :numout := testpkg2.testcasestmt_f(&anum);
print numout
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Sample 9:
This sample demonstrates the use of a case expression in a stored
package.
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set serveroutput on
create or replace package testpkg is
procedure testcase ( anum IN number );
function testcase_f ( anum IN number ) return number;
end testpkg;
create or replace package body testpkg is
procedure testcase ( anum IN number ) is
anumber number := anum;
anothernum number;
begin
anothernum :=
case
when anumber = 1 then anumber + 1
when anumber = 2 then anumber + 2
when anumber = 3 then anumber + 3
when anumber = 4 then anumber + 4
when anumber = 5 then anumber + 5
else 999
end;
dbms_output.put_line('The number was ' || anothernum);
end;
function testcase_f ( anum IN number ) return number is
anumber number := anum;
anothernum number;
begin
anothernum :=
case
when anumber = 1 then anumber + 1
when anumber = 2 then anumber + 2
when anumber = 3 then anumber + 3
when anumber = 4 then anumber + 4
when anumber = 5 then anumber + 5
else 999
end;
dbms_output.put_line('The number was ' || anothernum);
return anothernum;
end;
end testpkg;
variable numout number
exec testpkg.testcase(&anum);
exec :numout := testpkg.testcase_f(&anum);
print numout
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제약 사항
다음의 databasetype은 case 문에서 지원되지 않는다.
BLOB
BFILE
VARRAY
Nested Table
PL/SQL Record
PL/SQL Version 2 tables (index by tables)
Object type (user-defined type)
All of these types except for object types face a similar restriction
even for if statements (i.e. they cannot be compared for equality directly) so this is unlikely to change for these types. Lack of support for object types is simply an implementation restriction which may be relaxed in future releases.
Reference Ducumment
Oracle 8.1.7 Manual
NOTE:131557.1I have done the following code but doesn't
like the statement of - "case(butNext)". What do you mean "doesn't like" -- did you get an error message?
I'm guessing it won't compile because you're trying to switch on a Button.
I tried something
like "g.fillOval(100,50,70,90, BorderLayout.NORTH)"...no that doesn't make sense. You only use BorderLayout.NORTH when you're adding components to a BorderLayout layout manager. An oval is not a component and fillOval isn't adding a component and Graphics is not a Panel or layout manager.
Would appreciate it if someone could tell me how to position
shapes using the graohic method. I think the problem is that you're confusing shapes with components. -
SQL CASE statement in XML template- End tag does not match start tag 'group
Hi All,
I am developing a report that has the SQL CASE statement in the query. I am trying to load this into RTF with report wizard and it gives me below error
oracle.xml.parser.v2.XMLParseException: End tag does not match start tag 'group'
Does XML publisher support CASE statement?
My query is something like this
SELECT customercode,
SUM(CASE WHEN invoicedate >= current date - 30 days
THEN balanceforward ELSE 0 END) AS "0-30",
SUM(CASE WHEN invoicedate BETWEEN current date - 60 days
AND current date - 31 days
THEN balanceforward ELSE 0 END) AS "31-60",
SUM(CASE WHEN invoicedate < current date - 60 days
THEN balanceforward ELSE 0 END) AS "61>",
SUM(balanceforward) AS total_outstanding
FROM MyTable
GROUP BY customercode
ORDER BY total_outstanding DESC
Please advice if the CASE statement or the double quotes are causing this error
Thanks,
PPI got this to work in the XML but the data is returning zeros for all the case statements. When I run this in toad I get results for all the case conditions but when ran in XML the data displayed is all zeros. I am not sure what I am missing. Can someone shed some light on this please
Thanks!
PP -
I am working on a project for ambulance response times. In
the following query which is in my coldfusion code, I am using a
CASE statement on a subquery to count the ambulance response times
in bins. An ambulance should arrive at an emergency incident in
less than 8:59 (539 seconds) or else it is considered late. In my
coldfusion Transact-SQL code I am:
1.) doing a subquery.
2.) counting the 'event numbers' based on the time it took
for the ambulance to arrive.
3.) only counting Lee County ambulances and excluding A6 type
calls (non-emergencies).
4.) grouping it by the dateparts.
SELECT DATENAME("M", I.I_tTimeDispatch) as mths,
(DATEPART("yyyy", I.I_tTimeDispatch)) AS yr,
COUNT(CASE WHEN (DATEDIFF("S",I.I_tTimeDispatch,
I.I_tTimeArrival)) BETWEEN 0 AND 539 THEN evnt END) AS OnTime,
COUNT(CASE WHEN (DATEDIFF("S",I.I_tTimeDispatch,
I.I_tTimeArrival)) BETWEEN 540 AND 1028 THEN evnt END) AS Late,
COUNT(CASE WHEN (DATEDIFF("S",I.I_tTimeDispatch,
I.I_tTimeArrival)) > 1028 THEN evnt END) AS Outlier
FROM (SELECT I_EventNumber AS evnt, I_tTimeDispatch,
I_tTimeArrival, I_kTypeInfo, I_Agency FROM dbo.IIncident) as I
INNER JOIN dbo.ITypeInfo AS T ON I.I_kTypeInfo =
T.ITI_TypeInfo_PK
WHERE I.I_Agency='LC'
AND T.ITI_TypeID NOT LIKE 'A6*'
GROUP BY (DATEPART("M", I.I_tTimeDispatch)), (DATENAME("M",
I.I_tTimeDispatch)), (DATEPART("yyyy", I.I_tTimeDispatch))
ORDER BY (DATEPART("yyyy", I.I_tTimeDispatch)) ASC,
(DATEPART("M", I.I_tTimeDispatch)) ASC
Here is my problem!
I go into Microsoft Access to verify my statistics and I get
different counts. For instance, in April 2008 my coldfusion query
returns 3,944 on-time ambulance responses. My Access query for the
same time period using only Lee County ambulances and excluding A6
non-emergencies returns only 3,805 responses. This is an undercount
of 139 responses. Even for my other time bins I am getting an
undercount.
Here is my Access SQL for the on time response bin (<539
seconds or 8:59):
SELECT Count(dbo_IIncident.I_EventNumber) AS
CountOfI_EventNumber
FROM dbo_IIncident INNER JOIN dbo_ITypeInfo ON
dbo_IIncident.I_kTypeInfo = dbo_ITypeInfo.ITI_TypeInfo_PK
WHERE (((dbo_IIncident.I_Agency)="lc") AND
((dbo_ITypeInfo.ITI_TypeID) Not Like "a6*") AND
((dbo_IIncident.I_tTimeDispatch) Between #4/1/2008# And #5/1/2008#)
AND
((DateDiff("s",[dbo_IIncident]![I_tTimeDispatch],[dbo_IIncident]![I_tTimeArrival]))
Between 0 And 539));
How could two queries that are supposed to be doing the same
thing return such different results?
To clear up any confusion I am temporarily posting the page.
Please look at it because it may help you visualize the problem.
http://lcfcfn01/Secure/GTandLT_8_59.cfmThank you for your quick reply.
I thought about that, but it isn't what is causing the
discrepancy in the numbers. This is because Access is hitting the
SQL Server through ODBC. The time stamps in SQL Server are ODBC
datetime stamps so they look like this: 4/19/2008 6:20:18 PM
When my query uses the date #5/1/2008# it is like saying May
1, 2008 00:00:00. Please correct me if I am wrong. The query won't
return any results from May 1, 2008 because it stops at zero
hundred hours. I believe it will only go to April 30, 2008 23:59:59
and then stop there.
I do try and play with the date ranges and the 'seconds'
(<539 or >539) parameter and I consistently get different
results from what my coldfusion page is telling me.
David -
SQL Expression Field - Combine Declared Variable With Case Statement
Hello All, I have been using Crystal & Business Objects for a few months now and have figured out quite a bit on my own. This is the first real time I have struggled with something and while I could do this as a Formula Field I would like to know how to do this as a SQL Expression. Basically I want to create a SQL Expression that uses a CASE statement but I wanted to make the code a little more efficient and employ a variable to hold a string and then use the variable in the CASE statement. The expression editor accepts the CASE statement OK but I don't know how to declare the variable. Please assist with the syntax?
This is what I have:
CASE
WHEN u201CDatabaseu201D.u201DFieldu201D = u2018Hu2019 THEN u2018Hedgeu2019
WHEN u201CDatabaseu201D.u201DFieldu201D = u2018Pu2019 THEN u2018PVIu2019
ELSE u2018Noneu2019
END
This is what I want:
DECLARE strVar AS VARCHAR(25)
strVar = u201CDatabaseu201D.u201DFieldu201D
CASE
WHEN strVar = u2018Hu2019 THEN u2018Hedgeu2019
WHEN strVar = u2018Pu2019 THEN u2018PVIu2019
ELSE u2018Noneu2019
ENDHi Todd,
Please use the following for loop; your problem will be solved.
Local StringVar str := "";
Local NumberVar strLen := Length ({Database.Field});
Local NumberVar i;
For i := 1 To strLen Do
if {Database.Field} <i> = "H" then str := "Hedge"
else if {Database.Field} <i> = "P" then str := "PVI"
else str := "None"; exit for
str
Let me know once done!
Thank you,
Ashok -
CASE statement in Oracle 8i PL/SQL
I'm in the process of doing an upgrade from 8i to 10g and have the necessary instructions in performing it. however, after running the pre upgrade tasks (run utlu102i.sql) to show the preupgrade information, i found out that there are some INVALID objects.
Miscellaneous Warnings
WARNING: --> Database contains INVALID objects prior to upgrade.
.... USER INGITRN has 1 INVALID objects.
.... USER INGIUAT has 3 INVALID objects.
.... USER OEMMON has 7 INVALID objects.
.... USER RE_ITF_USER has 11 INVALID objects.
.... USER SYS has 1 INVALID objects.
Would it be ok to proceed with the upgrade and ignore the warnings?
Also, as i checked the invalid object for SYS, it shows:
OWNER OBJECT_NAME OBJECT_TYPE STATUS
SYS UTL_RECOMP PACKAGE VALID
SYS UTL_RECOMP PACKAGE BODY INVALID
Further more, i tried to do a fix by invoking utlirp.sql and the same objects are showing up. Same thing shows when invoking utlrp.sql or even doing a manual compile for the affected objects. I later found out that CASE statements are not accepted in PL/SQL for Oracle 8i.
Can you help me fixed the issue on the invalid object?
ThanksHi,
Try first to (re)compile ll invalid objects. then
you can run:
select owner,type,count(*) from all_errors
group by owner,typeif you still have uncompiled objects, then report the different errors:
select * from all_errors...
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