[CC] Search&Replace: Bug only with Regular Expressions

Can you confirm the following behaviour/bug?
Steps to reproduce:
1 Create a new document in DW CC
2 Enter that text in the source code view:
€
3 Open Search&Replace
Field Search in: Current document
Field Search: Text
Field Search (3rd Field): €
Start Search
Result: As expected the "€" is found.
4 [x] Regular Expressions
Start Search
Result: "€" isn't found
Can you reproduce that?
Do you regard that as a bug like me?
If not, why please?
Do you think it is technically impossible for the developers to solve the task?
Do you think the developers forgot to gray out "text" in the choice box and allow regular expressions only in source code?
Thanks.

Nice that you like the nick
Sure, I know that I can file a feature wish.
But my main interest in this forum is to know, what other users think about certain features, why they think so, which they miss, which they regard as a bug, ...
When I remember it right, you told me some time ago, that you don't use RegEx.
Than I understand, that everything around that feature is not important for you.
What I like to understand is, why you think the behaviour is logically.
For me it is the opposite.
You get a result with "Scope: Text", "[ ]RegEx".
And you get no result with "Scope: Text", "[x]RegEx".
Incredible strange.
I would appreciate, if you could explain more detailed your view.

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duplicate of Grouping & Back-references with regular expressions on Replace Text window

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First, Acrobat must "mount" the PDX.
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I have a unordered list, and I want to store all the strings between the li tags (<li>.?</li>)in an array:
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Assistance with Regular Expression and Tcl
Hello Everyone,
I recently began learning Tcl to develop scripts for automating network switch deployments.
In my script, I want to name the device with a location and the last three octets of the base mac address.
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([0-9a-f]{2}[:-]){2}([0-9a-f]{2}$)
But I have not been able to figure out how to call the regular expression in the tcl script.
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This worked for me.
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Base ethernet MAC Address       : 00:1B:D4:F8:B1:80
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1
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F8:B1:80
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%Warning! Hostname should contain at least one alphabet or '-' or '_' character
locationF8:B1:80(tcl)#

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Hi There!!
I have a problem with regular expression. I want to validate that one word and second word are same. For that I have written a regex
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Ram wrote:
ErasP wrote:
You are missing a backward slash in the regex
Pattern p = Pattern.compile("([a-z][a-zA-Z]*)\\s\\1");
But this will fail in this case.
Matcher m = p.matcher("Nikhil Nikhil");It is the reason for that *[a-z]*.The OP had [a-z][a-zA-Z]* in his code, so presumably he know what that means and wants that String not to match.

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two not-very-good-for-big-document suggestions
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Hi Vit,
According to your description, you mean that when you use the
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If yes, could you please provide me a screen shot about how you search the
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Generally, when we used the
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VS check this issue again.
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I am trying to figure out how to user regular expressions in
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*[A-Za-z0-9_
><.="']*
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SQL>with t as(
2 select 1 id,'a aa ---- ss-ee -' str from dual union
3 select 2, 'a aa -------- ss-ee ---- - - -' str from dual union
4 select 3, '-' str from dual union
5 select 4, '----- -- -a -' str from dual union
6 select 5, '-a-a-a-a----a-a-a-' str from dual
7 )
8 select id,
9 str,
10 trim(trim('-' from regexp_replace(str, '( |-){2,}', '\1'))) new_str,
11 length(str) len,
12 length(trim(trim('-' from regexp_replace(str, '( |-){2,}', '\1')))) new_len
13 from t;
ID STR NEW_STR LEN NEW_LEN
1 a aa ---- ss-ee - a aa ss-ee 19 10
2 a aa -------- ss-ee ---- - - - a aa ss-ee 34 10
3 - 1
4 ----- -- -a - a 13 1
5 -a-a-a-a----a-a-a- a-a-a-a-a-a-a 18 13

Replace All with Regular Expression

Hi all,
I need a help to replace the String:
to
"<a href=\"1\"">Java Programming</a>"
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Best regards

Hi prometheuzz,
you are the one!!
But how I could do to a Srting like this:
Ah, more requirements...
Things are getting a bit messy now:
import java.util.regex.Matcher;
import java.util.regex.Pattern;
class Main {
 public static void main(String[] args) {
 String line = "any text any text any text any text any text. "+
 "Click - [[Code: 6 Title: Java Programming]]. "+
 "any text any text any text any text any text. "+
 "- [[C�digo: 2 T�tulo: Sun]] text text "+
 "any text any text any text any text any text.";
 String newLine = line;
 String[] wikiTags = getWikiTags(newLine);
 for(String tag : wikiTags) {
 String newTag = "<a href=\""+get("(Code:|C�digo:)", " ", tag)+
 "\">"+get("(Title:|T�tulo:)", "$", tag)+"</a>";
 newLine = newLine.replaceFirst("\\[\\["+tag+"\\]\\]", newTag);
 System.out.println(line);
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 while(matcher.find()) {
 list.add(matcher.group());
 return list.toArray(new String[list.size()]);
 public static String get(String start, String end, String text) {
 Pattern pattern = Pattern.compile("(?<="+start+"\\s)(.*?)(?="+end+")");
 Matcher matcher = pattern.matcher(text);
 return matcher.find() ? matcher.group() : "#ERROR#";
}Details about regex:
http://java.sun.com/j2se/1.4.2/docs/api/java/util/regex/Pattern.html
http://www.regular-expressions.info/java.html
http://java.sun.com/docs/books/tutorial/essential/regex/
>
Thanks a lot for you helpLike I said, it's a bit of a messy solution. See if you can use (a part of) it.
Good luck.

Replace replace with regular expression possible?

Hi,
Just another regular expression question!
I want to replace the words "AND", "OR", "NOT" in a sentence with the symbols '&', '|', '~' respectively.
Obviously very simple to do with 3 replace statements, just wonder if I can use regexp_replace to achieve it?
Cheers

Hi,
Metacharacter symbols can be used in place of regular expressions.
Here's an implementation scenario:
http://www.oracle.com/technology/obe/obe10gdb/develop/regexp/regexp.htm
Hope it helps.
Regards,
Naveed.

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What is the best way to replace input string with following rules:
1. All occurences of two or more sequential Hyphen-symbols (symbol: "-") must be replaced with one hypen. So if input string was "---" then output should be "-". If input was "a-a-a" then output stays as it is.
2. All occurences of two or more sequential Space-symbols (symbol: " ") must be replaced with one Space. So if input string was " " then output should be " ". If input was "a a a" then output stays as it is.
3. After rules 1-2 are applied following rule apply: All occurences of Space-symbol followed immediately after Hypen-symbol or vice vers- hypen followed by Space must be replaced with Hypen. So if input string was " -" or "- " then output should be "-". If input was "a a-a" then output stays as it is.
4. After rules 1-2-3 are apllied following rule must be applied: String start and end symbol may not be Space or Hypen. So if input string was " a" or "-a" or "a " or "a-" then output should be "a".
All rules 1-4 must be apllied to input string.
Example of the replacement logic:
input: 'a aa ---- ss-ee -'
output: 'a aa-ss-ee'
I think i should use function "regexp_replace" somehow.
This solution below doesn't work because it outputs two consecuent hypens "--":
with t as(
select 'a   aa ---- ss-ee -' str from dual
select regexp_replace(str, '--','-') a from t;
/*a   aa -- ss-ee -*/Can you suggest one neat regular expression for that?

SQL>with t as(
2   select 1 id,'a   aa ---- ss-ee -' str from dual union
3   select 2, 'a        aa -------- ss-ee ---- - - -' str from dual union
4   select 3, '-' str from dual union
5   select 4, '----- -- -a -' str from dual union
6   select 5, '-a-a-a-a----a-a-a-' str from dual
7 )
8 select id,
9 str,
10 trim(trim('-' from regexp_replace(str, '( |-){2,}', '\1'))) new_str,
11 length(str) len,
12 length(trim(trim('-' from regexp_replace(str, '( |-){2,}', '\1')))) new_len
13 from t;
ID STR                                 NEW_STR                      LEN          NEW_LEN
1 a   aa ---- ss-ee -                 a aa ss-ee                    19               10
2 a     aa -------- ss-ee ---- - - - a aa ss-ee                    34               10
3 -                                                                  1
4 ----- -- -a -                       a                             13                1
5 -a-a-a-a----a-a-a-                  a-a-a-a-a-a-a                 18               13

Replace string with regular expression

I am new to the regular expression. I am just trying to remove double quotes from a string.
My sample string is sql statement(SELECT "SCHEMA"."TABLE1"."COLUMN1", "SCHEMA"."TABLE1"."COLUMN2" FROM "SCHEMA"."TABLE1", "SCHEMA"."TABLE2" WHERE "SCHEMA"."TABLE1"."COLUMN1" = "SCHEMA"."TABLE2"."COLUMN1" );
This is what I came up with.
String s = query.replaceAll("\\.\"", ".").replaceAll("\"\\.", ".").replaceAll("\\s\"", " ").replaceAll("\\s\"", " ").replaceAll("\",", ",").replaceAll("\"\\s", " ");
But I want to optimize this line.
Could anybody tell me how to call replaceAll once with using regular expression instead of calling replaceAll multiple times? Some table or column names can have double quotes, so I want to remove the double quotes without replacing the double quotes which is part of the table or column name.
I'd appreciated it.

caesarkim1 wrote:
I am new to the regular expression. I am just trying to remove double quotes from a string.
My sample string is sql statement(SELECT "SCHEMA"."TABLE1"."COLUMN1", "SCHEMA"."TABLE1"."COLUMN2" FROM "SCHEMA"."TABLE1", "SCHEMA"."TABLE2" WHERE "SCHEMA"."TABLE1"."COLUMN1" = "SCHEMA"."TABLE2"."COLUMN1" );
This is what I came up with.
String s = query.replaceAll("\\.\"", ".").replaceAll("\"\\.", ".").replaceAll("\\s\"", " ").replaceAll("\\s\"", " ").replaceAll("\",", ",").replaceAll("\"\\s", " ");
...Note that the following two lines are equivalent:
s = s.replaceAll("a","").replaceAll("b","");
s = s.replaceAll("a|b","");

Match beginning of line with Regular Expression

I'm confused about dreamweaver's treatment of the characters
^ and $ (beginning of line, end of line) in regex searches. It
seems that these characters match the beginning of the file, not
the beginning of the various lines in the file. I would expect it
to work the other way around. A search like:
(^.)
should match every line in the file, so that a find/replace
could be performed at the beginning of each line, like this:
HELLO$1
which would add 'HELLO' at the start of each line in the
file.
Instead, this action only matches the first character of the
file, sticks 'HELLO' in front of it, and then quits (or moves on to
the next file). The endline character $ behaves in a similar
fashion, matching only the end of the file, not the end of each
line.
I've searched, and all the literature about regular
expressions in dreamweaver seems to indicate that I'm expecting the
correct behavior:
www.adobe.com/devnet/dreamweaver/articles/regular_expressions_03.html
quote:
^ Beginning of input or line ^T matches "T" in "This good
earth" but not in "Uncle Tom's Cabin"
$ End of input or line h$ matches "h" in "teach" but not in
"teacher"
Thanks for any insight, folks.

Hi Winston,
I am still digesting the material from the regular expression book and will take sometime to become proficient with it.
It seems that using groupCount() to eliminate the unwanted text does not work in this case, since all the lines returned the same value. Ie 3 posted earlier. This may be because the patterns are complex and only a few were grouped together. Otherwise, could you provide an example using the string posted as opposed to a hyperthetic one. In the meantime, at least one solution have been found by defining an additional special pattern “\\A[^%].*\\Z”, before combining / intersecting both existing and the new special pattern to get the best of both world. Another approach that should also work is to evaluate the size of String.split() and only accept those lines with a minimum number of tokens.
Anyhow, I have come a crossed another minor stumbling block in the mean time with the following line, where some hidden characters is preventing the existing pattern from reading it:
o;?Mervan Bay 40 Boyde St 7 br t $250,000 X West Park AE
Below is the existing regular expression that works for other lines with the same pattern but not for special hidden characters such as “o;?”:
\\A([A-Z][a-z]*){1,2} [0-9]{0,4}/?[0-9]{0,4}-?[0-9]{0,4} ([A-Z][a-z]*){1,2} St|Rd|Av|Sq|Cl|Pl|Cr|Gr|Dr|Hwy|Pde|Wy|La [0-9] br [h|u|t] \\$\\d+,\\d+|\\$\\d*\\,\\d+,\\d+ ([A-Z][a-z]*){1,}\\ZIs it possible to come up with a regular expression to ignore them so that this line could be picked up? Would also like to know whether I could combine both the special pattern “\\A[^%].*\\Z” with existing one as opposed to using 2 separate patterns altogether?
Many thanks,
Jack

CF Search/Replace bug?

First off, I run CFB2 as a plugin to FB 4.5 on Win7 64bit. All was working properly until I installed the FB 4.6 release. Now, my "ColdFusion Search" no longer performs a replace. When I hit CTL+F I get the ColdFusion Search dialog like normal, type in my search criteria and hit Find it finds a match. If I hit Find All it finds all matches. So far so good. Now if I hit Replace All it does the search, but then I never get the "ColdFusion Replace Dialog". It just opens up my search view and shows my matches. Even if I use a single Replace it does not replace.
I've uninstalled FB 4.6 and CFB2 completely and re-installed and have the same problem. When I uninstall FB 4.6 and CFB2 then re-install with FB 4.5 and CFB2 the problem goes away.
Note: I have tried with and without the CFB2 hotfix 1 with same results.
So, am I the only one or should I log a bug report? I really want to use the new FB 4.6 features for our Air3 development, but can't sacrifice something as critical as a search/replace function on my CF stuff, and two standalone installs would defeat the purpose of having the IDE built on Eclipse.

I, too, am more than a little annoyed at the problematic "Find' function in files opened via RDS. The only way to get it to actually find anything is to do a replace on the same term! When I try to "Find All" I get a "No open file." message. The hotfix has done nothing to fix this problem.
HELP!

[CC] Search&Replace: Bug only with Regular Expressions

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