Cells in table don't accept number like this 0,5 (less than 1)
I don't know why but I couldn't put the number lower than 1. such as any decimal number, for instance 0,01, 0,00145 or 0,8. I don't why...
I would appreciate if someone could help me with the case.
Thanks a lot...:-) It really helped. When I changed the language i.e. to English, it suddenly started to work properly.
Thank you very much. I very appreciate that
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Table creation Error "Ref Count for this object is higher than 0"
Hi All
I have a problem in creation of table using SDK on a button event. I have a procedure to create tables and fields. If I call this procedure on a menu Event than it works fine but If I call this procedure on a button event than It gives error "Ref count for this object is higher than 0" . I know this error occur When an object does not release after creating a table. but this error occur at when first table is created. My code it given below. plz see and give me your valuable suggestions.
Dim oUserTablesMD As SAPbobsCOM.UserTablesMD
Try
oUserTablesMD = B1Connections.diCompany.GetBusinessObject(SAPbobsCOM.BoObjectTypes.oUserTables)
oUserTablesMD.TableName = "AM_OBIN"
oUserTablesMD.TableDescription = "PutAway Table"
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lRetCode = oUserTablesMD.Add
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If lRetCode <> 0 Then
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MsgBox(sErrMsg)
Else
B1Connections.theAppl.StatusBar.SetText("Table: " & oUserTablesMD.TableName & " was added successfully", BoMessageTime.bmt_Short, BoStatusBarMessageType.smt_Success)
End If
System.Runtime.InteropServices.Marshal.ReleaseComObject(oUserTablesMD)
oUserTablesMD = Nothing
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oUserTablesMD = B1Connections.diCompany.GetBusinessObject(SAPbobsCOM.BoObjectTypes.oUserTables)
oUserTablesMD.TableName = "AM_BIN1"
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oUserTablesMD.TableType = BoUTBTableType.bott_DocumentLines
lRetCode = oUserTablesMD.Add
'// check for errors in the process
If lRetCode <> 0 Then
If lRetCode = -1 Then
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B1Connections.diCompany.GetLastError(lRetCode, sErrMsg)
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End If
Else
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End If
System.Runtime.InteropServices.Marshal.ReleaseComObject(oUserTablesMD)
oUserTablesMD = Nothing
GC.Collect()
Catch ex As Exception
MsgBox(ex.Message)
End Try
Thanks
Regards
GorgeHi Gorge,
The "Ref count error..." usually occurs in case of Meta Data objects not being properly cleared. And yes, you have got the error in the right place, generally while creating tables / fields / UDOs. For this, you just need to clear the Meta Data object (At times even DI objects like Record Set) once they are used.
Eg: Release these objects in the below way in a Finally Block.
System.Runtime.InteropServices.Marshal.ReleaseComObject(oRecordSet);
Hope this helps.
Regards,
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Hie all,
I have a requirement in that I have to create the number of rows inside the cell of table. I did it using the subforms as a body page of a row.
but facing problems when you have number of rows such as data truncation and overlapping of rows..
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Reference Cells in table 2 by value in table 1
I'm looking for a shortcut to a cell referencing problem I can't seem to solve elegantly. I want to use a value found in a cell to reference another cell in a Formula... I've used VLOOKUP in the past but it just seems like it's overkill. I think I'm just formatting things incorrectly if you look at my examples below...
Let's say you have 2 tables with unique names (TableA and TableB). TableA consists of 2 columns. Column A is a sequential list of numbers from 1 to say 10. Column B's Header is 'North' and it is also 10 rows but with strings in each cell.
Moving to TableB I have numbers in column A that are not sequential.
What I want is a formula for Column B (of TableB) that will bring in the string from TableA that is in the second column and matches the Row with the same number as found in the column A of the current Row.
For example if TableB's cell A4 held the number '8' (without quotes) then I want to find the value in cell North '8' of TableA. So this I can type directly =TableA :: North '8'
but i really want a Formula that I can copy and paste into hundreds of cells. I'd think it'd be something like =TableA :: North 'TableB::A4' or perhaps =TableA :: North (VALUE(TableB::A4)) but these don't work! Is there a syntax trick that I haven't uncovered?
Thanks for any help!Demetrios wrote:
=INDIRECT(ADDRESS(A+1, 3, , , "TableA"))
Of course, if A+1 is higher than the number of rows available in "TableA" the formula will return an error.
It seems that it would be useful to look at the description of the function ADRESSE()
+ADDRESS(row, column, [type], [style], [table])+
+row: The row number of the address.+
+column: The column number of the address.+
+type: Optional; a number specifying whether the row and column numbers are relative or absolute:+
+1 or missing treats row and column as absolute references.+
+2 treats the row number as an absolute reference and the column number as a relative reference.+
+3 treats the row number as a relative reference and the column number as an absolute reference.+
+4 treats both row and column numbers as relative references.+
+style: Optional; the address style:+
+TRUE, 1, or omitted formats the address using the A1 style, in which the letter specifies the column and the number specifies the row.+
+FALSE formats the address using the R1C1 style, which isn’t supported and returns an error.+
+table: Optional; the name of the table. If the table is on another sheet, you must also include the name of the sheet.+
the first three parameters MUST be numbers so it's normal that you are not allowed to use "greek alphabet".
We may use:
=INDIRECT(ADDRESS(A+1,COLUMN(TableA :: greek alphabet),,,"TableA"))
as I did in this modified version.
The +1 added for the first parameter was required because I added a header row in TableA.
Yvan KOENIG (from FRANCE mercredi 12 mars 2008 21:02:49)
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