Coalesce or compress this index? what is the best solution in this case?
BANNER
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64biI have executed the following query on a specific index that I suspected to be smashed and got the following result
select
keys_per_leaf, count(*) blocks
from (
select sys_op_lbid (154813, 'L', jus.rowid) block_id,
count (*) keys_per_leaf
from xxx_table jus
where jus.id is not null
or jus.dat is not null
group by sys_op_lbid (154813, 'L', jus.rowid)
group by keys_per_leaf
order by keys_per_leaf;
keys_per_leaf blocks
1 80
2 1108
3 2816
4 3444
5 3512
6 2891
7 2579
8 2154
9 1943
10 1287
11 1222
12 1011
13 822
14 711
15 544
16 508
17 414
18 455
19 425
20 417
21 338
22 337
23 327
24 288
25 267
26 295
27 281
28 266
29 249
30 255
31 237
32 259
33 257
34 232
35 211
36 209
37 204
38 216
39 189
40 194
41 187
42 200
43 183
44 167
45 186
46 179
47 179
48 179
49 171
50 164
51 174
52 157
53 181
54 192
55 178
56 162
57 155
58 160
59 153
60 151
61 133
62 177
63 156
64 167
65 162
66 171
67 154
68 162
69 163
70 153
71 189
72 166
73 164
74 142
75 177
76 148
77 161
78 164
79 133
80 158
81 176
82 189
83 347
84 369
85 239
86 239
87 224
88 227
89 214
90 190
91 230
92 229
93 377
94 276
95 196
96 218
97 217
98 227
99 230
100 251
101 266
102 298
103 276
104 288
105 638
106 1134
107 1152
229 1
230 1 This is a 5 columns unique key index on (id number, dat date, id2 number, dat2 date type number).
Furthermore, a space analysis of this index using dbms_space.space_usage gives the following picture
Number of blocks with at least 0 to 25% free space = 0 -------> total bytes = 0
Number of blocks with at least 25-50% free space = 75 -------> total bytes = ,5859375
Number of Blocks with with at least 50 to 75% free space = 0 -------> Total Bytes = 0
number of blocks with at least 75 to 100% free space = 0 -------> total bytes = 0
Number of full blocks with no free space = 99848 -------> total bytes = 780,0625
Total blocks ______________________________
99923
Total size MB______________________________
799,384It seems for me that this index needs to be either coalesced or compressed.
Then, what would be the best option in your opinion?
Thanks in advance
Mohamed Houri
Edited by: Mohamed Houri on 12-janv.-2011 1:18
So let me continue my case
I first compressed the index as follows
alter index my_index rebuild compress 2;which immediately presents two new situations
(a) index space
Number of blocks with at least 0 to 25% free space = 0 -------> total bytes = 0
Number of blocks with at least 25-50% free space = 40 -------> total bytes =, 3125
Number of Blocks with at least 50 to 75% free space = 0 -------> total Bytes = 0
Number of blocks with at least 75 to 100% free space = 0 -------> total bytes = 0
Number of full blocks with no free space = 32361 -------> total bytes = 252, 8203125
Total blocks ______________________________
32401
Total size Mb______________________________
259,208meaning that the compress command freed up 67487 leaf blocks and reduced the size of the index from to 799,384 MB to 259,208 MB.
It also shows a relative nice pictue of number of keys per leaf block (when compared to the previous situation)
(b) on the number of key per leaf block
KEYS_PER_LEAF BLOCKS
4 1
6 1
13 1
15 1
25 1
62 1
63 1
88 1
97 1
122 1
123 3
124 6
125 4
126 2
289 4489
290 3887
291 3129
292 2273
293 1528
294 913
295 442
296 152
297 50
298 7
299 1 In a second step, I have coalesced the index as follows
alter index my_index coalesce;which produces the new figure
Number of blocks with at least 0 to 25% free space = 0 -------> total bytes = 0
Number of blocks with at least 25-50% free space = 298 -------> total bytes = 2,328125
Number of Blocks with at least 50 to 75% free space = 0 -------> Total Bytes = 0
Number of blocks with at least 75 to 100% free space = 0 -------> total bytes = 0
Number of full blocks with no free space = 32375 -------> total bytes = 252, 9296875
Total blocks ______________________________
32673
Total size MB______________________________
261,384meaning the the coalesce command has made
(a) 298-40 = 258 new blocks with 25-50% of free space
(b) 32375-32361 = 14 new additional blocks which have been made full
(c) The size of the index increased by 2,176MB (261,384-259,208)
While the number of key per leaf block keeps in the same situation
KEYS_PER_LEAF BLOCKS
4 2
5 3
9 1
10 2
12 1
13 1
19 1
31 1
37 1
61 1
63 1
73 1
85 1
88 1
122 1
123 4
124 4
125 3
126 1
289 4492
290 3887
291 3125
292 2273
293 1525
294 913
295 441
296 152
297 50
298 7
299 1 Could you please through some light on the difference between the compress and the coalesce on the effect they have made on
(a) the number of keys per leaf blocks within my index
(b) the space and size of my index?
Best regards
Mohamed Houri
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