Code to update a table using sqlldr

Question

Hi all,
can anybody give the code to update a table using sqlldr with an example
thank you

Answer 1

You want add the new line and modified the existing line (based on empno) from file e:\scripts\sql\emp2_ext.dat into table emp2 :
7782,CLARK,MANAGER,7839,09/06/81,80000,,10
8000,ORACLE,DATABASE,,11/02/07,99999,,20Then :
SQL> conn system/mypwd
Connected.
SQL>
SQL> create directory my_dir as 'e:\scripts\sql';
Directory created.
SQL>
SQL> grant read,write on directory my_dir to scott;
Grant succeeded.
SQL>
SQL> conn scott/mypwd
Connected.
SQL> create table emp2_ext
  2  (EMPNO    NUMBER(4),
  3   ENAME    VARCHAR2(10),
  4   JOB      VARCHAR2(9),
  5   MGR      NUMBER(4),
  6   HIREDATE DATE,
  7   SAL      NUMBER(7,2),
  8   COMM     NUMBER(7,2),
  9   DEPTNO   NUMBER(2)
10  )     
11  ORGANIZATION EXTERNAL
12  ( TYPE ORACLE_LOADER
13    DEFAULT DIRECTORY my_dir
14    ACCESS PARAMETERS
15    ( records delimited by newline
16      badfile my_dir:'emp2_ext.bad'
17      logfile my_dir:'emp2_ext.log'
18      fields terminated by ','
19      missing field values are null
20      ( empno, ename, job, mgr, hiredate char date_format date mask "dd/mm/yy",
21        sal, comm, deptno
22      )
23    ) LOCATION ('emp2_ext.dat')
24  ) ;
Table created.
SQL>
SQL> select * from emp2_ext;
     EMPNO ENAME      JOB              MGR HIREDATE        SAL       COMM     DEPTNO
      7782 CLARK      MANAGER         7839 09/06/81      80000                    10
      8000 ORACLE     DATABASE             11/02/07      99999                    20
SQL> select * from emp2;
     EMPNO ENAME      JOB              MGR HIREDATE        SAL       COMM     DEPTNO
      7782 CLARK      MANAGER         7839 09/06/81      24500                    10
      7839 KING       PRESIDENT            17/11/81      50000                    10
      7934 MILLER     CLERK           7782 23/01/82      13000                    10
SQL> merge into emp2 a
  2  using (select * from emp2_ext) b
  3  on    (a.empno=b.empno)
  4  when matched then update set a.ename=b.ename,
  5                               a.job=b.job,
  6                               a.mgr=b.mgr,
  7                               a.hiredate=b.hiredate,
  8                               a.sal=b.sal,
  9                               a.comm=b.comm,
10                               a.deptno=b.deptno
11  when not matched then insert (a.empno, a.ename, a.job, a.mgr, a.hiredate, a.sal, a.comm, a.deptno)
12                        values (b.empno, b.ename, b.job, b.mgr, b.hiredate, b.sal, b.comm, b.deptno);
2 rows merged.
SQL>
SQL> select * from emp2;
     EMPNO ENAME      JOB              MGR HIREDATE        SAL       COMM     DEPTNO
      7782 CLARK      MANAGER         7839 09/06/81      80000                    10 --modified line
      7839 KING       PRESIDENT            17/11/81      50000                    10
      7934 MILLER     CLERK           7782 23/01/82      13000                    10
      8000 ORACLE     DATABASE             11/02/07      99999                    20 --added line
SQL> HTH,
Nicolas.
Well, Hans has already give good explanation with docs links...
Message was edited by:
N. Gasparotto