Column of ascending numbers?

How do you create a column of ascending numbers?
I have searched high and low in iWork help and can't find the method.
Help!

In one cell type a starting number. In the same column but one row down enter another value in your sequence. select both cells, then grab (select and hold the little circle at the bottome right of the selection) and drag down to fill:
you can use a similar technique for horizontal fills. You can also enter 0 in one cell, then 2 in the next and Numbers will fill by 2s. You can also enter dates, days of the week by entering the first two then fill based on that pattern.
Another way is to enter a starting value, then entering a formula in the next cell (let's say you wanted you count by threes starting at 2):
enter "2" in cell A1
shorthand is:
A1=2
A2=A1+3
select A2 and fill down:

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Hi to all,
i have a table (sample) with cplumns: sno, sname,dob and so on..........
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Tangella wrote:
Hi to all,
i have a table (sample) with cplumns: sno, sname,dob and so on..........
In this table i have milions of rows with random numbers in column sno
i want to give the give the sequence numbers from 1 to 10000 in the sno column to the begining rows in the table
(Oracle)
could u post the code plese
thanks & Regards
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Hello,
I need to search in a number column for particular "subnumbers". For
example I have a column with 3453454 in it an I like to searh for the
number "53" in it. I know I could use
select * from table where number_column like '%53%'
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select * from table where contains(number_column, 53) > 0
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to a varchar2 column! Only full numbers are indexed and therefore only
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Example:
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2 /
Table created.
SCOTT@orcl12c> alter table x add (y_char varchar2(10))
2 /
Table altered.
SCOTT@orcl12c> create or replace trigger x_bir
2    before insert or update of y_num on x
3    for each row
4 begin
5    :new.y_char := to_char (:new.y_num);
6 end x_bir;
7 /
Trigger created.
SCOTT@orcl12c> begin
2    ctx_ddl.create_preference('mywordlist', 'BASIC_WORDLIST');
3    ctx_ddl.set_attribute('mywordlist','PREFIX_INDEX','TRUE');
4    ctx_ddl.set_attribute('mywordlist','PREFIX_MIN_LENGTH', '3');
5    ctx_ddl.set_attribute('mywordlist','PREFIX_MAX_LENGTH', '4');
6    ctx_ddl.set_attribute('mywordlist','SUBSTRING_INDEX', 'YES');
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9 /
PL/SQL procedure successfully completed.
SCOTT@orcl12c> create index x_idx on x (y_char)
2 indextype is ctxsys.context
3 parameters
4    ('wordlist mywordlist
5       sync      (on commit)')
6 /
Index created.
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2 /
1 row created.
SCOTT@orcl12c> commit
2 /
Commit complete.
SCOTT@orcl12c> select * from x where contains (y_char, '%53%') > 0
2 /
     Y_NUM Y_CHAR
   3453454 3453454
1 row selected.

Column of ascending numbers?

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