Comma separated string in rows
Hi All,
I have one table
select * from abcd;
No err
1 rishi,rahul
2 rishi,ak
I want output like:
No ERR
1 rishi
1 rahul
2 rishi
2 ak
i am using the below query for this:
select no,regexp_substr(err,'[^,]+', 1, level) from abcd
connect by regexp_substr(err, '[^,]+', 1, level) is not null
but this query is giving me output:
1
rishi
1
rahul
2
ak
2
rishi
1
rahul
2
ak
if i am using distinct then only desired output is coming.
select distinct no,regexp_substr(err,'[^,]+', 1, level) from abcd
connect by regexp_substr(err, '[^,]+', 1, level) is not null
but i don't want to use distinct because my table has millions of rows and err contains comma separated varchar(6000);
please help me.
Something like this?
SQL> ed
Wrote file afiedt.buf
1 WITH table_x AS(
2 SELECT 1 id, 'rishi,rahul' str FROM dual UNION ALL
3 SELECT 2 id, 'rishi,ak' str FROM dual
4 )
5 SELECT id,
6 REGEXP_SUBSTR (str,
7 '[^,]+',
8 1,
9 LEVEL)
10 --LEVEL,
11 --SYS_GUID ()
12 FROM table_x
13 CONNECT BY LEVEL <= LENGTH (REGEXP_COUNT (str, ',')) +1
14 AND PRIOR id = id
15 AND PRIOR Sys_Guid() IS NOT NULL
16* ORDER BY id, LEVEL
SQL> /
ID REGEXP_SUBS
1 rishi
1 rahul
2 rishi
2 ak
Trick here is: the usage of SYS_GUID() i.e. System Global Unique Identifier.
Alternative to this, can also use DBMS_RANDOM.value() here.
Read more here - https://forums.oracle.com/thread/2526535
HTH
-- Ranit
Similar Messages
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Convert comma separated string in rows
Dear Gurus,
I want to convert comma separated string in rows so as to insert in collection.
e.g. string 1234,2323,23232,2343,34234
Above string should be converted in rows so as to insert in table or collection
Thanks in advance
SanjeevOr slight variation...
SQL> ed
Wrote file afiedt.buf
1 with t as (select '1234,2323,23232,2343,34234' as txt from dual)
2 --
3 select REGEXP_SUBSTR (txt, '[^,]+', 1, level)
4 from t
5* connect by REGEXP_SUBSTR (txt, '[^,]+', 1, level) is not null
6 /
REGEXP_SUBSTR(TXT,'[^,]+',
1234
2323
23232
2343
34234... so it doesn't have to work out how many levels it needs to do, it just keeps going until it get's a no-value (of course that assumes that there is always a value between each comma) -
Converting comma separated string into rows
for my procedure varchar2 is i/p paramter. i will get this i/p from java. this string value is like 'VTP,VR','VM'.
i want to split taht string into rows ie o/p will be
VTR
VR
VM.
how to do this.Hi,
As always, the solution depends on your data, your requirements, and you Oracle version.
Here's one way:
-- Simulating Java input with a bind variable:
VARIABLE str VARCHAR2 (100)
EXEC :str := 'VTP,VR,VM';
SELECT LEVEL AS n
, REGEXP_SUBSTR ( :str
, '[^,]+'
, 1
, LEVEL
) AS str_part
FROM dual
CONNECT BY LEVEL <= 1 + REGEXP_COUNT (:str, ',')
I'm just guessing that your original string doesn't include single-quotes after VR or before VM. If it does, you can use TRIM to remove them from the string passed back by REGEXP_SUBSTR. -
MODEL clause to process a comma separated string
Hi,
I'm trying to parse a comma separated string using SQL so that it will return the parsed values as rows;
eg. 'ABC,DEF GHI,JKL' would return 3 rows;
'ABC'
'DEF GHI'
'JKL'
I'm thinking that I could possibily use the MODEL clause combined with REGULAR expressions to solve this as I've already got a bit of SQL which does the opposite ie. turning the rows into 1 comma separated string;
select id, substr( concat_string, 2 ) as string
from (select 1 id, 'ABC' string from dual union all select 1, 'DEF GHI' from dual union all select 1, 'JKL' from dual)
model
return updated rows
partition by ( id )
dimension by ( row_number() over (partition by id order by string) as position )
measures ( cast(string as varchar2(4000) ) as concat_string )
rules
upsert
iterate( 1000 )
until ( presentv(concat_string[iteration_number+2],1,0) = 0 )
( concat_string[0] = concat_string[0] || ',' || concat_string[iteration_number+1] )
order by id;
Can anyone give me some pointers how to parse the comma separated string using regexp and create as many rows as needed using the MODEL clause?Yes, you could do it without using ITERATE, but FOR ... INCREMENT is pretty much same loop. Couple of improvements:
a) there is no need for CHAINE measure
b) there is no need for CASE in RULES clause
c) NVL can be applies on measures level
with t as (select 1 id, 'ABC,DEF GHI,JKL,DEF GHI,JKL,DEF GHI,JKL,DEF,GHI,JKL' string from dual
union all
select 2,'MNO' string from dual
union all
select 3,null string from dual
SELECT id,
string
FROM T
MODEL
RETURN UPDATED ROWS
partition by (id)
DIMENSION BY (0 POSITION)
MEASURES(
string,
NVL(LENGTH(REGEXP_REPLACE(string,'[^,]+','')),0)+1 NB_MOT
RULES
string[FOR POSITION FROM 1 TO NB_MOT[0] INCREMENT 1] = REGEXP_SUBSTR(string[0],'[^,]+',1,CV(POSITION))
SQL> with t as (select 1 id, 'ABC,DEF GHI,JKL,DEF GHI,JKL,DEF GHI,JKL,DEF,GHI,JKL' string from dual
2 union all
3 select 2,'MNO' string from dual
4 union all
5 select 3,null string from dual
6 )
7 SELECT id,
8 string
9 FROM T
10 MODEL
11 RETURN UPDATED ROWS
12 partition by (id)
13 DIMENSION BY (0 POSITION)
14 MEASURES(
15 string,
16 NVL(LENGTH(REGEXP_REPLACE(string,'[^,]+','')),0)+1 NB_MOT
17 )
18 RULES
19 (
20 string[FOR POSITION FROM 1 TO NB_MOT[0] INCREMENT 1] = REGEXP_SUBSTR(string[0],'[^,]+',1,CV(POSITION))
21 )
22 /
ID STRING
1 ABC
1 DEF GHI
1 JKL
1 DEF GHI
1 JKL
1 DEF GHI
1 JKL
1 DEF
1 GHI
1 JKL
2 MNO
ID STRING
3
12 rows selected.
SQL> SY. -
Comma separated column into rows for each value
experts,
I have a two column table. The second column has comma separated string values. How can I put the values separate for each comma separated and make one row for each value?
example,
column1 | StringColumn
s1 | test, joy, happy
s2 | USA, England, India
I want the result to be like below
column1 | StringColumn
s1 | test
s1 | joy
s1 | happy
s2 | USA
s2 | England
s2 | India
thanks in advance
ebroHello ebro,
See the following for a possible solution:
http://gallery.technet.microsoft.com/scriptcenter/Convert-Small-CSV-Value-to-ffc142ff
Olaf Helper
[ Blog] [ Xing] [ MVP] -
Look Up For Comma Separated Strings
Hi,
How to look up for comma separated string from livecycle forms manager ??
Plz gimme an idea on this.
Raghava Kumar V.S.S.Hi
My point is that the more detailed you ask your question, the more likely you are to get an answer.
Those of us who monitor these newsgroups also appreciate you doing as much of your own research as possible, before asking us for help - we're more likely to spend our own (personal and valuable) time helping you, if we know that you've spent your own time doing research, and you've still not been able to solve the problem.
I look forward to your next question :-)
Howard -
Passing comma separated string to stored procedure
Hi,
There is thread with same query I created earlier and that was answered. That solution worked if I pass comma separated string containing IDs. But due to changes in the logic, I have to pass usernames instead of userIDs. I tried to modify the solution provided to use with this.
Following the link to previous post :
Re: Passing comma separated string to stored procedure
------Package-------
TYPE refcurQID IS REF CURSOR;
TYPE refcurPubs IS REF CURSOR;
procedure GetAllPersonalQueue (p_user_name in nvarchar2, TestQID OUT Test.refcurQID
, TestPubs OUT Test.refcurPubs);
------Package-------
------Package Body-------
PROCEDURE GetAllPersonalQueue (p_user_name in nvarchar2, TestQID OUT Test.refcurQID, TestPubs OUT Test.refcurPubs) as
BEGIN
Open TestQID for
select id from cfq where name in (p_user_name);
Open TestPubs for
SELECT qid FROM queues WHERE qid in(
select id from cfq where name in (p_user_name));
END GetAllPersonalQueue;
------Package Body-------
Thanks in advance
AdityaHi,
I modified the query as per the solution provided by isotope, after which the logic changed and I am passing username instead of userID in comma separated string.
Following is the changes SP, which does not throw any error, but no data is returned.
PROCEDURE GetAllPersonalQueue (p_user_name in nvarchar2, TestQID OUT Test.refcurQID, TestPubs OUT Test.refcurPubs
) is
--local variable
strFilter varchar2(100);
BEGIN
Open TestQID for
select id, name from cfq where name in
select regexp_substr(p_user_name||',','[a-z]+[0-9]+',1,level)
from dual
connect by level <= (select max(length(p_user_name)-length(replace(p_user_name,',')))+1
from dual)
Open TestPubs for
SELECT qid FROM queues WHERE qid in(
select id from cfq where name in
select regexp_substr(p_user_name||',','[a-z]+[0-9]+',1,level)
from dual
connect by level <= (select max(length(p_user_name)-length(replace(p_user_name,',')))+1
from dual)
END GetAllPersonalQueue;
Edited by: adityapawar on Feb 27, 2009 8:38 AM -
Revision: 15983
Revision: 15983
Author: [email protected]
Date: 2010-05-10 04:47:46 -0700 (Mon, 10 May 2010)
Log Message:
Updating VideoQoSPluginMetadataSynthesizer to create comma separated string values for all of the available keys.
Modified Paths:
osmf/trunk/apps/samples/plugins/VideoQoSPlugin/src/org/osmf/qos/VideoQoSPluginMetadataSyn thesizer.asRob:
"but the sad thing is, that managers will most likely respond with a "This used to be fast in MSSQL, but now it isn't any more in Oracle. Oracle is so slow ...""
On the bright side, it sounds like most of the database calls are implemented as stored procedures, so there is an opportunity to do it right (in Oracle terms) in the stored procedures.
I did a similar conversion a while back, converting bad SQLServer procedures to good Oracle procedures. Everyone said "Oracle is much faster that SQLServer"
John -
Using a comma seprated string as rows
i hv a column in which i store comma seprated name, i have to show them as rows in a report..
plz helpAs with most things, it depends greatly on your Oracle version (you should always post this information).
In release 11 here's a neat method.
http://laurentschneider.com/wordpress/2009/07/select-from-column-separated-list.html
In release 10 there's REGEXP
http://nuijten.blogspot.com/2009/07/splitting-comma-delimited-string-regexp.html
And it looks like you've been given a pre-10 answer already. -
Read/Insert values from comma separated string
I need Stored procedure to insert values in table using comma separated values from string based on algorithm as below.
There are two table Mtable(Parent table), Ctable(Child table).
Value passed from String can be like_
1,A001,R1,C1,R2,C2,R3,C3
2,A002,X1,Y1,X2,Y2
3,A003,A1,B1,A2,B2,A3,B3
1)For line1 I need to insert in Mtable values(1,A001)
And in ctable I need to insert 3 rows with values
ROW1 (1,R1,C1)
ROW2 (1,R2,C2)
ROW3 (1,R3,C3)
2)For line2 I need to insert in Mtable values(2,A002)
And in ctable I need to insert 2 rows with values
ROW1 (2,X1,Y1)
ROW2 (2,X2,Y2)
Please help me to overcome this.
Thankscreate table t as
select '1,A001,R1,C1,R2,C2,R3,C3' s from dual union
select '2,A002,X1,Y1,X2,Y2' from dual union
select '3,A003,A1,B1,A2,B2,A3,B3' from dual
Table created
select substr(s,1,instr(s,',')-1),
substr(s,instr(s,',',1,2*i)+1,instr(s||',',',',1,2*i+1)-instr(s,',',1,2*i)-1),
substr(s,instr(s,',',1,2*i+1)+1,instr(s||',',',',1,2*i+2)-instr(s,',',1,2*i+1)-1
from t, (select 1 i from dual union select 2 from dual union select 3 from dual)
where instr(s,',',1,2*i+1)>0
order by 1,i
SUBSTR(S,1,INSTR(S,',')-1) SUBSTR(S,INSTR(S,',',1,2*I)+1, SUBSTR(S,INSTR(S,',',1
1 R1 C1
1 R2 C2
1 R3 C3
2 X1 Y1
2 X2 Y2
3 A1 B1
3 A2 B2
3 A3 B3
8 rows selected -
Remove Duplicates From Comma Separated String
Hi,
I have one Column which contains duplicates values with comma separated.
Customer ID
5,5,5,5,6,6,5,5,5,6,7,4,1,2,1,4,7,2
I wrote this:
select REGEXP_REPLACE('5,5,5,5,6,6,5,5,5,6,7,4,1,2,1,4,7,2', '(^|,)([^,]*)(,\2)+','\1\2') from dual;
5,6,5,6,7,4,1,2,1,4,7,2
But it eliminates only continuous elements.
I want out put like:
5,6,7,4,1,2
Please help.
Thanks.
Amit
Edited by: 987565 on Feb 12, 2013 4:02 AMThanks Purvesh,
While testing with real data, it is ignoring some values. I didn't understand why it happening.
with data as
select '5714,5714,5714,5714,5714,5714,5714,5714,5714,5714,5714,5714,5668,5716,5714,5714,5714,5714,5714,5714,5714,5714,5714,5714,5714,5714,5668,5716' col from dual
select ltrim(max(sys_connect_by_path(col, ',')) keep (dense_rank last order by rn - 1), ',') col
from (
select col, row_number() over (order by 1) rn
from (
select distinct regexp_substr(col, '[^,]+', 1, level) col
from data
connect by level <= length(col) - length(replace(col, ','))
start with rn = 1
connect by prior rn = rn - 1;
Result I got is:
5714,5714,5716
My Real Query is like that:
declare
cursor c1 is
select o.id id
from order o;
v_char varchar2(200) := '';
begin
for a1 in c1 loop
with data as
select o.cust_id as col into v_char
from order o
where o.id = a1.id
select ltrim(max(sys_connect_by_path(col, ',')) keep (dense_rank last order by rn - 1), ',') col
from (
select col, row_number() over (order by 1) rn
from (
select distinct regexp_substr(col, '[^,]+', 1, level) col
from data
connect by level <= length(col) - length(replace(col, ','))
start with rn = 1
connect by prior rn = rn - 1;
SYS.dbms_output.put_line(v_char);
end loop;
end;
Later, i will update same cust_id with v_char. -
Inserting the Comma Separated Strings into Table
Hi Seniors,
i had two string and i want to insert the records in the Table COMMENT . In this way.
would u please give some programe to insert the records.
The Data and the Table
( 901,902,903,904 )
( 'hai','nice','good & mail is [email protected] ','excellent and the phone 011-235323' )
comm_id loc_id company_name comments
1 10 901 Hai
2 10 902 nice
3 10 903 good & mail is [email protected]
4 10 904 excellent and the phone 011-235323
Thanks
SeenuHi, Seenu,
In Oracle 10 (and up) you can easily split a comma-delimited list using REGEXP_SUBSTR.
INSTR and SUBSTR can do the same thing in any version, but it's more complicated.
See the general instructions below:
/* How to Split a Delimited String
This shows how to take a single row with a delimited string, such as
Animal amoeba,bat,cedusa,dodo
and transform it into multiple rows:
Animal 1 amoeba
Animal 2 bat
Animal 3 cedusa
Animal 4 dodo
PROMPT ========== -1. sep_char parameter ==========
VARIABLE sep_char VARCHAR2 (10)
EXECUTE :sep_char := ',';
SELECT :sep_char AS sep_char
FROM dual;
PROMPT ========== 0. string_test table ==========
DROP TABLE string_test;
CREATE TABLE string_test
( grp_name VARCHAR2 (10)
, list_txt VARCHAR2 (50)
INSERT INTO string_test (grp_name, list_txt) VALUES ('Animal', 'amoeba,bat,cedusa,dodo');
INSERT INTO string_test (grp_name, list_txt) VALUES ('Date', '15-Oct-1582,16-Oct-2008');
INSERT INTO string_test (grp_name, list_txt) VALUES ('Nothing', NULL);
INSERT INTO string_test (grp_name, list_txt) VALUES ('Place', 'New York');
INSERT INTO string_test (grp_name, list_txt) VALUES ('Skip', 'Hop,,Jump');
SELECT *
FROM string_test
ORDER BY grp_name;
PROMPT ========== Q1. Oracle 11 Query ==========
WITH cntr AS -- Requires Oracle 9
( -- Begin sub-query cntr, to generate n (1, 2, 3, ...)
SELECT LEVEL AS n -- Requires Oracle 9
FROM dual
CONNECT BY LEVEL <= 1 + (
SELECT MAX ( REGEXP_COUNT (list_txt, :sep_char) ) -- Requires Oracle 11
FROM string_test
) -- End sub-query cntr, to generate n (1, 2, 3, ...)
SELECT grp_name
, n
, REGEXP_SUBSTR ( list_txt -- Requires Oracle 10
, '[^' || :sep_char || ']' -- Anything except sep_char ...
|| '+' -- ... one or more times
, 1
, n
) AS item_txt
FROM string_test
JOIN cntr -- Requires Oracle 9
ON n <= 1 + REGEXP_COUNT (list_txt, :sep_char) -- Requires Oracle 11
ORDER BY grp_name
, n;
/* Notes:
REGEXP_SUBSTR (s, '[^,]+', 1, n)
returns the n-th item in a comma-delimited list s.
If there are fewer than n items, it returns NULL.
One or more consecutive characters other than comma make an item, so
'Hop,,Jump' has two items, the second one being 'Jump'.
The sub-query cntr produces a list of integers 1, 2, 3, ..., w
where w is the worst-case (the largest number of items in any list).
This actually counts separators, not items, (e.g., it counts both
commas in 'Hop,,Jump', even though), so the w it produces may be
larger than is really necessary. No real harm is done.
PROMPT ========== Q2. Possible Problems Fixed ==========
WITH cntr AS
( -- Begin sub-query cntr, to generate n (1, 2, 3, ...)
SELECT LEVEL AS n
FROM dual
CONNECT BY LEVEL <= 1 + (
SELECT MAX ( REGEXP_COUNT (list_txt, :sep_char) )
FROM string_test
) -- End sub-query cntr, to generate n (1, 2, 3, ...)
SELECT grp_name
, n
, REGEXP_SUBSTR ( list_txt
, '[^' || :sep_char || ']' -- Anything except sep_char ...
|| '+' -- ... one or more times
, 1
, n
) AS item_txt
FROM string_test
JOIN cntr ON n <= 1 + NVL ( REGEXP_COUNT (list_txt, :sep_char) -- Problem (1)
, 0
WHERE REGEXP_SUBSTR ( list_txt -- Problem (2)
, '[^' || :sep_char || ']' -- Anything except sep_char ...
|| '+' -- ... one or more times
, 1
, n
) IS NOT NULL
OR list_txt IS NULL -- Problems (1) and (2) together
ORDER BY grp_name
, n;
(Possible) Problems and Fixes
(1) If list_txt IS NULL, then REGEXP_COUNT (list_txt, :sep_char)
returns NULL, the join condition fails, and the output
contains nothing corresponding to the row from string_test.
If you want a NULL item to appear in the results, use
NVL to make sure the expression returns 0 instead of NULL.
(2) If list_txt contains multiple consecutive sep_chars (or if it
begins or ends with sep_char, then the original query
will return NULL items. To suppress these, add a WHERE
clause to test that the item_txt to be displayed IS NOT NULL.
PROMPT ========== Q3. Oracle 8.1 Query ===========
SELECT grp_name
, n
, SUBSTR ( list_txt
, begin_pos
, end_pos - begin_pos
) AS item_txt
FROM ( -- Begin sub-query to compute begin_pos and end_pos
SELECT grp_name
, n
, list_txt
, INSTR ( :sep_char || list_txt
, :sep_char
, 1
, n
) AS begin_pos
, INSTR ( list_txt || :sep_char
, :sep_char
, 1
, n
) AS end_pos
FROM string_test
, ( -- Begin sub-query cntr, to generate n (1, 2, 3, ...)
SELECT ROWNUM AS n
FROM all_objects
WHERE ROWNUM <= 1 + (
SELECT MAX ( LENGTH (list_txt)
- LENGTH (REPLACE (list_txt, :sep_char))
FROM string_test
) -- End sub-query cntr, to generate n (1, 2, 3, ...)
cntr
WHERE n <= 1 + ( LENGTH (list_txt)
- LENGTH (REPLACE (list_txt, :sep_char))
) -- End sub-query to compute begin_pos and end_pos
ORDER BY grp_name
, n;
/* Version-Dependent Features and Work-Arounds
The code above, Q3, runs in Oracle 8.1.
The following changes were made to Q1:
(11) REGEXP_COUNT was introduced in Oracle 11.
In earlier versions, to find the number of sep_chars in list_txt,
see how much the LENGTH changes when sep_chars are removed.
(10) REGEXP_SUBSTR was introduced in Oracle 10.
In earlier versions, use INSTR to find where the sep_chars are,
and use SUBSTR to get the sub-strings between them.
(Using this technique, 'Hop,,Jump' still contains three items,
but now item 2 IS NULL and item 3 is 'Jump'.)
(9.a) The WITH-clause was introduced in Oracle 9
In earlier versions, use in-line views.
(9.b) "CONNECT BY LEVEL < constant" doesn't work in Oracle 8.
Use ROWNUM from any sufficiently large table or view instead.
(9.c) ANSII join notation (JOIN table_name ON ...) was introduced in Oracle 9
In earlier versions, join condition go in a WHERE-clause.
*/ -
Passing comma separated string
1) This query works
select a.GSDB_SITE_CODE
from GFSTQ75_GSDB_SITE a
where a.IS_ASSEMBLY_PLANT_FLAG = 'Y'
and a.EFFECTIVE_OUT_DTS = '31-DEC-9999'
and a.ISO3_COUNTRY_CODE IN ('RUS','AUS','SA')
2) This query not working
select a.GSDB_SITE_CODE
from GFSTQ75_GSDB_SITE a
where a.IS_ASSEMBLY_PLANT_FLAG = 'Y'
and a.EFFECTIVE_OUT_DTS = '31-DEC-9999'
and a.ISO3_COUNTRY_CODE IN (SELECT value_text from GFSTU25_PARAMETER_VALUE
WHERE proj_acronym_code = 'CPM'
AND parameter_code ='W130'
AND parameter_qualifier_code='EU_COUNTRY_CODE3')
0 records
But the value_text returned is 'RUS','AUS','SA' from the below query.
SELECT value_text from GFSTU25_PARAMETER_VALUE
WHERE proj_acronym_code = 'CPM'
AND parameter_code ='W130'
AND parameter_qualifier_code='EU_COUNTRY_CODE3'
thanks,
vinodhTry this way.
SELECT a.GSDB_SITE_CODE
FROM GFSTQ75_GSDB_SITE a
WHERE a.IS_ASSEMBLY_PLANT_FLAG = 'Y'
AND a.EFFECTIVE_OUT_DTS = '31-DEC-9999'
AND a.ISO3_COUNTRY_CODE IN (SELECT REGEXP_SUBSTR (value_text, '[^,]+', 1, LEVEL)
FROM (SELECT value_text
FROM GFSTU25_PARAMETER_VALUE
WHERE proj_acronym_code = 'CPM'
AND parameter_code ='W130'
AND parameter_qualifier_code='EU_COUNTRY_CODE3')
CONNECT BY LEVEL <= regexp_count(value_text,',')+1)some sample check done on SCOTT schema.
SQL> SELECT *
FROM emp
WHERE deptno IN (SELECT REGEXP_SUBSTR ('10,20', '[^,]+', 1, LEVEL)
FROM dual
CONNECT BY LEVEL <= regexp_count('10,20',',')+1)
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7369 SMITH CLERK 7902 17/12/1980 800.00 200.00 20
7566 JONES MANAGER 7839 02/04/1981 2975.00 200.00 20
7782 CLARK MANAGER 7839 09/06/1981 2450.00 10
7788 SCOTT ANALYST 7566 19/04/1987 3000.00 20
7839 KING PRESIDENT 5000.00 10
7876 ADAMS CLERK 7788 23/05/1987 1100.00 20
7902 FORD ANALYST 7566 03/12/1981 3000.00 20
7934 MILLER CLERK 7782 23/01/1982 1300.00 10
8 rows selectedRegards,
Lokanath Giri
Edited by: Lokanath Giri on १६ मार्च, २०१२ ६:३१ अपराह्न -
Counting the values in comma separated string
Hi I've the following requirement .
The input is like below:
with test as
(select 'ABC,DEF,GHI,JKL,MNO' mystring from dual union all
select 'ABC,DEF' from dual union all
select 'JKL,MNO' from dual )
select * from testAnd the output should be lile below
str cnt
'ABC' 2
'DEF' 2
'GHI' 1
'JKL' 2
'MNO' 2I tried the following query to get like above but getting the wrong output
with test as
(select 'ABC,DEF,GHI,JKL,MNO' mystring from dual union all
select 'ABC,DEF' from dual union all
select 'JKL,MNO' from dual )
select str,count(*) from (
select regexp_substr(mystring,'[^,]+',1,level) str
from test
connect by level <= length(regexp_replace(mystring,'[^,]+')) + 1 )
group by strPlease help me to get the ouput as required
ThanksYou are almost close:
WITH test AS
(SELECT 'ABC,DEF,GHI,JKL,MNO' mystring FROM DUAL
UNION ALL
SELECT 'ABC,DEF' FROM DUAL
UNION ALL
SELECT 'JKL,MNO' FROM DUAL)
SELECT str, COUNT (*)
FROM ( SELECT REGEXP_SUBSTR (mystring,
'[^,]+',
1,
LEVEL)
str
FROM (SELECT ROWNUM r, test.* FROM test) test
CONNECT BY LEVEL <= REGEXP_COUNT (mystring, ',') + 1
AND PRIOR SYS_GUID () IS NOT NULL
AND r = PRIOR r)
GROUP BY str
ORDER BY 1Output:
STR COUNT(*)
ABC 2
DEF 2
GHI 1
JKL 2
MNO 2Cheers,
Manik. -
I know this has been asked many times, and I got the simple solution for converting a (comma separated) string to rows like this:
with t as (select 'aa;bb;cc;dd;ee;ff' as txt from dual)
select regexp_substr (txt, '[^;]+', 1, level)
from t
connect by level <= length(regexp_replace(txt,'[^;]*'))+1;This works fine for one string. But my situation is that I have a table like this:
col1 col2
A aa;bb;cc
B dd
etc.I want to convert this to:
A aa
A bb
A cc
B dd
etc.I can do this with a pipelined function or I can do this with a group by or unique in my sql, e.g.:
with t as (select 'A' as what, 'aa;bb;cc' as txt from dual
union
select 'B' as what, 'dd' as txt from dual)
select unique what,REGEXP_SUBSTR (txt, '[^;]+', 1, level)
from t
connect by level <= length(regexp_replace(txt,'[^;]*'))+1;
W REGEXP_S
A bb
A aa
B dd
A cc
4 rows selected.In this example, with only two records A and B, this is no problem. But in the actual table I am using in my WITH clause, this select is performing slowly due to the UNIQUE.
with t as
(select col1, col2
from mytable
select unique col1, regexp_substr (col2, '[^,]+', 1, level)
from t
connect by level <= length(regexp_replace(col2,'[^,]*'))+1;Anybody with a suggestion how to improve this statement?Hi,
It's very confusing to use "CONNECT BY LEVEL <= x" when there's more than one row.
Generate the highest level you'll ever need in a sub-query (called a counter table ) that is based on a one-row table.
Then join to the counter table in your main query.
For example:
WITH cntr AS
SELECT LEVEL AS n
FROM dual
CONNECT BY LEVEL <= 1 + ( SELECT MAX ( LENGTH ( REGEXP_REPLACE ( col2
, '[^;]'
FROM t
SELECT t.col1
, REGEXP_SUBSTR ( t.col2
, '[^;]+' -- Use + here, not *
, 1
, cntr.n
) AS col2_substr
FROM t
JOIN cntr ON cntr.n <= LENGTH ( REGEXP_REPLACE (col2 || ';', '[^;]'))
ORDER BY t.col1
, cntr.n
;Edited by: Frank Kulash on Oct 23, 2009 12:01 PM
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