Connecting to enterprise TTLS+PAP wireless

Question

Ok, here's the problem. I can't connect to our enterprise wireless. I'm one of the network admins, and our director has purchased an iPad, and want to be able to connect it to our internal wireless network. It's a RADIUS server that uses WPA2 Enterprise with TTLS and PAP. I can connect with a laptop, and with my Droid, but not the iPad.
We have to put legis\(username) so that RADIUS knows where to put the user. here's what it looks like in our logs when I make a SUCCESSFUL connection
09/29/2010 12:51:14 Raw Packet :
09/29/2010 12:51:14 |.../..0z....?.@.|
09/29/2010 12:51:14 |..*..........O..|
09/29/2010 12:51:14 |QX.5....nbylsma |
But here's what it looks like in the log when I try an dconnect with the iPad
09/29/2010 16:02:02 Raw Packet :
09/29/2010 16:02:02 000:|.G.5..g.U.:..:t.|
09/29/2010 16:02:02 010:|`.# ..legis\nbyl|
09/29/2010 16:02:02 020:|smaP....AV.j..8s|
09/29/2010 16:02:02 030:|..v{v |
As you can see, it does NOT strip off the "legis\" part (like it should) AND it adds a capitol "P" to the end of my username!!! WTH!?!
The final error that I get in the log is this
09/29/2010 16:02:02 Too many or too few authentication attributes in request; rejecting.
I'm REALLY hoping that I can get some help from someone...'cause our director's really wanting to use this internally.

Answer 1

If you can't get an iPad an iPod with wireless and IOS 5 or above has pretty much the same wifi network mechanics. Again, the iPhones aren't much different in the wi fi area either. Refer to http://support.apple.com/specs/ for the specific technical specs of the device you are using to test. The biggest difference is that the iphone and ipod do not support the "a" spectrum and are b g n only, whereas the iPad is a/b/g/n.  Perhaps the problem has something to do with 802.11a.  Make sure your wifi gear has all the latest firmware.  You could also turn off the the "a"  radio beacon, I don't use it anymore as it created too many problems and g and n are really all you need anymore.