Consecutive days of absence

Experts.
I have a query request using InfoSource 0HR_PT_2. (data volume is extremely large with this extractor.)
Business has 100k employees.
Client wants to see which persons have consecutive absences >= 20 days. (NOT 20 days or more total)
I have the restrictions on TYPES or ABSENCE and Users have not defined the periods of their search. (month to month, year to year?)
How can I count hours / days of data that sum up to 20 consecutive days?
Thanks for any suggestions, both backend or query based.
Steve

Similar Messages

Count consecutive days in array

Hi,
I'm looking for an algorithm to count consecutive days in array, but i don't find one.
for example, if i have this array.
2009/07/01
2009/07/02
2009/07/03
2009/07/06
2009/07/08
2009/07/09
2009/07/10
2009/07/11
The result be
3
1
4
Anyone have one?
Thanks for all.

jverd wrote:
kajbj wrote:
It's a fairly specialist algorithm so you are unlikely to find someone to post a solution. By just keeping a reference to the previous date, it is easy to iterate though the list counting consecutive dates.I think the trick to making this algorithm sucessful is to make sure that when you change months your algorithm doesn't set consec_days to 0 Why not?Presumably he's talking about this case:
7/31
8/1
and not this case
7/1
8/1
So he really should have said, "...when you increment month by one, or from 12 to 1, and the day went from the last day of the old month to 1, don't set consec_days to 0"Ok. I would use the Calendar class and SimpleDateFormat. The tricky part would otherwise be to keep track of days per month, and leap year.

How to find consecutive days?

Hi I have a requirement, where I need to find all employees who have taken 5 consecutive days off in one week.
I am trying to build a query in BI, which can identify these records, but of no avail. I am wondering if I can do this in visual Composer. My data output currently looks like this in a table.
Employee number     calendar day    time-off hours
100                           6/8/2009         8
100                           6/9/2009         8
100                           6/10/2009       8
100                           6/11/2009       8
100                           6/12/2009       8
101                           6/1/2009         8
101                           6/5/2009         8
I like to loop through this table, somehow, and identify that employee 100, has 5 consecutive days off, but not 101.
I like to filter those employees who do not have 5 consecutive days off, and just show those who have 5 days off, like employee number 100. My output should look like, this
Employee number     calendar day    time-off hours
100                           6/8/2009         8
100                           6/9/2009         8
100                           6/10/2009       8
100                           6/11/2009       8
100                           6/12/2009       8
Any ideas will be greatly appreciated. I am trying out dynamic expression, but cannot find a way to access the first row of data, while processing the second row.

Hi
Why dont you try with time characteristics '0CALWEEK'. Add '0CALWEEK' to your infocube & map it with the date which you already have in the table. Now consider the your example for employee '100' -
100 6/8/2009 8
100 6/9/2009 8
100 6/10/2009 8
100 6/11/2009 8
100 6/12/2009 8
by adding Calweek you will get - 100   24.2009 (that is 24 th week) 40 hrs.
Now in your query divide this 40 hrs (that is total working hours in week) with daily min working hrs. (In your case assume it 8 Hrs per day). So in query you will get number of working days in a week for each employee. From this you can easily find out how many leaves each employee has taken.
I think this is what you are looking for.
Regards
Sandeep

App Hangs in 3 consecutive days

Hi all,
11.2.0.1
Aix 6.1
Our database & app hangs for the first time, 3 consecutive days (Aug 11,12,13) during run of batch jobs at 12AM.
The batch operator said the batch job is deleting a table with only less than 1000 rows but was not able to lock the table as there lots of updates queues from lots of client app.
I check the alert log for the said time period and this is the output. I saw similar occurences at 1AM
Tue Aug 13 01:20:45 2013
Clearing standby activation ID 2855092487 (0xaa2d4107)
The primary database controlfile was created using the
'MAXLOGFILES 16' clause.
There is space for up to 10 standby redo logfiles
Use the following SQL commands on the standby database to create
standby redo logfiles that match the primary database:
ALTER DATABASE ADD STANDBY LOGFILE 'srl1.f' SIZE 262144000;
ALTER DATABASE ADD STANDBY LOGFILE 'srl2.f' SIZE 262144000;
ALTER DATABASE ADD STANDBY LOGFILE 'srl3.f' SIZE 262144000;
ALTER DATABASE ADD STANDBY LOGFILE 'srl4.f' SIZE 262144000;
ALTER DATABASE ADD STANDBY LOGFILE 'srl5.f' SIZE 262144000;
ALTER DATABASE ADD STANDBY LOGFILE 'srl6.f' SIZE 262144000;
ALTER DATABASE ADD STANDBY LOGFILE 'srl7.f' SIZE 262144000;
Tue Aug 13 02:00:00 2013
Closing scheduler window
Closing Resource Manager plan via scheduler window
Clearing Resource Manager plan via parameter
Tue Aug 13 04:36:07 2013
WARNING: Heavy swapping observed on system in last 5 mins.
pct of memory swapped in [9.53%] pct of memory swapped out [23.33%].
Please make sure there is no memory pressure and the SGA and PGA
are configured correctly. Look at DBRM trace file for more details.
Tue Aug 13 05:07:14 2013
Thread 1 cannot allocate new log, sequence 49033
Private strand flush not complete
AlertSunday Aug 11
https://app.box.com/s/6ut7uk0o5y6tg2sjfzvn
AlertMonday Aug 12
https://app.box.com/s/gafa2d1ngn7hpen6tfky
AlertTuesday Aug 13
https://app.box.com/s/o5v5gtul1mr3yra6vbgj
Do you have any idea what causes tha hang? Its weird because these did not happened before.
Please help...
Thanks a lot,
zxy

Thanks,
Does these ASH, & AWR reports shows anything?
ASH
https://app.box.com/s/bmuafe2y39mzo036bbij
https://app.box.com/s/jdfv3uauwhp7tttvqlig
https://app.box.com/s/7r0sej0r77n3jay7n1fd
AWR
https://app.box.com/s/fdyx0rare2tskd291f1w
https://app.box.com/s/0pd4u7kzt0p10rhgnivq
https://app.box.com/s/sjotdxe57pssjitabrj2
Thanks,

Single Class Split Over multiple non-consecutive Days??

How do I setup in OLM a class split over multiple days for Example:
I have a Diversity Awareness Course and Offering. The Class is 2 days long, but not on consecutive days, they are a week apart.
Do I create a Day1 Class and Day2 class under the same course and make it a prerequisite to attend day 1?
From a reporting point of view this now shows as 2 classes when it is only 1; inflating the class figures.
Or Can I split it into 2 sessions under the same class?
What is the best way to do this?

Hi!
You can create a Class with two Sessions underneath it (one for each day). Make the Start Date for the Class the day the Class begins and set the End Date to correspond to the last day. Your Duration should be set to 2 Days. Learners will be able to view details for each session, and you can assign different instructors and rooms for each day if you use Resource Bookings in OLM.
Anne
Anne Saulnier | Synergy Codeworks LLC
[email protected]
603-864-9942

Birthday from calendar appears on two consecutive days when synced with iPo

Hello.
This has utterly confounded me.

Hello, tt2.
My original post appeared twice because somehow I managed to click the wrong command before I finished it the first time. Either that or the cat walked across the keyboard!
Each birthday and anniversary in my iCal is set for 'all day', from and to the same date, to repeat annually and end never, but this is the only one that is in iCal for one day a year, yet on the iPod for two consecutive days a year.
I've removed all calendar files from the iPod manually and then re-synced, but the problem persists.
Thanks.

Select non-consecutive days in Calendar input

Hi Experts,
I designed a form in WD and have a requirement, where I need to show up a calendar display of months in which an user should be allowed to select only non-consecutive days from it.
Also I need to get all those selected days at run-time.
Is it possible?? I know that calendar is a standard input of date UI element and totally confused as how I can restrict an user to select only non-consecutive days.
Please clarify and help me in this.
BR,
RAM.

Hi RAM,
Unfortunately, with the date navigator ui element, we cannot select multiple dates except the date ranges.
Work around solution:
I suggest you to go for row repeater, in which you can place date navigator ui element and user can add multiple rows: also you he can input dates by selecting single dates.
Here you can also restrict the user to select only non-consecutive dates.
Pls refer the wiki for an example:
steps to create row repeater ui element - Web Dynpro ABAP - SCN Wiki
Try to convince the user with this or you can also for a table with single row.
Hope this helps you.
Regards,
Rama

Latest Number of Consecutive Days ("Current Streak")

Using SQL Server (On Azure)
I am trying to figure out how to get the latest number of consecutive days in an SQL query.
I have a habit tracking app in which I keep track of best streaks, originally I was storing this "Streak" value as it's own column in the Habit table and changing it directly. This of course led to incorrect syncing and accuracy issues. I realize
the best way to do it is to calculate from existing data.
I simplified the 2 tables as listed below:
Habit
id (the habit id)
Name (the name of the habit)
Target (the target number of entries required to be considered completed)
HabitEntry
id (the habit entry id)
HabitID (the corresponding habit id)
EntryDate (the date and time of the entry)
Looking to get a query that looks something like this:
SELECT habit.id, habit.Name, (*subquery*) as 'CurrentStreak' from habit join habitentry on habit.id = habitentry.habitid
And outputs something like this:
1, 'Exercise Daily', 7
If the habit's target is 2, there must be 2 entries within that date to be considered completed and to add to the streak.
Not sure if this complicates things, but days are measured from 3:00am to 3:00am, any help is greatly appreciated.

Figured I'd throw this in just for the fun of it. :)
IF OBJECT_ID('tempdb..#Habbit') IS NOT NULL DROP TABLE #Habbit
CREATE TABLE #Habbit (
ID INT PRIMARY KEY,
Name VARCHAR(255),
[Target] INT
INSERT #Habbit (ID,Name,Target) VALUES
(1,'Three Day Thing', 3),
(2,'Four Day Thing', 4),
(3,'Five Day Thing', 5)
--=============================================
IF OBJECT_ID('tempdb..#HabitEntry') IS NOT NULL DROP TABLE #HabitEntry
CREATE TABLE #HabitEntry (
UserID INT,
HabbitID INT,
EntryDate DATETIME
INSERT #HabitEntry (UserID,HabbitID,EntryDate) VALUES
(1, 1, '20150101 06:35:30'),
(1, 1, '20150102 08:35:30'),
(1, 1, '20150103 08:35:30'),
(1, 1, '20150110 09:35:30'),
(1, 1, '20150112 10:35:30'),
(1, 1, '20150115 22:35:30'),
(1, 1, '20150116 23:35:30'),
(1, 1, '20150117 00:35:30'),
(1, 1, '20150118 01:35:30'),
(1, 1, '20150122 04:35:30'),
(1, 1, '20150124 05:35:30'),
(1, 1, '20150126 15:35:30'),
(1, 1, '20150127 10:35:30'),
(2, 3, '20150101 06:35:30'),
(2, 3, '20150102 06:35:30'),
(2, 3, '20150103 02:35:30'),
(2, 3, '20150104 06:35:30'),
(2, 3, '20150105 06:35:30'),
(2, 3, '20150108 06:35:30'),
(2, 3, '20150110 06:35:30'),
(2, 3, '20150111 06:35:30'),
(2, 3, '20150112 06:35:30'),
(2, 3, '20150113 06:35:30'),
(2, 3, '20150114 06:35:30'),
(2, 3, '20150122 06:35:30'),
(2, 3, '20150123 06:35:30')
--=============================================
DECLARE @MinDate DATE, @RangeSize INT
SELECT @MinDate = DATEADD(dd, -1, MIN(he.EntryDate)) FROM #HabitEntry he
SELECT @RangeSize = DATEDIFF(dd, @MinDate, MAX(he.EntryDate) + 1) FROM #HabitEntry he
IF OBJECT_ID('tempdb..#CalRanges') IS NOT NULL DROP TABLE #CalRanges
SELECT TOP (@RangeSize)
DATEADD(dd, ROW_NUMBER() OVER (ORDER BY (SELECT NULL)), @MinDate) AS [Date],
DATEADD(hh, 3, DATEADD(dd, ROW_NUMBER() OVER (ORDER BY (SELECT NULL)), CAST(@MinDate AS DATETIME))) AS BegRange,
DATEADD(hh, 27, DATEADD(dd, ROW_NUMBER() OVER (ORDER BY (SELECT NULL)), CAST(@MinDate AS DATETIME))) AS EndRange
INTO #CalRanges
FROM sys.all_objects ao
--=============================================
;WITH cte AS (
SELECT
cr.Date,
he.UserID,
he.HabbitID,
he.EntryDate,
COALESCE(LAG(CASE WHEN he.EntryDate IS NOT NULL THEN cr.Date END, 1) OVER (PARTITION BY he.UserID, he.HabbitID ORDER BY cr.Date), '19000101') AS PrevDate
FROM
#CalRanges cr
JOIN #HabitEntry he
ON he.EntryDate BETWEEN cr.BegRange AND cr.EndRange
--AND he.UserID = 1
), cte2 AS (
SELECT
c.*,
CASE WHEN DATEDIFF(dd, c.PrevDate, c.Date) <> 1 THEN ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) END ConseqGroup
FROM cte c
WHERE c.Date <> c.PrevDate
), cte3 AS (
SELECT
c2.*,
CAST(SUBSTRING(MAX(CAST(c2.Date AS BINARY(4)) + CAST(c2.ConseqGroup AS BINARY(4))) OVER (PARTITION BY c2.UserID, c2.HabbitID ORDER BY c2.Date), 5, 4) AS INT) AS ConseqGroupFill
FROM cte2 c2
), cte4 AS (
SELECT
c3.UserID,
c3.HabbitID,
h.Name AS HabbitName,
MIN(c3.EntryDate) AS BegDate,
MAX(c3.EntryDate) AS EndDate,
COUNT(*) AS DaysInSeries
FROM
cte3 c3
JOIN #Habbit h
ON c3.HabbitID = h.ID
GROUP BY
c3.UserID,
c3.HabbitID,
c3.ConseqGroupFill,
h.Name
HAVING
COUNT(*) >= MAX(h.Target)
-- SELECT * FROM cte4
SELECT
c4.*
FROM (SELECT DISTINCT he.UserID, he.HabbitID FROM #HabitEntry he) AS a
CROSS APPLY (
SELECT TOP 1
FROM cte4 c4
WHERE a.UserID = c4.UserID
AND a.HabbitID = c4.HabbitID
ORDER BY c4.BegDate DESC
) c4
HTH,
Jason
Jason Long

Find Employee Worked 7 Consecutive days

Hello All,
I have a view with following columns
(EMP #, Dept #, Total hours worked, Date of the total hours, Current Pay period st date, Current Pay period end date, Previous pay period start date, Previous pay period start date, Next pay period st date, next pay period end date)
I need a query to find employees who worked consecutively for 7 Days
within a date range.
Please let me know...
Thanks,
Kottee
kotteeswaran

DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
SET @StartDate = '11/1/2010'
SET @EndDate ='11/10/2010'
SELECT       VP_ALLTOTALS.PERSONNUM,
       MIN(VP_ALLTOTALS.APPLYDATE) AS StartDate,
       MAX(VP_ALLTOTALS.APPLYDATE) AS Enddate
FROM       (
           SELECT   V.PERSONNUM,
               V.APPLYDATE,
               DATEDIFF(DAY, '17530101', VP_ALLTOTALS.APPLYDATE) - ROW_NUMBER() OVER (PARTITION BY VP_ALLTOTALS.PERSONNUM ORDER BY VP_ALLTOTALS.APPLYDATE) AS GroupID
           FROM   VP_ALLTOTALS V
           WHERE   VP_ALLTOTALS.APPLYDATE BETWEEN @StartDate AND @EndDate
       ) AS t
GROUP BY   VP_ALLTOTALS.PERSONNUM,
       GroupID
HAVING       COUNT(*) >= 7
I'm getting following errors
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.PERSONNUM" could not be bound.
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.PERSONNUM" could not be bound.
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.PERSONNUM" could not be bound.
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
Msg 4104, Level 16, State 1, Line 7
The multi-part identifier "VP_ALLTOTALS.APPLYDATE" could not be bound.
And Many Thanks for PESO and RAMIREDDY...
Thanks,
kotteesh
kotteeswaran

3 days continous absence

Dear All,
I am doing an Implementation project.My client has this scenario.
IF AN EMPLOYEE IS CONTINUOUSLY ABSENT FOR 3 DAYS, ONLY HIS CONVEYANCE(only One WT should be deducted) SHOULD BE DEDUCTED.
WE HAVE created an absence type which will deduct only conveyance. but how to communicate the system to automatically deduct this WT
when there is a continuous absence for 3 days.
Please suggest me.
Thank you in advance!!!
Smitha

Hi Smitha ,
You have to approach abaper on this. Whenever there there is continuous absence for 3 days for an employee there should be a deduction of Conveyance Wage type
Take a help of abaper to meet your requirement
Hope you configured LOP
When we record absence type through date that is 01.01.2014 till 03.01.2014 that is continuous absence
when there is no continuous absence among dates the system shouldn't consider deduction of wage type
when there is continuous absent it should deduct conveyance wagetype, ABAPER can build a logic based on this

XY graph crashes after about 3 consecutive days running

XY graph is getting 720 points a day. My program tries to erase XY graph each day by setting it to zero to avoid memory program. But it crashes every 2-3 day.

From what you say, there shouldn't be any memory leak issues, and the rate at which you're collecting data shouldn't be causing any trouble. Likewise the amount of data you're plotting is really rather modest.
Ok, Step 1: Write a replacement subVI that is a drop in replacement for the DAQ subVI and generates the 6 values at the exact same rate, but uses a random number generator to produce the datavalues. Insert this dummy into your code instead of the DAQ and let it run. This will isolate one large part of the code and a good approach in troubleshooting something like this is always "divide and conqure".
If this version works without crashing, you know its in the DAQ somewhere. If it still crashes, you have something that other people c
an look at and try to verify there isn't something hinky going on with your PC (Step 2).
Mike...
Certified Professional Instructor
Certified LabVIEW Architect
LabVIEW Champion
"... after all, He's not a tame lion..."
Be thinking ahead and mark your dance card for NI Week 2015 now: TS 6139 - Object Oriented First Steps

Leave Req - workflow - leave days and absence hours

Hi,
For a leave request in workflow, how do i read the leave days (total number of leave) and absense hours from the workflow container? Which fields give that information?
Regards

Hi Partha Kar,
These Links are useful to You,
[Leave request example in workflow]
[Re: Employee Leave Request]
[Leave request auto approvals]
Regards,
Raghava Channooru

Consecutive Absent Days Query.. Pls Help Gurus

I have a table which stores attendance information
For eg:
Emp_No Date
100 01-APR-2010
102 05-APR-2010
100 02-APR-2010
I need a query with parameter From Date and To date..
My Query Output should be like this .. considering that employee 100 is absent for 8 consecutive days and employee number 102 is absent for 2 consecutive days..
It should return number of consecutive days he is absent.
Empno Consecutive Days
100 8 Days
102 2 Days
Pls Help Gurus.
Edited by: suzvino on Jun 21, 2010 12:14 AM

TUBBY_TUBBZ?with data as
2 (
3     select 100 as emp_no, to_date('01-APR-2010','dd-mon-yyyy') as absent_date from dual union all
4     select 102 as emp_no, to_date('05-APR-2010','dd-mon-yyyy') as absent_date from dual union all
5     select 100 as emp_no, to_date('02-APR-2010','dd-mon-yyyy') as absent_date from dual union all
6     select 100 as emp_no, to_date('01-APR-2010','dd-mon-yyyy') as absent_date from dual union all
7     select 100 as emp_no, to_date('03-APR-2010','dd-mon-yyyy') as absent_date from dual union all
8     select 100 as emp_no, to_date('04-APR-2010','dd-mon-yyyy') as absent_date from dual union all
9     select 100 as emp_no, to_date('05-APR-2010','dd-mon-yyyy') as absent_date from dual union all
10     select 100 as emp_no, to_date('06-APR-2010','dd-mon-yyyy') as absent_date from dual union all
11     select 100 as emp_no, to_date('07-APR-2010','dd-mon-yyyy') as absent_date from dual union all
12     select 100 as emp_no, to_date('08-APR-2010','dd-mon-yyyy') as absent_date from dual union all
13     select 100 as emp_no, to_date('09-APR-2010','dd-mon-yyyy') as absent_date from dual
14 )
15 select
16     emp_no, max(level)
17 from data
18 connect by prior emp_no = emp_no and prior absent_date = absent_date - 1
19 group by emp_no
20 having max(level) >= 8;
            EMP_NO         MAX(LEVEL)
               100                  9
1 row selected.
Elapsed: 00:00:00.01
TUBBY_TUBBZ?Think i misread the post, so the query should be
TUBBY_TUBBZ?with data as
2 (
3     select 100 as emp_no, to_date('01-APR-2010','dd-mon-yyyy') as absent_date from dual union all
4     select 102 as emp_no, to_date('05-APR-2010','dd-mon-yyyy') as absent_date from dual union all
5     select 100 as emp_no, to_date('02-APR-2010','dd-mon-yyyy') as absent_date from dual union all
6     select 100 as emp_no, to_date('01-APR-2010','dd-mon-yyyy') as absent_date from dual union all
7     select 100 as emp_no, to_date('03-APR-2010','dd-mon-yyyy') as absent_date from dual union all
8     select 100 as emp_no, to_date('04-APR-2010','dd-mon-yyyy') as absent_date from dual union all
9     select 100 as emp_no, to_date('05-APR-2010','dd-mon-yyyy') as absent_date from dual union all
10     select 100 as emp_no, to_date('06-APR-2010','dd-mon-yyyy') as absent_date from dual union all
11     select 100 as emp_no, to_date('07-APR-2010','dd-mon-yyyy') as absent_date from dual union all
12     select 100 as emp_no, to_date('08-APR-2010','dd-mon-yyyy') as absent_date from dual union all
13     select 100 as emp_no, to_date('09-APR-2010','dd-mon-yyyy') as absent_date from dual
14 )
15 select
16     emp_no, max(level)
17 from data
18 connect by prior emp_no = emp_no and prior absent_date = absent_date - 1
19 group by emp_no;
            EMP_NO         MAX(LEVEL)
               100                  9
               102                  1
2 rows selected.
Elapsed: 00:00:00.01Edited by: Tubby on May 30, 2010 11:00 PM
Added second query since i misread the post originally.

How to get the account numbers which maintains negative balance for consecutive 5 days

Here is what I am trying to do
I am trying to get the accounts which has negative balance consecutively for five days
Here in this a/c 1 and 5 has consecutive negative balance
how to pull these accounts using sql query.
create table #p(cal date, ac# int, bal int)
insert into #p values ( GETDATE(), 1, -1),
( GETDATE(), 2, 1),
( GETDATE(), 3, 1),
( GETDATE(), 4, -2),
( GETDATE(), 5, -6),
( GETDATE()-1, 1, -1),
( GETDATE()-1, 2, 1),
( GETDATE()-1, 3, 1),
( GETDATE()-1, 4, 2),
( GETDATE()-1, 5, -7),
( GETDATE()-2, 1, -2),
( GETDATE()-2, 2, -1),
( GETDATE()-2, 3, -1),
( GETDATE()-2, 4, 2),
( GETDATE()-2, 5, -6),
( GETDATE()-3, 1, -2),
( GETDATE()-3, 2, -1),
( GETDATE()-3, 3, -1),
( GETDATE()-3, 4, 2),
( GETDATE()-3, 5, -2),
( GETDATE()-4, 1, -4),
( GETDATE()-4, 2, 1),
( GETDATE()-4, 3, 1),
( GETDATE()-4, 4, -2),
( GETDATE()-4, 5, -2),
( GETDATE()-5, 1, -4),
( GETDATE()-5, 2, 1),
( GETDATE()-5, 3, 1),
( GETDATE()-5, 4, 2),
( GETDATE()-5, 5, -1)
-- drop table #p

@ Jing
Again not sure if it is ok to comment on other people's answers, I hope you don't take it the wrong way, but your query will not account for CONSECUTIVE days. E.g. if the acc balance goes back to a positive value, day count must be reset.
Now I understand why people answered this so much faster than me LOL.
Edit: Besides, the requeriment for the acc being returned is that its value was negative for 5 days (120 hours). When a given account balance first switches to a negative value, it has 0 hours in that state. It all add a day to its "negative balance consecutive
day count" property the next time its value is checked (cal + 1). With that said, if your query worked, it would be cnt > 6 not cnt > 5.
Thanks for pointing the issue. I have improved my query to address it.
I try to come up with something to my understanding to the questions. It may not interpret right from the question itself for various reasons. I still consider it is a great learning experience. Thank you for your comments.
create table #p(cal date, ac# int, bal int)
insert into #p values ( GETDATE(), 1, -1),
( GETDATE(), 2, 1),
( GETDATE(), 3, 1),
( GETDATE(), 4, -2),
( GETDATE(), 5, -6),
( GETDATE()-1, 1, -1),
( GETDATE()-1, 2, 1),
( GETDATE()-1, 3, 1),
( GETDATE()-1, 4, 2),
( GETDATE()-1, 5, -7),
( GETDATE()-2, 1, -2),
( GETDATE()-2, 2, -1),
( GETDATE()-2, 3, -1),
( GETDATE()-2, 4, 2),
( GETDATE()-2, 5, -6),
( GETDATE()-3, 1, -2),
( GETDATE()-3, 2, -1),
( GETDATE()-3, 3, -1),
( GETDATE()-3, 4, 2),
( GETDATE()-3, 5, -2),
( GETDATE()-4, 1, -4),
( GETDATE()-4, 2, 1),
( GETDATE()-4, 3, 1),
( GETDATE()-4, 4, -2),
( GETDATE()-4, 5, -2),
( GETDATE()-5, 1, -4),
( GETDATE()-5, 2, 1),
( GETDATE()-5, 3, 1),
( GETDATE()-5, 4, 2),
( GETDATE()-5, 5, -1),
( GETDATE()-6, 5, -1)
--update #p
-- set bal=-1*bal
-- where cal='2014-09-22' and [ac#]=5
;with mycte as ( Select *
,row_number() Over(Order by [ac#], cal) - row_number() Over(Partition by [ac#], sign(bal) Order by [ac#], cal) rnDelta
from #p)
,mycte1 as (
select * ,
sum(Case when bal< 0 Then 1 Else 0 End) Over(Partition by [ac#], rnDelta Order by [ac#],cal ) cnt
from mycte
SELECT distinct [ac#] from mycte1
Where cnt>=5
drop table #p

Auto Calculation of Calendar and absence day on 2001 screen.

dear gurus
I have half day absent type Z108, subtype of 2001.
i want to default calender days on 2001 screen.
I mean, when user select to create Half day leave/absent on 2001 and subtype z108,
calendar day and absence should be calculated 0.5 automatically.
I have worked with T554L,V_554S_G,V_T554E,V_T554C,T556 but didnt work
at this moment, I am getting this on 2001 screen
Absence hours                8,00
Absence days                 1,00
Calendar days                1,00
when select Z108.
I want above 3 as
Absence hours                4,00
Absence days                 0,50
Calendar days                0,50
kindly help in this scenario.

Hi Monam,
Can yuou check the view V_T554S for your absence type.
The minimum duration and maximum duration in 'Input Chceks' Box should be '000' and '999'.
Minimum duration in days
The Minimum duration in days defines the minimum permitted duration of
    an attendance or absence.
Attendances and absences that are allowed to last for less than one
    workday are assigned the indicator 000. Attendances and absences that
    are to be rejected by the system if they are shorter than one day are
    denoted by an indicator greater than or equal to 001.
Dependencies
In the Unit field, you determine which of the three durations in days
    should be used for the validation.
Thanks & Regards, Swapnil Mishra

Consecutive days of absence

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