Conversion from BitSet to long

Question

Hi!
I want to convert a BitSet to a number in long format, and it shouldn't be very complicated because BitSet uses an internal array of longs, but I don't know how to do it.
Any idea?
Thanks!

Answer 1

platters wrote:
Thanks so much!
I always have a lot of problems with bits! In the reverse mode, that is, from long to BitSet, until now I do:
long data      = ..
String sd = Long.toBinaryString(data);and then I convert the String to BitSet, is that very few efficient??If you want only the first 64 bits, why are you using a BitSet anyway? Converting to and from a long all the time isn't very efficient. You can use the long itself as if it were a 64 bit set. A few getBit(long set, int bit) and setBit(long set, int bit, boolean value) methods are al you have to implement:
boolean getBit(long set, int bit) { // get bit 'bit' from the set
   return (set&(1L<<bit)) != 0;
long setBit(long set, int bit, boolean value) { // return the new set with bit 'bit' (un)set
   if (value)
      return set|(1L<<bit);
   else
      return set&~(1<<bit);
}kind regards,
Jos