Convert columns to rows by a select query

I have a table with 10 columns. Pk is combination of 3 columns, let us say A, B and C. I need a select query which returns 7 rows with four columns each let us say A,B,C and D where D contains the value of non PK column. i.e. for first row, D will contain value of fourth column of the table, for second row, D will contain fifth column of the table and so on.
Please help.

Maybe NOT TESTED!
select col_a,col_b,col_c,column_4 col_d
  from (select col_a,col_b,col_c,col_d,col_e,col_f,col_g,col_h,col_i,col_j
          from the_table
unpivot include nulls (column_4 for source_column in (col_d as 'col_d',
                                                      col_e as 'col_e',
                                                      col_f as 'col_f',
                                                      col_g as 'col_g',
                                                      col_h as 'col_h',
                                                      col_i as 'col_i',
                                                      col_j as 'col_j'
                      )Regards
Etbin

Similar Messages

  • Convert columns to row equivalent to stragg function in oracle sql

    Hi,
    Sorry i forgot my Oracle version :
    SQL> select * from v$version;
    BANNER
    Oracle Database 10g Enterprise Edition Release 10.2.0.3.0 - 64bi
    PL/SQL Release 10.2.0.3.0 - Production
    CORE    10.2.0.3.0      Production
    TNS for 64-bit Windows: Version 10.2.0.3.0 - Production
    NLSRTL Version 10.2.0.3.0 - ProductionI searched in google but i didn't found the solution.
    I looking for a function in discoverer equivalent to stragg sql function.
    Note : stragg function convert columns to rows.
    Thanks
    SELECT   deptno, stragg ('-' || ename)
        FROM emp_test
    GROUP BY deptno;
        DEPTNO STRAGG_STR                                                 
            10 -CLARK-KING-MILLER                                         
            20 -SMITH-FORD-ADAMS-SCOTT-JONES                              
            30 -ALLEN-BLAKE-MARTIN-TURNER-JAMES-WARD                      
    3 rows selected.Edited by: Salim Chelabi on 2010-01-29 08:32

    Hi again,
    *1- I created  my function in my schema.*
    CREATE OR REPLACE TYPE t_string_agg AS OBJECT
      g_string  VARCHAR2(32767),
      STATIC FUNCTION ODCIAggregateInitialize(sctx  IN OUT  t_string_agg)
        RETURN NUMBER,
      MEMBER FUNCTION ODCIAggregateIterate(self   IN OUT  t_string_agg,
                                           value  IN      VARCHAR2 )
         RETURN NUMBER,
      MEMBER FUNCTION ODCIAggregateTerminate(self         IN   t_string_agg,
                                             returnValue  OUT  VARCHAR2,
                                             flags        IN   NUMBER)
        RETURN NUMBER,
      MEMBER FUNCTION ODCIAggregateMerge(self  IN OUT  t_string_agg,
                                         ctx2  IN      t_string_agg)
        RETURN NUMBER
    SHOW ERRORS
    CREATE OR REPLACE TYPE BODY t_string_agg IS
      STATIC FUNCTION ODCIAggregateInitialize(sctx  IN OUT  t_string_agg)
        RETURN NUMBER IS
      BEGIN
        sctx := t_string_agg(NULL);
        RETURN ODCIConst.Success;
      END;
      MEMBER FUNCTION ODCIAggregateIterate(self   IN OUT  t_string_agg,
                                           value  IN      VARCHAR2 )
        RETURN NUMBER IS
      BEGIN
        SELF.g_string := self.g_string || ',' || value;
        RETURN ODCIConst.Success;
      END;
      MEMBER FUNCTION ODCIAggregateTerminate(self         IN   t_string_agg,
                                             returnValue  OUT  VARCHAR2,
                                             flags        IN   NUMBER)
        RETURN NUMBER IS
      BEGIN
        returnValue := RTRIM(LTRIM(SELF.g_string, ','), ',');
        RETURN ODCIConst.Success;
      END;
      MEMBER FUNCTION ODCIAggregateMerge(self  IN OUT  t_string_agg,
                                         ctx2  IN      t_string_agg)
        RETURN NUMBER IS
      BEGIN
        SELF.g_string := SELF.g_string || ',' || ctx2.g_string;
        RETURN ODCIConst.Success;
      END;
    END;
    SHOW ERRORS
    CREATE OR REPLACE FUNCTION string_agg (p_input VARCHAR2)
    RETURN VARCHAR2
    PARALLEL_ENABLE AGGREGATE USING t_string_agg;
    SHOW ERRORS
    *2- I ran my query in my schema with sqlplus.*
    SELECT deptno,ename,sal, string_agg(ename)over(partition by deptno) AS employees
    FROM   emp_test
    order by deptno;
        DEPTNO ENAME             SAL EMPLOYEES                                        
            10 CLARK            2450 CLARK,KING,MILLER                                
            10 KING             5000 CLARK,KING,MILLER                                
            10 MILLER           1300 CLARK,KING,MILLER                                
            20 JONES            2975 JONES,FORD,ADAMS,SMITH,SCOTT                     
            20 FORD             3000 JONES,FORD,ADAMS,SMITH,SCOTT                     
            20 ADAMS            1100 JONES,FORD,ADAMS,SMITH,SCOTT                     
            20 SMITH             800 JONES,FORD,ADAMS,SMITH,SCOTT                     
            20 SCOTT            3000 JONES,FORD,ADAMS,SMITH,SCOTT                     
            30 WARD             1250 WARD,TURNER,ALLEN,JAMES,BLAKE,MARTIN             
            30 TURNER           1500 WARD,TURNER,ALLEN,JAMES,BLAKE,MARTIN             
            30 ALLEN            1600 WARD,TURNER,ALLEN,JAMES,BLAKE,MARTIN             
            30 JAMES             950 WARD,TURNER,ALLEN,JAMES,BLAKE,MARTIN             
            30 BLAKE            2850 WARD,TURNER,ALLEN,JAMES,BLAKE,MARTIN             
            30 MARTIN           1250 WARD,TURNER,ALLEN,JAMES,BLAKE,MARTIN             
    14 rows selected.
    *3- I import this function in discoverer administration*
    4- My problem :When i use the function string_agg(ename)over(partition by deptno) in discover deskto i got the error you can't use over in this place.
    Any ideas.
    Thank in advance.
    Regards Salim.

  • How to get number of rows return in SELECT query

    i'm very new in java, i have a question:
    - How to get number of rows return in SELECT query?
    (i use SQL Server 2000 Driver for JDBC and everything are done, i only want to know problems above)
    Thanks.

    make the result set scroll insensitve, do rs.last(), get the row num, and call rs.beforeFirst(), then you can process the result set like you currently do.
             String sql = "select * from testing";
             PreparedStatement ps =
              con.prepareStatement(sql,ResultSet.TYPE_SCROLL_INSENSITIVE,ResultSet.CONCUR_READ_ONLY);
             ResultSet rs = ps.executeQuery();
             rs.last();
             System.out.println("Row count = " + rs.getRow());
             rs.beforeFirst();~Tim
    NOTE: Ugly, but does the trick.

  • Needs  help to retrive the last row in a  select query without using rownum

    Hi ,
    i need to retrive the last row from the select sub query without using rownum.
    is there any other way to retrive the last row other than the below query.
    is that the ROWNUM=1 will always retrive the 1 row of the select query ?
    select from*
    *(select ename from employee where dept_id=5 order by desc) where rownum=1;*
    Please advise.
    thanks for your help advance,
    regards,
    Senthur

    957595 wrote:
    Actually my problem is ithat while selecting the parents hiearchy of the child data using
    CONNECT BY PRIOIR query
    I need the immediate parent of my child data.
    For example my connect BY query returns
    AAA --- ROOT
    BBB --PARENT -2
    CCC --PARENT-1
    DDD IS my input child to the connect by query
    Immediate parent of my child data "DDD" ---> CCC(parent -1)
    i want the data "CCC" from the select query,for that i am taking the last row of the query with rownum.
    I got to hear that using ROWNUM to retrive the data will leads to some problem.It is a like a magic number.I am not sure what the problem will be.
    So confusing with using this rownum in my query.
    Please advice!!!It's not quite clear what you're wanting, but perhaps this may help?
    you can select the PRIOR values to get the parent details if you want...
    SQL> ed
    Wrote file afiedt.buf
      1  select empno, lpad(' ',(level-1)*2,' ')||ename as ename, prior empno as mgr
      2  from emp
      3  connect by mgr = prior empno
      4* start with mgr is null
    SQL> /
         EMPNO ENAME                                 MGR
          7839 KING
          7566   JONES                              7839
          7788     SCOTT                            7566
          7876       ADAMS                          7788
          7902     FORD                             7566
          7369       SMITH                          7902
          7698   BLAKE                              7839
          7499     ALLEN                            7698
          7521     WARD                             7698
          7654     MARTIN                           7698
          7844     TURNER                           7698
          7900     JAMES                            7698
          7782   CLARK                              7839
          7934     MILLER                           7782
    14 rows selected.(ok, not the best of examples as the mgr is already known for a row, but it demonstrates you can select prior data)

  • To convert columns into row

    Hi All,
    I need help in building view which actually can show columns data as row.
    e.g.
    row is as follows
    Name Age Salary
    ABC 25 10000
    BBC 28 12000
    The above tables data I want to get as
    Name ABC BBC
    Age 25 28
    Salary 10000 12000
    Thanks in advance.

    Even if I don't really understand such requirement, I wrote some times ago such function to play around that :
    Re: Converting Columns into rows
    Nicolas.

  • Need help with query for converting columns to rows

    Hello,
    I know this is a very common question asked in the forum. I have searched regading this, i did find some threads, but i was not able to achieve what i require from the answers posted. So anybody please help me.
    I have a table which is having multiple columns as follows:
    Insert into table_1 (X,Y,Z,A,B,C,D,E,F,G,H,I) values (0,0,2,0,0,1,3,0,0,0,0,0);I want to convert the result into a two column, multiple rows i.e., I want the result as follows:
    Col1 Col2
    X      0
    Y     0
    Z      2
    A     0
    B     0
    C     1
    D     3
    E     0
    F     0
    G     0
    H     0
    I      0Please anybody help me in writing the query for this..

    Is this what you are expecting:
    SQL> WITH T AS
      2  (
      3  SELECT 0 X, 0 Y, 2 Z, 0 A, 0 B, 1 C, 3 D, 0 E, 0 F, 0 G, 0 H, 0 I FROM DUAL
      4  )
      5  SELECT  'X' col1, X col2 FROM T
      6  UNION ALL
      7  SELECT  'Y' col1, Y col2 FROM T
      8  UNION ALL
      9  SELECT  'Z' col1, Z col2 FROM T
    10  UNION ALL
    11  SELECT  'A' col1, A col2 FROM T
    12  UNION ALL
    13  SELECT  'B' col1, B col2 FROM T
    14  UNION ALL
    15  SELECT  'C' col1, C col2 FROM T
    16  UNION ALL
    17  SELECT  'D' col1, D col2 FROM T
    18  UNION ALL
    19  SELECT  'E' col1, E col2 FROM T
    20  UNION ALL
    21  SELECT  'F' col1, F col2 FROM T
    22  UNION ALL
    23  SELECT  'G' col1, G col2 FROM T
    24  UNION ALL
    25  SELECT  'H' col1, H col2 FROM T
    26  UNION ALL
    27  SELECT  'I' col1, I col2 FROM T
    28  /
    C       COL2                                                                   
    X          0                                                                   
    Y          0                                                                   
    Z          2                                                                   
    A          0                                                                   
    B          0                                                                   
    C          1                                                                   
    D          3                                                                   
    E          0                                                                   
    F          0                                                                   
    G          0                                                                   
    H          0                                                                   
    C       COL2                                                                   
    I          0                                                                   
    12 rows selected.

  • Converting Column to Rows

    Hello,
    I am trying to build and SQL to convert columns from multiple rows to the all rows - see below test data and result expected:
    CREATE TABLE XX_TEST(NAME VARCHAR2(10),A1 VARCHAR2(10),A2 VARCHAR2(10), A3 VARCHAR2(10),A4 VARCHAR2(10),A5 VARCHAR2(10));
    INSERT INTO XX_TEST VALUES('LIST','A','B','C','D','E');
    INSERT INTO XX_TEST VALUES('L1','1',NULL,'3',NULL,NULL);
    INSERT INTO XX_TEST VALUES('L2','1','5','4',NULL,NULL);
    COMMIT
    SELECT * FROM XX_TEST;
    Result expected:
    NAME is Column from table XX_TEST but COLUMN and VALUE are the columns converted to rows-
    NAME COLUMN VALUE
    L1 A1 1
    L1 A2 NULL
    L1 A3 3
    L1 A4 NULL
    L1 A5 NULL
    L2 A1 1
    L2 A2 5
    L2 A3 4
    L2 A4 NULL
    L2 A5 NULL
    Thanks
    BS

    Hi,
    Thanks for posting the sample data in such a useful form!
    Whenever you post a question, you should always say what version of Oracle you're using, too.
    Displaying multiple columns from one row as one column on multiple rows is called Unpivoting .
    In Oracle 11, you can use the SELECT ... UNPIVOT feature to do that.
    In any version of Oracle, you can cross-join your table to a Counter that has as many rows as your original table has columns to be unpivoted.
    In this problem, we need a self-join of the unpivoted data, to join the rows with name='LIST' to every other row.
    WITH     cntr     AS
         SELECT     LEVEL     AS n
         FROM     dual
         CONNECT BY     LEVEL     <= 5
    ,     unpivoted_xx_test     AS
         SELECT     x.name
         ,     'A' || c.n     AS col
         ,     CASE  c.n
                   WHEN 1     THEN x.a1
                   WHEN 2     THEN x.a2
                   WHEN 3     THEN x.a3
                   WHEN 4     THEN x.a4
                   WHEN 5     THEN x.a5
              END          AS val
         FROM          cntr     c
         CROSS JOIN     xx_test     x
    SELECT       u.name
    ,       u.col
    ,       l.val          AS val1
    ,       u.val          AS val2
    FROM       unpivoted_xx_test     l
    JOIN       unpivoted_xx_test     u  ON     l.col     = u.col
    WHERE       l.name     =  'LIST'
    AND       u.name     != 'LIST'
    ORDER BY  name
    ,       col
    ;Output:
    NAME       COL VAL1       VAL2
    L1         A1  A          1
    L1         A2  B
    L1         A3  C          3
    L1         A4  D
    L1         A5  E
    L2         A1  A          1
    L2         A2  B          5
    L2         A3  C          4
    L2         A4  D
    L2         A5  EThe query above uses some features that were new in Oracle 9, but the basic strategy will work in earlier versions.
    If your columns don't have such regular names (A1, A2, A3, ...) then you can use another CASE expression to derive unpivoted_xx_test.col.

  • How to convert column to row in 10g  and calculate the count

    876602 wrote:
    Hi ,
    i need to convert the column to row in my DB 10g , i cant use the Decode method because i have about 2000 items in MDN column
    this is sample of my date ,
    MDN             Date
    5C4CA98EABA3     20111205235240
    5C4CA98EABA3     20110925121833
    5C4CA98EABB0     20111025103700
    5C4CA98EABB0     20111124103700
    5C4CA98EABB5     20111030175717
    5C4CA98EABB8     20110925142653
    5C4CA98EABB8     20111126175853i need the result to be ,
    MDN             Date                                   count
    5C4CA98EABA3     20111205235240 ;  20110925121833    2
    5C4CA98EABB0     20111025103700 ;  20111124103700    2
    5C4CA98EABB5    20111030175717                      1
    5C4CA98EABB8   20110925142653 ; 20111126175853       2any help please ,
    Edited by: 876602 on 15/12/2011 01:33 ص

    SQL> with t as
      2  (
      3  select '5C4CA98EABA3' MDN ,'20111205235240' Dte  from dual
      4  union all
      5  select '5C4CA98EABA3','20110925121833' from dual
      6  union all
      7  select '5C4CA98EABB0','20111025103700' from dual
      8  union all
      9  select '5C4CA98EABB0','20111124103700' from dual
    10  union all
    11  select '5C4CA98EABB5','20111030175717' from dual
    12  union all
    13  select '5C4CA98EABB8','20110925142653' from dual
    14  union all
    15  select '5C4CA98EABB8','20111126175853' from dual
    16  )
    17  select mdn,ltrim(sys_connect_by_path(dte,';'),';') s,rw as "count"
    18  from
    19  (
    20  select mdn,dte,row_number() over(partition by mdn order by mdn) rw
    21  from t
    22  )
    23  where connect_by_isleaf = 1
    24  start with rw = 1
    25  connect by prior rw = rw-1
    26  and prior mdn = mdn
    27  ;
    MDN          S                                                                                     count
    5C4CA98EABA3 20111205235240;20110925121833                                                             2
    5C4CA98EABB0 20111025103700;20111124103700                                                             2
    5C4CA98EABB5 20111030175717                                                                            1
    5C4CA98EABB8 20110925142653;20111126175853                                                             2

  • How to convert columns to rows

    I have 70 columns and I need to convert them into rows. Please help!
    Currently, it is showing as listed below
    message 1 message 2 message 3 message 4 message 5 .......... message 70
    system 1 20 10 40 60 100
    system 2 40 30 50 80 110
    system 3 60 60 70 90 120
    The desire output
    system 1 system 2 system 3
    message 1 20 40 60
    message 2 10 30 60
    message 3 40 50 70
    message 70

    Something like...
    SQL> ed
    Wrote file afiedt.buf
      1  select decode(rn,1,'Empno :'||empno
      2                  ,2,'Ename ('||empno||') :'||ename
      3                  ,3,'Job ('||empno||') :'||job
      4               ) as col
      5  from emp
      6       cross join (select rownum rn from dual connect by rownum <= 3)
      7* order by empno, rn
    SQL> /
    COL
    Empno :7369
    Ename (7369) :SMITH
    Job (7369) :CLERK
    Empno :7499
    Ename (7499) :ALLEN
    Job (7499) :SALESMAN
    Empno :7521
    Ename (7521) :WARD
    Job (7521) :SALESMAN
    Empno :7566
    Ename (7566) :JONES
    Job (7566) :MANAGER
    Empno :7654
    Ename (7654) :MARTIN
    Job (7654) :SALESMAN
    Empno :7698
    Ename (7698) :BLAKE
    Job (7698) :MANAGER
    Empno :7782
    Ename (7782) :CLARK
    Job (7782) :MANAGER
    Empno :7788
    Ename (7788) :SCOTT
    Job (7788) :ANALYST
    Empno :7839
    Ename (7839) :KING
    Job (7839) :PRESIDENT
    Empno :7844
    Ename (7844) :TURNER
    Job (7844) :SALESMAN
    Empno :7876
    Ename (7876) :ADAMS
    Job (7876) :CLERK
    Empno :7900
    Ename (7900) :JAMES
    Job (7900) :CLERK
    Empno :7902
    Ename (7902) :FORD
    Job (7902) :ANALYST
    Empno :7934
    Ename (7934) :MILLER
    Job (7934) :CLERK
    42 rows selected.

  • Converting columns into rows

    Dear all....I need to convert all columns into rows in a table. For example table has following columns:
    Emp_Cod........Val1......Val2......Val3
    1 a b c
    Now I wish that each column should display as a value like:
    Emp_Cod........Val1
    1 a
    1 b
    1 c
    Now the one way to solve this job is to write a union statement for each column but for this I'll have to write equal number of select statements as there are columns.
    What I need that is there anyway to write minimum code for this job, is there any alternate way???

    SQL> with t as(select 1 emp_code, 'a' val1, 'b' val2, 'c' val3 from dual)
      2  select*from t unpivot(v for c in(val1,val2,val3));
    EMP_CODE  C     V                                                      
            1  VAL1  a                                                      
            1  VAL2  b                                                      
            1  VAL3  c                                                      
    SQL> col COLUMN_VALUE for a20
    SQL> with t as(select 1 emp_code, 'a' val1, 'b' val2, 'c' val3 from dual)
      2  select*from t,table(sys.odcivarchar2list(val1,val2,val3));
    EMP_CODE  V  V  V  COLUMN_VALUE                                        
            1  a  b  c  a                                                   
            1  a  b  c  b                                                   
            1  a  b  c  c                                                   

  • How to convert column to row in 10g

    Hi ,
    i need to convert the column to row in my DB 10g , i cant use the Decode method because i have about 2000 items in MDN column
    this is sample of my date ,
    MDN             Date
    5C4CA98EABA3     20111205235240
    5C4CA98EABA3     20110925121833
    5C4CA98EABB0     20111025103700
    5C4CA98EABB0     20111124103700
    5C4CA98EABB5     20111030175717
    5C4CA98EABB8     20110925142653
    5C4CA98EABB8     20111126175853i need the result to be ,
    MDN             Date
    5C4CA98EABA3     20111205235240 ;  20110925121833 
    5C4CA98EABB0     20111025103700 ;  20111124103700
    5C4CA98EABB5    20111030175717
    5C4CA98EABB8   20110925142653 ; 20111126175853any help please ,
    Edited by: 876602 on 15/12/2011 01:33 ص

    Note the name of this forum is "SQL Developer *(Not for general SQL/PLSQL questions)*", so only for issues with the SQL Developer tool. Please post these questions under the dedicated {forum:id=75} forum.
    Regards,
    K.

  • Converting columns to row

    Hi,
    I have 6 columns and 4 rows and i want to convert it into 6 rows and 4 columns and want to display in table control.
    plz help me in this ....

    Hi Kinjal,
       Question is not clear. You want to change the internal table values with 6 columns & 4 rows to 4 columns & 6 rows?
    If my understanding is correct, check the bleow logic:
    loop at itab1.
    case sy-tabix.
      when 1.
       itab2-c1 = itab1-c1.
       append itab2.
       itab2-c1 = itab1-c2.
       append itab2.
       itab2-c1 = itab1-c3.
       append itab2.
       itab2-c1 = itab1-c4.
       append itab2.
       itab2-c1 = itab1-c5.
       append itab2.
       itab2-c1 = itab1-c6.
       append itab2.
    when 2.
      itab2-c2 = itab1-c1.
      modify itab2 transporting c2 index 1.
      itab2-c2 = itab1-c2.
      modify itab2 transporting c2 index 2.
      itab2-c2 = itab1-c3.
      modify itab2 transporting c2 index 3.
      itab2-c2 = itab1-c4.
      modify itab2 transporting c2 index 4.
      itab2-c2 = itab1-c5.
      modify itab2 transporting c2 index 5.
      itab2-c2 = itab1-c6.
      modify itab2 transporting c2 index 6.
    when 3.
       itab2-c3 = itab1-c1.
      modify itab2 transporting c3 index 1.
    when 4.
       itab2-c4 = itab1-c1.
      modify itab2 transporting c4 index 1.
    Endloop.
    Finally you will get 6 rows with 4 coulmns.

  • How do I get last 15 rows from a select query

    Hello,
    I am writing a query, and I need to filter the last 15 rows of from the select query.
    For example: Select id, name,join_date from emp order by join_date;
    So I need to get the last 15 rows from emp table so that we can who are the last 15 employees joined the organization. I want to show the result in ascending order, otherwise I would have taken first 15 rows with order by clause as descinding order.
    Thanks in advance,
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