Convert comma separated string in rows

Dear Gurus,
I want to convert comma separated string in rows so as to insert in collection.
e.g. string 1234,2323,23232,2343,34234
Above string should be converted in rows so as to insert in table or collection
Thanks in advance
Sanjeev

Or slight variation...
SQL> ed
Wrote file afiedt.buf
1 with t as (select '1234,2323,23232,2343,34234' as txt from dual)
2 --
3 select REGEXP_SUBSTR (txt, '[^,]+', 1, level)
4 from t
5* connect by REGEXP_SUBSTR (txt, '[^,]+', 1, level) is not null
6 /
REGEXP_SUBSTR(TXT,'[^,]+',
1234
2323
23232
2343
34234... so it doesn't have to work out how many levels it needs to do, it just keeps going until it get's a no-value (of course that assumes that there is always a value between each comma)

Similar Messages

Converting comma separated string into rows

for my procedure varchar2 is i/p paramter. i will get this i/p from java. this string value is like 'VTP,VR','VM'.
i want to split taht string into rows ie o/p will be
VTR
VR
VM.
how to do this.

Hi,
As always, the solution depends on your data, your requirements, and you Oracle version.
Here's one way:
-- Simulating Java input with a bind variable:
VARIABLE str VARCHAR2 (100)
EXEC     :str := 'VTP,VR,VM';
SELECT LEVEL AS n
,       REGEXP_SUBSTR ( :str
                      , '[^,]+'
                      , 1
                      , LEVEL
                      ) AS str_part
FROM     dual
CONNECT BY LEVEL <= 1 + REGEXP_COUNT (:str, ',')
I'm just guessing that your original string doesn't include single-quotes after VR or before VM. If it does, you can use TRIM to remove them from the string passed back by REGEXP_SUBSTR.

Comma separated string in rows

Hi All,
I have one table
select * from abcd;
No err
1    rishi,rahul
2    rishi,ak
I want output like:
No ERR
1 rishi
1 rahul
2 rishi
2 ak
i am using the below query for this:
select no,regexp_substr(err,'[^,]+', 1, level) from abcd
connect by regexp_substr(err, '[^,]+', 1, level) is not null
but this query is giving me output:
1
rishi
1
rahul
2
ak
2
rishi
1
rahul
2
ak
if i am using distinct then only desired output is coming.
select distinct no,regexp_substr(err,'[^,]+', 1, level) from abcd
connect by regexp_substr(err, '[^,]+', 1, level) is not null
but i don't want to use distinct because my table has millions of rows and err contains comma separated varchar(6000);
please help me.

Something like this?
SQL> ed
Wrote file afiedt.buf
1 WITH table_x AS(
2    SELECT 1 id, 'rishi,rahul' str FROM dual UNION ALL
3    SELECT 2 id, 'rishi,ak' str FROM dual
4 )
5 SELECT id,
6             REGEXP_SUBSTR (str,
7                            '[^,]+',
8                            1,
9                            LEVEL)
10             --LEVEL,
11             --SYS_GUID ()
12        FROM table_x
13 CONNECT BY     LEVEL <= LENGTH (REGEXP_COUNT (str, ',')) +1
14             AND PRIOR id = id
15             AND PRIOR Sys_Guid() IS NOT NULL
16*   ORDER BY id, LEVEL
SQL> /
        ID REGEXP_SUBS
         1 rishi
         1 rahul
         2 rishi
         2 ak
Trick here is: the usage of SYS_GUID() i.e. System Global Unique Identifier.
Alternative to this, can also use DBMS_RANDOM.value() here.
Read more here - https://forums.oracle.com/thread/2526535
HTH
-- Ranit

Need to Convert Comma separated data in a column into individual rows from

Hi,
I need to Convert Comma separated data in a column into individual rows from a table.
Eg: JOB1 SMITH,ALLEN,WARD,JONES
OUTPUT required ;-
JOB1 SMITH
JOB1 ALLEN
JOB1 WARD
JOB1 JONES
Got a solution using Oracle provided regexp_substr function, which comes handy for this scenario.
But I need to use a database independent solution
Thanks in advance for your valuable inputs.
George

Go for ETL solution. There are couple of ways to implement.
If helps mark

Comma separated column into rows for each value

experts,
I have a two column table. The second column has comma separated string values. How can I put the values separate for each comma separated and make one row for each value?
example,
column1 |   StringColumn
s1          |   test, joy, happy
s2          | USA, England, India
I want the result to be like below
column1   |    StringColumn
s1            |      test
s1            |      joy
s1            |      happy
s2            |     USA
s2            |     England
s2            |     India
thanks in advance
ebro

Hello ebro,
See the following for a possible solution:
http://gallery.technet.microsoft.com/scriptcenter/Convert-Small-CSV-Value-to-ffc142ff
Olaf Helper
[ Blog] [ Xing] [ MVP]

MODEL clause to process a comma separated string

Hi,
I'm trying to parse a comma separated string using SQL so that it will return the parsed values as rows;
eg. 'ABC,DEF GHI,JKL' would return 3 rows;
'ABC'
'DEF GHI'
'JKL'
I'm thinking that I could possibily use the MODEL clause combined with REGULAR expressions to solve this as I've already got a bit of SQL which does the opposite ie. turning the rows into 1 comma separated string;
select id, substr( concat_string, 2 ) as string
from (select 1 id, 'ABC' string from dual union all select 1, 'DEF GHI' from dual union all select 1, 'JKL' from dual)
model
return updated rows
partition by ( id )
dimension by ( row_number() over (partition by id order by string) as position )
measures ( cast(string as varchar2(4000) ) as concat_string )
rules
upsert
iterate( 1000 )
until ( presentv(concat_string[iteration_number+2],1,0) = 0 )
( concat_string[0] = concat_string[0] || ',' || concat_string[iteration_number+1] )
order by id;
Can anyone give me some pointers how to parse the comma separated string using regexp and create as many rows as needed using the MODEL clause?

Yes, you could do it without using ITERATE, but FOR ... INCREMENT is pretty much same loop. Couple of improvements:
a) there is no need for CHAINE measure
b) there is no need for CASE in RULES clause
c) NVL can be applies on measures level
with t as (select 1 id, 'ABC,DEF GHI,JKL,DEF GHI,JKL,DEF GHI,JKL,DEF,GHI,JKL' string from dual
   union all
    select 2,'MNO' string from dual
    union all
   select 3,null string from dual
SELECT id,
         string
FROM   T
   MODEL
    RETURN UPDATED ROWS
    partition by (id)
    DIMENSION BY (0 POSITION)
    MEASURES(
             string,
             NVL(LENGTH(REGEXP_REPLACE(string,'[^,]+','')),0)+1 NB_MOT
    RULES
     string[FOR POSITION FROM 1 TO NB_MOT[0] INCREMENT 1] = REGEXP_SUBSTR(string[0],'[^,]+',1,CV(POSITION))
SQL> with t as (select 1 id, 'ABC,DEF GHI,JKL,DEF GHI,JKL,DEF GHI,JKL,DEF,GHI,JKL' string from dual
2     union all
3      select 2,'MNO' string from dual
4      union all
5     select 3,null string from dual
6      )
7   SELECT id,
8           string
9    FROM   T
10     MODEL
11      RETURN UPDATED ROWS
12      partition by (id)
13      DIMENSION BY (0 POSITION)
14      MEASURES(
15               string,
16               NVL(LENGTH(REGEXP_REPLACE(string,'[^,]+','')),0)+1 NB_MOT
17              )
18      RULES
19      (
20       string[FOR POSITION FROM 1 TO NB_MOT[0] INCREMENT 1] = REGEXP_SUBSTR(string[0],'[^,]+',1,CV(POSITION))
21      )
22 /
        ID STRING
         1 ABC
         1 DEF GHI
         1 JKL
         1 DEF GHI
         1 JKL
         1 DEF GHI
         1 JKL
         1 DEF
         1 GHI
         1 JKL
         2 MNO
        ID STRING
         3
12 rows selected.
SQL> SY.

[svn:osmf:] 15983: Updating VideoQoSPluginMetadataSynthesizer to create comma separated string values for all of the available keys .

Revision: 15983
Revision: 15983
Author:   [email protected]
Date:     2010-05-10 04:47:46 -0700 (Mon, 10 May 2010)
Log Message:
Updating VideoQoSPluginMetadataSynthesizer to create comma separated string values for all of the available keys.
Modified Paths:
    osmf/trunk/apps/samples/plugins/VideoQoSPlugin/src/org/osmf/qos/VideoQoSPluginMetadataSyn thesizer.as

Rob:
"but the sad thing is, that managers will most likely respond with a "This used to be fast in MSSQL, but now it isn't any more in Oracle. Oracle is so slow ...""
On the bright side, it sounds like most of the database calls are implemented as stored procedures, so there is an opportunity to do it right (in Oracle terms) in the stored procedures.
I did a similar conversion a while back, converting bad SQLServer procedures to good Oracle procedures. Everyone said "Oracle is much faster that SQLServer"
John

Look Up For Comma Separated Strings

Hi,
How to look up for comma separated string from livecycle forms manager ??
Plz gimme an idea on this.
Raghava Kumar V.S.S.

Hi
My point is that the more detailed you ask your question, the more likely you are to get an answer.
Those of us who monitor these newsgroups also appreciate you doing as much of your own research as possible, before asking us for help - we're more likely to spend our own (personal and valuable) time helping you, if we know that you've spent your own time doing research, and you've still not been able to solve the problem.
I look forward to your next question :-)
Howard

Passing comma separated string to stored procedure

Hi,
There is thread with same query I created earlier and that was answered. That solution worked if I pass comma separated string containing IDs. But due to changes in the logic, I have to pass usernames instead of userIDs. I tried to modify the solution provided to use with this.
Following the link to previous post :
Re: Passing comma separated string to stored procedure
------Package-------
TYPE refcurQID IS REF CURSOR;
TYPE refcurPubs IS REF CURSOR;
procedure GetAllPersonalQueue (p_user_name in nvarchar2, TestQID OUT Test.refcurQID
, TestPubs OUT Test.refcurPubs);
------Package-------
------Package Body-------
PROCEDURE GetAllPersonalQueue (p_user_name in nvarchar2, TestQID OUT Test.refcurQID, TestPubs OUT Test.refcurPubs) as
BEGIN
Open TestQID for
select id from cfq where name in (p_user_name);
Open TestPubs for
SELECT qid FROM queues WHERE qid in(
select id from cfq where name in (p_user_name));
END GetAllPersonalQueue;
------Package Body-------
Thanks in advance
Aditya

Hi,
I modified the query as per the solution provided by isotope, after which the logic changed and I am passing username instead of userID in comma separated string.
Following is the changes SP, which does not throw any error, but no data is returned.
PROCEDURE GetAllPersonalQueue (p_user_name in nvarchar2, TestQID OUT Test.refcurQID, TestPubs OUT Test.refcurPubs
) is
--local variable
strFilter varchar2(100);
BEGIN
Open TestQID for
select id, name from cfq where name in
select regexp_substr(p_user_name||',','[a-z]+[0-9]+',1,level)
from dual
connect by level <= (select max(length(p_user_name)-length(replace(p_user_name,',')))+1
from dual)
Open TestPubs for
SELECT qid FROM queues WHERE qid in(
select id from cfq where name in
select regexp_substr(p_user_name||',','[a-z]+[0-9]+',1,level)
from dual
connect by level <= (select max(length(p_user_name)-length(replace(p_user_name,',')))+1
from dual)
END GetAllPersonalQueue;
Edited by: adityapawar on Feb 27, 2009 8:38 AM

Using a comma seprated string as rows

i hv a column in which i store comma seprated name, i have to show them as rows in a report..
plz help

As with most things, it depends greatly on your Oracle version (you should always post this information).
In release 11 here's a neat method.
http://laurentschneider.com/wordpress/2009/07/select-from-column-separated-list.html
In release 10 there's REGEXP
http://nuijten.blogspot.com/2009/07/splitting-comma-delimited-string-regexp.html
And it looks like you've been given a pre-10 answer already.

Read/Insert values from comma separated string

I need Stored procedure to insert values in table using comma separated values from string based on algorithm as below.
There are two table Mtable(Parent table), Ctable(Child table).
Value passed from String can be like_
1,A001,R1,C1,R2,C2,R3,C3
2,A002,X1,Y1,X2,Y2
3,A003,A1,B1,A2,B2,A3,B3
1)For line1 I need to insert in Mtable values(1,A001)
And in ctable I need to insert 3 rows with values
     ROW1     (1,R1,C1)
     ROW2     (1,R2,C2)
     ROW3     (1,R3,C3)
2)For line2 I need to insert in Mtable values(2,A002)
And in ctable I need to insert 2 rows with values
     ROW1     (2,X1,Y1)
     ROW2     (2,X2,Y2)
Please help me to overcome this.
Thanks

create table t as
select '1,A001,R1,C1,R2,C2,R3,C3' s from dual union
select '2,A002,X1,Y1,X2,Y2' from dual union
select '3,A003,A1,B1,A2,B2,A3,B3' from dual
Table created
select substr(s,1,instr(s,',')-1),
substr(s,instr(s,',',1,2*i)+1,instr(s||',',',',1,2*i+1)-instr(s,',',1,2*i)-1),
substr(s,instr(s,',',1,2*i+1)+1,instr(s||',',',',1,2*i+2)-instr(s,',',1,2*i+1)-1
from t, (select 1 i from dual union select 2 from dual union select 3 from dual)
where instr(s,',',1,2*i+1)>0
order by 1,i
SUBSTR(S,1,INSTR(S,',')-1) SUBSTR(S,INSTR(S,',',1,2*I)+1, SUBSTR(S,INSTR(S,',',1
1                          R1                             C1
1                          R2                             C2
1                          R3                             C3
2                          X1                             Y1
2                          X2                             Y2
3                          A1                             B1
3                          A2                             B2
3                          A3                             B3
8 rows selected

Remove Duplicates From Comma Separated String

Hi,
I have one Column which contains duplicates values with comma separated.
Customer ID
5,5,5,5,6,6,5,5,5,6,7,4,1,2,1,4,7,2
I wrote this:
select REGEXP_REPLACE('5,5,5,5,6,6,5,5,5,6,7,4,1,2,1,4,7,2', '(^|,)([^,]*)(,\2)+','\1\2') from dual;
5,6,5,6,7,4,1,2,1,4,7,2
But it eliminates only continuous elements.
I want out put like:
5,6,7,4,1,2
Please help.
Thanks.
Amit
Edited by: 987565 on Feb 12, 2013 4:02 AM

Thanks Purvesh,
While testing with real data, it is ignoring some values. I didn't understand why it happening.
with data as
select '5714,5714,5714,5714,5714,5714,5714,5714,5714,5714,5714,5714,5668,5716,5714,5714,5714,5714,5714,5714,5714,5714,5714,5714,5714,5714,5668,5716' col from dual
select ltrim(max(sys_connect_by_path(col, ',')) keep (dense_rank last order by rn - 1), ',') col
from (
select col, row_number() over (order by 1) rn
from (
select distinct regexp_substr(col, '[^,]+', 1, level) col
from data
connect by level <= length(col) - length(replace(col, ','))
start with rn = 1
connect by prior rn = rn - 1;
Result I got is:
5714,5714,5716
My Real Query is like that:
declare
cursor c1 is
select o.id id
from order o;
v_char varchar2(200) := '';
begin
for a1 in c1 loop
with data as
select o.cust_id as col into v_char
from order o
where o.id = a1.id
select ltrim(max(sys_connect_by_path(col, ',')) keep (dense_rank last order by rn - 1), ',') col
from (
select col, row_number() over (order by 1) rn
from (
select distinct regexp_substr(col, '[^,]+', 1, level) col
from data
connect by level <= length(col) - length(replace(col, ','))
start with rn = 1
connect by prior rn = rn - 1;
SYS.dbms_output.put_line(v_char);
end loop;
end;
Later, i will update same cust_id with v_char.

Convert comma separated to string into multiple row

Hi,
I have SQL query which will fetch the data like below.
{code}
ID     NAME     CODE
1     A,B          5,2
2     X              10
3     Z               4
{code}
So now i have to split the data like below
{code}
ID     NAME     CODE
1     A               5
1     B               2
2     X              10
3     Z               4
{code}

https://forums.oracle.com/thread/2549548

Inserting the Comma Separated Strings into Table

Hi Seniors,
i had two string and i want to insert the records in the Table COMMENT . In this way.
would u please give some programe to insert the records.
The Data and the Table
( 901,902,903,904 )
( 'hai','nice','good & mail is [email protected] ','excellent and the phone 011-235323' )
comm_id loc_id company_name comments
1      10 901      Hai
2      10 902      nice
3 10      903      good & mail is [email protected]
4      10 904      excellent and the phone 011-235323
Thanks
Seenu

Hi, Seenu,
In Oracle 10 (and up) you can easily split a comma-delimited list using REGEXP_SUBSTR.
INSTR and SUBSTR can do the same thing in any version, but it's more complicated.
See the general instructions below:
/*     How to Split a Delimited String
This shows how to take a single row with a delimited string, such as
     Animal     amoeba,bat,cedusa,dodo
and transform it into multiple rows:
     Animal     1     amoeba
     Animal     2     bat
     Animal     3     cedusa
     Animal     4     dodo
PROMPT     ========== -1. sep_char parameter ==========
VARIABLE     sep_char     VARCHAR2 (10)
EXECUTE     :sep_char := ',';
SELECT     :sep_char     AS sep_char
FROM     dual;
PROMPT     ========== 0. string_test table ==========
DROP TABLE     string_test;
CREATE TABLE     string_test
(     grp_name     VARCHAR2 (10)
,     list_txt     VARCHAR2 (50)
INSERT INTO string_test (grp_name, list_txt) VALUES ('Animal',     'amoeba,bat,cedusa,dodo');
INSERT INTO string_test (grp_name, list_txt) VALUES ('Date',     '15-Oct-1582,16-Oct-2008');
INSERT INTO string_test (grp_name, list_txt) VALUES ('Nothing',     NULL);
INSERT INTO string_test (grp_name, list_txt) VALUES ('Place',     'New York');
INSERT INTO string_test (grp_name, list_txt) VALUES ('Skip',     'Hop,,Jump');
SELECT     *
FROM     string_test
ORDER BY     grp_name;
PROMPT     ========== Q1. Oracle 11 Query ==========
WITH     cntr     AS          -- Requires Oracle 9
(     -- Begin sub-query cntr, to generate n (1, 2, 3, ...)
     SELECT     LEVEL     AS n     -- Requires Oracle 9
     FROM     dual
     CONNECT BY     LEVEL     <= 1 +     (
                         SELECT     MAX ( REGEXP_COUNT (list_txt, :sep_char) )     -- Requires Oracle 11
                         FROM     string_test
)     -- End sub-query cntr, to generate n (1, 2, 3, ...)
SELECT     grp_name
,     n
,     REGEXP_SUBSTR     ( list_txt     -- Requires Oracle 10
               , '[^' || :sep_char || ']'     -- Anything except sep_char ...
                    || '+'               -- ... one or more times
               , 1
               , n
               )     AS item_txt
FROM     string_test
JOIN     cntr                                   -- Requires Oracle 9
ON     n     <= 1 + REGEXP_COUNT (list_txt, :sep_char)     -- Requires Oracle 11
ORDER BY     grp_name
,          n;
/*     Notes:
     REGEXP_SUBSTR (s, '[^,]+', 1, n)
returns the n-th item in a comma-delimited list s.
If there are fewer than n items, it returns NULL.
One or more consecutive characters other than comma make an item, so
'Hop,,Jump' has two items, the second one being 'Jump'.
The sub-query cntr produces a list of integers 1, 2, 3, ..., w
where w is the worst-case (the largest number of items in any list).
This actually counts separators, not items, (e.g., it counts both
commas in 'Hop,,Jump', even though), so the w it produces may be
larger than is really necessary. No real harm is done.
PROMPT     ========== Q2. Possible Problems Fixed ==========
WITH     cntr     AS
(     -- Begin sub-query cntr, to generate n (1, 2, 3, ...)
     SELECT     LEVEL     AS n
     FROM     dual
     CONNECT BY     LEVEL     <= 1 +     (
                         SELECT     MAX ( REGEXP_COUNT (list_txt, :sep_char) )
                         FROM     string_test
)     -- End sub-query cntr, to generate n (1, 2, 3, ...)
SELECT     grp_name
,     n
,     REGEXP_SUBSTR     ( list_txt
               , '[^' || :sep_char || ']'     -- Anything except sep_char ...
                    || '+'               -- ... one or more times
               , 1
               , n
               )     AS item_txt
FROM     string_test
JOIN     cntr          ON n     <= 1 + NVL     ( REGEXP_COUNT (list_txt, :sep_char)     -- Problem (1)
                              , 0
WHERE     REGEXP_SUBSTR     ( list_txt     -- Problem (2)
               , '[^' || :sep_char || ']'     -- Anything except sep_char ...
                    || '+'               -- ... one or more times
               , 1
               , n
               )     IS NOT NULL
OR     list_txt     IS NULL          -- Problems (1) and (2) together
ORDER BY     grp_name
,          n;
     (Possible) Problems and Fixes
(1) If list_txt IS NULL, then REGEXP_COUNT (list_txt, :sep_char)
     returns NULL, the join condition fails, and the output
     contains nothing corresponding to the row from string_test.
     If you want a NULL item to appear in the results, use
     NVL to make sure the expression returns 0 instead of NULL.
(2) If list_txt contains multiple consecutive sep_chars (or if it
     begins or ends with sep_char, then the original query
     will return NULL items. To suppress these, add a WHERE
     clause to test that the item_txt to be displayed IS NOT NULL.
PROMPT     ========== Q3. Oracle 8.1 Query ===========
SELECT     grp_name
,     n
,     SUBSTR     ( list_txt
          , begin_pos
          , end_pos - begin_pos
          )     AS item_txt
FROM     (     -- Begin sub-query to compute begin_pos and end_pos
     SELECT     grp_name
     ,     n
     ,     list_txt
     ,     INSTR     ( :sep_char || list_txt
               , :sep_char
               , 1
               , n
               )     AS begin_pos
     ,     INSTR     ( list_txt || :sep_char
               , :sep_char
               , 1
               , n
               )     AS end_pos
     FROM     string_test
     ,     (     -- Begin sub-query cntr, to generate n (1, 2, 3, ...)
          SELECT     ROWNUM     AS n
          FROM     all_objects
          WHERE     ROWNUM     <= 1 +     (
                         SELECT     MAX     ( LENGTH (list_txt)
                                   - LENGTH (REPLACE (list_txt, :sep_char))
                         FROM     string_test
          )     -- End sub-query cntr, to generate n (1, 2, 3, ...)
          cntr
     WHERE     n     <= 1 +     ( LENGTH (list_txt)
                    - LENGTH (REPLACE (list_txt, :sep_char))
     )     -- End sub-query to compute begin_pos and end_pos
ORDER BY     grp_name
,          n;
/*     Version-Dependent Features and Work-Arounds
The code above, Q3, runs in Oracle 8.1.
The following changes were made to Q1:
(11) REGEXP_COUNT was introduced in Oracle 11.
     In earlier versions, to find the number of sep_chars in list_txt,
     see how much the LENGTH changes when sep_chars are removed.
(10) REGEXP_SUBSTR was introduced in Oracle 10.
     In earlier versions, use INSTR to find where the sep_chars are,
     and use SUBSTR to get the sub-strings between them.
     (Using this technique, 'Hop,,Jump' still contains three items,
     but now item 2 IS NULL and item 3 is 'Jump'.)
(9.a) The WITH-clause was introduced in Oracle 9
     In earlier versions, use in-line views.
(9.b) "CONNECT BY LEVEL < constant" doesn't work in Oracle 8.
     Use ROWNUM from any sufficiently large table or view instead.
(9.c) ANSII join notation (JOIN table_name ON ...) was introduced in Oracle 9
     In earlier versions, join condition go in a WHERE-clause.
*/

Converting comma seperated values in rows

Hi Friends
I have a column in which values are like
col1
1,2,3How do I convert them into the following:
col2
1
2
3Thanks...

darshilm wrote:
Oracle Database 10g Enterprise Edition Release 10.2.0.2.0 - 64bit Production
With the Partitioning, OLAP and Data Mining options
with data as
   select 1 as col1, 'a,b,c' as col2 from dual union all
   select 2, 'd,e,f' from dual
select
   col1,
   regexp_substr(col2, '[^,+]', 1, t.column_value) as split_string
from
   data d,
   table(cast(multiset(select level from dual connect by level <= length(regexp_replace (d.col2, '[^,]+')) + 1) as sys.OdciNumberList)) t
12 /
              COL1 SPLIT
                 1 a
                 1 b
                 1 c
                 2 d
                 2 e
                 2 f
6 rows selected.
Elapsed: 00:00:01.12
ME_XE?
ME_XE?select * from v$version;
BANNER
Oracle Database 10g Express Edition Release 10.2.0.1.0 - Product
PL/SQL Release 10.2.0.1.0 - Production
CORE     10.2.0.1.0     Production
TNS for Linux: Version 10.2.0.1.0 - Production
NLSRTL Version 10.2.0.1.0 - Production
5 rows selected.
Elapsed: 00:00:01.00
ME_XE?

Convert comma separated string in rows

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