Convert Epoch date to Minutes

How to convert epoch date to minutes in CR XI?
Can anyone help?

It's my understanding that Epoch is the number of seconds that have elapsed since 1/1/1970.
So is you want to convert it to a date, the following formula should work.
DateAdd("s", {TableName.EpochDate}, #1/1/1970#)
If all you are wanting to do is convert seconds to minutes, then simply divide by 60
{TableName.EpochDate} / 60
HTH,
Jason

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Convert Epoch Date Time to Date Time format

I am trying to convert Epoch Date time in GMT to Human Readable Date time format in UTC. I used the one below but it returns just the date in GMT but how can get datetime in UTC ?
select To_Char( To_Date( '01.01.1970 06:00:00','DD.MM.YYYY HH24:Mi:Ss') + STARTIME / 86400,'DD.MM.YYYY HH24:Mi:ss') FROM HQ_AVAIL_DATA_RLE;
I refered a couple of forums and applied everything, but still I wouldn't get the timestamp.
Please note that i'm looking for datetime stamp, not just the date.
Thanks in advance!
Edited by: 830754 on Jan 27, 2011 11:18 AM
Edited by: 830754 on Jan 27, 2011 11:19 AM

Works for me. I see date and time (submitted 1000 for STARTTIME):
select To_Char( To_Date( '01.01.1970 06:00:00','DD.MM.YYYY HH24:Mi:Ss') + 1000 / 86400,'DD.MM.YYYY HH24:Mi:ss')
from dual
TO_CHAR(TO_DATE('01
01.01.1970 06:16:40Or do you mean something else?

Converting EPOCH time stamp to time stamp in Oracle

Hi,
I need a help regarding how to convert the epoch Time stamp, to oracle date and time format.
for example,
for epoch time stamp:1204104116656
the time stamp should be :2008-02-13 12:43:00.351
Thanks in Advance
Basil Abraham

Are you sure you've got the right timestamp? Assuming this is a standard unix epoch time stamp with the epoch date starting at 1970-01-01 UTC the interval between 1970-01-01 UTC and 2008-02-13 is 13922 days, but your epoch timestamp divided by the number of miliseconds in a day 1204104116656/(1000*60*60*24) comes out to 13936.390... days a difference of 14 days 9 hours 21 minutes 56 seconds and 656 miliseconds.
Anyway to convert you need to convert your epoch date into an interval and add it to the starting epoch date (as a timestamp):
select to_timestamp_tz('1970-01-01 utc', 'yyyy-mm-dd tzr')+
numtodsinterval(1204104116656/1000,'second') dstamp
from dual;Message was edited by:
Sentinel

How to convert epoch time to datetime in sql*loader Oracle

Hello,
I wan't to question how to convert epoch time to datetime in sql*loader Oracle. I try this script for convert epoch time to datetime in sql*loader, but error:
Record 1: Rejected - Error on table TEMP_TEST_LANGY, column DATADATA.
ORA-01722: invalid number
Record 2: Rejected - Error on table TEMP_TEST_LANGY, column DATADATA.
ORA-01722: invalid number
Record 3: Rejected - Error on table TEMP_TEST_LANGY, column DATADATA.
ORA-01722: invalid number
This is my loader:
LOAD DATA INFILE 'C:\Documents and Settings\Administrator\My Documents\XL_EXTRACT_211\load.csv'
into table TEMP_TEST_LANGY append
FIELDS TERMINATED BY ','
TRAILING NULLCOLS
DATADATA CHAR "TO_DATE('01-JAN-1970','DD-MON-YYYY')+:datadata/86400"
This is my csv file:
79314313.7066667
79314336.2933333
79314214.3466667
This is my table:
CREATE TABLE TEMP_TEST_LANGY
DATADATA DATE
Thanks
Edited by: xoops on Sep 21, 2011 8:56 AM
Edited by: xoops on Sep 21, 2011 8:58 AM

thanks for your answer, but I asked to use sql loader instead of the external table, which so my question is why can not the epochtime converted to datetime, if there is no way to convert a datetime epochtime using sql loader, so I'm required to use the external table. thank you.
This is my error log:
Column Name Position Len Term Encl Datatype
DATADATA FIRST * , CHARACTER
SQL string for column : "TO_DATE('1-Jan-1970 00:00:00','dd-MM-YYYY hh24:mi:ss') + (:DATADATA/60/60/24)"
Record 1: Rejected - Error on table TEMP_TEST_LANGY, column DATADATA.
ORA-01722: invalid number
Record 2: Rejected - Error on table TEMP_TEST_LANGY, column DATADATA.
ORA-01722: invalid number
Record 3: Rejected - Error on table TEMP_TEST_LANGY, column DATADATA.
ORA-01722: invalid number
Edited by: xoops on Sep 21, 2011 12:33 PM

I need a formula to convert a date into an integer (for use in Lookout)

I have a DATA logger with the following:
40001 = 4 (2004)
40002 = 2 (February)
40003 = 5 (5th)
40004 = 13 (1:00pm)
40005 = 12 (12 minutes)
Lookout requires a date that it understands (eg. January 1, 1900).
All I need is a basic formula to convert the date and time.
This formula does not need to be specifically written for Lookout. Just a basic formula that I can do on paper or a calculator.
I can integrate that formula into the Lookout software myself.

Hello Smigman,
First of all, I apologize in advance for not giving you "just the formula." And for the lengthy explanation (had to wait till after work hours), which you are very likely aware of already. I am writing this response in much detail so that it may benefit others.. hopefully And so that we understand the underlying principle involved, which will hopefully help us in building the formula the best way that suits us.
As you have figured out, the data and time in Lookout is represented as a real number. This real number's integer portion represents days, and the decimal portion denotes time. The integer portion is basically the number of days since 01/01/1900. And the decimal portion is the number of seconds since midnight.
So, for instance, if you insert the today() Expression in Lookout, you'll get a integer 38022 (which corresponds to today, Feb. 5th, 2004). In other words, today is the 38022nd day since 01/01/1900. Tomorrow, Feb. 6th 2004, will be 38023 and so on.
The decimal part denotes time. A day has 24*60*60 = 86400 seconds, obviously. So, 1/86400 = 1.15741E-5 roughly represents one second. For instance, 38022.00001157 will give 02/05/2004 00:00:01.
Coming to the formula now, for Time, first convert it to total seconds from midnight. E.g., 5:15:07pm would be (17*60*60) + (15*60) + 7 = 62107 seconds total since midnight. To get the Lookout's decimal part, divide this by 86400.
62107/86400 = 0.71883102
Therefore, 38022.71883102 would now give 02/05/2004 17:15:07. Computing Time is relatively easy.
For the Date -- which is more complicated-- you could keep track of the total number of days either from 01/01/1900, or better still, a more recent day, like say 12/31/2003, which corresponds to 37986. To this reference you will keep adding 1 for each additional day to get the number for the current day. Note, you will have to accomodate leap years (Feb. 29th of this year, for instance).
It's very helpful to have the reference day as the last day of the past year. That can be derived by counting the number of days since 01/01/1900 as follows:
104 years * 365 days = 37960;
+ 1 day for each leap year
A leap year is a year divisible by 4 (and 400 if the year ends with two zeros). There were 26 leap years from 1900 till 2003.
So, 37960 + 26 = 37986. 12/31/2003 is thus represented by 37986.
To get the integer for the Current Date we would first find what day of the year it is. Then add it to the reference day. Feb 5th, is the 36th day of the year. Adding this to 37986, gets us 38022.
In your case you will have to come up with the correct day of the year using registers 40002 and 40003. Not sure if this helped or confused you more.
I tried
Khalid

Converting a Date to a Double. How?

I need to be able to a Date to a double in the "days since 12/30/1899 . fractional part is time format".
This is the format use in OLE 2.0 Automation as well as languages such as Delphi.
Any ideas?

I assume this format (double) is the same format used for a MS date and if this is the case MS uses a base date (zero) of "Dec. 30, 1899 12:00:00 AM.". To take the 12:00:00 AM time into consideration when converting your date you should use a Java base date of "Dec. 29, 1899 23:00:00.000 GMT" or -2209147200000L as a long. Here is the code I use to convert between Java dates (long) and MS dates (double):
import java.util.Date;
public class MSDate extends Date {
   private final static int MILLISECONDS_IN_A_DAY = 86400000;
   private final static long MS_BASE_DATE = -2209147200000L; // December 29, 1899, 23:00:00.000 GMT.
   /** Allocates a MSDate object and initializes it so that it
       represents the time at which it was allocated, measured to the
       nearest millisecond. */
   public MSDate() {
      super();
   /** Allocates a MSDate object and initializes it to represent the
       specified number of milliseconds since the standard base time
       known as "the epoch", namely January 1, 1970, 00:00:00 GMT. */
   public MSDate(long date) {
      super(date);
   /** Allocates a MSDate object using the given MS date. */
   public MSDate(double MSDate) {
      this.setMSDate(MSDate);
   /** Sets this MSDate object to represent the MS date (double) provided. */
   public void setMSDate(double MSDate) {
      double dMilliseconds;
      // Convert MS Date (double) to the number of milliseconds since January 1, 1970, 00:00:00.000 GMT.
      dMilliseconds = MSDate * MILLISECONDS_IN_A_DAY;
      // Add MS's base date.
      dMilliseconds += MS_BASE_DATE;
      super.setTime(Math.round(dMilliseconds));
   /** Returns a MS date (double) that represented by this MSDate object. */
   public double getMSDate() {
      double dMSDate = 0;
      double dMilliseconds;
      // Get the number of milliseconds since January 1, 1970, 00:00:00.000 GMT.
      dMilliseconds = this.getTime();
      // Subtract MS's base date.
      dMilliseconds -= MS_BASE_DATE;
      // Convert milliseconds back to a MS date (double).
      dMSDate = dMilliseconds / MILLISECONDS_IN_A_DAY;
      // Return the MS date.
      return dMSDate;
}The only thing that I have noticed is that MS (VB) doesn't display the milliseconds, so a MS date gets rounded up by one second if your Java date has more then 500 milliseconds.

How can I convert a .dat to a .zip on a Mac?

Hi -
I friend wanted me to update his company's website which runs on a MS Exchange Server/Sharepoint set up. He zipped all the html, jpeg, and assorted text files and attached that zip file to an email. When I received it on my Mac it had been converted to a ".dat" file. He tells me that this is the result of sending a zipped file over the MS Exchange Server mail system to a Mac. (Whatever happened to cross-platform?)
Is there a Mac utility I can use to convert this dat file back to a zip file that I then can open on my Mac?
TIA
Josh

Hello:
This article addresses your issue:
http://docs.info.apple.com/article.html?path=Mail/10.7/en/mlhlp1141.html
Barry

How can i convert the date from M to MM ?

Dear Guru ,
I need to upload my list to SAP table , and in the list , we are using YYYY/M/D format ( Eg. 2010/5/20 , 2010/10/1 ) .
And now i want to convert all date format to YYYY/MM/DD , Is it possibile to do that ?
Here is my code , but it doesn't work . It returned "2009//3//5" format .
data: ld_date_int type datum.
data : test(10) type c.
test = '2009/3/5' .
ld_date_int = test .
WRITE : SY-SUBRC , LD_DATE_int .
Does SAP provide a standard function can convert the date format ?
Thanks .
Best Regards,
Carlos Zhang

Hi Dear
You can try in this way :::
data: ld_date_int type string.
DATA : ld_string TYPE string.
data : test(10) type c,
       ld_res1(4) TYPE c,
       ld_res2(2) TYPE c,
       ld_res3(2) TYPE c.
DATA : ll_res2 TYPE i,
       ll_res3 TYPE i.
test = '2009/03/5' .
ld_date_int = test .
ld_string = strlen( ld_date_int ).
CASE ld_string.
WHEN 10.
   WRITE : SY-SUBRC , LD_DATE_int.
WHEN OTHERS.
    SPLIT ld_date_int at '/' INTO ld_res1 ld_res2 ld_res3 in CHARACTER MODE.
    ll_res2 = strlen( ld_res2 ).
    ll_res3 = strlen( ld_res3 ).
    IF NOT ll_res2 eq 2 and not ll_res3 eq 2.
      CONCATENATE: '0' ld_res2 INTO ld_res2.
      CONCATENATE: '0' ld_res3 INTO ld_res3.
      CONCATENATE ld_res1 '/' ld_res2 '/' ld_res3 INTO ld_date_int.
      WRITE : SY-SUBRC , LD_DATE_int.
    ENDIF.
    IF ll_res2 eq 2 and not ll_res3 eq 2.
      CONCATENATE '0' ld_res3 INTO ld_res3.
      CONCATENATE ld_res1 '/' ld_res2 '/' ld_res3 INTO ld_date_int.
      WRITE : SY-SUBRC , LD_DATE_int.
    ENDIF.
    IF NOT ll_res2 eq 2 and ll_res3 eq 2.
       CONCATENATE: '0' ld_res2 INTO ld_res2.
        CONCATENATE ld_res1 '/' ld_res2 '/' ld_res3 INTO ld_date_int.
         WRITE : SY-SUBRC , LD_DATE_int.
    ENDIF.
ENDCASE.

How can i convert the data from mutiple-table to the other database(MSSQL)?

Dears,
How can i convert the data from mutiple-table to the other database such as MS-SQL?
I have a third party system based on MS-SQL 2000.
Now we want to make a integration between SAP R/3(Oracle) and SQL server.
When my user releases the purchase order in R/3, the application we coded will convert the releated data to the temp database on the SQL server.
But i don't know which tools will help me reach the purpose. BAPI, LSMW, IDoc... ???
Would anybody tell me which way is better and how to do?
Thanks a lot!
Kevin Wang

Hello Kevin,
The question to use which method depend on your detail requirements. If you use BAPI, you need to find which Bapi can provide the data you want. Bapi normally use as a function called by external system. So you need to develop an external program like VB/Java to call this Bapi and move it to SQL. LSMW is use when you want to upload data from an external system to SAP. So it does not serve your requirement. Idoc can be use to export data to an external system. Again like Bapi, you need to find what Idoc can provide the data you want. However, it does not any programming from the external system. If I were you, based on your requirements, I think writing an Abap program that read the data you want and download it to NT/SQL server will be faster and easier.

Convert a date in String format to a Date

Hi,
How can I convert a date in String format to a Date object?
I have tried:
import java.text.*;
import java.io.*;
import java.util.Date;
import java.util.Locale;
import java.sql.*;
public class casa {
public static Connection con = null;
public static Statement s = null;
public static String sql = null;
public static String mydate = "01.01.2001";
/** Creates a new instance of casa */
public casa() {
public static void main(String[] args) throws SQLException{
try {
DateFormat shortFormat = DateFormat.getDateInstance(DateFormat.SHORT);
Date date = shortFormat.parse(mydate);
//Open Database
con = getConnection();
s = con.createStatement();
sql = "select date1 from table1 where date1 <= '"+date+"'";
ResultSet rs = s.executeQuery(sql);
while(rs.next()){
String aba = rs.getString("datum");
System.out.println("New Datum = "+aba);
} catch (Exception ex ) {
ex.printStackTrace();
closeConnection(s, con);
//Connection
private static Connection getConnection() {
Connection con = null;
String user ="aouzi";
String passe ="aouzi";
String url = "jdbc:db2:EjbTest";
try {
//Datenbanktreiber laden
Class.forName("COM.ibm.db2.jdbc.app.DB2Driver");
//Verbindung herstellen
con = DriverManager.getConnection(url,user,passe);
}catch(ClassNotFoundException e){
} catch(SQLException e){}
return con;
//close Connection
private static void closeConnection(Statement s, Connection con) {
try {
s.close();
} catch (SQLException e) {}
try {
con.close();
} catch (SQLException e) {}
I'm getting the following errors:
COM.ibm.db2.jdbc.DB2Exception: [IBM][CLI Driver][DB2/NT] SQL0180N
The syntax of the representation of a date/time of day value as character sequence is false. .SQLSTATE=22007

I'm pretty sure it won't understand what date.toString() returns. If you know what format the database understands, you do it like this:
SimpleDateFormat sdf = new SimpleDateFormat("dd-MMM-yy"); // e.g. 18-Apr-02
String datestring = sdf.parse(date);
and use that instead of date in your sql string. Some databases understands it if you do
"to_date('18-Apr-02')"
so you could include that in your sql string as well..
You could also try to make it a java.sql.Date and hope your jdbc driver knows how to convert it to a string that the database understands if you don't know the format:
con = getConnection();
PreparedStatement ps = con.prepareStatement("select date1 from table1 where date1 <= ?");
ps.setDate(new java.sql.Date(date.getTime()));
ResultSet rs = s.executeQuery(sql);

How to convert the date time from MM-DD-YYYThh:mm:ss to YYYY-MM-DDThh:mm:ss format

Hi All,
I have a requirement in my project like to convert the date time from one format to another.my situation is like to convert the date time from MM-DD-YYYThh:mm:ss to YYYY-MM-DDThh:mm:ss format. I am using the soa suite 11.1.1.6.
Can any one suggest me how to convert in the BPEL transformation.
Thanks,
Sanju.

Hi Sanju,
Store the date to be converted into a variable viz. dateVar. Now, process an expression in assign as: xp20:format-dateTime($dateVar,'[Y0001]-[M01]-[D01] [h]:[m01]:[s01]').
Regards

ABAP code in update rules to convert the date

Hi,
Could any one send me the ABAP code that is written in the update rules to convert the date (DD/MM/YYYY -- lenght 10) to YYYYMMDD --- length 8 format.
Also please let me know where I should write this code; while creating update rules or while creating infosource.
Thanks,

Hi Bharath,
Hi Bharath,
I suggest you do the conversion of dates in the transfer rules. Here is the correct code you need:
* Assuming the source data field is called MYDATE
* Place the ff. in the routine in the transfer rules:
concatenate tran_structure-mydate+6(4) tran_structure-mydate+3(2) tran_structure-mydate(2) into result.
replace MYDATE with the name of the source field (10 chars) in the transfer structure. Hope this helps.

Which Function Module is used for converting the DATE in BDC

HI,
Which Function Module is used for converting the DATE Format in BDC for Uploading purpose please help me.

data : date like sy-datum.
data : odate(10) type c.
date = sy-datum.        " in format YYYYMMDD
CALL FUNCTION 'CONVERSION_EXIT_PDATE_OUTPUT'
EXPORTING
   input         = date
IMPORTING
   OUTPUT        = odate         .
write:/ odate. "in ur format '.
1.
In ur itab make a field for date as 10 characters and use this Fm to store the date .
2. Pass the date as the charcter field to the screen and now check .

Sample code converting binary data to image file

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I need sample code to convert binary data (bytes) in to an image file.
any help will be appreciated.
Thanks and Regards,
Naresh

You need to show binary and decimal? Or now just decimal?
If binary and decimal, you can right click on your indicator and choose "Display Format...". If you select the Advanced Editing Mode, you can make soft interesting display formats. This includes showing the same value in mulitple ways in the indicator. Try something like "%032b - %d" for the format string.
There are only two ways to tell somebody thanks: Kudos and Marked Solutions
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Converting a date time to a date only

Post Author: Dockman
CA Forum: Formula
I am working on a report that has a running total field. The running total field keeps a running total and resets every time that a date changes. the problem is that my dates include times, therefore the running total resets on every line. How can I convert my date (in date time format) to be only a date so that it does not reset on every line?
Obviously, I am not a programmer so I apologize if this is a stupid question.

Post Author: yangster
CA Forum: Formula
if you are doing it inside crystal you can use the date functiondate({your.datetimefield})if you are doing it at the db level in a command this will vary depending on your db

Convert Epoch date to Minutes

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