Convert XML using XSLT mapping

Question

Hi,
I have an XML in the following format and would want to cnvert it in the target format shown below. Kindly let me know the XSLT mapping to conert from hierarchy to flat structure.
<u><b>Source XML:</b></u>
<group Level1="Mac Tools Item Classifications">
    <group Level2="6-Other Merchandise">
        <group Level3="61-Racing">
     <group Level4="011-Collectibles">
         <group Level5="001-NASCAR"/>
         <group Level5="002-NHRA"/>
         <group Level5="003-Other"/>
     </group>
     <group Level4="012-Apparel">
         <group Level5="001-Jackets"/>
         <group Level5="002-Shirts"/>
         <group Level5="003-Other">
             <group PartNumber="SHOE823-060"/>
             <group PartNumber="SHOE823-070"/>
             <group PartNumber="SHOE823-080"/>
             <group PartNumber="SHOE823-085"/>
                <group PartNumber="SHOE823-090"/>
                    </group>
     </group>
             </group>
       </group>
</group>
<u><b>Target XML:</b></u>
<Group>
      <part>
     <Level1/>
     <Level2/>
     <Level3/>
     <Level4/>
     <PartNumber/>
       </part>
       <part>
                <Level1/>
     <Level2/>
     <Level3/>
     <Level4/>
     <PartNumber/>
        </part>
</Group>
I am not clear how to capture level1, level 2, etc. till the end node.
Regards,
Swaroopa

Answer 1

HI,
  This is a sample
<b>
<xsl:variable name="var0_floatToString" select="user0:floatToString(/body/getQuote/inputGetQuote/@customerIDFloatAttr)"/>
            <xsl:if test="@customerIDFloatAttr">
                <xsl:attribute name="customerIDFloatAttr">
                    <xsl:value-of select="@customerIDFloatAttr"/>
                </xsl:attribute>
            </xsl:if>
            <xsl:attribute name="customerIDAttr">
                <xsl:value-of select="$var0_floatToString"/>
            </xsl:attribute></b>
using  <xsl:attribute name      here name ="leval1" like that u can use  in XSLT Mapping .
     Hope it helps
Regards.,
V.Rangrajan