Could someone explain what is wrong with this refind expression?

Hi, could someone explain what is wrong with this refind expression
faultCode:Server.Processing faultString:'Unable to invoke CFC - Malformed regular expression "^[0-2][0-9][/][0-1][0-2][/][1-2][0-9]{3}+$".'
thanks

^[0-2][0-9][/][0-1][0-2][/][1-2][0-9]{3}$ works,
thanks
dates 12/12/2007matching

Similar Messages

Can someone see what is wrong with this? Im stumped

   public class Card {
     int suit;
     int value;
     static int isStraight = 0;
     static int isFlush = 0;
     static int handCounter = 0;
     static int cardCounter = 0;
     boolean inUse = false;
     public int getSuit() {
          return suit;
     public void setSuit(int suit) {
          this.suit = suit;
     public int getValue() {
          return value;
     public void setValue(int value) {
          this.value = value;
     public boolean isInUse() {
          return inUse;
     public void setInUse(boolean inUse) {
          this.inUse = inUse;
    public static int checkPairs(int[] handValues){
         for (int x = 0; x<5; x++ ){
              for (int y = 0; y<5; y++ ){
                   if(handValues[x]==handValues[y]){
                        cardCounter ++;
              handCounter = handCounter + (cardCounter - 1);
               cardCounter = 0;
         System.out.println(handCounter);
         return handCounter;
    public static int checkStraight(int[] handValues){
              if(handValues[0] == (handValues[1]-1)){
                   if (handValues[1] == (handValues[2]-1)){
                        if (handValues[2] == (handValues[3]-1)){
                             if (handValues[3] == (handValues[4]-1)){
                                  ///System.out.println("straight");
                                      isStraight = 1;
                                  if (handValues[4] == 12){
                                        isStraight = 2;
              return isStraight;
    public static int checkFlush(Card[]inputHand){
         if (inputHand[0].suit == inputHand[1].suit){
              if (inputHand[1].suit == inputHand[2].suit){
                   if (inputHand[2].suit == inputHand[3].suit){
                        if (inputHand[3].suit == inputHand[4].suit){
                             isFlush = 1;
         return isFlush;
//handCheckerApp ,
import tcdIO.*;
public class handCheckerApp {
     ///these string arrays just hold the names of the values
     static String[] suitsArray = {"hearts" , "spades" , "diamonds" , "clubs" };
     static String[] valuesArray = {"two" , "three" , "four" , "five" , "six" , "seven" , "eight" , "nine" , "ten" , "jack" , "queen" , "king" ,"ace" };
     public static void main (String arguments []) {
          Terminal terminal = new Terminal();
          Card[] inputHand = new Card[5];
          Card[] deck = new Card[52];
          Card currentCard = new Card();
          for(int number = 0 ; number <= 12 ; number++){
               deck[number]= new Card();
               deck[number].suit = 0;
               deck[number].value = number;
          for(int number = 13 ; number <= 25 ; number++){
               deck[number]= new Card();
               deck[number].suit = 1;
               deck[number].value = (number - 13);
          for(int number = 26 ; number <= 38 ; number++){
               deck[number]= new Card();
               deck[number].suit = 2;
               deck[number].value = (number - 26);
          for(int number = 39 ; number <= 51 ; number++){
               deck[number]= new Card();
               deck[number].suit = 3;
               deck[number].value = (number - 39);
          terminal.println("Poker Hand Checker");
          terminal.println("~~~~~~~~~~~~~~~~~~");
          terminal.println("Suits key:..Hearts = 1");
          terminal.println("...................Spades = 2");
          terminal.println("...................Diamonds = 3");
          terminal.println("...................Clubs = 4");
          terminal.println(".............................");
          terminal.println("Values key:.Twos = 2");
          terminal.println("......................Threes = 3");
          terminal.println("......................Fours = 4");
          terminal.println("......................Fives = 5");
          terminal.println("......................Sixes = 6");
          terminal.println("......................Sevens = 7");
          terminal.println("......................Eights = 8");
          terminal.println("......................Nines = 9");
          terminal.println("......................Tens = 10");
          terminal.println("......................Jacks = 11");
          terminal.println("......................Queens = 12");
          terminal.println("......................Kings = 13");
          terminal.println("......................Aces = 14");
      ///this block of code marks cards in the deck as in use and adds them to the hand
      for(int i = 0; i < 5; i++){///for1
          currentCard.value = (terminal.readInt("please enter card " + (i+1) + " value: " )-2);
          currentCard.suit = (terminal.readInt("please enter card " + (i+1) + " suit: " )-1);
          for (int x = 0; x< 52; x++){///for2
               if (deck[x].value == currentCard.value){///if1
                    if (deck[x].suit == currentCard.suit){///if2
                        if (deck[x].inUse == true){///elseif1
                             terminal.println("you chose that card already");
                             i--;
                        }///if3
                        else if(deck[x].inUse == false){///if3
                             deck[x].inUse = true;
                             inputHand[i] = deck[x];
                             terminal.println("this card is the " + valuesArray[(inputHand.value)] + " of " + suitsArray[(inputHand[i].suit )]);
                    }///elseif1
               }///if2
          }///if1
     }///for2
     }///for1
     int handValues[] = {inputHand[0].value, inputHand[1].value, inputHand[2].value, inputHand[3].value, inputHand[4].value};
     java.util.Arrays.sort(handValues);
     ///this method checks for pairs, two pairs, three of a kind, full house & four of a kind
     Card.checkPairs(handValues);
     if (Card.handCounter == 2) {
               terminal.println("You have a pair");
          if (Card.handCounter == 4) {
               terminal.println("You have two pair");
          if (Card.handCounter == 6) {
               terminal.println("You three of a kind");
          if (Card.handCounter == 8) {
               terminal.println("You have a full house");
          if (Card.handCounter == 12) {
               terminal.println("You have four of a kind");
          } else {
               terminal.println("");
          Card.checkStraight(handValues);
          Card.checkFlush(inputHand);
               if (Card.isStraight == 1 && Card.isFlush == 0){
                    terminal.println("You have a straight");
               if (Card.isStraight == 1 && Card.isFlush == 1){
                    terminal.println("You have a straight flush");
               if (Card.isStraight == 2 && Card.isFlush == 0){
                    terminal.println("You have a royal straight");
               if (Card.isStraight == 2 && Card.isFlush == 1){
                    terminal.println("You have a royal straight flush");
               if (Card.isStraight == 0 && Card.isFlush == 1){
                    terminal.println("You have a flush");
               if (Card.isStraight == 0 && Card.isFlush == 0){
                    terminal.println("");
Okay it's not recognising deck.inUse....i can't see why.
Can someone possibly point out some suggestions. Thanks, much appreciated.

> if (deck[x].inUse == true){///elseif1
>
it's giving me an error on this If else statement...
sorry ....
How about going the extra mile and actually posting the error message you receive rather than expecting everyone to guess? The more pertinent information you can provide, the easier it is to answer your question. And you want your question answered easily and quickly, right?
~

What's wrong with the regular expression?

Hi all,
For the life of me I can not figure out what is wrong with this regular expression
.*\bA specific phrase\.\b.*
This is just an example the actual phrase can be an specific phrase. My problem comes when the specific phrase ends in a period. I've escaped the period but it still gives me an error. The only time I don't get an error is when I take off the end boundry character which will not suffice as a solution. I need to be able to capture all the text before and after said phrase. If the phrase doesn't have a period it would look like this...
.*\bA specific phrase\b.*
which works fine. So what is it about the \.\b combination that is not matching?
I've been banging my head on this for a while and I'm getting nowhere.
The application highlights text that comes from a server. The user builds custom highlights that have some options. Highlight entire line, match partial word, and ignore case. The code that builds my pattern is here
String strHighlight = _strHighlight;
        strHighlight = strHighlight.replaceAll("\\*", "\\\\*");
        strHighlight = strHighlight.replaceAll("\\.", "\\\\.");
        String strPattern = strHighlight;
        if(_bEntireParagraph)
            if(_bPartialWord)
                strPattern = ".*" + strHighlight + ".*";
            else
                strPattern = ".*\\b" + strHighlight + "\\b.*";
        else
            if(_bPartialWord)
                strPattern = strHighlight;
            else
                strPattern = "\\b" + strHighlight + "\\b";
        if(_bIgnoreCase)
            _patHighlight = Pattern.compile(strPattern, Pattern.CASE_INSENSITIVE);
        else
            _patHighlight = Pattern.compile(strPattern);So for example I matching the phrase: The dog ate the cat. And that phrase came over in the following text: Look there's a dog. The dog ate the cat. "Oh my!"
And my user has the entire line and ignore case options selected then my regex woud look like this: .*\bThe dog ate the cat\b.*
That should get highlighted, but for some reason it doesn't. Correct me if I'm wrong but doesn't the regex read as follows:
any characters
word boundry
The dog ate the cat[period]
word boundry
any characters until newline.
Any help will be much appreciated

A word boundary (in the context of regexes) is a position that is either followed by a word character and not preceded by one (start of word) or preceded by a word character and not followed by one (end of word). A word character is defined as a letter, a digit, or an underscore. Since a period is not a word character, the only way the position following it could be a word boundary is if the next character is a letter, digit or underscore. But a sentence-ending period is always followed by whitespace, if anything, so it makes no sense to look for a word boundary there. I think, instead of \b, you should use negative lookarounds, like so: strPattern = ".*(?<!\\w)" + strHighlight + "(?!\\w).*";

Can someone tell me what's wrong with this LOV query please?

This query works fine..
select FILTER_NAME display_value, FILTER_ID return_value
from OTMGUI_FILTER where username = 'ADAM'
But this one..
select FILTER_NAME display_value, FILTER_ID return_value
from OTMGUI_FILTER where username = apex_application.g_user
Gives the following error.
1 error has occurred
* LOV query is invalid, a display and a return value are needed, the column names need to be different. If your query contains an in-line query, the first FROM clause in the SQL statement must not belong to the in-line query.
Thanks very much,
-Adam vonNieda

Ya know, I still don't know what's wrong with this.
declare
l_val varchar2(100) := nvl(apex_application.g_user,'ADAM');
begin
return 'select filter_name display_value, filter_id return_value
from otmgui_filter where username = '''|| l_val || '''';
end;
Gets the same error as above. All I'm trying to do is create a dropdown LOV which selects based on the apex_application.g_user.
What am I missing here?
Thanks,
-Adam

What is wrong with this code? on(release) gotoAndPlay("2")'{'

Please could someone tell me what is wrong with this code - on(release)
gotoAndPlay("2")'{'
this is the error that comes up and i have tried changing it but it is not working
**Error** Scene=Scene 1, layer=Layer 2, frame=1:Line 2: '{' expected
     gotoAndPlay("2")'{'
Total ActionScript Errors: 1 Reported Errors: 1
Thanks

If you have a frame labelled "2" then it should be:
on (release) {
    this._parent.gotoAndPlay("2");
or other wise just the following to go to frame 2:
on (release) {
     this._parent.gotoAndPlay(2);
You just had a missing curly bracket...

What's wrong with this content type definition?

Could someone tell me what's wrong with this content type definition? When I click "New Folder" in a custom list, it should bring two fields 1) Name 2) Custom Order. However in my case when I click new folder, I see 1) Member (which is totally
weird) 2) custom order. Where is it getting that Member field from?
<Elements xmlns="http://schemas.microsoft.com/sharepoint/">

<ContentType ID="0x012000c0692689cafc4191b6283f72f2369cff"
Name="Folder_OrderColumn"
Group="Custom"
Description="Folder with order column"
Inherits="TRUE"
Version="0">
<FieldRefs>
<FieldRef ID="{35788ED2-8569-48DC-B6DE-BA72A4F87B7A}" Name="Custom_x0020_Order" DisplayName="Custom Order" />
</FieldRefs>
</ContentType>
</Elements>

Hi,
According to your post, my understanding is that you had an issue about the custom content type with custom column.
I don’t think there is any issue in the content type definition, and it also worked well in my environment.
Did you have the Member field in the project?
I recommend you create a simple project only with one custom Order column and one custom Folder_OrderColumn, then you can add more fields one by one.
By doing this, it will be easier to find out the root cause of this error.
Thanks,
Jason
Forum Support
Please remember to mark the replies as answers if they help and unmark them if they provide no help. If you have feedback for TechNet Subscriber Support, contact
[email protected]
Jason Guo
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Could someone explain what is Object?

Could someone explain what is Object? I have a little
idea what is it, but not sure. Please give me some
concret example. Thanks.

An object is an Instance of a class. A class describes a uniwue entity with behaviors and attributes. For example you can consider your arm.
public class Arm {
/** How many hairs on the arm. */
private int hairCount; // <== This is an attribute
/** This is a method to set the hairCount Variable.
   * We dont let the outside user set it directly because that would
   * create problems if we wanted to change its implementation to
   * use a float. In addition we might have logic in this setter to
   * prevent bad data.
public void setHairCount(final int hairCount) {
    // this is a good example of logic in the set method that we dont
    // want the user to bypass.
    if (hairCount < 0) {
      throw new IllegalArgumentException();
    this.hairCount = hairCount; // <-- Note how we have to use this. to
                                //     access the instance variable
                                //     insead of the parameter.
/** This is a method to move the arm.
   * This is behavior of the class. ONLY behavior pertaining to an arm
   * belongs in the arm class. For example, the method "sneeze" would
   * not belong here but be in the Nose class instead. You can see then
   * that each class describes an entity.
public void move() {
    // code to move the arm.
}We have only ONE class per type but we can have many objects. For example the description of an arm does not change no matter who'se arm it is. The data in the class changes but not the actual essence of the arm. So we instantiate two arms for every person (assuming they arent disabled). To instantiate is to create a new object like so.
Arm myarm = new Arm(): This creates a new object that we can work with.
So consider the old inteview question of, "What is the difference between a class and an object?" The answer is, "A class is a map or desription of an object; whereas an object is a descrite instance of a class."

After upgrade my Iphone 4 to iso5, I can't add contact and I can't access the settings for mail,contacts and calender. The moment I select the setting for Mails, Contact and Calender it will jump back to home. Can someone advice what's wrong with it?

After upgrade my Iphone 4 to iso5, I can't add contact and I can't access the settings for mail,contacts and calender. The moment I select the setting for Mails, Contact and Calender it will jump back to home. Can someone advice what's wrong with it?Problr

Dear All
i have done the same activity ( buy a new iphone 4 -> upgrade to ios5 - > configure email) with success-
than when i start to move the contacts from old mobile to iphone (using the microsim) i receive the same crash
in disgnosis e use i saw 2 dump with this title 'latestCrash-Preferences.plist and LatestCrash.plist. in each file the date is the same and i read:
Exception Tyle: EXC_CRASH (SIGABRT)
Exception code: 0x00000000, 0x00000000
Chrashed Thread: 6
in thread 6: name: Dispatch queue:
com.apple.addressBookUI.ContactsSettingPlugin
and thaan a lot of data.
Have you any idea?
thank in advance
Fabio

It says that "there was a problem connecting to the server". What's wrong with this, and how can I deal with this problem?

I just got my new iPad Mini2, and when I choose "sign in with your apple ID", it says that "there was a problem connecting to the server". What's wrong with this, and how can I deal with this problem?

1. Turn router off for 30 seconds and on again
2. Settings>General>Reset>Reset Network Settings

I can't figure out what's wrong with this code

First i want this program to allow me to enter a number with the EasyReader class and depending on the number entered it will show that specific line of this peom:
One two buckle your shoe
Three four shut the door
Five six pick up sticks
Seven eight lay them straight
Nine ten this is the end.
The error message i got was an illegal start of expression. I can't figure out why it is giving me this error because i have if (n = 1) || (n = 2) statements. My code is:
public class PoemSeventeen
public static void main(String[] args)
EasyReader console = new EasyReader();
System.out.println("Enter a number for the poem (0 to quit): ");
int n = console.readInt();
if (n = 1) || (n = 2)
System.out.println("One, two, buckle your shoe");
else if (n = 3) || (n = 4)
System.out.println("Three, four, shut the door");
else if (n = 5) || (n = 6)
System.out.println("Five, six, pick up sticks");
else if (n = 7) || (n = 8)
System.out.println("Seven, eight, lay them straight");
else if (n = 9) || (n = 10)
System.out.println("Nine, ten, this is the end");
else if (n = 0)
System.out.println("You may exit now");
else
System.out.println("Put in a number between 0 and 10");
I messed around with a few other thing because i had some weird errors before but now i have narrowed it down to just this 1 error.
The EasyReader class code:
// package com.skylit.io;
import java.io.*;
* @author Gary Litvin
* @version 1.2, 5/30/02
* Written as part of
* <i>Java Methods: An Introduction to Object-Oriented Programming</i>
* (Skylight Publishing 2001, ISBN 0-9654853-7-4)
* and
* <i>Java Methods AB: Data Structures</i>
* (Skylight Publishing 2003, ISBN 0-9654853-1-5)
* EasyReader provides simple methods for reading the console and
* for opening and reading text files. All exceptions are handled
* inside the class and are hidden from the user.
* <xmp>
* Example:
* =======
* EasyReader console = new EasyReader();
* System.out.print("Enter input file name: ");
* String fileName = console.readLine();
* EasyReader inFile = new EasyReader(fileName);
* if (inFile.bad())
* System.err.println("Can't open " + fileName);
* System.exit(1);
* String firstLine = inFile.readLine();
* if (!inFile.eof()) // or: if (firstLine != null)
* System.out.println("The first line is : " + firstLine);
* System.out.print("Enter the maximum number of integers to read: ");
* int maxCount = console.readInt();
* int k, count = 0;
* while (count < maxCount && !inFile.eof())
* k = inFile.readInt();
* if (!inFile.eof())
* // process or store this number
* count++;
* inFile.close(); // optional
* System.out.println(count + " numbers read");
* </xmp>
public class EasyReader
protected String myFileName;
protected BufferedReader myInFile;
protected int myErrorFlags = 0;
protected static final int OPENERROR = 0x0001;
protected static final int CLOSEERROR = 0x0002;
protected static final int READERROR = 0x0004;
protected static final int EOF = 0x0100;
* Constructor. Prepares console (System.in) for reading
public EasyReader()
myFileName = null;
myErrorFlags = 0;
myInFile = new BufferedReader(
new InputStreamReader(System.in), 128);
* Constructor. opens a file for reading
* @param fileName the name or pathname of the file
public EasyReader(String fileName)
myFileName = fileName;
myErrorFlags = 0;
try
myInFile = new BufferedReader(new FileReader(fileName), 1024);
catch (FileNotFoundException e)
myErrorFlags |= OPENERROR;
myFileName = null;
* Closes the file
public void close()
if (myFileName == null)
return;
try
myInFile.close();
catch (IOException e)
System.err.println("Error closing " + myFileName + "\n");
myErrorFlags |= CLOSEERROR;
* Checks the status of the file
* @return true if en error occurred opening or reading the file,
* false otherwise
public boolean bad()
return myErrorFlags != 0;
* Checks the EOF status of the file
* @return true if EOF was encountered in the previous read
* operation, false otherwise
public boolean eof()
return (myErrorFlags & EOF) != 0;
private boolean ready() throws IOException
return myFileName == null || myInFile.ready();
* Reads the next character from a file (any character including
* a space or a newline character).
* @return character read or <code>null</code> character
* (Unicode 0) if trying to read beyond the EOF
public char readChar()
char ch = '\u0000';
try
if (ready())
ch = (char)myInFile.read();
catch (IOException e)
if (myFileName != null)
System.err.println("Error reading " + myFileName + "\n");
myErrorFlags |= READERROR;
if (ch == '\u0000')
myErrorFlags |= EOF;
return ch;
* Reads from the current position in the file up to and including
* the next newline character. The newline character is thrown away
* @return the read string (excluding the newline character) or
* null if trying to read beyond the EOF
public String readLine()
String s = null;
try
s = myInFile.readLine();
catch (IOException e)
if (myFileName != null)
System.err.println("Error reading " + myFileName + "\n");
myErrorFlags |= READERROR;
if (s == null)
myErrorFlags |= EOF;
return s;
* Skips whitespace and reads the next word (a string of consecutive
* non-whitespace characters (up to but excluding the next space,
* newline, etc.)
* @return the read string or null if trying to read beyond the EOF
public String readWord()
StringBuffer buffer = new StringBuffer(128);
char ch = ' ';
int count = 0;
String s = null;
try
while (ready() && Character.isWhitespace(ch))
ch = (char)myInFile.read();
while (ready() && !Character.isWhitespace(ch))
count++;
buffer.append(ch);
myInFile.mark(1);
ch = (char)myInFile.read();
if (count > 0)
myInFile.reset();
s = buffer.toString();
else
myErrorFlags |= EOF;
catch (IOException e)
if (myFileName != null)
System.err.println("Error reading " + myFileName + "\n");
myErrorFlags |= READERROR;
return s;
* Reads the next integer (without validating its format)
* @return the integer read or 0 if trying to read beyond the EOF
public int readInt()
String s = readWord();
if (s != null)
return Integer.parseInt(s);
else
return 0;
* Reads the next double (without validating its format)
* @return the number read or 0 if trying to read beyond the EOF
public double readDouble()
String s = readWord();
if (s != null)
return Double.parseDouble(s);
// in Java 1, use: return Double.valueOf(s).doubleValue();
else
return 0.0;
Can anybody please tell me what's wrong with this code? Thanks

String[] message = {
    "One, two, buckle your shoe",
    "One, two, buckle your shoe",
    "Three, four, shut the door",
    "Three, four, shut the door",
    "Five, six, pick up sticks",
    "Five, six, pick up sticks",
    "Seven, eight, lay them straight",
    "Seven, eight, lay them straight",
    "Nine, ten, this is the end",
    "Nine, ten, this is the end"
if(n>0)
    System.out.println(message[n]);
else
    System.exit(0);

What's wrong with this function

What's wrong with this Function(PL/SQL) in this formaula column definition in Reports 6i
function currdateFormula return Date is
curr_date date;
begin
select to_char(sysdate, 'DD-MM-YYYY') into curr_date from dual;
return(curr_date);
end;
I get the following error in compiling
REP-1401. 'currdateformula'.Fatal PL/SQL error occured. ORA-01843 not a valid month.
The SQL select to_char(sysdate, 'DD-MM-YYYY') from dual; worked well in SQL Plus prompt.
I got a clean compile when i use just sysdate in the function (see below).
function currdateFormula return Date is
curr_date date;
begin
select sysdate into curr_date from dual;
return(curr_date);
end;
Appreciate your help
Raja Lakshmi

hello,
what you are trying to do :
fetch the current date and return it as the result of the formula-column.
what you are actually doing :
fetch the current date, convert it to text, assign this text to a date-variable which causes an implicit type-conversion.
in your case you create a date-string with the format dd-mm-yyyy. the implicit conversion then tries to convert this string back to date using the NLS settings of your session. depending on your NLS_LANG and NLS_DATE_FORMAT this might work, if your session-date-format is dd-mm-yyyy which obviously it is NOT as you get the error.
what you should do :
select sysdate into curr_date from dual;
this fetches the sysdate and stores it in your date-variable. there is no type conversion needed what so ever.
regards,
the oracle reports team

What's wrong with this SQL?

what's wrong with this SQL?
Posted: Jan 16, 2007 9:35 AM Reply
Hi, everyone:
when I insert into table, i use the fellowing SQL:
INSERT INTO xhealthcall_script_data
(XHC_CALL_ENDED, XHC_SWITCH_PORT, XHC_SCRIPT_ID, XHC_FAX_SPECIFIED)
VALUES (SELECT TO_DATE(HH_END_DATE||' '||HH_END_TIME,'MM/DD/YY HH24:MI:SS'), HH_SWITCHPORT, HH_SCRIPT,'N'
FROM tmp_healthhit_load WHERE HH_SCRIPT !='BROCHURE' UNION
SELECT TO_DATE(HH_END_DATE||' '||HH_END_TIME,'MM/DD/YY HH24:MI:SS'), HH_SWITCHPORT, HH_SCRIPT,'N' FROM tmp_healthhit_load WHERE HH_SCRIPT !='BROCHURE');
I always got an error like;
VALUES (SELECT TO_DATE(HH_END_DATE||' '||HH_END_TIME,'MM/DD/YY HH24:MI:SS'), HH_SWITCHPORT,
ERROR at line 3:
ORA-00936: missing expression
but I can't find anything wrong, who can tell me why?
thank you so much in advance
mpowel01
Posts: 1,516
Registered: 12/7/98
Re: what's wrong with this SQL?
Posted: Jan 16, 2007 9:38 AM in response to: jerrygreat Reply
For starters, an insert select does not have a values clause.
HTH -- Mark D Powell --
PP
Posts: 41
From: q
Registered: 8/10/06
Re: what's wrong with this SQL?
Posted: Jan 16, 2007 9:48 AM in response to: mpowel01 Reply
Even I see "missing VALUES" as the only error
Eric H
Posts: 2,822
Registered: 10/15/98
Re: what's wrong with this SQL?
Posted: Jan 16, 2007 9:54 AM in response to: jerrygreat Reply
...and why are you doing a UNION on the exact same two queries?
(SELECT TO_DATE(HH_END_DATE||' '||HH_END_TIME,'MM/DD/YY HH24:MI:SS') ,HH_SWITCHPORT ,HH_SCRIPT ,'N' FROM tmp_healthhit_load WHERE HH_SCRIPT !='BROCHURE' UNION SELECT TO_DATE(HH_END_DATE||' '||HH_END_TIME,'MM/DD/YY HH24:MI:SS') ,HH_SWITCHPORT ,HH_SCRIPT ,'N' FROM tmp_healthhit_load WHERE HH_SCRIPT !='BROCHURE');
jerrygreat
Posts: 8
Registered: 1/3/07
Re: what's wrong with this SQL?
Posted: Jan 16, 2007 9:55 AM in response to: mpowel01 Reply
Hi,
thank you for your answer, but the problem is, if I deleted "values" as you pointed out, and then execute it again, I got error like "ERROR at line 3:
ORA-03113: end-of-file on communication channel", and I was then disconnected with server, I have to relogin SQLplus, and do everything from beganing.
so what 's wrong caused disconnection, I can't find any triggers related. it is so wired?
I wonder if anyone can help me about this.
thank you very much
jerry
yingkuan
Posts: 1,801
From: San Jose, CA
Registered: 10/8/98
Re: what's wrong with this SQL?
Posted: Jan 16, 2007 9:59 AM in response to: jerrygreat Reply
Dup Post
jerrygreat
Posts: 8
Registered: 1/3/07
Re: what's wrong with this SQL?
Posted: Jan 16, 2007 10:00 AM in response to: Eric H Reply
Hi,
acturlly what I do is debugging a previous developer's scipt for data loading, this script was called by Cron work, but it never can be successfully executed.
I think he use union for eliminating duplications of rows, I just guess.
thank you
jerry
mpowel01
Posts: 1,516
Registered: 12/7/98
Re: what's wrong with this SQL?
Posted: Jan 16, 2007 10:03 AM in response to: yingkuan Reply
Scratch the VALUES keyword then make sure that the select list matches the column list in number and type.
1 insert into marktest
2 (fld1, fld2, fld3, fld4, fld5)
3* select * from marktest
UT1 > /
16 rows created.
HTH -- Mark D Powell --
Jagan
Posts: 41
From: Hyderabad
Registered: 7/21/06
Re: what's wrong with this SQL?
Posted: Jan 16, 2007 10:07 AM in response to: jerrygreat Reply
try this - just paste the code and give me the error- i mean past the entire error as it is if error occurs
INSERT INTO xhealthcall_script_data
(xhc_call_ended, xhc_switch_port, xhc_script_id,
xhc_fax_specified)
SELECT TO_DATE (hh_end_date || ' ' || hh_end_time, 'MM/DD/YY HH24:MI:SS'),
hh_switchport, hh_script, 'N'
FROM tmp_healthhit_load
WHERE hh_script != 'BROCHURE'
UNION
SELECT TO_DATE (hh_end_date || ' ' || hh_end_time, 'MM/DD/YY HH24:MI:SS'),
hh_switchport, hh_script, 'N'
FROM tmp_healthhit_load
WHERE hh_script != 'BROCHURE';
Regards
Jagan
jerrygreat
Posts: 8
Registered: 1/3/07
Re: what's wrong with this SQL?
Posted: Jan 16, 2007 11:31 AM in response to: Jagan Reply
Hi, Jagan:
thank you very much for your answer.
but when I execute it, I still can get error like:
ERROR at line 1:
ORA-03113: end-of-file on communication channel
so wired, do you have any ideas?
thank you very much

And this one,
Aother question about SQL?
I thought I already told him to deal with
ORA-03113: end-of-file on communication channel
problem first.
There's nothing wrong (syntax wise) with the query. (of course when no "value" in the insert)

I HATE my new MACBOOK PRO, it will not let me open any PDF files and I downloaded the ADOBE READER three freaking times and it keeps saying that all the files are corrupt. I would rather have my 2008 Dell at this point. what is wrong with this thing

I HATE my new MACBOOK PRO, it will not let me open any PDF files and I downloaded the ADOBE READER three freaking times and it keeps saying that all the files are corrupt or damaged. I would rather have my 2008 Dell at this point. what is wrong with this thing

Perhaps the PDF files are corrupted.
Hit the command key and spacebar, a blue Spotlight in the upper right hand corner appears, now type Preview and press return on the Preview program.
Now you can try opening the PDF's from the file menu and see what's going on.
If they are corrupted, perhaps they are trojans from your Windows PC or gotten from a bad location online.
Download the free ClamXav and run a scan on the possibly infected folder.

What's wrong with this Forum? Why does Adobe take so long to reply to posts?!

What's wrong with this Forum? Why does Adobe take so long to reply to posts?!
This is actually "specific" to this Photoshop Forum.
I typically get responses back from other Adobe forum promptly.
Chime in.

The Adobe engineering folks DO duck in here from time to time - and that's a BLESSING! Please name any other big company where you get to interact with the engineers AT ALL. I can't. But I suspect the engineers actually have a lot oof real work to do, and their time here is necessarily limited.
Your comments are more along the line of "I pay a huge amount, for that I expect better support". These are very valid comments. But reality is different from what we may expect, and this forum is not the place to expect Adobe support participation AT ALL. In fact, the technical support people at Adobe often direct users to come here (something I've always found amusing).
At the higher level, Adobe may simply not be spending enough on support for literally millions of users. Is is greed or smart business to try to minimize support cost? That's up for individuals to decide.
I suggest you write a snail-mail letter to the Adobe president if you're not getting the support you need.
-Noel

What's wrong with this simple code?

What's wrong with this simple code? Complier points out that
1. a '{' is expected at line6;
2. Statement expected at the line which PI is declared;
3. Type expected at "System.out.println("Demostrating PI");"
However, I can't figure out them. Please help. Thanks.
Here is the code:
import java.util.*;
public class DebugTwo3
// This class demonstrates some math methods
public static void main(String args[])
          public static final double PI = 3.14159;
          double radius = 2.00;
          double area;
          double roundArea;
          System.out.println("Demonstrating PI");
          area = PI * radius * radius;
          System.out.println("area is " + area);
          roundArea = Math.round(area);
          System.out.println("Rounded area is " + roundArea);

Change your code to this:
import java.util.*;
public class DebugTwo3
     public static final double PI = 3.14159;
     public static void main(String args[])
          double radius = 2.00;
          double area;
          double roundArea;
          System.out.println("Demonstrating PI");
          area = PI * radius * radius;
          System.out.println("area is " + area);
          roundArea = Math.round(area);
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Klint

Could someone explain what is wrong with this refind expression?

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