Count with multiple conditions (XML publisher)

I'm trying to only count an EMPLID if multiple conditions have been met in an RTF.
This works for 1 condition: <?count(xdoxslt:distinct_values(EMPLID[../FIRSTYEARFRESHMAN=1]))?>
But how do I do multiple conditions? I've tried <?count(xdoxslt:distinct_values(EMPLID[../FIRSTYEARFRESHMAN=1] AND [../APPLIED_FOR_NEED_B=1]))?> and <?count(xdoxslt:distinct_values(EMPLID[../FIRSTYEARFRESHMAN=1 AND ../APPLIED_FOR_NEED_B=1]))?> but those both don't work.
Thanks!

similar problem for xdoxslt:distinct_values(EMPLID[condition1 and/or condition2])
How to calculate count distinct (by xdoxslt:distinct_values) with a condition expression

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You could try
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MEDICATION.DRUGID
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MEDICATION
WHERE
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Hi,
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Deleting data from another table with multiple conditions

Hi frnds
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Edited by: Danilo Kasparian on Apr 14, 2011 4:08 PM

Printing issue with pdftops for XML publisher reports.

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- Restarted the manager.
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The 'lpstat -t' shows the following status for the failing printer.
=============
printer PRT1 is idle. enabled since Tue 23 Jul 2013 03:24:40 PM EDT
/usr/lib/cups/filter/pstoraster failed
=============
The printer queue logs on the application servers shows the following details for the failing printer.
=========================================
I [22/Jul/2013:15:00:48 -0400] [Job 137] Queued on "PRT1" by "appldfin".
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I [22/Jul/2013:15:00:48 -0400] [Job 137] Started filter /usr/lib/cups/filter/pstoraster (PID 13531)
I [22/Jul/2013:15:00:48 -0400] [Job 137] Started filter /usr/lib/cups/filter/hpcups (PID 13532)
I [22/Jul/2013:15:00:48 -0400] [Job 137] Started backend /usr/lib/cups/backend/socket (PID 13533)
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==========
The printer that works fine on the same application server has the following message.
==========
I [22/Jul/2013:15:16:44 -0400] [Job 139] Queued on "PRT2" by "appldfin".
I [22/Jul/2013:15:16:44 -0400] [Job 139] Started filter /usr/lib/cups/filter/pdftops (PID 15825)
I [22/Jul/2013:15:16:44 -0400] [Job 139] Started backend /usr/lib/cups/backend/socket (PID 15826)
I [22/Jul/2013:15:16:44 -0400] [Job 139] Completed successfully.
==============
It only goes through 2 filters and prints just fine
The system admin team has tried to re-install the printer driver but no luck.
Any idea what could be the cause and how can fix it?
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Thanks Hussein.
I will check the 2 options you recommended. At the same, I would like to test the direct print from the OS using pdftops utility. But not sure how can I do that?
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Sunil

Error In Query Level export with multiple conditions

When i am running the following Query for Export with i am getting the result.
C:\Documents and Settings\ITL>exp scott/tiger@orcl tables=(emp) QUERY='"WHERE deptno > 10 and sal !=2850"' LOG=log011.log FILE=exp.dmp
Export: Release 10.2.0.1.0 - Production on Wed Jan 30 10:01:27 2013
Copyright (c) 1982, 2005, Oracle. All rights reserved.
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EXP-00091: Exporting questionable statistics.
EXP-00091: Exporting questionable statistics.
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But When I run with The following condition then it shows the following error...
C:\Documents and Settings\ITL>exp scott/tiger@orcl tables=(emp) QUERY='"WHERE deptno > 10 and job!='CLERK' "' LOG=log011.log FILE=Exp01.dmp
LRM-00111: no closing quote for value ' LOG=log01'
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LRM-00112: multiple values not allowed for parameter 'query'
EXP-00019: failed to process parameters, type 'EXP HELP=Y' for help
EXP-00000: Export terminated unsuccessfully
Please suggest a solution for it.

966523 wrote:
Padma.... wrote:
Hi,
The single quotes used for CLERK are causing the issue most probably.
C:\Documents and Settings\ITL>exp scott/tiger@orcl tables=(emp) QUERY='"WHERE deptno > 10 and job!='CLERK' "' LOG=log011.log FILE=Exp01.dmp
try replacing with this
C:\Documents and Settings\ITL>exp scott/tiger@orcl tables=(emp) QUERY='"WHERE deptno > 10 and job!=''CLERK'' "' LOG=log011.log FILE=Exp01.dmp
Two single quotes(not double quotes) in the place of one single quote for CLERK.
Thanks
Padma...Thanks A Lot...if/when you place all inside control file, then you do not have to worry about such complications

Customer Report with multiple conditions?

Hello <<text removed>>
I have a project that I am curious if it is possible using BW and BEx Analyzer.
I have a Cube that contains Customer, Brand, Revenue etc....
Lets say i have the following values
Customer: 1,2,3,4,5,6
Brand:      1,2,3
I need a report, series of reports, or a workbook that can provide the following.
a. List and count of customers that purchased $500+ of only Brand 1
b. LIst and count of customers that purchased $500+ of only Brand 2
c. List and count of customers that purchased $500+ of only Brand 3
d. List and count of customers that purchased $500+ of Brand 1 and $500+ of Brand 2
e. List and count of customers that purchased $500+ of Brand 1 and $500+ of Brand 3
f. List and count of customers that purchased $500+ of Brand 1, $500+ of Brand 2 and $500+ of Brand 3.
I think you get the point
This report should look at the previous 12 months of data. And the Customer should not appear on the report more then once because that is how the criteria presented above should work.
I was able to get this to work for a,b,c by restricting a query to the brand and using a condition of $500+ for revenue
I was also able to get this to work for d and e by using the resolution for the single brand as a value set as input for the dealers in a similiar query restricted to a different brand.
Anyway I hope i can find some ideas/approaches that would meet this requirement!
Thank you,
Nick
Edited by: Matt on Jan 13, 2011 9:06 AM

Hi Nick,
See if this works.......
Put customer in Rows.
Create 3 restricted key figures for Revenue one with each brand. gets difficult if you want to do this for many brands...
Create a calculated key fig and use the expression revenue_rkf1 > 500. this expression in the calc key fig returns 1 if revenue is > 500, othewise returns 0. Similarly create 2 more CKFs with expressions using the other RKFs for revenue.
Now report may look like this:
Customer      brand1         brand2          brand3
Cust1...........            0..........                   1............                    1
Cust2...........            1..........                   1...........                     0
Now add logic to get customers who bought brand 1 > 500 and brand2 > 500 and other combinations. For that create different formulas like brand1brand2, brand 2brand3, brand1brand3, brand1brand2+brand3.
Now report may look like this:
Customer      brand1         brand2          brand3     for1        for2       for3       for4
Cust1..........0............1..........1........1......2....1.....2
Cust2..........1............1..........0........2......1....1.....2
cust3..........1............1..........1........2.......2....2.....3
Now create 4 calc key figures. In CKF1 use expression for1 > 1. This checks if value in formula1 is greater than 1, if yes puts 1 otherwise 0. Use the same expression for CKF2 and CKF3 using for2 and for3. Create CKF4 with expression for4 > 2.
Now the report looks like this:
Customer      brand1         brand2          brand3     for1        for2       for3       for4    CKF1      CKF2     CKF3       CKF4
Cust1...........0...........1...........1.......1......2.....1.....2......0........1.......0........0
Cust2...........1...........1...........0.......2......1.....1.....2......1........0.......0........0
cust3...........1...........1...........1.......2......2.....2.....3......1.........1.......1........1
Count of CKF1 gives the number of customers who bought brand1 for 500+ usd and brand2 for 500+ usd.
Count of CKF4 gives the number of customers who bought all brands for more than 500 $ each.
The repot gives the data needed but may not look good with number display against customers.
Regards,
Murali.
Edited by: Murali Krishna K on Jan 7, 2011 10:52 AM
Edited by: Murali Krishna K on Jan 7, 2011 11:10 AM

Count with multiple conditions (XML publisher)

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