Create new application with same ID as a previous application

10gR2, webtogo client. We are in a situation where due to what looks like some corruption issue/inability to publish correctly, we may need to drop our existing application and re-create. So the application will have a new applications.id. applications.dsn and applications.publication value. This will most certainly force all our offline users to do a re-install which we want to avoid. (correct? - I'm assuming the offline databases like a1121.odb are keyed to the 1121 applications.id)
Wondering if there is any way to re-create a new application but with the old application ID. One way we think we could do this is that after dropping the application, reset the mobileadmin APPIDS sequence so that it will pick up the ID of the old app when we create the new one. And so have the same applications.id. applications.dsn and applications.publication value.
However, wondering if we do this, we'd cause some other issue. Anyone have any ideas? (we have ticket open for the publication problem, but not much progress yet on that end.)

You may create new mode with the same transaction.
I'm not sure, that you may just "copy-paste" the content from one mode into another.
To create new mode with the same transaction, you may use the following code:
data: l_current_tcode like sy-tcode.
move sy-tcode to l_current_tcode.
 CALL FUNCTION 'TH_CREATE_MODE'
 EXPORTING
 transaktion = l_current_tcode
 del_on_eot = 1
* PARAMETERS = l_pars
 process_dark = 'X'
 IMPORTING
* mode =
 EXCEPTIONS
 max_sessions = 1
 internal_error = 2
 no_authority = 3
 OTHERS = 4.
 IF sy-subrc <> 0.
 MESSAGE ID sy-msgid TYPE sy-msgty NUMBER sy-msgno
 WITH sy-msgv1 sy-msgv2 sy-msgv3 sy-msgv4.
 ENDIF.
What transaction do you need to display?
Message was edited by: Cyrill Smirnov

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You have posted in the itunes U forum, where colleges, universities and museums post educational content for students.
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You shouldn't do any of that for troubleshooting. The test user account should be pristine. If you copy stuff from the old account, then you also copy whatever is causing a problem.
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Things You Can Do To Resolve Slow Downs
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Joshua Wein wrote:
yes, the same password.
I don't think that's possible... But who am I to say.
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(100546)

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hi
A new user created in OCS has only one default folder(Inbox).
I want to create new user with customized default folder.
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a new user has more than one default folder(Inbox,Outbox,Draft,Dustbin...)
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When sending messages, place a copy in Outbox
Keep message drafts in Draft
Move deleted messages to Dustbin
who know that?
thanks

The same reason that Apple and 3rd Party vendors put multi-size templates in one file I expect. I am trying to construct an in-house standard template for use in our company, and it is easier to manage if there is only one file to send to people rather than many - both initially and for subsequent edits / updates to the template.
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Hello,
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Vik

Error while trying to create new assignment with supervisor through API

Hi Experts,
I'am trying to create new assignment with supervisor for employee, but i'am facing this error:
=============================================================
ORA-20008: Error While Create new assignment..-20001
ORA-20001: The supervisor assignment that you have entered is invalid.
Please check that you have entered the supervisor,
that the supervisor assignment belongs to this supervisor and that the assignment is effective.
ORA-06512: at line 198
=============================================================
This is my script, (Oracle EBS 12.1.1)(DB 11):
DECLARE
v_user_id NUMBER;
v_res_id NUMBER;
v_res_appl_id NUMBER;
v_org_now_no_manager_warning BOOLEAN;
v_spp_delete_warning BOOLEAN;
v_other_manager_warning BOOLEAN;
v_tax_district_changed_warning BOOLEAN;
v_entries_changed_warning VARCHAR(4000);
v_person_id per_all_assignments_f.person_id %TYPE;
v_business_group_id hr_all_organization_units_tl.organization_id %TYPE;
v_people_group_id per_all_assignments_f.people_group_id %TYPE;
v_object_version_number per_all_assignments_f.object_version_number %TYPE;
v_special_ceiling_step_id per_all_assignments_f.special_ceiling_step_id %TYPE;
v_group_name pay_people_groups.group_name %TYPE;
v_ass_effective_start_date per_all_assignments_f.effective_start_date %TYPE;
v_effective_start_date per_all_assignments_f.effective_start_date %TYPE;
v_effective_end_date per_all_assignments_f.effective_end_date %TYPE;
v_assignment_id per_all_assignments_f.assignment_id %TYPE;
v_sup_assignment_id per_all_assignments_f.assignment_id %TYPE;
v_supervisor_assignment_id per_all_assignments_f.assignment_id %TYPE;
v_job_id per_jobs.job_id %TYPE;
v_grade_id per_grades.grade_id %TYPE;
v_location_id hr_locations_all.location_id %TYPE;
v_payroll_id pay_all_payrolls_f.payroll_id %TYPE;
v_pay_basis_id per_pay_bases.pay_basis_id %TYPE;
BEGIN
v_user_id := FND_GLOBAL.user_id ;
v_res_id := FND_GLOBAL.resp_id ;
v_res_appl_id:= FND_GLOBAL.resp_appl_id;
FND_GLOBAL.apps_initialize(v_user_id, v_res_id, v_res_appl_id);
BEGIN
SELECT organization_id
INTO v_business_group_id
FROM hr_all_organization_units_tl
WHERE name = 'Vision University'
AND language = 'US';
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20000,'Error While Retrieving (Business Group ID) Info...'||SQLCODE||' '||SQLERRM);
END;
FOR R IN (SELECT * FROM xx_assignment) LOOP
BEGIN
SELECT assignment_id , ass_f.object_version_number
INTO v_assignment_id , v_object_version_number
FROM per_all_assignments_f ass_f, per_all_people_f p_f
WHERE ass_f.person_id = p_f.person_id
AND ass_f.business_group_id = p_f.business_group_id
AND ass_f.business_group_id = v_business_group_id
AND p_f.employee_number = R.employee_number
AND TRUNC(p_f.effective_start_date)= TRUNC(ass_f.effective_start_date)
AND TRUNC(p_f.effective_end_date) = TRUNC(ass_f.effective_end_date);
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20001,'Error While Retrieving (Assignmet_ID) for employee..'||SQLCODE||' '||SQLERRM);
END;
BEGIN
SELECT job_id
INTO v_job_id
FROM per_jobs
WHERE trim(lower(name)) = trim(lower(r.employee_job))
AND business_group_id = v_business_group_id;
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20002,'Error While Retrieving (Job_ID) Info...'||SQLCODE||' '||SQLERRM);
END;
BEGIN
SELECT grade_id
INTO v_grade_id
FROM per_grades
WHERE trim(lower(name)) = trim(lower(r.employee_grade))
AND business_group_id = v_business_group_id;
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20003,'Error While Retrieving (Grade_ID) Info...'||SQLCODE||' '||SQLERRM);
END;
BEGIN
SELECT location_id
INTO v_location_id
FROM hr_locations_all
WHERE trim(lower(description))= trim(lower(r.employee_location))
AND business_group_id = v_business_group_id;
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20004,'Error While Retrieving (Location_ID) Info...'||SQLCODE||' '||SQLERRM);
END;
BEGIN
SELECT payroll_id
INTO v_payroll_id
FROM pay_all_payrolls_f
WHERE trim(lower(payroll_name)) = trim(lower(r.payroll_name))
AND business_group_id = v_business_group_id;
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20005,'Error While Retrieving (Payroll_ID) Info...'||SQLCODE||' '||SQLERRM);
END;
BEGIN
SELECT pay_basis_id
INTO v_pay_basis_id
FROM per_pay_bases
WHERE trim(lower(pay_basis)) = trim(lower(r.pay_basis))
AND business_group_id = v_business_group_id;
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20006,'Error While Retrieving (Pay_Basis_ID) Info...'||SQLCODE||' '||SQLERRM);
END;
BEGIN
SELECT person_id
INTO v_person_id
FROM per_all_people_f
WHERE employee_number = r.supervisor_number
AND business_group_id= v_business_group_id;
SELECT assignment_id
INTO v_sup_assignment_id
FROM per_all_assignments_f
WHERE person_id = v_person_id
AND business_group_id = v_business_group_id;
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20007,'Error While Retrieving (Assignmet_ID) for supervisor..'||SQLCODE||' '||SQLERRM);
end;
BEGIN
hr_assignment_api.update_emp_asg_criteria(p_effective_date => TRUNC(SYSDATE),
p_datetrack_update_mode => 'CORRECTION',
p_assignment_id => v_assignment_id,
p_validate => FALSE,
p_called_from_mass_update => NULL,
p_grade_id => v_grade_id,
p_position_id => NULL,
p_job_id => v_job_id,
p_payroll_id => null,--v_payroll_id,
p_location_id => v_location_id,
p_organization_id => v_business_group_id,
p_pay_basis_id => v_pay_basis_id,
p_segment1 => NULL,
p_segment2 => NULL,
p_segment3 => NULL,
p_segment4 => NULL,
p_segment5 => NULL,
p_segment6 => NULL,
p_segment7 => NULL,
p_segment8 => NULL,
p_segment9 => NULL,
p_segment10 => NULL,
p_segment11 => NULL,
p_segment12 => NULL,
p_segment13 => NULL,
p_segment14 => NULL,
p_segment15 => NULL,
p_segment16 => NULL,
p_segment17 => NULL,
p_segment18 => NULL,
p_segment19 => NULL,
p_segment20 => NULL,
p_segment21 => NULL,
p_segment22 => NULL,
p_segment23 => NULL,
p_segment24 => NULL,
p_segment25 => NULL,
p_segment26 => NULL,
p_segment27 => NULL,
p_segment28 => NULL,
p_segment29 => NULL,
p_segment30 => NULL,
p_employment_category => NULL,
p_concat_segments => NULL,
p_grade_ladder_pgm_id => NULL,
p_supervisor_assignment_id => v_sup_assignment_id,
p_people_group_id => v_people_group_id,
p_object_version_number => v_object_version_number,
p_special_ceiling_step_id => v_special_ceiling_step_id,
p_group_name => v_group_name,
p_effective_start_date => v_ass_effective_start_date,
p_effective_end_date => v_effective_end_date,
p_org_now_no_manager_warning => v_org_now_no_manager_warning ,
p_spp_delete_warning => v_spp_delete_warning,
p_entries_changed_warning => v_entries_changed_warning,
p_tax_district_changed_warning => v_tax_district_changed_warning,
p_other_manager_warning => v_other_manager_warning);
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20008,'Error While Create new assignment..'||SQLCODE||' '||SQLERRM);
END;
END LOOP;
COMMIT;
END;
Thank you & Best Regards

I think this is essentially saying that the Supervisor Assignment is wrong or no longer effective. Looking at your SQL to fetch the Supervisor Assignment there are a number of potential issues. This is what you've currently got:
SELECT person_id
INTO v_person_id
FROM per_all_people_f
WHERE employee_number = r.supervisor_number
AND business_group_id= v_business_group_id;
SELECT assignment_id
INTO v_sup_assignment_id
FROM per_all_assignments_f
WHERE person_id = v_person_id
AND business_group_id = v_business_group_id;
Potential Problems/Clarifications
1. What is r.supervisor_number, what does it contain and how is it derived? I can't see that anywhere else in the block...
2. Is there a chance that r.supervisor_number is referencing an employee who has left, ie, now an ex-employee?
3. The SELECT statement that fetches the assignment_id does not perform any date-effective restrictions, which means you might be lucky enough to fetch the person's current assignment. But you might also fetch an old or future-dated assignment.
4. The SELECT statement that fetches the assignment_id does not restrict the type of assignment, so if this manager has applied for a job (ie, they have an applicant assignment) or some other type of non-employee assignment you might be picking that up.
This would work better for you:
SELECT paaf.assignment_id
INTO v_sup_assignment_id
FROM per_all_people_f papf
,per_all_assignments_f paaf
WHERE papf.employee_number = r.supervisor_number
AND papf.business_group_id = v_business_group_id
AND nvl(papf.current_employee_flag, 'N') = 'Y'
AND trunc(sysdate) BETWEEN
papf.effective_start_date AND papf.effective_end_date
AND papf.person_id = paaf.person_id
AND paaf.assignment_type = 'E'
AND paaf.primary_flag = 'Y'
AND trunc(sysdate) BETWEEN
paaf.effective_start_date AND paaf.effective_end_date;
If it doesn't return a row it means that the supervisor (or whatever employee is returned by r.supervisor_number) is not active as at sysdate and cannot be used. Note that this SQL only applies for employees. If you can have Contingent Workers as supervisors in your implementation then this needs tweaking.
Does that help?

How to create new docs with custom swatch palette?

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How To Create Table View With Same Column name But Different Table?

Hi All,
I have the problem to create a tableview with same column name but in different table.
The Table that i have:-
Table - PAC051MPROFORMA
Column - mrn,visitid
Table - PAC051TPROFORMA
Column - mrn,visitid
Table - PAC052MTRANSBILL
Column - mrn,visitid
Then i want to create a table view to view that table. This is my SQL
CREATE VIEW pacviewproforma (mrn,visitid,mrn,visitid,mrn,visitid)
As Select PAC051MPROFORMA.mrn,PAC051MPROFORMA.visitid,PAC051TPROFORMA.mrn,PAC051TPROFORMA.visitid,PAC052MTRANSBILL.mrn,PAC052MTRANSBILL.visitid
where
*(a.PAC051MPROFORMA.mrn=PAC051TPROFORMA.mrn)*
and
*(a.PAC051TPROFORMA.mrn=PAC052TRANSBILL.mrn)*
That SQL Return this error = ORA-00957: duplicate column name
Then I modify that SQL to
CREATE VIEW pacviewproforma (mrn,visitid)
As Select PAC051MPROFORMA.mrn,PAC051MPROFORMA.visitid,PAC051TPROFORMA.mrn,PAC051TPROFORMA.visitid,PAC052MTRANSBILL.mrn,PAC052MTRANSBILL.visitid
where
*(a.PAC051MPROFORMA.mrn=PAC051TPROFORMA.mrn)*
and
*(a.PAC051TPROFORMA.mrn=PAC052TRANSBILL.mrn)*
This time this error return = ORA-01730: invalid number of column names specified
What should i do?
Thanks...

Hi,
SQL> CREATE VIEW pacviewproforma (mrn,visitid,mrn,visitid,mrn,visitid)
2 As Select
3 PAC051MPROFORMA.mrn,
4 PAC051MPROFORMA.visitid,
5 PAC051TPROFORMA.mrn,
6 PAC051TPROFORMA.visitid,
7 PAC052MTRANSBILL.mrn,
8 PAC052MTRANSBILL.visitid
9 from PAC051MPROFORMA,PAC051TPROFORMA,PAC052MTRANSBILL
10 where
11 (PAC051MPROFORMA.mrn=PAC051TPROFORMA.mrn)
12 and
13 (PAC051TPROFORMA.mrn=PAC052MTRANSBILL.mrn);
CREATE VIEW pacviewproforma (mrn,visitid,mrn,visitid,mrn,visitid)
ERROR at line 1:
ORA-00957: duplicate column namePlease give different names to each column.
Something like this..
SQL> CREATE OR REPLACE VIEW pacviewproforma (MPROFORMA_mrn,MPROFORMA_visitid,TPROFORMA_mrn,TPROFORMA
_visitid,MTRANSBILL_mrn,MTRANSBILL_visitid)
2 As Select
3 PAC051MPROFORMA.mrn,
4 PAC051MPROFORMA.visitid,
5 PAC051TPROFORMA.mrn,
6 PAC051TPROFORMA.visitid,
7 PAC052MTRANSBILL.mrn,
8 PAC052MTRANSBILL.visitid
9 from PAC051MPROFORMA,PAC051TPROFORMA,PAC052MTRANSBILL
10 where
11 (PAC051MPROFORMA.mrn=PAC051TPROFORMA.mrn)
12 and
13 (PAC051TPROFORMA.mrn=PAC052MTRANSBILL.mrn);
View created.
SQL> DESC pacviewproforma;
Name                                      Null?    Type
MPROFORMA_MRN                                      NUMBER
MPROFORMA_VISITID                                  NUMBER
TPROFORMA_MRN                                      NUMBER
TPROFORMA_VISITID                                  NUMBER
MTRANSBILL_MRN                                     NUMBER
MTRANSBILL_VISITID                                 NUMBER
ORA-01730: invalid number of column names specifiedThe list of column nmae you specified during the CREATE VIEW should match with the SELECT list of the view.
Twinkle

How to create logical directories with same name on two databases

Hi,
OS: Windows
Oracle Version : 10g
I have to databases in one oracle home. I have created some logical directories in one database. When I am trying to create logical directories with same name in another database, it is overwriting the first database directory paths with the second one
Can't we create directories with same name but different path in two databases on one machine?
Pls suggest me on this
Regards,
Vijay

I am trying to create logical directory using CREATE
DIRECTORY statement. I am very much aware that the
create directory statement doesn't create directory
on OS. But we can attach the physical directory on OS
to logical directory in oracle
My requirement is to create logical directories in
oracle mapping the OS directories. Both the
databases, wil have same logical directory names but
different OS directory mappingsIf I understand you correctly, you can do this:
On DB 1
CREATE OR REPLACE DIRECTORY same_dir_name as 'C:\myoracle\mydir1';
On DB 2
CREATE OR REPLACE DIRECTORY same_dir_name as 'D:\myoracle\mydir2';
What stops you from doing that ?
Note: If what you have is one database but different connections, then you are connecting to one database. The above second statement will drop and replace with the first one

Create New user with ...

Hi all
I need to create new user with the following privileges :
1- access any table data (read only)
2- access the tables structure (read only)
3- access the tables relations (read only)
thanx in advance

Hi,
giggs11 wrote:
I did the following :
create user youruser identified by yourpassword;
grant connect to youruser;
grant SELECT_CATALOG_ROLE to username;
but I cann't see my tables
there is no erroExample :-
Step 1:-
sql> Conn system/manager@orcl;
connected.
step 2:-
SQL> create user trial identified by trial;
User created.
Step 3:-
SQL> grant connect to trial;
Grant succeeded.
SQL>grant SELECT_CATALOG_ROLE to trial;
Grant succeeded.
SQL> grant select any table to trial;
Grant succeeded.
Step 4:
SQL> conn trial/trial@orcl;
Connected.
SQL> select * from tab;
no rows selected
Step 5:
SQL> select * from scott.dept;
DEPTNO DNAME LOC
10 ACCOUNTING NEW YORK
20 RESEARCH DALLAS
30 SALES CHICAGO
40 OPERATIONS BOSTON
Step 6:
SQL> desc scott.dept;
Name Null? Type
DEPTNO NOT NULL NUMBER(2)
DNAME VARCHAR2(14)
LOC VARCHAR2(13)
you must read about privileges..
http://download.oracle.com/docs/cd/B10501_01/server.920/a96521/privs.htm
Regards
S.Azar
DBA
"Question is Unquestionable"
Edited by: azarmohds on Aug 15, 2009 6:28 AM
Edited by: azarmohds on Aug 15, 2009 6:32 AM

Bug report about create new footprint with Rounded rectangle in 3D info Bottom

I create new footprint with rounded rectangle in 3D info Bottom,the rounded rectangle must be in bottom,but In fact,the rounded rectangle
created in top layer.i think it's wrong.
I used ultiboard 10.1.357.

Hi,
Thank you for reporting this. This has been a long standing issue with Ultiboard and we are looking into resolving this.
There is a work around although a very inconvenient one. You can set the height to what you require and use a negative offset to move the shape to the other side of the board. The 3D shape will appear on the other side, but in reality is just shifted, not mirrored.
Hope that helps. We apologize for the inconvenience.
Yi
Software Developer
National Instruments - Electronics Workbench Group

IDCS3 - Paste image into new frame with same cropping offsets?

Anyone know if there's a better way do to this? It used to work in CS2, and (I know this comment won't be popular, but since half the studio I'm trying to convert brings up this point, I'll pass it along <G>), it's always worked in Quark. <G> http://indesignsecrets.com/paste-image-into-new-frame-with-same-cropping-offsets.php Be nice to get this to work without having to jump through hoops. (And please, please don't tell me I need to update to CS4 to get this basic functionality BACK). k.

Thanks, Rob. Unfortunately, I got a new error with the latest script you posted (sorry--not trying to be a pest!!). It says,
Apple Script Error!
Error Number: -2753
Error String: The variable myRend is not defined.
(One thing that's different is I'm working on a different machine than I was the first day I posted about this, but I'm using the exact same version of InDesign. Would this make a difference? I forgot to copy the original script file from the other computer before coming to work today... If I need to do that, I can.)
Thanks for your continued help!

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