Creating an XML document from a DTD in Java

Hi All,
I need help on the following requirement very badly. Pls help me.
I have a requirement to implement with java and XML. I am quit new to XML.Can any of you pls help me.
I have a DTD file. I need to generate XML document from it using java code. I have to use DTD as a template to generate my XML document.
After going through WEB sites, I understtod that, we have to user Java API JAXB for my requirement. But I could not find JAXB.jar anywhere.
I need to know the following inforamtion ....
1. Is my understanding of using JAXB for my requirement is correct?
2. Where can I get JAXB.jar?
3. What are the steps to create XML document from a DTD in Java?
If can give me a sample code for this would help me a lot.
Pls pls reply me. Your help is greatly appreciated.
Thanks in Advance.
Regards,
Gayathri.

hi Gayathri,
iam currently working in the same field.
firs download jaxb from this link:
http://java.sun.com/xml/downloads/jaxb.html
first u need to marshall it.
cheers
shashi

Similar Messages

How to Create an XML document from XSQL servlet which follows a particular DTD struct

how to Create an XML document from XSQL servlet which follows a particular DTD structure.Could anyone send me a sample code for this.

You'll need to associate an XSLT transformation with your XSQL page that transforms the canonical result into your DTD-valid format.
For example, given an XSQL page like:
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="rss.xsl" ?>
<xsql:query max-rows="3" connection="demo" xmlns:xsql="urn:oracle-xsql">
select title,id,description,url,to_char(timestamp,'Mon DD') timestamp
from site_entry
order by id desc
</xsql:query>and an "rss.xsl" stylesheet that looks like this:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes" doctype-system="rss-0.91.dtd"/>
<xsl:template match="/">
<xsl:for-each select="ROWSET/ROW">
<rss version="0.91">
<channel>
<title>Do You XML?</title>
<link>http://xml.us.oracle.com</link>
<description>Oracle XML Website Demo</description>
<language>en-us</language>
<xsl:for-each select="ITEM">
<item>
<title><xsl:value-of select="TITLE"/></title>
<link><xsl:value-of select="URL"/></link>
<description><xsl:value-of select="DESCRIPTION"/></description>
</item>
</xsl:for-each>
</channel>
</rss>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>You produce DTD-valid output against the rss-0.91.dtd DTD that looks like:
<?xml version = '1.0' encoding = 'UTF-8'?>
<!DOCTYPE rss SYSTEM "rss-0.91.dtd">
<rss version="0.91">
<channel>
<title>Do You XML?</title>
<link>http://xml.us.oracle.com</link>
<description>Oracle XML Website Demo</description>
<language>en-us</language>
</channel>
</rss>
<rss version="0.91">
<channel>
<title>Do You XML?</title>
<link>http://xml.us.oracle.com</link>
<description>Oracle XML Website Demo</description>
<language>en-us</language>
</channel>
</rss>
<rss version="0.91">
<channel>
<title>Do You XML?</title>
<link>http://xml.us.oracle.com</link>
<description>Oracle XML Website Demo</description>
<language>en-us</language>
</channel>
</rss>

How to create an XML document from a String.

Can anyone help,
 In the Microsoft XML Document DOM there is a load function load(string) which will create an XML document, but now we are switching to Java and I do not know how to create and XML document from a string, this string �xml document� is passed to my program from a webservice and I need to read several xml elements form it in a web server.
This string is a well formatted XML document:
<?xml version="1.0" encoding="UTF-8"?>
<Countries NumberOfRecords="1" LanguageID="en-us">
 <Country>
 <CountryCode>AU</CountryCode>
 <CountryName>AUSTRALIA</CountryName>
 </Country>
</Countries>

Thanks PC!
I made it work using:
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
factory.setIgnoringComments(true); // We want to ignore comments
// Now use the factory to create a DOM parser
DocumentBuilder parser = factory.newDocumentBuilder();
//TransformThisStringBuffer is a string buffer wich contain the 'XML document (String)'
InputStream in = new ByteArrayInputStream(TransformThisStringBuffer.toString().getBytes());
// Parse the InputStream and build the document
Document document = parser.parse(in);
But which one is faster InputSource or InputStream, were would you put the "new InputSource(new StringReader(yourString))" in the above code?

Create an XML document from a HTML form???

Good morning, is it possible to create an XML document from a HTML form
if yes, can someone tell me how to proceed exactely, I would be very thankful!

Hi,
A very simple intro at this link. Apologies for anything unclear.
http://cswww.essex.ac.uk/TechnicalGroup/TechnicalHelp/xmlCreate.htm
best
kev

How to use java to create an XML document from an SQL database?

Hi,
I'm a complete novice at XML and have only recently started programming in Java.
I'm currently trying to develop a package in Java 1.1.8 which requires a set of very specifically formatted XML documents. These documents would need to be updated regularly by people with no knowledge of Java and I would like to make it as simple as possible.
Since the data will already be in an SQL database, I thought it might be possible to generate the XML documents from the data using a small Java application, but I'm not too sure how to go about this or if this is even possible! Any help or pointers in the right direction would be very much appreciated.
Louise

Do you have the option of upgrading to a newer version of the JDK?
JAXB does what you are wanting very easily. Also there are tools if you don't want to write your own. JAXB is available as early release on Sun's site as is the newest JDK. Otherwise, you have to design a factory and interface that will do this for you (which is what JAXB basically is in a very simplified view).

Create single XML document from multiple queries

hi all!
being a new programmer in XML world,my question might sound a bit stupid but your answers would mean a world to me. i have to generate a single XML document from my database by querying more than one table. for example i have 3 tables i.e HR_EMP_NAME, HR_PRODUCTS_DETAIL, HR_PAYROLL_SUMMARY. all three tables have completely different columns except one ID column which is a foreign kay from HR_MASTER_LIST. i want to get any insert operation on these tables as a single document. so far as i have studied, one option is to generate XMLDoc using XSU and then add child nodes using JAXP but i am ot geting the logic right.
please do reply.
thanks a lot
usman

This is an SQL/XML based answer so how much it helps you is hard to say, but it would be one option. You can have the SQL statement build the XML for you as shown by this simple example.
SELECT XMLElement("root",
 XMLForest(emp.dummy AS "emp_name",
 prod.dummy AS "prod_lvl",
 pay.dummy AS "pay_scale"))
FROM dual emp,
 dual prod,
 dual pay
WHERE emp.dummy = prod.dummy
AND emp.dummy = pay.dummy;which produces (formatted for human readability)
<root>
<emp_name>X</emp_name>
<prod_lvl>X</prod_lvl>
<pay_scale>X</pay_scale>
</root>Whether that works with what you are trying to do via Java you will have to decide.

Creating an xml document from filenames of selected files

Hey guys, I am totally new to automator and applescript so please be kind!
I have an xml/flash image portfolio website which has image galleries. Each gallery has an xml document which specifies a thumbnail and full size photo to be displayed in the gallery. If I want to make a new gallery I have to make a new xml document and enter all the filenames of the images I want to display in the gallery. ( I guess you can see where this is going).
This is fine if I have 10 images in the gallery but if I want to make a gallery with 350 images in then it could get pretty tedious.
What I would love to be able to do is select a group of images and then have a script or automator action that can copy the files names and create a new gallery xml document containing the relevant code with all the files names. Ideally then saving the gallery with a sequential filename.
Tying this into the new contextual services menu in snow leopard would really make the task incredibly easy.
Is this possible? I'm not scared of learning how to do this therefore some pointers in the right direction would be great.
Thanks,
Chris

Thanks Camalot,
I was just thinking of selecting images from the finder but if this could be integrated into Aperture's export dialog that would be even better.
this is the xml:
<?xml version="1.0" encoding="utf-8"?>
<gallery thumbwidth="220" thumbheight="138" columns="3" gap="4">
<item>
<ID>1</ID>
<title><![CDATA[Title 1]]></title>
<desc><![CDATA[This is description 1. This is a colourful text. This is a <a href="http://www.flashden.net/user/iceonflames">link</a>. This is italic text. This is bold text. This is bold italic text. This text is styled by a CSS document. ]]></desc>
<thumb>images/thumbs/7.jpg</thumb>
<image>images/big/7.jpg</image>
</item>
<item>
<ID>2</ID>
<thumb>images/thumbs/8.jpg</thumb>
<image>images/big/8.jpg</image>
</item>
<item>
<ID>3</ID>
<title><![CDATA[Title 3]]></title>
<desc><![CDATA[This is description 3. This is a colourful text. This is a <a href="http://www.flashden.net/user/iceonflames">link</a>. This is italic text. This is bold text. This is bold italic text. This text is styled by a CSS document. ]]></desc>
<thumb>images/thumbs/9.jpg</thumb>
<image>images/big/9.jpg</image>
</item>
</gallery>

How can I create a XML document from a DOM?

Hello,
I'm using the parser for C, version 2 in the DOM modus. How can I dump the object model to a (XML) string after changing some field?
Do I need to create my own function or is there a function in the DOM interface??

You need to create your own function. The Java XML parser has such a function
and we'll probably add one in a future release as well.
Oracle XML Team

Best way to generate the XML files from a DTD file

Hey,
I am writing an application that needs to convert a complicated data structure into an xml file. I have design a DTD file that describes the data structure.
My question is what is the best, most efficient way to covert the data structures (objects) into the XML files with a DTD file.
Thank you very much.
Candy

Convert the DTd to an XML Schema. Generate java classes from Schema with Jaxb. Create an XML document from the java classes.

Heap space error while creating XML document from Resultset

I am getting Heap space error while creating XML document from Resultset.
It was working fine from small result set object but when the size of resultset was more than 25,000, heap space error
I am already using -Xms32m -Xmx1024m
Is there a way to directly write to xml file from resultset instead of creating the whole document first and then writing it to file? Code examples please?
here is my code:
stmt = conn.prepareStatement(sql);
result = stmt.executeQuery();
result.setFetchSize(999);
Document doc = JDBCUtil.toDocument(result, Application.BANK_ID, interfaceType, Application.VERSION);
JDBCUtil.write(doc, fileName);
public static Document toDocument(ResultSet rs, String bankId, String interfaceFileType, String version)
 throws ParserConfigurationException, SQLException {
 DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
 DocumentBuilder builder = factory.newDocumentBuilder();
 Document doc = builder.newDocument();
 Element results = doc.createElement("sims");
 results.setAttribute("bank", bankId);
 results.setAttribute("record_type", "HEADER");
 results.setAttribute("file_type", interfaceFileType);
 results.setAttribute("version", version);
 doc.appendChild(results);
 ResultSetMetaData rsmd = rs.getMetaData();
 int colCount = rsmd.getColumnCount();
 String columnName="";
 Object value;
 while (rs.next()) {
 Element row = doc.createElement("rec");
 results.appendChild(row);
 for (int i = 1; i <= colCount; i++) {
 columnName = rsmd.getColumnLabel(i);
 value = rs.getObject(i);
 Element node = doc.createElement(columnName);
 if(value != null)
 node.appendChild(doc.createTextNode(value.toString()));
 else
 node.appendChild(doc.createTextNode(""));
 row.appendChild(node);
 return doc;
public static void write(Document document, String filename) {
 //long start = System.currentTimeMillis();
 // lets write to a file
 OutputFormat format = new OutputFormat(document); // Serialize DOM
 format.setIndent(2);
 format.setLineSeparator(System.getProperty("line.separator"));
 format.setLineWidth(80);
 try {
 FileWriter writer = new FileWriter(filename);
 BufferedWriter buf = new BufferedWriter(writer);
 XMLSerializer FileSerial = new XMLSerializer(writer, format);
 FileSerial.asDOMSerializer(); // As a DOM Serializer
 FileSerial.serialize(document);
 writer.close();
 } catch (IOException ioe) {
 ioe.printStackTrace();
 //long end = System.currentTimeMillis();
 //System.err.println("W3C File write time :" + (end - start) + " " + filename);
 }

you can increase your heap size..... try setting this as your environment variable.....
variable: JAVA_OPTS
value: -Xms512m -Xmx1024m -XX:PermSize=256m -XX:MaxPermSize=512m

Creating new analysis gives "Error loading XML Document from ..."

Trying to create analysis and getting "Error loading XML Document from saw.dll/answers/answersproperties.xml?fmapId=S1clug.
The response given was:" after choosing subject area. Analysis editor is opened but Subject Areas is empty and can't do anything.
The problem is on Mozilla 12 (16.0.2, 17.0.1) and IE 8. Chrome works fine.
My system is Win 7, BI 11.1.1.6.0 is on Oracle Linux (and by the way Mozilla from Linux system works fine)
What could be the reason of this?
Edited by: 898973 on 4/12/2012 15:11

Reinstalling Mozilla with "Remove personal data" option checked resolved the problem.

How to create an XML file from scratch ?

Hi all,
I'm afraid that I will seem dummy, but I think I really misunderstand something or I'm trying to do something that is not possible...
I would like to create a XML file containing the following:<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="pl.xsl"?>
<!DOCTYPE playlist SYSTEM "pl.dtd">
<playlist id="2">
</playlist>I really need to have both the stylesheet and the DOCTYPE declarations... Does anyone know if this is possible ?
To create the XML Document, I am using the DocumentBuilder object from javax.xml package (jaxp-1.2-ea2). I think this, at least, is correct.
To print out the XML document I have tried to use :
- the Transformer from javax.xml package (jaxp-1.2-ea2) but I could obtain only the DOCTYPE declaration.
- the Serializer from Xerces parser (version 2.0.1) to print out the Document I am creating with the jaxp, but I was able only to obtain the stylesheet declaration...
So far I have just understand that there is a difference between Serializer and Transformer (one is serializing, and the other is transforming ;-)), but I couldn't figure out which one would be suitable to produce the XML file above...
I would really appreciate if one could help me with that ;-)
Thanks,
Karau

Could send me an example ?
For the moment I am using Transformer in that way:
 TransformerFactory tfactory = TransformerFactory.newInstance();
 try {
 Transformer transformer = tfactory.newTransformer();
 DOMSource source = new DOMSource(playlistDoc.getDocumentElement());
 StreamResult res = new StreamResult(new File(path));
 transformer.setOutputProperty(OutputKeys.DOCTYPE_SYSTEM, PL_DTD);
 transformer.setOutputProperty(OutputKeys.INDENT, "yes");
 transformer.transform(source, res);
 catch (TransformerConfigurationException tce) {
 throw tce;
 catch (TransformerException te) {
 throw te;
 }

Create an XML file from XSD file in JDeveloper

Hi,
I am working on XML DTD and XSD to validate xml file using JDeveloper.
1. How we can create xml file from XSD in JDeveloper.
2. How to design content model very easily..
3. where can I learn XSD easily.. any URL
can anyone help out..
with regards
Abu Sufian

The XML node in the new gallery has an option to create XML document from schema
See this demo:
http://www.oracle.com/technology/products/jdev/viewlets/1013/xml_viewlet_swf.html
There are several places on the Web that teaches XSD
for example: http://www.w3schools.com/schema/

Create a xml file from an internal table: CALL TRANSFORMATION

Hello gurus,
I want to create a xml file using data from scustom table. I will create an internal table and will select some records to it.
I searched the forum and i discovered the call transformation, but when i execute the example program at the CALL TRANSFORMATION shows a dump screen.
How we create a xml file from internal table??
Please help me. I will mark the useful answers.

I'm using if_ixml class to create xml documents
TYPES: BEGIN OF xml_line,
         data(256) TYPE x,
       END OF xml_line.
DATA: o_ixml          TYPE REF TO if_ixml,
      o_document      TYPE REF TO if_ixml_document,
      o_element       TYPE REF TO if_ixml_element,
      o_streamfactory TYPE REF TO if_ixml_stream_factory,
      o_ostream       TYPE REF TO if_ixml_ostream,
      o_renderer      TYPE REF TO if_ixml_renderer.
DATA: t_xml_table     TYPE TABLE OF xml_line,
      v_xml_size      TYPE i.
o_ixml = cl_ixml=>create( ).
o_document = o_ixml->create_document( ).
* The o_document have a set of methods to add elements, attributes, etc.
o_element = o_document->create_simple_element(
                  name = 'RootNode'
                  value = 'some text'
                  parent = o_document ).
o_streamfactory = o_ixml->create_stream_factory( ).
o_ostream = o_streamfactory->create_ostream_itable( table = t_xml_table ).
o_renderer = o_ixml->create_renderer( ostream = o_ostream document = o_document ).
o_renderer->render( ).
v_xml_size = o_ostream->get_num_written_raw( ).
CALL METHOD cl_gui_frontend_services=>gui_download
EXPORTING
    bin_filesize = v_xml_size
    filename     = 'C:a.xml'
    filetype     = 'BIN'
CHANGING
    data_tab     = t_xml_table.

XML Document from XML Schema Bug

When an XML document is generated from an XML Schema the XML document does not have all the elements specified in the XML Schema. The XML document only has the root element.
1. Register an XML Schema.
2. Create an XML document with File>New>General>XML>XML Document from XML Schema. The "Generate only Required Elements" is unchecked.
3. The XML document has only the root element.
In JDeveloper 10.1.3 all the elements in the XML Schema get generated.

Also, the component palette for the XML document generated from the XML Schema does not list all the elements in the XML Schema, only the root element is listed. Even if elements are specified as required in the XML Schema with minOccurs="1" and the "Generate only Required Elements" checkbox is selected only the root element gets generated.

Creating an XML document from a DTD in Java

Similar Messages

Maybe you are looking for