Creating an xml file from the Basic java Object

how to create an XML file using the values available in the object with reference to an xsd or dtd file..
(OR )
is it possible to write the contents of an object to an xml file without knowing the dtd or xsd file .......

how to create an XML file using the values available in the object with reference to an xsd or dtd file..
(OR )
is it possible to write the contents of an object to an xml file without knowing the dtd or xsd file .......

Similar Messages

  • How do I create individual xml files from the parsed data output of a xml file?

    I have written a program (DOM Parser) that parses data from a XMl File. I would like to create an individual file with the corresponding name for each set of data parsed from the xml document. If the parsed output is Single, Double, Triple, I would like to create an individual xml file (Single.xml, Double.xml, Triple.xml)with those corresponding names. How do I create the xml files and give each file the name of my parsed data output? Thanks in advance for your help.
    import java.io.IOException;
    import javax.xml.parsers.DocumentBuilder;
    import javax.xml.parsers.DocumentBuilderFactory;
    import javax.xml.parsers.ParserConfigurationException;
    import org.w3c.dom.Document;
    import org.w3c.dom.Element;
    import org.w3c.dom.Node;
    import org.w3c.dom.NodeList;
    import org.xml.sax.SAXException;
    public class MyDomParser {
      public static void main(String[] args) {
      DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
      try {
      DocumentBuilder builder = factory.newDocumentBuilder();
      Document doc = builder.parse("ENtemplate.xml");
      doc.normalize();
      NodeList rootNodes = doc.getElementsByTagName("templates");
      Node rootNode = rootNodes.item(0);
      Element rootElement = (Element) rootNode;
      NodeList templateList = rootElement.getElementsByTagName("template");
      for(int i=0; i < templateList.getLength(); i++) {
      Node theTemplate = templateList.item(i);
      Element templateElement = (Element) theTemplate;
      System.out.println("Template" + ": " +templateElement.getAttribute("name")+ ".xml");
      } catch (ParserConfigurationException e) {
      // TODO Auto-generated catch block
      e.printStackTrace();
      } catch (SAXException e) {
      // TODO Auto-generated catch block
      e.printStackTrace();
      } catch (IOException e) {
      // TODO Auto-generated catch block
      e.printStackTrace();

    Ive posted the new code but now I'm getting a FileAlreadyExistException error. How do I handle this exception error correctly in my code?
    import java.io.IOException;
    import java.nio.file.FileAlreadyExistsException;
    import java.nio.file.Files;
    import java.nio.file.Paths;
    import javax.xml.parsers.DocumentBuilder;
    import javax.xml.parsers.DocumentBuilderFactory;
    import javax.xml.parsers.ParserConfigurationException;
    import org.w3c.dom.Document;
    import org.w3c.dom.Element;
    import org.w3c.dom.Node;
    import org.w3c.dom.NodeList;
    import org.xml.sax.SAXException;
    public class MyDomParser {
      public static void main(String[] args) {
      DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
      try {
      DocumentBuilder builder = factory.newDocumentBuilder();
      Document doc = builder.parse("ENtemplate.xml");
      doc.normalize();
      NodeList rootNodes = doc.getElementsByTagName("templates");
      Node rootNode = rootNodes.item(0);
      Element rootElement = (Element) rootNode;
      NodeList templateList = rootElement.getElementsByTagName("template");
      for(int i=0; i < templateList.getLength(); i++) {
      Node theTemplate = templateList.item(i);
      Element templateElement = (Element) theTemplate;
      System.out.println(templateElement.getAttribute("name")+ ".xml");
      for(int i=0; i < templateList.getLength(); i++) {
      Node theTemplate = templateList.item(i);
      Element templateElement = (Element) theTemplate;
      String fileName = templateElement.getAttribute("name") + ".xml";
      Files.createFile(Paths.get(fileName));
      System.out.println("File" + ":" + fileName + ".xml created");
      } catch (ParserConfigurationException e) {
      // TODO Auto-generated catch block
      e.printStackTrace();
      } catch (SAXException e) {
      // TODO Auto-generated catch block
      e.printStackTrace();
      } catch (IOException e) {
      // TODO Auto-generated catch block
      e.printStackTrace();

  • How to create a xml file from the jsp page?

    I'm a beginner of the develop xml,my question like this,
    there has a jsp page,some parameters in it,I wanna get the parameters and create a xml file,so,what parser method should I use?
    And how to create a new xml file,when the file haven't exist at first?
    pls give some code,thanks.

    a ggod link for u http://www.theserverside.com/resources/article.jsp?l=JSP-XML2

  • How I can create a XML file from java Aplication

    How I can create a XML file from java Aplication
    whith have a the following structure
    <users>
    <user>
    <login>anyName</login>     
    <password>xxxx</password>
    </user>
    </users>
    the password label must be encripted
    accept any suggestion

    Let us assume you have all the data from the jsp form in an java bean object..
    Now you want a xml file. This can be acheived in 2 ways
    1. Write it into a file using java.io classes. Say you have a class with name
    write("<name>"+obj.getName+</name>);
    bingo you have a flat file with the xml
    2. Use data binding to do the trick
    will recommend JiBx and Castor for the 2nd option
    Regards,
    Rajagopal

  • HO w to use SAX parser to create an XML file on the fly

    Hi All,
    Currently I am using the DOM parser to create an XML file from a text file. But as the DOM takes much memory and inefficient, I need to convert the DOM translator to SAX translator. Can I do that ?? If YES then how to go about that and if NO then what may be the workaround for that.
    Please help me out
    Thanx in advance
    kaushik

    Incidentally, look at this thread:
    http://forum.java.sun.com/thread.jsp?forum=34&thread=252415
    It has an example of how to transform an XML file via XSLT. If you change this to use the zero-argument form of newTransformer, it will apply the "identity transformation" to your input, thus outputting your XML in valid form. Now you just need to figure out how to provide SAX input to this, and the JAXP download includes an example of that.

  • Creating an xml file from recordset

    Hi...
    XML newbie here - so.
    Is it possible to create and xml file from a recordset?
    I need to create a datafeed of our e-commerce products.
    Also, some of the db data contains HTML Code (product
    description field),
    how will this effect the xml file?
    Another problem is that my xml file needs to contain url's
    for the products
    and product images. My ASP pages contain these URL in hard
    code and then
    pull the actual file names from the db
    Hope that makes some sense
    Thanks for any help
    Andy

    Hi David
    Thanks for your help.
    I think it will have to be option 1 as i am using Access DB.
    I don't know how to go about it but will serach good old
    Google.
    Here is my recordset below, that pulls the required data from
    Access.
    The product and product image URL's need to be in the xml
    file but only the
    product image name and product id are in the database, e.g
    image name
    (imagename.jpg) productid (21)
    The actual URL's are hardcoded in my ASP pages, e.g <img
    src="products/medium/<%=(RSDetails.Fields.Item("Image").Value)%>"
    Not sure if this makes things any clearer :-|
    Thanks Again
    Andy
    <%
    Dim RSdatafeed
    Dim RSdatafeed_numRows
    Set RSdatafeed = Server.CreateObject("ADODB.Recordset")
    RSdatafeed.ActiveConnection = MM_shoppingcart_STRING
    RSdatafeed.Source = "SELECT Products.Product,
    Products.Description,
    Products.Image, Products.image2, Products.ListPrice,
    Products.Price,
    Products.xml_feed, Manufacturers.Manufacturer,
    Shipping.ShippingCost FROM
    Shipping, Products INNER JOIN Manufacturers ON
    Products.ManufacturerID =
    Manufacturers.ManufacturerID WHERE
    (((Products.xml_feed)=No));"
    RSdatafeed.CursorType = 0
    RSdatafeed.CursorLocation = 2
    RSdatafeed.LockType = 1
    RSdatafeed.Open()
    RSdatafeed_numRows = 0
    %>
    "DEPearson" <[email protected]> wrote in
    message
    news:[email protected]...
    > Andy,
    >
    > There are two ways you can create a xml file from a
    recordset
    >
    > 1. Is to code it using Server.CreateObject(XMLDOM)
    > 2. If you are using SQL server 2005, just request the RS
    returns as XML
    > data. using FOR XML AUTO after the where cause ( the
    best way with 2005
    > and
    > higher sql server)
    >
    > The db data containing HTML code should not effect your
    xml file, unless
    > it
    > is bad markup. You could wrap the data with
    <![CDATA[the data or html
    > markup, or javascript]]>
    >
    > If the url is a recordset field, then it will return
    with the xml data.
    > If
    > not you can create a storage procedure that will build
    your URL from the
    > data
    > in the database.
    >
    > It is best to use storage procedure (SP )for security
    reason when pulling
    > data
    > from a MS Sql server, make all calls to the database in
    a SP. Also be sure
    > to
    > validate the values in the querystrings before accepting
    them, check for
    > hack
    > code.
    >
    > David
    >

  • Create a xml file from an internal table: CALL TRANSFORMATION

    Hello gurus,
    I want to create a xml file using data from scustom table. I will create an internal table and will select some records to it.
    I searched the forum and i discovered the call transformation, but when i execute the example program at the CALL TRANSFORMATION shows a dump screen.
    How we create a xml file from internal table??
    Please help me. I will mark the useful answers.

    I'm using if_ixml class to create xml documents
    TYPES: BEGIN OF xml_line,
             data(256) TYPE x,
           END OF xml_line.
    DATA: o_ixml          TYPE REF TO if_ixml,
          o_document      TYPE REF TO if_ixml_document,
          o_element       TYPE REF TO if_ixml_element,
          o_streamfactory TYPE REF TO if_ixml_stream_factory,
          o_ostream       TYPE REF TO if_ixml_ostream,
          o_renderer      TYPE REF TO if_ixml_renderer.
    DATA: t_xml_table     TYPE TABLE OF xml_line,
          v_xml_size      TYPE i.
    o_ixml = cl_ixml=>create( ).
    o_document = o_ixml->create_document( ).
    * The o_document have a set of methods to add elements, attributes, etc.
    o_element  = o_document->create_simple_element(
                      name = 'RootNode'
                      value = 'some text'
                      parent = o_document ).
    o_streamfactory = o_ixml->create_stream_factory( ).
    o_ostream = o_streamfactory->create_ostream_itable( table = t_xml_table ).
    o_renderer = o_ixml->create_renderer( ostream  = o_ostream document = o_document ).
    o_renderer->render( ).
    v_xml_size = o_ostream->get_num_written_raw( ).
    CALL METHOD cl_gui_frontend_services=>gui_download
      EXPORTING
        bin_filesize = v_xml_size
        filename     = 'C:a.xml'
        filetype     = 'BIN'
      CHANGING
        data_tab     = t_xml_table.

  • How to create an XML file from scratch ?

    Hi all,
    I'm afraid that I will seem dummy, but I think I really misunderstand something or I'm trying to do something that is not possible...
    I would like to create a XML file containing the following:<?xml version="1.0" encoding="UTF-8"?>
    <?xml-stylesheet type="text/xsl" href="pl.xsl"?>
    <!DOCTYPE playlist SYSTEM "pl.dtd">
    <playlist id="2">
    </playlist>I really need to have both the stylesheet and the DOCTYPE declarations... Does anyone know if this is possible ?
    To create the XML Document, I am using the DocumentBuilder object from javax.xml package (jaxp-1.2-ea2). I think this, at least, is correct.
    To print out the XML document I have tried to use :
    - the Transformer from javax.xml package (jaxp-1.2-ea2) but I could obtain only the DOCTYPE declaration.
    - the Serializer from Xerces parser (version 2.0.1) to print out the Document I am creating with the jaxp, but I was able only to obtain the stylesheet declaration...
    So far I have just understand that there is a difference between Serializer and Transformer (one is serializing, and the other is transforming ;-)), but I couldn't figure out which one would be suitable to produce the XML file above...
    I would really appreciate if one could help me with that ;-)
    Thanks,
    Karau

    Could send me an example ?
    For the moment I am using Transformer in that way:
         TransformerFactory tfactory = TransformerFactory.newInstance();
         try {
             Transformer transformer = tfactory.newTransformer();
             DOMSource source = new DOMSource(playlistDoc.getDocumentElement());
             StreamResult res = new StreamResult(new File(path));
             transformer.setOutputProperty(OutputKeys.DOCTYPE_SYSTEM, PL_DTD);
             transformer.setOutputProperty(OutputKeys.INDENT, "yes");
             transformer.transform(source, res);
         catch (TransformerConfigurationException tce) {
             throw tce;
         catch (TransformerException te) {
             throw te;
         }

  • Creating an xml file from a playlist - message for iTunes staff

    When I created an xml file from a playlist I noticed that in the xml file the track name was merged with the artist name in this manner "I want you - Bob Dylan".
    That was hardly a problem as I could easily correct this in the FileMaker Pro environment.
    But subsequently I found out, that within iTunes the track name was similarly changed to the same format. Apparently this happened when iTunes created the xml file and inadvertently also changed the track name within iTunes.
    It can easily be corrected by entering File/Info, but I had over 10.000 songs in that list and it will take a lot of time. I have to do this, as I created earlier for each song a file path in FileMaker Pro, which are unrecognizable now.
    Could you please correct the xml file creating procedure?

    I must confess that I can't reproduce this result myself anymore.
    I created the xml file in iTunes via File/Library/Export Playlist/xml structure (I translate the Dutch terms loosely) and subsequently I imported the xml file into a Filemaker Pro via File/Import/xml.
    The xsl style sheet looks ok.
    It looks like a freak of nature.
    Still I have the evidence in my iTunes playlist, where I have another 9000 clicks to go to repair the damage.
    Let's forget about it, until it happens again.
    Thanks for your time.

  • Possible to create a JAR file from within a java app?

    Is it possible to create a jar file from within a java application?
    Can it be done more elegantly than by spawning-off another
    process with the Runtime and exec() portions of the api?
    Thanks
    Scott

    Thanks! I was mislead by the API notes for java.util.jar:
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    of a JAR file to any output stream.
    I was looking for a class or method to make jar files.
    Seems this is it ;)
    Thanks
    Scott

  • Is there anyway to create a xml file from a list so that xml file is available like an RSS.xml

    Hello
    My objective is to have a xml file created from a list for anonymous access.  The SharePoint RSS feed is a .aspx file not xml, as shown below: 
    _layouts/listfeed.aspx?List=21c2cdaa%2D52f3%2D4057%2Db674%2D45e63ba77e31&View=535eb328%2Db5fb%2D45c5%2D8fe8%2Da130e92afc41
    Also, is there a way to do this so that the xml content has current data like the list.
    Thank you for any insight and direction.

    Hi,
    According to your post, my understanding is that you wanted to create a xml file from a SharePoint list.
    To generate a XML file, we can use the SharePoint Object Model or PowerShell to achieve it.
    Generate a hierarchical XML file from SharePoint list using Client Object Model.
    http://maxderungs.wordpress.com/2012/05/12/generate-a-hierarchical-xml-file-from-sharepoint-list/
    Get SharePoint list items and export them to XML using PowerShell
    http://www.robertkuzma.com/2012/09/get-sharepoint-list-items-and-export-them-to-xml-using-powershell/
    More reference:
    http://www.robertkuzma.com/2010/08/how-to-create-a-custom-xml-output-using-sharepoint-services-3-0/
    http://traceynolte.com/blog/convert-sharepoint-list-to-xml/
    Thanks & Regards,
    Jason
    Jason Guo
    TechNet Community Support

  • Creating an xml file from abap code

    Hello All,
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    Paul.

    This has been discussed before
    XML files from ABAP programs

  • Hello Anybody, I have a question. Can any of you please suggest me how to make an xml file from the database table with all the rows? Note:- I am having the XSD Schema file and the resulted XML file should be in that XSD format only.

    Hello Anybody, I have a question. Can any of you please suggest me how to make an xml file from the database table with all the records?
    Note:- I am having the XSD Schema file and the resulted XML file should be in that XSD format only.

    The Oracle documentation has a good overview of the options available
    Generating XML Data from the Database
    Without knowing your version, I just picked 11.2, so you made need to look for that chapter in the documentation for your version to find applicable information.
    You can also find some information in XML DB FAQ

  • Help on how to read the content of an XML file from the payload

    I have a receiver channel / mail adapter, that sends e-mails with a XML attachment.
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    <u><i>Can anyone help me with how to read the content of the XML file from the payload.</i></u>
    <i><b>Frank</b></i>

    hi,
    check this: http://jakarta.apache.org/poi/

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