Creating Jtree Using ArryList

Question

Good Evening.
Am new to swing, i need to create Dynamic Swing JTree for below StringArray.
Root has leaf node and Folders
Folders may have Folder node or leaf node
String path[] = {"Root/TS1",
     "Root/Folder1/TS2",
     "Root/Foder2/Folder3/TS3"};
It would be great help if you send me the code.
Thanks in advance.
Shrinivas
Edited by: Shrinivas on Feb 18, 2011 7:00 AM

Answer 1

Hi Shrinivas,
one way could be to create the nodes level by level: first all level 0 nodes, than all level 1 nodes, and so on. In this case we don't have to bother about a parent node being already created or not. To find the parent node for a particular node we just make a simple method that processes the tree recursively, for example like this:
private void buildTree(final String[] flatData, final int maxLevel) {
    for (int level = 0; level < maxLevel; level++) {
        for (String nodeData : flatData) {
            String[] nodePath = nodeData.split("/");
            if (level < nodePath.length) {
                DefaultMutableTreeNode newChild = new DefaultMutableTreeNode(nodePath[level]);
                parent = (DefaultMutableTreeNode) tree.getModel().getRoot();
                findParent(tree.getModel().getRoot(), nodePath, level);
                if (parent != null) {//null = exists already
                    ((DefaultTreeModel) tree.getModel()).insertNodeInto(newChild, parent, parent.getChildCount());
private void findParent(final Object o, final String[] nodePath, final int level) {
    int cc = tree.getModel().getChildCount(o);
    for (int i = 0; i < cc; i++) {
        DefaultMutableTreeNode child = (DefaultMutableTreeNode) tree.getModel().getChild(o, i);
        if (child.getLevel() == level && child.toString().equals(nodePath[level - 1])) {
            parent = child;
        } else if (child.getLevel() == (level + 1) && child.toString().equals(nodePath[level])) {
            parent = null;//exists already
        if (!tree.getModel().isLeaf(child)) {
            tree.expandPath(new TreePath(child.getPath()));
            findParent(child, nodePath, level);
}Cheers,
André