Creating new user get message "Name is used by an other user"

10.9.2.
Trying to create a new user getting the message "Name is used by an other user" under the short name. 
How can I remove the remnants of this user that I suppose has been transferred when I migrated the users from an old mac to this one?  Becuase it might have been there in the past, but has been deleted.  Needless to say there is presently only one user in the 'Users & Groups' control panel.  And this one is not using this name. 
I tried in Terminal
sudo rm -rf /Users/ShortName\\ deleted
(ShortName to be replaced by the name of the account it refuses to create). This does not make a change.

I found the solution here:
http://reviews.cnet.com/8301-13727_7-20102973-263/stubborn-user-accounts-returni ng-when-deleted-in-os-x/
Thanks to Topher Kessler

Similar Messages

  • How to to create new user in Azure AD by using C# programming manually

    Hi 
    I am using MVC 5 with Azure AD.
    I want to create new user in Azure AD by using C# programming manually, I don't want to configure it.
    Suppose I have an application where We have an option to create new user, so how we can write program for it.
    Thanks in advance!!

    Hello,
    Microsoft Azure forums are over here:
    https://social.msdn.microsoft.com/forums/azure/en-US/home
    Karl
    When you see answers and helpful posts, please click Vote As Helpful, Propose As Answer, and/or Mark As Answer.
    My Blog: Unlock PowerShell
    My Book:
    Windows PowerShell 2.0 Bible
    My E-mail: -join ('6F6C646B61726C406F75746C6F6F6B2E636F6D'-split'(?<=\G.{2})'|%{if($_){[char][int]"0x$_"}})

  • Cannot get new ipad to message or facetime using my iphone number. Will only allow messaging and facetime with my email address

    cannot get new ipad to message or facetime using my iphone number. Will only allow messaging and facetime with my email address

    Using FaceTime  >  http://support.apple.com/kb/ht4319
    Troubleshooting FaceTime
    iOS   http://support.apple.com/kb/TS3367
    About Messages
    Troubleshooting Messages
    http://support.apple.com/kb/TS2755

  • Error while creating new user in Oracle 11i EBS

    I am getting following error while creating new user. How solve this issue?
    “Unable to load java class % specified profile option SIGNON_PASSWORD_CUSTOM. Please verify that the class exists and that it implements the java interface oracle.apps.fnd.security.PasswordValidation”.

    Following is the text from Note for Custom Password Validation logic:
    Customers who wish to use their own password validation logic may do
      so by writing their own Java classes that implement the
      oracle.apps.fnd.security.PasswordValidation Java interface.  The
      interface requires 3 methods to be implemented:
      1) public boolean validate(String user, String password)
        - This method takes a username and password, and then returns true
      or false, indicating whether the user's password is valid or invalid,
      respectively.
      2) public String getErrorStackMessageName()
        - This method returns the name of the message to display when the
      user's password is deemed invalid (i.e., the validate() method returns
      false).
      3) public String getErrorStackApplicationName()
        - This method returns the application shortname for the
      aforementioned error message.
      After writing the Java class to perform customized password
      validation, the customer must then set the value of the profile option
      SIGNON_PASSWORD_CUSTOM to be the full name of the class.  If, for
      example, the name of the Java class is
      oracle.apps.fnd.security.AppsPasswordValidation, then the value of the
      SIGNON_PASSWORD_CUSTOM profile option must be
      oracle.apps.fnd.security.AppsPasswordValidation.  Note that AOL/J
      will attempt to load this class dynamically.  Hence it is necessary to
      make the class accessible by AOL/J.  This means that in Forms, the
      class must first be loaded into the database using the loadjava
      command.
    You will need to apply the following patches for 11.5.1:
       1344802
       1363919
       1472974
       1351004
       1377615
    You will need to apply the following patches for 11.5.2:
       1377615

  • Old user account not accessible - Had to create new user account

    Why was I forced to create a new user account in order to access Apple discussions? The last time I had posted to Apple discussions was 11/06. From the emails notifying me of replies to my post, I can still go to the link where my question and the replies are. Last week I wanted to post another question. Instead I encountered a circular problem. Every time I tried to log in to discussions with my Apple ID and password (the same as my .Mac name and password, which were working fine for accessing .Mac), I was told that there was an error in my password. When I tried again, I was repeatedly re-directed to a "create new user account" web page that listed my .Mac email address as my Apple ID, as it should have. I tried to re-create my old user account with my own [real] name (as before) and was told that name was in use! Of course, it was me! (I had always used by real first name and surname as my name on Apple discussions.) So finally, very frustrated, I created a new name, a nickname, for discussions, and it worked. Now, all my previous posts are gone. It's as if I didn't exist in the Apple world until today, 9/16/07, but I originally had established my user account in 2004. I tried asking about this in a phone call to Apple support, but I was re-directed to the .Mac web site. Then I posted a question at .Mac feedback to no avail. I had a feeling that as soon as I "obeyed" and created a new user account that wouldn't be recognized as myself, my past posts would be sent into oblivion. I don't like losing all my previous posts that were attached to my user account. I have found this problem very frustrating and would really like an explanation.

    Hi decemberbaby,
    Try this procedure.
    Delete all the Apple Cookies in your browser, and empty the Cache.
    Go here Discussions Sign In, and try logging in with your original Apple ID again.
    If that still doesn't work, delete the Cookies again, and go to My Info, and log in with the original Apple ID.
    If you get the error message "Your Apple ID or password was entered incorrectly.", click on "Did you forget your password? Click here for assistance".
    On the page that opens, you can also click on "Forget your Apple ID
    ali b

  • Not able to get group name by using memberof class, getting Total groups as 0 even I am member of that group.

    Not able to get group name by using memberof class, getting Total groups as 0 even I am member of that group. Through this memberof class I am trying to find full qualified name(DN) of my group.
    code I have used:
    //specify the LDAP search filter
                   String searchFilter = "(&(objectClass=user)(CN=Username))";
                   //Specify the Base for the search
                   String searchBase = "";
    Also I have used,
                 String searchFilter = "(&(objectClass=user)(CN=Username))";
                   //Specify the Base for the search
                   String searchBase = "ou=ibmgroups,o=ibm.com";
    But in both cases I am getting value for Total groups as 0.
    Code Reference:
    * memberof.java
    * December 2004
    * Sample JNDI application to determine what groups a user belongs to
    import java.util.Hashtable;
    import javax.naming.*;
    import javax.naming.ldap.*;
    import javax.naming.directory.*;
    public class memberof     {
         public static void main (String[] args)     {
              Hashtable env = new Hashtable();
              String adminName = "CN=Administrator,CN=Users,DC=ANTIPODES,DC=COM";
              String adminPassword = "XXXXXXX";
              String ldapURL = "ldap://mydc.antipodes.com:389";
              env.put(Context.INITIAL_CONTEXT_FACTORY,"com.sun.jndi.ldap.LdapCtxFactory");
              //set security credentials, note using simple cleartext authentication
              env.put(Context.SECURITY_AUTHENTICATION,"simple");
              env.put(Context.SECURITY_PRINCIPAL,adminName);
              env.put(Context.SECURITY_CREDENTIALS,adminPassword);
              //connect to my domain controller
              env.put(Context.PROVIDER_URL,ldapURL);
              try {
                   //Create the initial directory context
                   LdapContext ctx = new InitialLdapContext(env,null);
                   //Create the search controls          
                   SearchControls searchCtls = new SearchControls();
                   //Specify the search scope
                   searchCtls.setSearchScope(SearchControls.SUBTREE_SCOPE);
                   //specify the LDAP search filter
                   String searchFilter = "(&(objectClass=user)(CN=Andrew Anderson))";
                   //Specify the Base for the search
                   String searchBase = "DC=antipodes,DC=com";
                   //initialize counter to total the group members
                   int totalResults = 0;
                   //Specify the attributes to return
                   String returnedAtts[]={"memberOf"};
                   searchCtls.setReturningAttributes(returnedAtts);
                   //Search for objects using the filter
                   NamingEnumeration answer = ctx.search(searchBase, searchFilter, searchCtls);
                   //Loop through the search results
                   while (answer.hasMoreElements()) {
                        SearchResult sr = (SearchResult)answer.next();
                        System.out.println(">>>" + sr.getName());
                        //Print out the groups
                        Attributes attrs = sr.getAttributes();
                        if (attrs != null) {
                             try {
                                  for (NamingEnumeration ae = attrs.getAll();ae.hasMore();) {
                                       Attribute attr = (Attribute)ae.next();
                                       System.out.println("Attribute: " + attr.getID());
                                       for (NamingEnumeration e = attr.getAll();e.hasMore();totalResults++) {
                                            System.out.println(" " +  totalResults + ". " +  e.next());
                             catch (NamingException e)     {
                                  System.err.println("Problem listing membership: " + e);
                   System.out.println("Total groups: " + totalResults);
                   ctx.close();
              catch (NamingException e) {
                   System.err.println("Problem searching directory: " + e);
    Any help will be highly appreciated.

    Not able to get group name by using memberof class, getting Total groups as 0 even I am member of that group. Through this memberof class I am trying to find full qualified name(DN) of my group.
    code I have used:
    //specify the LDAP search filter
                   String searchFilter = "(&(objectClass=user)(CN=Username))";
                   //Specify the Base for the search
                   String searchBase = "";
    Also I have used,
                 String searchFilter = "(&(objectClass=user)(CN=Username))";
                   //Specify the Base for the search
                   String searchBase = "ou=ibmgroups,o=ibm.com";
    But in both cases I am getting value for Total groups as 0.
    Code Reference:
    * memberof.java
    * December 2004
    * Sample JNDI application to determine what groups a user belongs to
    import java.util.Hashtable;
    import javax.naming.*;
    import javax.naming.ldap.*;
    import javax.naming.directory.*;
    public class memberof     {
         public static void main (String[] args)     {
              Hashtable env = new Hashtable();
              String adminName = "CN=Administrator,CN=Users,DC=ANTIPODES,DC=COM";
              String adminPassword = "XXXXXXX";
              String ldapURL = "ldap://mydc.antipodes.com:389";
              env.put(Context.INITIAL_CONTEXT_FACTORY,"com.sun.jndi.ldap.LdapCtxFactory");
              //set security credentials, note using simple cleartext authentication
              env.put(Context.SECURITY_AUTHENTICATION,"simple");
              env.put(Context.SECURITY_PRINCIPAL,adminName);
              env.put(Context.SECURITY_CREDENTIALS,adminPassword);
              //connect to my domain controller
              env.put(Context.PROVIDER_URL,ldapURL);
              try {
                   //Create the initial directory context
                   LdapContext ctx = new InitialLdapContext(env,null);
                   //Create the search controls          
                   SearchControls searchCtls = new SearchControls();
                   //Specify the search scope
                   searchCtls.setSearchScope(SearchControls.SUBTREE_SCOPE);
                   //specify the LDAP search filter
                   String searchFilter = "(&(objectClass=user)(CN=Andrew Anderson))";
                   //Specify the Base for the search
                   String searchBase = "DC=antipodes,DC=com";
                   //initialize counter to total the group members
                   int totalResults = 0;
                   //Specify the attributes to return
                   String returnedAtts[]={"memberOf"};
                   searchCtls.setReturningAttributes(returnedAtts);
                   //Search for objects using the filter
                   NamingEnumeration answer = ctx.search(searchBase, searchFilter, searchCtls);
                   //Loop through the search results
                   while (answer.hasMoreElements()) {
                        SearchResult sr = (SearchResult)answer.next();
                        System.out.println(">>>" + sr.getName());
                        //Print out the groups
                        Attributes attrs = sr.getAttributes();
                        if (attrs != null) {
                             try {
                                  for (NamingEnumeration ae = attrs.getAll();ae.hasMore();) {
                                       Attribute attr = (Attribute)ae.next();
                                       System.out.println("Attribute: " + attr.getID());
                                       for (NamingEnumeration e = attr.getAll();e.hasMore();totalResults++) {
                                            System.out.println(" " +  totalResults + ". " +  e.next());
                             catch (NamingException e)     {
                                  System.err.println("Problem listing membership: " + e);
                   System.out.println("Total groups: " + totalResults);
                   ctx.close();
              catch (NamingException e) {
                   System.err.println("Problem searching directory: " + e);
    Any help will be highly appreciated.

  • Creating new user in AD

    Hi all,
    I am trying to write a script to create new user in Active Directory using power-shell
    $sam = "13653123"
    try{
    get-aduser -Identity $sam -ErrorAction Stop
    catch [Microsoft.ActiveDirectory.Management.ADIdentityNotFoundException]
    $error1= [System.Windows.Forms.MessageBox]::Show("ERROR : Account Not found")
    $SamAccountName = $sam
    $gn = "Jack Sparrow"
    $Initials = "ZX"
    $dn = "$gn "+" $Initials"
    $Department = "1260"
    $title = "AM"
    $pwd1 = read-host "Please enter the password"
    $pwd2 = read-host "Please enter the password"
    if($pwd1 -eq $pwd2)
    $pwd = $pwd1 = $pwd2
    try
    $userprinicpalname = $SamAccountName + "@XXX.com"
    New-ADUser -SamAccountName $SamAccountName -UserPrincipalName $userprinicpalname -GivenName $gn -Initials $Initials -Name $dn -DisplayName $dn -Title $title -Department $Department -Office $Department -Path "OU=XXXX,DC=XXX,DC=com" -AccountPassword (ConvertTo-SecureString $pwd -AsPlainText -force) -Enabled $True -PasswordNeverExpires $False -ErrorAction Stop
    catch [Microsoft.ActiveDirectory.Management.ADPasswordComplexityException]
    $error7= [System.Windows.Forms.MessageBox]::Show("ERROR : The password you entered doesnot meet the complexity set in the Password Policy" )
    break
    else
    $error2= [System.Windows.Forms.MessageBox]::Show("ERROR : passwords donot match")
    I am getting issue when The password complexity error is coming. It is showing up the error in the catch, but it is creating the account in AD and disabling it. 
    What I want is if any error is found and caught in the catch, then the user should not be created. How to do that?
    Please provide your valuable suggestions and help me out
    Naveen Basati

    This is a good way to get teh paassword to abort when it fails the test.
    function Test-Password{
    Param($Password)
    Try{
    $pwd=ConvertTo-SecureString $Password -AsPlainText -force
    Set-ADAccountPassword testuser11 -NewPassword $pwd –Reset
    # it worked so return the encrypted password
    $pwd
    Catch{
    Throw $_
    $sam = "13653123"
    if(get-aduser -Filter "SamAccountName -eq $sam"){
    Write-Host 'User already exists' -ForegroundColor green
    }else{
    Try{
    $pwdText='x123!heLno34' # 3 levels of compexity plus length > 9
    $pwd=Test-Password $pwdText
    $given='Jack'
    $surname='Sparrow'
    $Initials='Z'
    $Department='1260'
    $title='AM'
    $props=@{
    SamAccountName=$sam
    UserPrincipalName="$[email protected]"
    GivenName=$given
    Initials=$Initials
    Name="$given $initials $surname"
    DisplayName="$given $initials $surname"
    Title=$title
    Department=$Department
    Office=$Department
    Path='OU=TestOU,DC=testnet,DC=local'
    AccountPassword=$pwd
    Enabled=$True
    PasswordNeverExpires=$False
    New-ADUser @props -ErrorAction Stop
    Catch{
    throw $_
    We just re-throw the error and it propagates to the outer try/catch block.
    ¯\_(ツ)_/¯

  • Login page keeps going to "Create new user account" on login

    For about 3 weeks, whenever I log in, the next page I get is nearly always the "Create new user account" page. This happens regardless of whether I wait to let AutoFill enter my user name and password or whether I fill in the correct info myself.
    When I click the back button on my browser and finally arrive at the page with the forums list, I'm always registered as logged in. But sometimes I just end up back on the login page with a blank entry box.
    How do I get to the forums page without having to get out of the "new user account" page first? (While this isn't a huge problem, it's time-wasting and kind of annoying, and it didn't used to happen.)

    Hi Turtlewiz!
    Have you tried deleting your browser cache & cookies?
    Good Luck!
    ali b

  • Can't create new users after GroupWise is moved from NetWare to Linux

    Hi,
    I moved GroupWise (Version 6.5 SP 6, single domain and single office)
    from NetWare 6.5 server to SUSE Linux Enterprise server 9. It seems the
    GroupWise server is running oaky. Existing users are able to connect
    their mail box and send and receive messages. But I can't create new
    users on the GroupWise server.
    I used ConsoleOne installed on the Linux server to create new GroupWise
    users. It seemed that I was able to do it. The new users appear on the
    NDS and the GroupWise File IDs were assigned for these users. And I was
    able to add these new users to distribution lists. But the users DB
    files (userXXX.db) were not created under /grpwise/po/ofuser on the Linux
    server and they cannot connect to the server. Old users cannot find them
    in Novell GroupWise Address book.
    Does anyone how to fix the problem?
    Thanks in advance!
    Jinkang

    Hi,
    [email protected] wrote:
    >
    > Hi,
    >
    > I moved GroupWise (Version 6.5 SP 6, single domain and single office)
    > from NetWare 6.5 server to SUSE Linux Enterprise server 9. It seems the
    > GroupWise server is running oaky. Existing users are able to connect
    > their mail box and send and receive messages. But I can't create new
    > users on the GroupWise server.
    >
    > I used ConsoleOne installed on the Linux server to create new GroupWise
    > users. It seemed that I was able to do it. The new users appear on the
    > NDS and the GroupWise File IDs were assigned for these users. And I was
    > able to add these new users to distribution lists. But the users DB
    > files (userXXX.db) were not created under /grpwise/po/ofuser on the Linux
    > server and they cannot connect to the server. Old users cannot find them
    > in Novell GroupWise Address book.
    >
    > Does anyone how to fix the problem?
    This clearly sounds like your domain (which is the part of groupwise
    which you admin against) doesn't/can't talk to the postoffice, so the
    change you made (to the domain) does never get to the PO (which is where
    the addressbook of your other users come from, and is what is
    responsible for creating the user DB). This seems very likely to be
    caused by your move not being done properly, and old information (either
    path or IP address) for the PO still being in the domain and/or domain
    database.
    So how's the domain linked to the PO?
    CU,
    Massimo Rosen
    Novell Product Support Forum Sysop
    No emails please!
    http://www.cfc-it.de

  • Failed to create new user null

    All Experts
    I am getting the following error message when I am trying to start Java Engine. I am trying to add Java Add on to the ABAP Stack. This was taken from security.0.log .
    #1.5#001143312344001E00000003000006B400044C1E4BBCD4E7#1209592910253#/System/Security/UserStoreUME##com.sap.security.core.server.userstore.UserContextUME#######SAPEngine_System_Thread[impl:5]_14##0#0#Error#1#com.sap.security.core.server.userstore.UserContextUME#Plain###
    Failed to create new user null#
    #1.5#001143312344001E00000005000006B400044C1E4BBCFE64#1209592910253#/System/Security/UserStoreUME##com.sap.security.core.server.userstore.UserContextUME.engineCreateUser(String)#######SAPEngine_System_Thread[impl:5]_14##0#0#Info#1#com.sap.security.core.server.userstore.UserContextUME#Java###Created new user #1#<null>#
    #1.5#001143312344001E00000006000006B400044C1E4BBCFFBA#1209592910253#/System/Security/UserStoreUME##com.sap.security.core.server.userstore.UserContextUME#######SAPEngine_System_Thread[impl:5]_14##0#0#Error#1#/System/Security/UserStoreUME#Java###Error during creation of default users or role assignments: #1#
    Could not create user null: LOGONID_IS_NULL#
    #1.5#001143312344001E00000008000006B400044C1E4BBD03D0#1209592910253#/System/Security##com.sap.engine.services.userstore.UserContext.<init>(UserContextSpi, Properties)#######SAPEngine_System_Thread[impl:5]_14##0#0#Fatal#1#com.sap.engine.services.userstore#Plain###Can not instantiate UserContext with given properties.#
    #1.5#001143312344001E0000000B000006B400044C1E4BBD5C7C#1209592910284#/System/Security##com.sap.engine.services.security#######SAPEngine_System_Thread[impl:5]_14##0#0#Error#1#com.sap.engine.services.security#Java#security_0001#com.sap.engine.services.security.exceptions.SecurityResourceBundle#Unexpected exception:##
    Please suggest

    Hi Prasanna
    I am getting this error while installing the Java Add-on. The installation was in the last stage and there it got struck when it tried to reboot the java engine. I am using SAPJSF user to communicate with ABAP stack and it has the full authorizations. I even checked and see that SAPJSF user is not locked. I also tried with another user and still the same issue. As per the log it the java engine is able to login with the user, but it is trying to create a user and fialing there. I am not sure why it is creating this user.
    Regards,
    Mahesh

  • [syntax_error] in Creating New User - After applying SP ABAP & Basis lv 8

    Hi Gurus.
    actually I already created message to SAP regarding this. but i havent receieve any respond. I post here just in case maybe I can have immediate solution from you guys..
    I have 2 system HLC and MFG
    which is using same OS and DB
    DB Information
    DB client lib.     SQL_Server_8.00
    DB releases        MSSQL 7.00.699 or higher, MSSQL 8.00.194
    DBSL version       700.08
    DBSL Patch Level   144
    System Information
    SAP versions       700
    Operating System   Windows NT 5.0, Windows NT 5.1, Windows NT 5.2, Wi
    OP release         5.2
    which have same Kernel and SP patches
    Kernel release    700
    Sup.Pkg lvl.      146
    SAP_ABA     700     0008     SAPKA70008
    SAP_BASIS     700     0008     SAPKB70008
    ST-PI 2005_1_700     0006     SAPKITLQI6
    PI_BASIS     2005_1_700     0005     SAPKIPYJ75
    Problem
    previously both of the system HLC and MFG is in level 6 SP ABAP and BASIS
    when i try to create EWA report for both of them, i have missing module in the report
    and i read a note that i need to upgrade to level 8.
    when i upgrade both of them to level 7, then i run sgen and there are no problem on both system
    but when i upgrade both of them to level 8
    in my MFG system, i can run sgen with no problem.
    in my HLC system, i run sgen and it take a long time to validate the programs which are need to be recompiled. so i never run sgen to recompile on HLC system after i update the SP to level 8. but i believe this shouldnt be an issue.
    the day after i update the SP, one of my user raise an issue.
    (same issue is not happened in MFG system only in HLC system)
    when we try to create new user..
    SU01 -> create new user -> fill all the details -> save -> abap dumps
      Error in the ABAP Application Program
      The current ABAP program "/SAPSLL/CL_IM_BP_ADDRESS======CP" had to be
       terminated because it has
      come across a statement that unfortunately cannot be executed.
      The following syntax error occurred in program "/SAPSLL/SAPLBP_ADDRESS " in
       include "/SAPSLL/LBP_ADDRESSTOP " in
      line 22:
      "Statement "/SAPSLL/DEBUG_DATA" is not defined. Check your spelling . ."
      The include has been created and last changed by:
      Created by: "SAP "
      Last changed by: "SAP "

    Hi all
    problem is solved..
    after doing some debugging, we found out
    there are some missing entries in table TRMAC
    so i just copy the missing entries from my MFG server to HLC server since they are both in same condition.
    now i am wondering why do the support package miss to enter the rows in TRMAC table >.<
    SAPache man..

  • How to create new user with more than one default folder

    hi
    A new user created in OCS has only one default folder(Inbox).
    I want to create new user with customized default folder.
    for example:
    a new user has more than one default folder(Inbox,Outbox,Draft,Dustbin...)
    And also I want to automaticly enable the functions:
    When sending messages, place a copy in Outbox
    Keep message drafts in Draft
    Move deleted messages to Dustbin
    who know that?
    thanks

    The same reason that Apple and 3rd Party vendors put multi-size templates in one file I expect. I am trying to construct an in-house standard template for use in our company, and it is easier to manage if there is only one file to send to people rather than many - both initially and for subsequent edits / updates to the template.
    Of course it would be possible to create several templates (one for each size). But since it is clear that templates can be combined, it appears sensible to do this - unless the doing of it is horridly complicated

  • Unable to create new user thru Portal

    Hi,
    I am unable to create user from the oracle portal web page under the Administer tab.
    I have logged in as user PORTAL30 which has DBA rights.
    When I click the Create new user link, it generates an error page WWC-00000.
    Would appreciate if any can help me out urgently.
    OS: NT4 SP5
    9iAS 1.0.2.1
    Vipul
    null

    Cindy,
    Thanks for the solution. It worked fine after changing servername to lowercase.
    The servername was set in in httpd.conf by the 9iAS installer itself. I would like to express that Oracle should have checked before launching or should have listed it in the release notes.
    Once again thanks for the inputs, Cindy.
    Regards,
    Vipul
    <BLOCKQUOTE><font size="1" face="Verdana, Arial">quote:</font><HR>Originally posted by cindy:
    I too was having the same problem. I found this in another post:
    "this is reported as
    BUG:1534919
    the solution is to use lower case server name in httpd.conf. It must be in lower case."
    I made the change and am now able to create users.<HR></BLOCKQUOTE>
    null

  • Cannot copy or create new user in portal

    Hi all,
    I have tried to create new users in dual stack abap & java installation. However, j2ee_admin and sap* both display critical stop with message "An error has occured, contact your system administrator." Unfortunately, there is nothing more than this message in portal. I have used visual administrator from go.bat also but the result is the same with error:
    Caused by: java.lang.ClassNotFoundException: com.sap.security.core.persistence.datasource.PersistenceException
         at java.net.URLClassLoader$1.run(Unknown Source)
         at java.security.AccessController.doPrivileged(Native Method)
    Any clues!
    Regards.

    Hi Eduardo/Jo,
    That's fine, I can see abap user in both visual administrator and portal's identity mgt area.
    However, when attempted to logon with an super admin role abap user, the portal displays, user is locked... okay, go to portal with j2ee_admin and unlock this user... again login and message user is still locked.... Go to visual administrator the same user appears as locked. click the pencil button and try to unlock, visual admin displays message "unable to unlock user. details are available in status bar".
    Following is the perhaps relevant part of the long error details.
    Caused by: com.sap.security.core.persistence.datasource.PersistenceException: Attribute "islocked" on namespace "com.sap.security.core.usermanagement" of principal "UACC.R3_DATASOURCE.MOHAMMAD" is not modifiable.
    So, all in all, portal cannot logon with super administrator becuase it appears locked in visual admin, cannot unlock this user in visual admin because of above error message.
    Any clues, please.
    Regards.

  • Sample workflow for Create new user in IDM

    Hi,
    I'm new to Identity Manager. I had obtain task to create new workflow with this requirements:
    - create new user
    - make some approvals
    - deploy this user to some resource (AD, LDAP, SQL)
    I have problem with first step. I tried to create user by the help of http://www.javapassion.com/idm/ create user samples, but I'm affraid that mentioned samples aren't enough for real deployment. They are good for understanding of IDM.
    So I decided to explore workflows/rules that are used as default in IDM. I think Create User dialog that is in menu Accounts -> List Accounts -> New Actions -> New User . But I'm not sure which workflow is used for this dialog. Is it Create User in ProvisioningTask, or some template in TaskDefinition, or Create User Template in TaskTemplate, or something another?
    (I'm listing this templates through List Object in Debug interface).
    I appreciate every help
    Petr

    Chapo,
    thanks a lot for informations. I have try to find corresponding process mapping for 'Create User' under Configure tab. I found process 'createUser'. So I looked for 'createUser' workflow under 'Task definition' or 'Configuration' in debug. But there was no such workflow. Only workflow with similar name was 'Create Resource User', but it doesn't look like right workflow. I expected workflow with name 'Create User'. Does anybody have this workflow under 'Task Definition' in debug?

Maybe you are looking for