Cross Join Slowness

Hi All,
We have a ASO cube with 9 dimensions and a fairly large data set. One of our account members has the following formula:
[Taxes] = Case When IsLeaf(Organization.CurrentMember)
then (([1000_LI] - [2000_LI]) * [9999_LI])
else Sum(CrossJoin({Tax},Children (Organization.CurrentMember)))
end
What this formula is attempting to do is calculate the tax amount for each Organization leaf level member (the rate is stored in 9999_LI for each leaf level Org) then aggregate up the account hierarchy. I'm not sure what the reason is, but the data retrieval is taking a very long time. When I first open an blank spreadsheet and perform a retrieve it takes almost a full minute before data is brought back. I'm not even selecting the Tax member. It seems like the aggregation at high level is the reason, if I drill to lower level values in the cube, data retrieval is much faster. Is there any way to improve this formula?
Please let me know..
Thanks in advance.
T

Did you figure out the way to improve the performance. We're experiencing same issue now.
Thanks

Similar Messages

  • [8i] Need help with full outer join combined with a cross-join....

    I can't figure out how to combine a full outer join with another type of join ... is this possible?
    Here's some create table and insert statements for some basic sample data:
    CREATE TABLE     my_tab1
    (     record_id     NUMBER     NOT NULL     
    ,     workstation     VARCHAR2(4)
    ,     my_value     NUMBER
         CONSTRAINT my_tab1_pk PRIMARY KEY (record_id)
    INSERT INTO     my_tab1
    VALUES(1,'ABCD',10);
    INSERT INTO     my_tab1
    VALUES(2,'ABCD',15);
    INSERT INTO     my_tab1
    VALUES(3,'ABCD',5);
    INSERT INTO     my_tab1
    VALUES(4,'A123',5);
    INSERT INTO     my_tab1
    VALUES(5,'A123',10);
    INSERT INTO     my_tab1
    VALUES(6,'A123',20);
    INSERT INTO     my_tab1
    VALUES(7,'????',5);
    CREATE TABLE     my_tab2
    (     workstation     VARCHAR2(4)
    ,     wkstn_name     VARCHAR2(20)
         CONSTRAINT my_tab2_pk PRIMARY KEY (workstation)
    INSERT INTO     my_tab2
    VALUES('ABCD','WKSTN 1');
    INSERT INTO     my_tab2
    VALUES('A123','WKSTN 2');
    INSERT INTO     my_tab2
    VALUES('B456','WKSTN 3');
    CREATE TABLE     my_tab3
    (     my_nbr1     NUMBER
    ,     my_nbr2     NUMBER
    INSERT INTO     my_tab3
    VALUES(1,2);
    INSERT INTO     my_tab3
    VALUES(2,3);
    INSERT INTO     my_tab3
    VALUES(3,4);And, the results I want to get:
    workstation     sum(my_value)     wkstn_name     my_nbr1     my_nbr2
    ABCD          30          WKSTN 1          1     2
    ABCD          30          WKSTN 1          2     3
    ABCD          30          WKSTN 1          3     4
    A123          35          WKSTN 2          1     2
    A123          35          WKSTN 2          2     3
    A123          35          WKSTN 2          3     4
    B456          0          WKSTN 3          1     2
    B456          0          WKSTN 3          2     3
    B456          0          WKSTN 3          3     4
    ????          5          NULL          1     2
    ????          5          NULL          2     3
    ????          5          NULL          3     4I've tried a number of different things, googled my problem, and no luck yet...
    SELECT     t1.workstation
    ,     SUM(t1.my_value)
    ,     t2.wkstn_name
    ,     t3.my_nbr1
    ,     t3.my_nbr2
    FROM     my_tab1 t1
    ,     my_tab2 t2
    ,     my_tab3 t3
    ...So, what I want is a full outer join of t1 and t2 on workstation, and a cross-join of that with t3. I'm wondering if I can't find any examples of this online because it's not possible....
    Note: I'm stuck dealing with Oracle 8i
    Thanks!!

    Hi,
    The query I posted yesterday is a little more complicated than it needs to be.
    Since my_tab2.workstation is unique, there's no reason to do a separate sub-query like mt1; we can join my_tab1 to my_tab2 and get the SUM all in one sub-query.
    SELECT       foj.workstation
    ,       foj.sum_my_value
    ,       foj.wkstn_name
    ,       mt3.my_nbr1
    ,       mt3.my_nbr2
    FROM       (     -- Begin in-line view foj for full outer join
              SELECT        mt1.workstation
              ,        SUM (mt1.my_value)     AS sum_my_value
              ,        mt2.wkstn_name
              FROM        my_tab1   mt1
              ,        my_tab2   mt2
              WHERE        mt1.workstation     = mt2.workstation (+)
              GROUP BY   mt1.workstation
              ,        mt2.wkstn_name
                    UNION ALL
              SELECT      workstation
              ,      0      AS sum_my_value
              ,      wkstn_name
              FROM      my_tab2
              WHERE      workstation     NOT IN (     -- Begin NOT IN sub-query
                                               SELECT      workstation
                                       FROM      my_tab1
                                       WHERE      workstation     IS NOT NULL
                                     )     -- End NOT IN sub-query
           ) foj     -- End in-line view foj for full outer join
    ,       my_tab3  mt3
    ORDER BY  foj.wkstn_name
    ,       foj.workstation
    ,       mt3.my_nbr1
    ,       mt3.my_nbr2
    ;Thanks for posting the CREATE TABLE and INSERT statements, as well as the very clear desired results!
    user11033437 wrote:
    ... So, what I want is a full outer join of t1 and t2 on workstation, and a cross-join of that with t3. That it, exactly!
    The tricky part is how and when to get SUM (my_value). You might approach this by figuring out exactly what my_tab3 has to be cross-joined to; that is, exactly what should the result set of the full outer join between my_tab1 and my_tab2 look like. To do that, take your desired results, remove the columns that do not come from the full outer join, and remove the duplicate rows. You'll get:
    workstation     sum(my_value)     wkstn_name
    ABCD          30          WKSTN 1          
    A123          35          WKSTN 2          
    B456          0          WKSTN 3          
    ????          5          NULL          So the core of the problem is how to get these results from my_tab1 and my_tab2, which is done in sub-query foj above.
    I tried to use self-documenting names in my code. I hope you can understand it.
    I could spend hours explaining different parts of this query in more detail, but I'm sure I'd waste some of that time explaining things you already understand. If you want an explanation of somthing(s) specific, let me know.

  • Illegal cross join within the same dimension caused by incorrect subject ar

    hi!
    Imagine the following BMM:
    There is one Logical Dimension Table "Service Account" with the following LTS:
    - LTS "D_SERVICE"
    - LTS "D_SERVICE_CLASS"
    - LTS "D_SERVICE_STATUS"
    This Logical Tabe "Service Account" joins (One-to-many) with several Fact Tables (other Logical Tables).
    In the Physical Layer the joins for the "Service Account" LTS are:
    - One-to-many between D_SERVICE_CLASS and D_SERVICE
    - One-to-many between D_SERVICE_STATUS and D_SERVICE
    The problem is that when I build a report in Answers using only the following columns of the Logical Table "Service Account":
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    - Service Status Desc (which exists in the Logical Table "Service Account" and in the Physical Tabl D_SERVICE_STATUS)
    - MSISDN (which existis in the Logical Table "Service Account" and in the Phsyical Table D_SERVICE)
    the following error appears:
    Estado: HY000. Código: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 14065] Illegal cross join within the same dimension caused by incorrect subject area setup: [ (select * from prd.D_SERVICE where SOURCE_SYS in ('ARBOR','PPB') and DW_SERV_ST_ID in (100000003,100000009)) as T1836, D_SERVICE_CLASS T1916] with [ D_SERVICE_STATUS T1948] (HY000)
    SQL emitido: SELECT "SERVICE ACCOUNT"."TLC MSISDN9" saw_0, "SERVICE ACCOUNT"."IWS Service Class Desc" saw_1, "SERVICE ACCOUNT"."TLC Service Status Desc" saw_2 FROM "VFPT - Upgrade Siebel" WHERE "SERVICE ACCOUNT"."TLC MSISDN9" = '917330340' ORDER BY saw_0, saw_1, saw_2
    Help, please!
    Thanks.

    Physically, only D_SERVICE is joined to the facts. Then D_SERVICE_CLASS is joined to D_SERVICE (one-to-many) and D_SERVICE_STATUS is joined also to D_SERVICE (one-to-many).
    In the BMM, there is only one Logical Dimension Table for those 3 physical tables. This Logical Dimension Table is called "Service Account" and has 3 LTS: D_SERVICE, D_SERVICE_CLASS, D_SERVICE_STATUS. The Logical Dimension Table has several logical columns that are associated to those 3 LTS: SERVICE_KEY, SERVICE_CLASS_KEY, SERVICE_STATUS_KEY, SERVICE_MSISDN, SERVICE_CLASS_DESC, SERVICE_STATUS_DESC.
    The Logical Dimension Table "Service Account" is then joined to a fact table (one-to-many).
    I didn't understand the suggestion about the 3 LTS... Aren't we doing that already? Can you explain it better, please?
    thanks.

  • OBIEE: non empty cross join function problem with some reports

    Hi all,
    I am getting some problem ,when we are excuting some requests in OBIEE its taking long time , Actually our OBIEE is connected with Essbase when we are generating some reports its taking long time so i captured the Query in OBIEE and Iam excuting that query in Essbase MDX editor
    its having the the function " NON EMPTy CROSS JOIN"
    which reports having non empty crossjoin function its taking long time so how can i disable this function in OBIEEfor that reports
    I dont want to use that function for my reports so how can i do this in OBIEE
    your help would be appriciated.
    Thanks
    Edited by: user8815661 on 26 mai 2010 08:44

    Any Help

  • How to avoid duplicates in CROSS JOIN Query

    Hi,
    I am using CROSS JOIN to get all the subset of a table col values as shown below:
    PRODUCT (Col Header)
    Bag
    Plate
    Biscuit
    While doing cross join we will get as
    Bag Bag
    Bag Plate
    Bag Biscuit
    Plate Bag
    Plate Plate
    Plate Biscuit ..... like this
    By placing where condition prod1 <> prod2 to avoid Bag Bag and Plate Plate values. So the output will be like below
    Bag Plate
    Bag Biscuit
    Plate Bag
    Plate Biscuit
    Now "Bag Plate" and "Plage Bag" are same combination how to avoid these records. My expected result is
    Bag Biscuit
    Plate Biscuit
    How to derive this ?
    Sridhar

    Hi,
    This is the the solution that I found as fit to the OP question, but
    Visakh16 already posted the same idea (assuming the names are unique) from the start and I don't think that anyone notice it!
    Sridhar.DPM did
    you check Visakh16's response
    (the second response received)?!?
    I will mark his response as an answer. If this is not what you need pls clarify and you can unmark it :-)
    [Personal Site] [Blog] [Facebook]

  • How to resolve illegal cross join error

    Can someone please tell me how can we avoid illegal cross join error in modeling? If someone has any reference document , please share it.
    I have 5 tables - Dim (A, B , C,E) and Fact( D). C is lookup table which is used to resolve the lookup code column in table E.
    The relationships between these are
    A--< B--< E >--C
    & A--<D
    My requirement is i have to expose Attributes of A,B ,C & E within Dimension.
    These attributes (from B,C,E) will be treated as property of A.
    Someone may query these attributes without selecting any column from fact table.
    Thanks & Regards,
    Ashish

    Hi Ashish,
    it's not the first time you come up with this kind of question and I'm wondering if you understand the principle of granularity when I read your questions.
    On physical level, a fact table must always join with the lowest level of detail of your dimension table. Let me explain, by giving an example which looks like your situation.
    Assume I have three tables:
    Table "E" contains products, which has attributes like: product_id and product_name
    Table "B" contains order line items, which has attributes like: order_line_item_id, order_id and product_id.
    Table "A" contains orders, which has attributes like: order_id and customer_name.
    Table "D" contains facts ("metrical data") about my order: which has attributes like: order_id, order_revenue.
    This will be the diagram on physical level: E--<B--<A--<D
    Here are my joins: E.product_id on B.produc_id, B.order_id on A.order_id, A.order_id--<D.order_id
    Now, my question to you is: will I be able to get the revenue of a certain product?
    The answer is: No, because I don't know what part of my order is spent on a certain product. The problem is thus that the data in the fact table isn't stored on that level of detail, or in other words the fact and dimension table don't share the same level of granularity.
    How it should be:
    If you want to get the revenue per product, you will need to have a second fact table "G", which has data which is stored on order line item level. This table contains the following attributes: order_line_item_id, product_id and order_line_item_revenue.
    This will become your diagram on physical level:
    B--<G>--E
    Joins: B.order_line_item_id on G.order_line_item_id and E.product_id on G.product_id
    Table E has become a dimension of fact table G.
    The first physical diagram should look like this:
    A--<D
    If you want you can model both physical diagrams into one logical diagram, assuming that A and D (order dimension and fact table) are aggregates of B and G (order line items dimension and fact table). In that case you should read this blog item: http://obiee101.blogspot.com/2008/11/obiee-making-it-aggregate-aware.html
    Regards,
    Stijn

  • Cross join of dimensions

    Hi,
    For example:  two dimension tables and one fact table.
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    branch1
    branch2
    dim2: time
    day1
    day2
    fact: sales
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    And I have tried set branch - fact and time - fact as outer join. In answers,
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    day2, 100
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    branch2, null
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    branch 2, null, null

  • [nQSError: 14065] Illegal cross join

    I am getting the following the following error “[nQSError: 14065] Illegal cross join” in the following situation.
    We have one dimension table Called “WC_CUSTOMER_D” and in that table we are storing 2 row_wids one to store the “Status Wid” (data comes from WC_LOV_D) and “Risk Wid” (again data comes from WC_LOV_D) of the customer . We have 2 alias table as Dim_Status_WC_LOV_D and Dim_Risk_WC_LOV_D and it joins to the Dim_WC_CUSTOMER_D .
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    Error comes only if we use alias of same physical type more than once
    Query Status: Query Failed: [nQSError: 14065] Illegal cross join within the same dimension caused by incorrect subject area setup: [
    WC_CUSTOMER_D T624599,
    WC_LOV_D T624699] with [
    WC_LOV_D T628734]
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    from
    WC_LOV_D T628734 /* Dim_Risk_WC_LOV_D_ */ ,
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    WC_CUSTOMER_D T624599 /* Dim_W_CUSTOMER_D */ ,
    WC_CUSTOMER_F T623979 /* Fact_WC_CUSTOMER_F */
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    order by c1, c2, c3
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    Thanks
    Barna

    Hi,
    Maybe you have already resolved this issue. In any case, I found a solution following instructions in support note ID 1329237.1.
    Best regards,
    Cristina

  • [nQSError: 14065] Illegal cross join within the same dimension

    Hey guys,
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    Try this;
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    Chris.

  • Cross Join in ABAP Open SQL

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    form append_itab.
      append itab.
    endform.               
    Regards
    Sridhar.

  • Error occurred when executing query involving cross join or outer join

    Hi,
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              extractValue(po.content, '/PurchaseOrder/Header/DocumentID/RID')
              = extractValue(value(invoice_line_item), '/LineItem/Product/PurchaseOrderIdentifier/documentCreatorIdentifier')
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         Error: ORA-00904: "INVOICE"."SYS_NC0012900130$": invalid identifier
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         Error: ORA-00904: "INVOICE"."SYS_NC0012900130$": invalid identifier
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    Hi,
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    Since, few reports are working on the infoset , this could be those reports are not using the fields from the infoobjects. so it is working it seems.
    Please check and let me know.
    Thanks,
    V.Senthil

  • CONNECT BY with CROSS JOIN and WHERE not executing as described in doc

    Hello all,
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    The 2nd statement shows one row more than the first, but the CROSS JOIN with WHERE is the same as the INNER JOIN.
    The result would be OK if Oracle did:
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    JOIN (and WHEREs for JOINS) -> CONNECT BY PRIOR -> Rest of WHERE
    See http://docs.oracle.com/cd/E11882_01/server.112/e26088/queries003.htm#SQLRF52332 for details. There it says:
    Oracle processes hierarchical queries as follows:
    A join, if present, is evaluated first, whether the join is specified in the FROM clause or with WHERE clause predicates.
    The CONNECT BY condition is evaluated.
    Any remaining WHERE clause predicates are evaluated.
    +.....+
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    --Statement 1:
    WITH t1
    AS
    (SELECT 1 a, 2 b FROM DUAL UNION ALL
    SELECT 2 a, 3 b FROM DUAL UNION ALL
    SELECT 3 a, 4 b FROM DUAL UNION ALL
    SELECT 4 a, 5 b FROM DUAL UNION ALL
    SELECT 5 a, 6 b FROM DUAL),
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    (SELECT 1 c FROM DUAL UNION ALL
    SELECT 2 c FROM DUAL UNION ALL
    SELECT 3 c FROM DUAL UNION ALL
    SELECT 5 c FROM DUAL)
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    CONNECT BY t1.a = PRIOR t1.b
    START WITH t1.a = 1
    ORDER BY
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    --1     1     2     1     /1
    --2     2     3     2     /1/2
    --3     3     4     3     /1/2/3
    --Statement 2:
    WITH t1
    AS
    (SELECT 1 a, 2 b FROM DUAL UNION ALL
    SELECT 2 a, 3 b FROM DUAL UNION ALL
    SELECT 3 a, 4 b FROM DUAL UNION ALL
    SELECT 4 a, 5 b FROM DUAL UNION ALL
    SELECT 5 a, 6 b FROM DUAL),
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    (SELECT 1 c FROM DUAL UNION ALL
    SELECT 2 c FROM DUAL UNION ALL
    SELECT 3 c FROM DUAL UNION ALL
    SELECT 5 c FROM DUAL)
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    --Result:
    --1     1     2     1     /1
    --2     2     3     2     /1/2
    --3     3     4     3     /1/2/3
    --5     5     6     5     /1/2/3/4/5My details:
    Oracle Database 11g Enterprise Edition Release 11.2.0.2.0 - 64bit Production
    PL/SQL Release 11.2.0.2.0 - Production
    CORE     11.2.0.2.0     Production
    TNS for Solaris: Version 11.2.0.2.0 - Production
    NLSRTL Version 11.2.0.2.0 - Production

    blama wrote:
    Hello Paul,
    that means that "a,b" isn't the same as "a CROSS JOIN b".
    I don't think that that is really the case.
    Do you have docs on this one?No explicit docs just (my) logic - having said that, I suppose it is implied that if you are doing ANSI style joins, it's not the where clauses that
    are specifying the join.
    If you do t1,t2 where t1.a=t2.a then Oracle figures out the kind of join from the (relevant) where clauses and treats the other where clauses after the CONNECT BY.
    If you do t1 cross join t2 where t1.a=t2.a then you are saying the join is completely specified by the CROSS JOIN - i.e it's Cartesian. Oracle doesn't look at the where clauses for this. Therefore
    all where clauses are treated as 'other' and are evaluated after the CONNECT BY.
    So, in my mind it's 10g that has the bug.

  • Cross joins on queries

    HI,
        how we can apply cross joins on select query.plz help me .I am using tables ekko,ekpo and lfa1 .Plz help.

    Hi Amardeep,
    as code given by one of guru's in the above joins statement is good when only if use the KEY-FIELDS in where condition if not it causes performance issue , so that you can use the FOR ALL ENTRIES IN statement which it gives good perfomance.
    Table declarations
    TABLES: ekko, "Purchasing Document Header
            ekpo, "Purchasing Document Item
            lfa1. "Vendor Master (General Section)
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             ebeln TYPE ebeln,
             lifnr TYPE lifnr,
           END OF tbl_ekko.
    data: BEGIN OF tbl_ekpo,
             ebeln TYPE ebeln,
             ebelp TYPE ebelp,
           END OF tbl_ekpo.
    data: BEGIN OF tbl_lfa1,
             lifnr TYPE lifnr
             ebelp TYPE ebelp,
           END OF tbl_lfa1.
    *Selection screen:
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    SELECT lifnr
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    if sy-subrc = 0.
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    endif.
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    SELECT ebeln lifnr
       FROM ekko
        INTO  table tbl_ekko
         FOR ALL INTRIES IN tbl_lfa1
    WHERE ebeln EQ p_ebeln
         AND  lifnr EQ tbl_lfa1-lifnr.
    if sy-subrc = 0.
    sort tbl_ ekko by ebeln.
    endif.
    endif.
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    SELECT ebeln ebelp
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    if sy-subrc = 0.
    sort tbl_ ekpo by ebeln.
    endif.
    endif.
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      LOOP AT tbl_ekpo.
    read table ekko with key ebeln = tbl_ekpo-ebeln BINARY SEARCH.
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                      tbl_ekpo-lifnr.
    endif.
      ENDLOOP.
    <b>NOTE : use only KEY-FIELDS in WHERE condition for better perfomance</b>
    In that above code you can change a/c to ur inputs availabe.
    <b>Reward with points if helpful.</b>
    Regards,
    Vijay

  • Fetch multiple rows using cross-join technique

    Hello.
    Can anyone suggest a method to return 3 rows from a query when only one row would otherwise be returned?
    I'm trying to achieve the Logical SQL analog to this -
    SELECT x.foo, p.id, p.name FROM people p CROSS JOIN (SELECT 1 AS foo UNION ALL SELECT 2 UNION ALL SELECT 3) x;Reason: I want to force a three (n) row result and use GROUP BY with case statements to create 3-level summary.
    Here is a simple Logical SQL expression that works for my OBI setup -
    SELECT
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         "- Nx_CSDG0_Repair_Orders (Depot Repair Views)".SR_Operating_Unit_Name saw_1
    FROM
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    WHERE
         ("- Nx_CSDG0_Repair_Orders (Depot Repair Views)".Repair_Number = '338246')But I think I cannot do this -
    SELECT
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         "- Nx_CSDG0_Repair_Orders (Depot Repair Views)".SR_Operating_Unit_Name saw_1
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         "[Noetix-NoetixGlobalRepository] NoetixViews for Oracle Service"
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    WHERE
         ("- Nx_CSDG0_Repair_Orders (Depot Repair Views)".Repair_Number = '338246')But what can I do?
    Thank you.
    -cs

    Hi CSeelig ,
    The BI Server uses the ANSI SQL standard. Then all SQL that follows this specification will in OBIEE work.
    I have made an example with a densification:
    http://gerardnico.com/wiki/dat/obiee/logical_sql/obiee_sql_densification
    You will see a cross join to make a densification.
    Cheers
    Nico

  • CARTESIAN/CROSS JOIN

    HI,
    i use OBIEE version 11.1.1.6.0. I created dummy fact table and column in physical layer. and join all dimensional table with this fact. but i dont know ow handle with it in business model. can anyone help me to create cross join?
    Thanks
    Edited by: 968086 on Oct 30, 2012 12:59 AM

    Follow this link
    http://www.rittmanmead.com/2009/08/oracle-bi-ee-10-1-3-4-1-reporting-on-non-transactional-dimension-values-equivalence-of-outer-joins/
    Pls mark if helps

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