Data recovery on server failure

Hi all,
According to Rule-of-thumb: each 1 GB JVM can store 350 MB of actual object data, assume we need to have 8GB data on Coherence, according to above rule:
8192/350 = ~24 JMVs required => 24*1.2 = ~29 GB
Then at least we need 2 servers of 16G RAM.
we plan to have 4 JVMs as cache servers on each of the two 16GB servers as it recommends not to have more than 4GB heap for each cluster node.
I wonder if one of the servers crashes, the 4 cluster nodes residing on it go down. If primary and backup of some data are both distributed inside those 4 cluster nodes that go down, then data is lost even the other server has enough capacity to have full redundancy.
Is this correct? If yes, how to solve it? Is Coherence smart enough to put primary and backup in different boxes, not just different node whenever possible?

922963 wrote:
Hi JK,
Thanks for response. Yes, I am worried that it may not be enough. How about if I increase memory to 32GB, ie. I have two servers, both with 32GB? Will it be sufficient in case of one physical server fail for 8GB data?
What is the point in having the 3rd physical box if two boxes have enough memory/capacity? You know, we need to pay licence according to no of CPU.
thanks,
HenryHi Henry,
actually the recommended minimum number of physical boxes is 4 so that the witness protocol participants can all be on separate machines.
But a minimum of 3 is highly recommended for a number of reasons related to partitioning:
1. If you have only 2, then you are much more vulnerable to split brain scenarios (should for some reason the two servers not be able to communicate with each other, it is harder to decide which half should be the winner). In short how do you decide which box is unable to communicate with the rest of the cluster if there are only 2 boxes?
2. You can't ensure a balanced and also machine safe partition distribution if you have a mismatching number of nodes on only 2 boxes. It would either be balanced or machine safe, but you can't get both at the same time. And you will either have mismatching number of nodes at startup or have mismatching number of nodes after one node failure.
Best regards,
Robert

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