Database design problem. Need Help?

I have to display records in a table in a UI where users are allowed to move records to specify priority for the records.
Here is an example, a db table has 4 records:
RecordId Ranking
A 1
B 2
C 3
D 4
Now if a user tries to set the Ranking of the record with RecordId "D" to say 1, I now have to update all records in this table. So the result should be the following:
RecordId Ranking
D 1
A 2
B 3
C 4
This means that if a user wants to change the Ranking of the last record to be that of the first record, I have to update all records in the table. I am trying to figure out an algorithm that can do this better than deleting all records and adding new records or updating all records. Any help will be greatly appreciated. Thank you in advance.
null

Well, does your computer actually support the required features? Is OpenGL enabled in PS? If not, you can't do anything with 3D. OpenGL support is mandatory. If it doesn't work you can try to update your graphics driver, but otherwise there is no way to enforce it. Also did you uninstall your Design Standard before installing Premium? if it's still using the old serioal number, then the features wouldn't show up in PS, eitehr.
Mylenium

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Oracle Designer Problem Please help me

Sir,
1) I created a database
2) Run>cd d:\Oracle_home\repadm61\admin\@ckqa
@ckparams.txt
@ ckvalqa
@ ckcreate
3)Opened Repository Administration Utility
Log in as 'repos_manager/repos_manager@orcltest'
Installed Repository.
4) Opened Oracle 9i Designer. I am able to connect
as 'repos_manager/repos_manager@orcltest'
But I am not able to logon as any other user in same database/ any other user in different database. Why?
Please help me.
regards
Mathew

duplicate thread, see this one -> Re: Oracle Designer Problem Please help me

SIMPLE Database Design Problem !

Mapping is a big problem for many complex applications.
So what happens if we put all the tables into one table called ENTITY?
I have more than 300 attributeTypes.And there will be lots of null values in the records of that single table as every entityType uses the same table.
Other than wasting space if I put a clustered index on my entityType coloumn in that table.What kind of performance penalties to I get?
Definition of the table
ENTITY
EntityID > uniqueidentifier
EntityType > Tells the entityTypeName
Name >
LastName >
CompanyName > 300 attributeTypes
OppurtunityPeriod >
PS:There is also another table called RELATION that points the relations between entities.

>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
check the coloumn with WHERE _entityType='PERSON'
as there is is clustered index on entityType...there
is NO performance decrease.
there is also a clustered index on RELATION table on
relationType
when we say WHERE _entityType ='PERSON' or
WHERE relationType='CONTACTMECHANISM'.
it scans the clustered index first.it acts like a
table as it is physically ordered.I was thinking in terms of using several conditions in the same select, such as
WHERE _entityType ='PERSON'
AND LastName LIKE 'A%' In your case you have to use at least two indices, and since your clustered index comes first ...
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
Have you ever thought of using constraints in your
modell? How would you realize those?
...in fact we did.We have arranged the generic object
model in an object database.The knowledge information
is held in the object database.So your relational database is used only as a "simple" storage, everything has go through your object database.
But the data schema is held in the RDBMS with code
generation that creates a schema to hold data.If you think that this approach makes sense, why not.
But in able to have a efficent mapping and a good
performance we have thought about building only one
table.The problem is we know we are losing some space
but the thing is harddisk is much cheaper than RAM
and CPU.So our trade off concerated on the storage
cost.But I still wonder if there is a point that I
have missed in terms performance?Just test your approach by using sufficiently data - only you know how many records you have to store in your modell.
PS: it is not wise effective using generic object
models also in object databases as CPU cost is a lot
when u are holding the data.I don't know if I'd have taken your approach - using two database systems to hold data and business logic.
PS2: RDBMS is a value based system where object
databases are identity based.we are trying to be in
the gray area of both worlds.Like I wrote: if your approach works and scales to the required size, why not? I would assume that you did a load test with your approach.
What I would question though is that your discussing a "SIMPLE Database Design" problem. I don't see anything simple in your approach when it comes to implementation.
C.

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johnnnyp wrote:
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If the functions in Rescue Mode aren't working properly then you need to contact Creative Support.

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Hi,
I need some help:
I am using Oracle 10g Server Release 2
For Clientele activilty I am using Oracle Client where the Application resides.
For Better performance I want to use the In-Memory Database Cache option Times-Ten Database.
Is it possible to do so where there is Oracle Database Server Relaease 2 and in the Client there is Times-Ten In-Memory Database Cache?
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Still stuck with the same old producer consumer weight problem need help

Hello All,
This is the problem I am stuck with right now.
I have two array lists one producer array list and one consumer array list denoted by a and b
P1 P2 P3 P4 P5
5 6 7 8 9
C1 C2 C3 C4 C5
2 3 4 5 6
Now we find all those producer consumer pairs which satisfy the criteria Pi>=Ci
We have the following sets
(5,2)(6,2)(7,2),(8,2),(9,2)
(5,3)(6,3)(7,3),(8,3),(9,3)
(5,4)(6,4)(7,4),(8,4),(9,4)
(5,5)(6,5)(7,5),(8,5),(9,5)
(6,6)(7,6)(8,6),(9,6)
Let us done each of them with Si
so we have S1,S2,S3,S4,S5
we assign a third parameter called weight to each element in Si which has satisfied the condition Pi>=Ci;
so we we will have
(5,2,ai),(6,2,bi),(7,2,ci)....etc for S1
similarly for S2 and so on.
We need to find in each set Si the the pair which has the smallest weight.
if we have (5,2,3) and (6,2,4) then 5,2,3 should be chosen.We should make sure that there is only one pair in every set which is finally chosen on the basis of weight.
Suppose we get a pair (5,2,3) in S1 and (5,2,3) in S2 we should see that (5,2,3) is not used to compare to compare with any other elements in the same set S2,
Finally we should arrive at the best element pair in each set.They should be non repeating in other sets.
Given a problem
P0 P1 P2 P3 P4
9 5 2 2 8
6 5 4 5 3
C0 C1 C2 C3 C4
we have So as (P0,C0) and (P4,C0)
assuming that the one with the smaller index has lesser weight PO is selected.In the program I have used random weights.from set S1 we select the pair PO,CO
S1 =(P0,C1),(P1,C1) and (P4,C1)
since P0 and P4 are already used in previous set we dont use them for checking in S1 so we have (P1,C1) as best.
S2=(P0,C2),(P1,C2) and (P4,C2) so we dont use P0,C2 and P1 and C2 because PO and P1 are already used in S1.
So we choose P4,C2
in S3 and S4 ae have (P0,C3),(P1,C3),(P4,C3) so we dont choose anything
and same in S4 also.
So answer is
(P0,C0),(P1,C1) and (P4,C2).
My program is trying to assign weights and I am trying to print the weights along with the sets.It doesnt work fine.I need help to write this program to do this.
Thanks.
Regards.
NP
What I have tried till now.
I have one more question could you help me with this.
I have an array list of this form.
package mypackage1;
import java.util.*;
public class DD
private int P;
private int C;
private int weight;
public void set_p(int P1)
P=P1;
public void set_c(int C1)
C=C1;
public void set_weight(int W1)
weight=W1;
public int get_p()
return P;
public int get_c()
return C;
public int get_x()
return weight;
public static void main(String args[])
ArrayList a=new ArrayList();
ArrayList min_weights_int=new ArrayList();
ArrayList rows=new ArrayList();
ArrayList temp=new ArrayList();
Hashtable h=new Hashtable();
String v;
int o=0;
DD[] d=new DD[5];
for(int i=0;i<4;i++)
d=new DD();
for(int i=0;i<4;i++)
d[i].set_p(((int)(StrictMath.random()*10 + 1)));
d[i].set_c((int)(StrictMath.random()*10 + 1));
d[i].set_weight(0);
System.out.println("Producers");
for(int i=0;i<4;i++)
System.out.println(d[i].get_p());
System.out.println("Consumers");
for(int i=0;i<4;i++)
System.out.println(d[i].get_c());
System.out.println("Weights");
for(int i=0;i<4;i++)
System.out.println(d[i].get_x());
for(int i=0;i<4;i++ )
int bi =d[i].get_c();
ArrayList row=new ArrayList();
for(int j=0;j<4;j++)
if( d[j].get_p() >=bi)
d[j].set_weight((int)(StrictMath.random()*10 + 1));
row.add("(" + bi + "," + d[j].get_p() + "," +d[j].get_x() + ")");
else
d[j].set_weight(0);
row.add("null");
rows.add(row);
System.out.println(rows);
int f=0;
for(Iterator p=rows.iterator();p.hasNext();)
temp=(ArrayList)p.next();
String S="S" +f;
h.put(S,temp);
String tt=new String();
for(int j=0;j<4;j++)
if(temp.get(j).toString() !="null")
// System.out.println("In if loop");
//System.out.println(temp.get(j).toString());
String l=temp.get(j).toString();
System.out.println(l);
//System.out.println("Comma matches" + l.lastIndexOf(","));
//System.out.println(min_weights);
f++;
for(Enumeration e=h.keys();e.hasMoreElements();)
//System.out.println("I am here");
int ii=0;
int smallest=0;
String key=(String)e.nextElement();
System.out.println("key=" + key);
temp=(ArrayList)h.get(key);
System.out.println("Array List" + temp);
for( int j=0;j<4;j++)
String l=(temp.get(j).toString());
if(l!="null")
System.out.println("l=" +l);
[\code]

In your example you selected the pair with the greatest
distance from the first set, and the pair with the least
distance from the second. I don't see how the distance
function was used.
Also it's not clear to me that there is always a solution,
and, if there is, whether consistently choosing the
furthest or the closest pairs will always work.
The most obvious approach is to systematically try
all possibilities until the answer is reached, or there
are no possibilities left. This means backtracking whenever
a point is reached where you cannot continue. In this case
backtrack one step and try another possibility at this
step. After all possible choices of the previous step,
backtrack one more step and so on.
This seems rather involved, and it probably is.
Interestingly, if you know Prolog, it is ridiculously
easy because Prolog does all the backtracking for you.
In Java, you can implement the algorithm in much the same
way as Prolog implementations do it--keep a list of all the
choice points and work through them until success or there
are none left.
If you do know Prolog, you could generate lots of random
problems and see if there is always a solution.

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1. Be sure to use Disk Utility first to repair the disk before performing the Archive and Install.
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Hi All,
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anybody help me please?
I including my code.
My documents are:
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Oracle interMedia audio, document, image, and video is designed to manage Internet media content
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Oracle interMedia Users Guide and Reference, Release 9.0.1
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Oracle application server.
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Thanks,
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set serveroutput on
set echo on
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document ordsys.orddoc);
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INSERT INTO my_doc VALUES(2,ORDSYS.ORDDoc.init());
INSERT INTO my_doc VALUES(3,ORDSYS.ORDDoc.init());
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obj ORDSYS.ORDDoc;
ctx RAW(4000) := NULL;
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UPDATE my_doc SET document = obj WHERE id = 3;
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obj ORDSYS.ORDDoc;
idnum INTEGER;
ext VARCHAR2(5);
dotpos INTEGER;
mimetype VARCHAR2(50);
fname VARCHAR2(50);
ctx RAW(4000) := NULL;
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DBMS_OUTPUT.PUT_LINE('Content is NULL.');
DBMS_OUTPUT.PUT_LINE('No information available.');
ELSIF TO_CHAR(DBMS_LOB.getLength (obj.getContent())) <> 0 THEN
DBMS_OUTPUT.PUT_LINE('Document Source: ' || obj.getSource());
DBMS_OUTPUT.PUT_LINE('Document Name: ' || obj.getSourceName());
DBMS_OUTPUT.PUT_LINE('Document Type: ' || obj.getSourceType());
DBMS_OUTPUT.PUT_LINE('Document Location: ' || obj.getSourceLocation());
DBMS_OUTPUT.PUT_LINE('Document MIME Type: ' || obj.getMimeType());
DBMS_OUTPUT.PUT_LINE('Document File Format: ' || obj.getFormat());
DBMS_OUTPUT.PUT_LINE('BLOB Length: ' || TO_CHAR(DBMS_LOB.getLength (obj.getContent())));
END IF;
DBMS_OUTPUT.PUT_LINE('----------------------------------------');
END LOOP;
EXCEPTION
END;
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create index my_doc_idx1
on my_doc(document.comments)
indextype is ctxsys.context;
commit;
alter index my_doc_idx1
rebuild online
parameters('sync memory 10m');
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select id from my_doc t
where contains(t.document.comments,'oracle') > 0
order by id;
select id from my_doc t
where contains(t.document.comments,'application server') > 0
order by id;
select id from my_doc t
where contains(t.document.comments,'index creation') > 0
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Hi,
Which is best depends on the type of application you are building and the nature of the docs. For simple use with pdf's and word docs I prefer to use bfile or blob which is why I mentioned it. No sense in overcomplicating it.
My recommendation - look at the interMedia docs and determine if you need the advanced features it provides. I like the application a lot, but am a firm believer in not adding complexity if there is no benefit to be had. Unless you are just playing around with it to learn, I'd recommend matching your project requirements up with what best meets them and go whichever route that is.
Thanks,
Ron

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The G5 ports are DVI-I. Any good DVI-I to VGA adapter should be fine.

Database design problem. Need Help?

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