Days Since Jan 1, 1900. Days of the week

If I Had a long date,
04/16/2002 would be something like 37362.
How can I figure out what day of the week it would be?

If I Had a long date,
04/16/2002 would be something like 37362.
How can I figure out what day of the week it would
be?What day of week was for Jan 1, 1900? From that, you can do
( 37362 % 7 + (day of week for Jan 1, 1900) ) % 7
Of course, you need to make up a consistent representation of 0~6 for Mon~Sun.
--lichu

Similar Messages

How can i find the 1st business day of the week ?

Hi,
How can i find the 1st business day of the week excluding saturaday,sunday and holidays? i have holiday table which contains the columns name HolidayDate and HolidayDescription.
Ex:
10-1-2011 is monday(i.e) 1st business day.check If it is in holiday table,then return the result as 11-1-2011 else return the result as 11-1-2011(which is the first business day of this week).
Can anyone tell me the Query to solve it?

Does this help:
SQL> ed
Wrote file afiedt.buf
1 with t as (SELECT TRUNC(SYSDATE,'IW') holiday FROM dual
2 UNION SELECT TRUNC(SYSDATE + 7,'IW') from dual)
3 SELECT MIN(Dat),wk FROM
4 (SELECT TO_CHAR(dat,'IW') wk,dat FROM
5 (SELECT dat + lvl dat FROM
6 (SELECT TRUNC(SYSDATE,'RRRR') dat, level - 1 lvl
7 FROM dual
8 CONNECT BY level <= TO_DATE('31-DEC'||TO_CHAR(SYSDATE,'RRRR')) - TRUNC(SYSDATE,'RRRR'))
9 ) x
10 WHERE x.dat NOT IN (select holiday from t))
11 WHERE TO_CHAR(Dat,'DY') <> 'SAT'
12 AND TO_CHAR(dat,'DY') <> 'SUN'
13* group by wk
SQL> /
MIN(DAT) WK
04-JAN-11 01 -- since 03-JAN-2011 is in holiday list, 04 is taken as first business day of first week
11-JAN-11 02 -- similar to week 1
17-JAN-11 03
24-JAN-11 04
31-JAN-11 05
07-FEB-11 06
14-FEB-11 07
21-FEB-11 08
28-FEB-11 09
07-MAR-11 10
14-MAR-11 11
21-MAR-11 12
28-MAR-11 13
04-APR-11 14
11-APR-11 15
18-APR-11 16
25-APR-11 17
02-MAY-11 18
09-MAY-11 19
16-MAY-11 20
23-MAY-11 21
30-MAY-11 22
06-JUN-11 23
13-JUN-11 24
20-JUN-11 25
27-JUN-11 26
04-JUL-11 27
11-JUL-11 28
18-JUL-11 29
25-JUL-11 30
01-AUG-11 31
08-AUG-11 32
15-AUG-11 33
22-AUG-11 34
29-AUG-11 35
05-SEP-11 36
12-SEP-11 37
19-SEP-11 38
26-SEP-11 39
03-OCT-11 40
10-OCT-11 41
17-OCT-11 42
24-OCT-11 43
31-OCT-11 44
07-NOV-11 45
14-NOV-11 46
21-NOV-11 47
28-NOV-11 48
05-DEC-11 49
12-DEC-11 50
19-DEC-11 51
26-DEC-11 52
52 rows selected.
SQL>

Oracle returning incorrect day of the week

Hi there,
I have a table named Performance, which includes a date field named PDATE, some other attributes such as title, etc, and a field named WEEKDAY, which includes the numerical value for the day of the week. Here is an example:
PER#
P#
THEATRE#
WEEKDAY
PDATE
PHOUR
PMINUTE
COMMENTS
1
1
1
1
02-MAR-10
19
30
Normal evening time
2
1
1
2
03-MAR-10
19
30
Normal evening time
58
6
6
3
04-MAR-10
19
30
Normal evening time
5
1
1
4
05-MAR-10
19
30
Normal evening time
I went to verify the day of the week in a calendar (in fact I checked more than one) and I noticed that the Weekday value seems incorrect. For instance, the 2nd of March was a Tuesday so I would expect WEEKDAY to say 3 (considering Sunday to be the 1st day of the week, which is the universal norm), or perhaps 2 (considering Monday to be the 1st day of the week).
First thing that came to mind is, since the WEEKDAY is a number field which has been pre-populated, the person who populated it made a mistake.
So I went to verify this by running a query that would give me the correct day of the week by extracting it from the PDATE field:
SELECT DISTINCT pdate, EXTRACT(year from pdate) year,
to_char(to_date(pdate,'DD/MM/YYYY'),'DY') weekdaycalc, weekday
FROM ops$yyang00.Performance
ORDER BY pdate
And to my astonishment, I got the following table as a return:
PDATE
YEAR
WEEKDAYCALC
WEEKDAY
02-MAR-10
2010
SUN
1
03-MAR-10
2010
MON
2
04-MAR-10
2010
TUE
3
05-MAR-10
2010
WED
4
06-MAR-10
2010
THU
5
07-MAR-10
2010
FRI
6
08-MAR-10
2010
SAT
7
09-MAR-10
2010
SUN
1
10-MAR-10
2010
MON
2
As you can see, all of the above WEEKDAYCALC values are incorrect, and seem to match the incorrect values in WEEKDAY.
I could perhaps understand some weird WEEKDAY numbering if there is some general database setting where I could specify any day of the week to be the first day. However, I can't think of any logical explanation on why Oracle would call a Tuesday Sunday.
Could someone please advise what I mght be doing wrong? This is driving me insane!
Thank you in advance for all the help and support.
Regards,
P.

Hi,
1bded5c7-e555-4306-ac86-45da83dff439 wrote:
Thanks both Frank and Solomon for the help. I am quite new to Oracle and I feel you folks went the extra mile on the explanation
Based on your explanations, I changed the formula so the date format would be processed as YY rather than YYY.
SELECT DISTINCT pdate, EXTRACT(year from pdate) year,
to_char(to_date(pdate,'DD/MM/YY'),'DY') weekdaycalc, weekday
FROM Performance
ORDER BY pdate
And I got the correct values now:
PDATE
YEAR
WEEKDAYCALC
WEEKDAY
02-MAR-10
2010
TUE
1
03-MAR-10
2010
WED
2
04-MAR-10
2010
THU
3
05-MAR-10
2010
FRI
4
06-MAR-10
2010
SAT
5
07-MAR-10
2010
SUN
6
08-MAR-10
2010
MON
7
The interesting bit here, is the original WEEKDAY field, which clearly has been created with the same mistake I did (this whole table wasn't created by me). I reckon I spotted a design bug.
Regards,
P.
No; you're still calling TO_DATE on something that is already a DATE, and you're still using an implicit conversion (only now you're using a format such that the current NLS settings don't cause you to get punished. If your DBA changes the NLS settings next week, then you will have similar errors again.)
If you want to see what day of the week pdate is, then use:
TO_CHAR (pdate, 'DY')
or, to make it NLS-independent:
TO_CHAR (pdate, 'DY', 'NLS_DATE_LANGUAGE=ENGLISH')
This is simpler than what you posted, it's more efficient and easier to debug and to maintain, and it also gets the results you want in all cases.
One more time: TO_DATE, as the name hints, converts something (a VARCHAR2, to be precise) TO a DATE. If pdate is already a DATE, then what do you need to convert? You're implicitly converting a DATE to a VARCHAR2, then explicitly converting that VARCHAR2 back to a DATE, and then calling TO_CHAR. That's 3 function calls (1 of them error prone) where only 1 is needed.
Also if you ever have to reconcile 2-digit years with 4-digit years (and, again, in this problem you don't) the correct way is to convert the 2-digit year to a 4-digit year, not vice-versa.
Calling Tuesday the 1st day of the week could make sense in a particular application.

I have several recuring alarms set up on my calendar for each day of the week. In the past few weeks, an alarm will occasionaly notify me roughly 15 minutes to an hour and a half late. These daily alarms are identical and repeat every day.

I have several recuring alarms set up on iCal for each day of the week. In the past few weeks, an alarm will occasionaly notify me roughly 15 minutes to an hour and a half late. These daily alarms are identical and repeat every day and there seems to be no apparent pattern to why or when an alarm happens after the event is past.

I assume you meant iCal rather than iTunes? Yes, iCal the time zone is correct. The delayed alarms only happen sporadically. Since I posted this message, the problem stopped happening every day at the same time, but it still happens occasionally with no rhyme or reason as to when. It's gotten so that I can't depend on my iCal alarms anymore.

From where to get "First day of the week" data for all the locales, is it present in CLDR spec 24?

I am trying to get "First day of the week" data from CLDR spec24 but cannot find where to look for it in the spec. I need this data to calculate numeric value of "LOCAL day of the week".
This data to implement "c" and "cc" day formats that equals numeric local day of the week.
e.g if "First day of the week" data for a locale is 2 (Monday) , it means numeric value for local day of the week will be 1 if it is Monday that day, 2 if it is Tuesday that day and likewise.

Hi
If you want to week to be started with Sunday then use the following formula:
TimestampAdd(SQL_TSI_DAY, 1-DAYOFWEEK(Date'@{var_Date}'), Date'@{var_Date}') if it's retail week(starts from Monday) then the follow below:
TimestampAdd(SQL_TSI_DAY, 1-DAYOFWEEK(Date'@{var_Date}'), Date'@{var_Date}')
I'm assuming var_Date is the presentation variable for prompt...
Edited by: Kishore Guggilla on Jan 3, 2011 4:48 PM

Want to make Monday as the first day of the week in GregorianCalendar. how?

hi
I need to know what day is the first of the month is. for example the 1st of Nov 2004 is Moday and 1st of Dec 2004 is saturday.
I am using the GregorianCalendar:
1. GregorianCalendar calendar = new GregorianCalendar(2004,11,1); //set date to 1st Nov 2004
2. int firstDay = calendar.get(Calendar.DAY_OF_WEEK);now firstDay is 2. This is because the week starts from Sunday, so Monday is the 2nd day.
But I am in Uk and my Uk Calendar shows monday as the first day (even in Windows 2000 Calendar).
I would like the GregorianCalendar to have Monday as the first day of the week, so that the
int firstDay = calendar.get(Calendar.DAY_OF_WEEK);
returns 1 in the above case.
I also tried adding
calendar.setFirstDayOfWeek(Calendar.MONDAY); just between line 1 and line 2, but it did not help.
This is because i don't want to manually subtract 1. If i manually subtract one, then the program might not work in other locale and timezones.
Also if I subtract 1, then for 1 Feb 2004,
int firstDay = calendar.get(Calendar.DAY_OF_WEEK);
will return 1 as 1st Feb 2004 falls on Sunday. so if i subtract 1 it will be 0, so I have to do a extra checking for 0.
Is there anyway to make the Calendar have Monday as the first day of the week??
Tanveer

hi
I need to know what day is the first of the month is.Why does this matter? Since we know that 1 == Sunday and 2 == Monday... Why do you need Monday to be == 1? and couldn't you just subtract 1 if it's so important?
for example the 1st of Nov 2004 is Moday and 1st of
Dec 2004 is saturday.
I am using the GregorianCalendar:
1. GregorianCalendar calendar = new
GregorianCalendar(2004,11,1); //set date to 1st Nov
2004
2. int firstDay = calendar.get(Calendar.DAY_OF_WEEK);now firstDay is 2. This is because the week starts
from Sunday, so Monday is the 2nd day.
But I am in Uk and my Uk Calendar shows monday as the
first day (even in Windows 2000 Calendar).
I would like the GregorianCalendar to have Monday as
the first day of the week, so that the
int firstDay = calendar.get(Calendar.DAY_OF_WEEK);
returns 1 in the above case.
I also tried adding
calendar.setFirstDayOfWeek(Calendar.MONDAY);[/cod
] just between line 1 and line 2, but it did not help.
This is because i don't want to manually subtract 1.
If i manually subtract one, then the program might not
work in other locale and timezones.
Also if I subtract 1, then for 1 Feb 2004,
int firstDay = calendar.get(Calendar.DAY_OF_WEEK);
will return 1 as 1st Feb 2004 falls on Sunday. so if i
subtract 1 it will be 0, so I have to do a extra
checking for 0.
Is there anyway to make the Calendar have Monday as
the first day of the week??
Tanveer

Is there a way to change the start day for the week?

So I really like the "Insert Categories from the following" functionality of the Reorganize tool, and I fell in love with it's ability to break down by date automagically. I've encountered one problem with my use of it, though: I start my "work week" on Sunday, and it defaults to Monday as the first day of a week without any seeming way to change it to Sunday. Is there a way to do this?

Hi Christopher,
The WEEKDAY function allows specifying either Sunday or Monday as the first day of the week:
WEEKDAY
The WEEKDAY function returns a number that is the day of the week for a given date. WEEKDAY(date, first-day)
Â date: The date the function should use. date is a date/time value. The time portion is ignored by this function.
Â first-day: An optional value that specifies how days are numbered.
Sunday is 1 (1 or omitted): Sunday is the first day (day 1) of the week and Saturday is day 7.
Monday is 1 (2): Monday is the first day (day 1) of the week and Sunday is day 7. Monday is 0 (3): Monday is the first day (day 0) of the week and Sunday is day 6.
But I think you are referring to the first day of the 'workweek', for which I do not see a means of defining a custom value.
Since you want to 'insert categories', though, you could easily define your own, using WEEKDAY(date) or WEEKDAY(date,1), plus an IF statement to return the category label appropriate to the day. Here's one for a Sunday to Thursday work week. Dates are in column A, the formula is in whichever column you want as the Category column. For the example, I've placed it in column B.
B2, and filled down: =IF(WEEKDAY(A)<6,"Work","Off")
The top table shows the weekday numbers returned for each day of the week for each of the three permitted values for the optional second argument. The bottom table shows the results from the formula above, used to define a category label for each date:
A10 was left blank intentionally, to determine if the lack of data resulted in an error. The Warning message, flagged by the blue 'warning' triangle, is "The formula uses a number in place of a date." The 'date' assigned to this numerical value of zero was a Friday, but I'm not certain when. Probably best to avoid extra rows with no date shown.
Regards,
Barry

Moving a GregorianCalendar to the first day of the week

I'm using a GregorianCalendar class in order to get the time stamp for the nearest Sunday's date.
here's what I'm trying to do:
1. get a timeStamp and set it into a date
Date startDate = new Date(startTime);2. create a new GregorianCalendar using the above date as the start time.
GregorianCalendar calendar = new GregorianCalendar((startDate.getYear()+1900),startDate.getMonth(),startDate.getDate());3. the tricky part: make sure the calnedar's date is set to Sunday, if the current date is on any day other then Sunday, I will have to move it back to the nearest Sunday. I'm trying to do this by using:
calendar.set(Calendar.DAY_OF_WEEK, 0); for some reason this does not work...
am I doing anything wrong here?

thanks for that info but the problem is still there. here's some more input:
//creating the date, the ts here is 1153858800000 which is the dated in 7/25/2006
Date startDate = new Date(startTime);
//creating the new calendar
GregorianCalendar calendar = new GregorianCalendar((startDate.getYear()+1900),startDate.getMonth(),startDate.getDate());
//setting the calendar to the first hour (not sure it necessary)
calendar.set(Calendar.HOUR, 1);
//setting the calendar to the first day of the week
calendar.set(Calendar.DAY_OF_WEEK, 1);
//this returns 1153778400000 which is still dated 7/25/2006 whic is a Tuesday I would expect it to returns a different date
calendar.getTimeInMillis()

Days of the week - Newbie question

Please excuse my question as it is probably very elementary and basic to all of you, but I am just getting started learning how to use Numbers and have run into a question that I can't find an answer for in the books or on the tutorials.
I want to have a column with the days of the week (Mon, Tues...) to automatically update as I proceed down the rows of data. I can not come up with the proper formula or the proper way to express a formula to make it perform that task. Any help would be appreciated.
This isn't as important as most of your things since I'm retired and just using this for my personal enjoyment, but I'm sure learning a lot! Thanks, John.

Type Monday in one row, Tuesday in the row below it. Select both. Drag down on the little circle in the bottom right of the selection box. It will fill in the rest of the days.
A second way to do it would be using the DAYNAME formula. You will have to modify the formula depending on which row you start in but it is basically this:
=DAYNAME(ROW()-1)
Change the "-1" to whatever value that makes ROW()+value = 2 (assuming you want to start with Monday)
EDIT: You did not specify if you only wanted monday through Friday. The methods above assume you want every day of the week.
In the first method, if you only want Monday-Friday, type all the days of the week in consecutive rows, select all five cells, copy them to the next five rows, select all ten cells, then drag down. For the other method the formula will be something like
=DAYNAME(MOD(ROW()-1,5)+2)
Message was edited by: Badunit

Days of the Week/Months are listed as numbers

My computer has recently been updated and rebooted, and since then my iCal has displayed the date, days of the week, etc differently. iCal does not display any months or days of the week- they are simply just numbers. I haven't been able to see that this is a setting- can anyone help? Thanks!

Icheney,
1. Open System Preferences...>Language & Text>Formats>Region: and set/re-set the appropriate region.
2. Find and resolve duplicate fonts with Mac 101: Font Book

How can I get the day of the week to display in ical5?

I can only see the date, e.g. 20, 21, 22 but not the day of the week, e.g. 20 Wednesday, 21 Thursday. How do change this view? Thank you

You need to create a stringwriter, wrap it in a printwriter, then print to the printwriter, then convert the stringwriter to a string.
Here's an example:
StringWriter sw = new java.io.StringWriter();
PrintWriter pw = new java.io.PrintWriter(sw);
e.printStackTrace(pw);
String strError = sw.toString();
I hope this works. I didn't test the above code. I don't think I'm leaving anything out, but it's been a while since I've done it. Either way, it should get you on the right track to get what you need.
Hope that helps.
Michael

Figure out dates corresponding to days of the week, constructing a schedule

Hi everyone,
I'm sorry if this topic has already been covered. I've searched the forums for an answer, but did not see anything I took to be an answer (I'm not very good at this).
I'm trying to make a simple table to tell me which dates a particular day of the week falls on. For instance, I'm making a syllabus for a class that meets every Tuesday and Thursday. I want to know which dates corresponds to every Tuesday and Thursday from here on out.
I currently have a table with two columns. The first column is the day of the week. The first row is Tuesday, the second is Thursday, the third Tuesday, etc. I was able to do this easily with auto fill. I want the next column to be the date.
Here's a picture of what I mean:
Is there a formula that will let me do this?
Thanks!

Hi Macademic,
How about putting both into the first column?
Select all of column A and use the Cell Format inspector to set the format as Date and Time, with the Date: and Time: pop-up menus set to:
Date: Mon, Jan 5, 2009
or: Monday, January 5, 2009
or to a Custom format, Date and Time, including only the elements you want in the format you want them.
Time: None
Enter the starting date into A2, and confirm that it is either a Tuesday or a Thursday.
In A3, enter
=A2+2 (if the course starts on a Tuesday)
or
=A2+5 (if the course starts on a Thursday)
In A4, enter
=A2+7
Select A3 and A4, then grab the control (small circle at the lower right corner of the selection) and drag down until you reach the last date of the course.
Regards,
Barry

Regarding Start day of the week

Suppose in a program if User enters the start day of the week be 'Tuesday', then I have to get that day of the week as '1' and end the week with 'Monday' i.e the '7'. Is there any Query or NLS_Parameter setting?

Hi,
Since Tuesday is 1 day after the start of the ISO week,
TRUNC (dt) - TRUNC (dt - 1, 'IW')will be an integer in the range 1-7, where 1 means dt was a Tuesday, and 7 means dt was a Monday.
This does not depend on NLS settings.
NLS_TERRITORY controls which day of the week
TO_CHAR (dt, 'D')will be '1', but all the settings I know of make that Saturday, Sunday or Monday. I don't know if there's a value that makes it Tuesday.

Formula for calculating the average takings for a given day in the week?

I would like to calculate the average takings for each day of the week for a given financial year.

Rick,
I've looked at your document, made some additions and returned it to you. In your document you were not only using AVERAGE, but also MIN and MAX. Unfortunately, MIN and MAX don't have "IF" versions, so they can't be used to selectively operate on data matching criteria in a range.
What I did to accommodate the need for MIN and MAX was to add a column for each criteria, in this case the different days of the week.
In your document you also indicated the need for a Chart to graphically summarize the performance by day of the week. I rearranged your summary stats table to facilitate creating a chart from that table. I chose the mixed category chart with Bars for Min and Max and a Line for Average.
Following are Screen Shots for the modified Data table, the Stats table and the Chart:
The key expressions are:
For Monday receipts:
=IF(WEEKDAY($B)=2, $G, "")
For Monday Minimum:
=MIN(INDIRECT("Ledger::"&CHAR(70+ROW())))
You had pre-filled Column A with 3-letter abbreviations of the Days of the Week. I am not sure this is important, since you could have formatted the Date (Column B) to show the same information, but I didn't like seeing the abbreviations for days that didn't have data entered yet so I replaced the text with an expression...
=IF(LEN(B)>0, LEFT(DAYNAME(WEEKDAY(B)), 3), "")
I seems that you may have filled the table with several months worth of rows of Mon, Tue, etc. Now, if you wish, you can trim the blank rows to just a few and add more as you need them.
Let me know if you have any questions about maintaining the document.
Jerry

Generating the last day of the week

HI All,
I have the Year value (for eg 2002, 2006) and the week number value in the year ( for eg : 32, 52) . Based on this information, how can I get the last day of the particular week.
for eg What is the last day of the week - 2002,32
Any pointer would be great.
Thanks and Regards
Venkat

Or try this:
SQL> WITH t AS
     (SELECT 2006 YEAR, 1 week
        FROM DUAL
      UNION ALL
      SELECT 2002 YEAR, 32 week
        FROM DUAL
      UNION ALL
      SELECT 2005 YEAR, 52 week
        FROM DUAL
      UNION ALL
      SELECT 2006 YEAR, 52 week
        FROM DUAL)
SELECT YEAR,
       week,
       CASE
          WHEN TO_CHAR (TRUNC (TO_DATE (YEAR, 'RR'), 'RR'), 'IW') != 1
             THEN TRUNC (TRUNC (TO_DATE (YEAR, 'RR'), 'RR') + 7, 'IW')
          ELSE TRUNC (TRUNC (TO_DATE (YEAR, 'RR'), 'RR'), 'IW')
       END
       + 6 + (week - 1) * 7 LAST_DAY
FROM t
                                              YEAR                                               WEEK LAST_DAY
                                              2006                                                  1 08-JAN-06
                                              2002                                                 32 11-AUG-02
                                              2005                                                 52 01-JAN-06
                                              2006                                                 52 31-DEZ-06
4 rows selected.

Days Since Jan 1, 1900. Days of the week

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