Deleting last character of a string

Hi Abapers,
I want to delete the last character of my workarea and then store into table.
The workarea says that it is FAX|
I have to remove the last character.
How to do tht.
Please reply.
Thanks

hi
do this in following way
frist find the String length
let it will be
w_str = 'sdn is wonderfull'
now use.
w_len = strlen(w_str) .
now
w_result = w_str+0(w_len - 1).
Cheers
Snehi

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How to delete last character in a string

Guys i have a question...
how can i delete the last character in a string..
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how do i delete the last character in this string which is a "," ?

String newString = myString.substring(0, myString.length()-1);

Truncating last character in a string

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Here's an example
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someStr = someStr.substring(0,someStr.length-1)
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How we can find the last character in a string(Urgent Plz!)

Gurus!
How we can find the last character in a string.
e.g i have a string say "Str" with value "10-01".
Now i want to find the last character in "Str" i.e "ONE=1".
i am using Oracle developer 6i with Oracle 8i(1.7).
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Many thanks!

Use the substr() and length() functions -
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Testing the last character of a string using .endsWith

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javadocs:
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endsWith
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Hi Gurus,
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Thanks in Advance.

Hi Pradeep,
Just find the String Length and use the offset commands
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Hi Everybody !!!
Do you know a method that can permit to delete in a string the first and the last character?
For instance I have in my string this word : [the word]
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Look at the substring method of the String class.
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I have a string that is created as follows: strBuffer += k.getKeyChar();(k is KeyPressed ...KeyEvent) How can I delete the last Char in the string strBuffer?

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Want to single out the last character of a string

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SQL> with t as (
2 select 'AB001XUV' col from dual
3 union
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5 union
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7 )
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9 /
S
V
K
V
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Removing last character of a string

Hi Gurus,
Is there any way to remove the last character of staring other that finding the string length and doing it?
waiting for reply
Ravi

HI,
yaa u can do this by one logic
wht u do is concatenate one special symbol like $ to the string wht u have and in the next statement by using tht special symbol u can find fdpos i.e. field postion i.e. at which lenght it is there and then in again another statement u can increa fdpos by one and u can cut the string at tht length
i think u got my logic
further if u have any quiries u can contact me on [email protected]
plzz reward if it is usefull....

Select last character of a string

Hello,
I would like to select the last character of an address string. For example, in '165 John Ave W' -- select result 'W'. I tried to use RIGHT but it doesn't work. I'm using SQL Plus.
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Thanks!

The SUBSTR function can take a negative start parameter, which counts in from the end of the string
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Carl

The last character of a string

How to judge the last char of a string is " ?
if (s.endsWith("""))or
if (s.endsWith("/""))

bet
you just copied and pasted what the OP had written
and quickly put that
backslash in, hit post without previewing first just
to make me look like
a slow old sod! It's not fair ;-)
kind regards,
JosNope, I used the Alt-[numeric code] combinations to manually type each character. Cut-n-paste is for wimps, and actually typing single-stroke keys is for milquetoasts.
Alt-[numeric code] is for real men ;-)

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When I type: java Commands -all one two three
the result is: one,two,three,
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This is my program. Somebody told me to try a substring by I cannot seem to figure it out.
public class Commands{
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Jim

Any easier way to replace the last character of a string?

this is what I got:
select SUBSTR('tjgb005dy_01_31_08',1,LENGTH('tjgb005dy_01_31_08')-1)||'1' from dual;
tjgb005dy_01_31_01and I am not quite fond of it. it looks ugly and it is long.
so, I wonder if you guys have better ideas?
Thanks

(Perhaps with replace there is no easier solution than the primary posted.)Well, look where I ended up...
SQL> -- generating sample data:
SQL> with t as ( select 'tjgb005dy_01_31_08' str from dual union
2              select 'tjgb005dy_01_31_03' from dual union
3              select '888888888888888888' from dual
4            )
5 --
6 -- actual query
7 --
8 select str
9 ,      case
10           when substr(str, -1) = 8
11           then
12             substr(str, 1, length(str)-1)||'1'
13           else
14             str
15         end
16 from t;
STR                CASEWHENSUBSTR(STR,-1)=8THENSU
888888888888888888 888888888888888881
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I should find each space that is the last character in a string set in a particular character style. For example, in the passage "123 456 789" (the underlined part here indicating a passage set in a particular character style), my ideal GREP search would yield a match after the digit 6.
How do this?

Excellent! This works perfectly. I have used your string with the bold character formatting, and replaced the matches with [nothing], set in None style.
On second thought, I was surprised that it indeed had worked: why was the space replaced, and not deleted? Shouldn't I have used
(?<!.)(\s)(?=\w)
and replaced it with
$2

Deleting last character of a string

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