Deleting rows from table based on value from other table
Hello Members,
I am struck to solve the issue said below using query. Would appreciate any suggestions...
I have two tables having same structures. I want to delete the rows from TableA ( master table ) with the values from TableB ( subset of TableA). The idea is to remove the duplicate values from tableA. The data to be removed are present in TableB. Catch here is TableB holds one row less than TableA, for example
Table A
Name Value
Test 1
Test 1
Test 1
Hello 2
Good 3
TableB
Name Value
Test 1
Test 1
The goal here is to remove the two entries from TableB ('Test') from TableA, finally leaving TableA as
Table A
Name Value
Test 1
Hello 2
Good 3
I tried below queries
1. delete from TestA a where rowid = any (select rowid from TESTA b where b.Name = a.Name and a.Name in ( select Name from TestB ));
Any suggestions..
We need TableB. The problem I mentioned above is part of process. TableB contains the duplicate values which should be deleted from TableA. So that we know what all values we have deleted from TableA. On deleted TableA if I later insert the value from TableB I should be getting the original TableA...
Thanks in advance
drop table table_a;
drop table table_b;
create table table_b as
select 'Test' name, 1 value from dual union all
select 'Test' ,1 from dual;
create table table_a as
select 'Test' name, 1 value from dual union all
select 'Test' ,1 from dual union all
select 'Test' ,1 from dual union all
select 'Hello' ,2 from dual union all
select 'Good', 3 from dual;
/* Formatted on 11/23/2011 1:53:12 PM (QP5 v5.149.1003.31008) */
DELETE FROM table_a
WHERE ROWID IN (SELECT rid
FROM (SELECT ROWID rid,
ROW_NUMBER ()
OVER (PARTITION BY name, VALUE
ORDER BY NULL)
rn
FROM table_a a
WHERE EXISTS
(SELECT 1
FROM table_b b
WHERE a.name = b.name
AND a.VALUE = b.VALUE))
WHERE rn > 1);
select * from table_a
NAME VALUE
Test 1
Hello 2
Good 3Edited by: pollywog on Nov 23, 2011 1:55 PM
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