Difference between and != operators

Hi All,
My question may be very basic to you all
Please let me know the difference between <> and != operators
Thanks in advance

user609996 wrote:
Sorry to all,
the operator "<>" is not printed
I want the difference between "<>" and "!=" operators.And as you've already been told there is no difference between the <> and != operators. They mean the same thing, but are just different representations of it.
The only difference is that the Oracle forum can't display <> if it is just typed in normally. To show it we have to type &lt and &gt with a ";" after each.

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Difference between & and && operators in if.

Hi,
this question seems like silly, but I am confused when I used these two operators in "if "condition,
is these 2 operators are act like same in if statement. like for example
if( 10 == 10 & "a".equals("a")){
System.out.print("true");
if( 10 == 10 && "a".equals("a")){
System.out.print("true");
when I executed above statements both printing true.
Can you please clarify on this.
Thanks in advance

Usually true, but not entirely accurate. the single & operator is also used for boolean And, but it does not short circuit the evel. try this code ofr a test
String s = null;
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in my answer
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Difference between " " and ' ' in oracle

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d
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Mrsthebraggster wrote:
So it might look:
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From an earlier post of mine:
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The way I look at it conceptually:
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<<
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968217 wrote:
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Greetings to all,
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i have also seen the value ALL in some roles in my org...
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Are you meaning (taglib in plain HTML):
<form action="<bean:write name='beanname' property='propname' />">...</form>
or are you meaning you can do this (nested taglib tags):
<html:form action="<bean:write name='beanname' property='propname' />">...</html:form>
?? Cuz I've do this with no problems:
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Differences between == and .equals

I'm rather new to Java programming and have learned that == can only be used to compare primitive types in Java (for example when comparing to int) and when comparing objects, one should use the .equals-method (that should be overloaded from the one in Object). This is because == compare the object's reference adress (is this correct?) For example:
Vector v1 = new Vector();
Vector v2 = new Vector();
v1.add("hello");
v2.add("hello");
System.out.println(v1 == v2);This program should print false, since v1 and v2 are different objects.
System.out.println(v1 == v1);should print true.
OK, so far so good. However, an experiment I've made clearly shows that there's an exception to this rule. When comparing objects of type String, you don't need to use .equals, == works perfectly. My question is why?

When comparing objects of type String, you
don't need to use .equals, == works perfectly. My
question is why?It doesn't work perfectly at all.
String literals
Don't confuse String's equals() method with the equality operator '=='. The == operator checks that two references refer to the same object. If you want to compare the contents of Strings (whether two strings contain the same character sequence), use equals(), e.g. if (str1.equals(str2))...
Example:String s1 = "foo";
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[Solved] Shell: Is there a difference between / and // in directories?

Hello:
I'm making this tiny program in Shell:
# Function.
# NAME: chk_df
# Synopsis:
# Check if a local directory (dirName) exist and has a file (fileName).
# The return codes are the following:
# 99 : dirName does not exists
# 0 : dirName exists and has fileName
# 1 : dirName exists and has not fileName
# Parameters:
# In values: dirName <string> fileName <string>
# Out values: returnCode <int>
# How to use:
# chk_df dirName fileName
chk_df(){
# Check the number of arguments that could be passed.
# In this case, two, dirName, fileNAme.
if [[ ${#@} != 2 ]]; then
echo "Error ...Use [Funtion]: chk_df <dirName> <fileName>"
echo "Ex: chk_df /foo lola.txt"
exit
fi
DIR=$1
FILE=$2
[[ ! -d $DIR ]] && return 99
[[ -d $DIR && ! -e $DIR/$FILE ]] && return 1
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I) If we do: chk_df /foo lola.txt
We get: /foo/lola.txt
II) If we do: chk_df /foo/ lola.txt
We get: /foo//lola.txt [Notice the //]
In both cases the code seems to work. Why?
Could I leave it like that or it will bring problems? Is there a difference? UNIX assume it to the right way?
EXTRA QUESTION: why I can not do the returns with negative numbers? This is: return -1
Thank you.
Last edited by gromlok (2011-11-07 15:48:44)

If this script is bash only, you could use bash parameter expansion to get rid of any number of //:
$ DIR="/long//numerous//doubleslashed/path/to/"
$ FILE="file"
$ MYPATH="$DIR/$FILE"
$ cd $MYPATH
bash: cd: /long//numerous//doubleslashed/path/to//file: No such file or directory
$ cd ${MYPATH//\/\//\/}
bash: cd: /long/numerous/doubleslashed/path/to/file: No such file or directory
See http://mywiki.wooledge.org/BashGuide/Pa … _Expansion if you want a better explanation.
Edit: changed variable name from PATH to MYPATH. Boy was I surprised by bash: pacman: command not found
Last edited by alphaniner (2011-11-07 17:26:02)

Difference between = * and *=

Could anyone of you tell a reason why the following behave so.
Line 1: short s1 = 2, s2 = 3;
Line 2: s1 *= s2;
Line 3: System.out.print(s1);
Line 4: s2 = s2 * s1;
Line 5: System.out.print(s2);
Compilation error at Line 4 is the result. Line 4 will get the compilation error, since operation performs in int (32-bit), and is trying to assign to a short (16-bit). OK. But the question is why the rule is not applicatble to Line 2? If ! comment out line 4 and 5, it will compile, run and print "6". Can anyone tell the reason or tell me how java implemented these assign operators?
Thanks in Advance,
Sameer B.

Wow, most people just go, holy crap.. I don't ever want to see that byte code crap again...
Here's how I did that one.
make a file Test.java
public class Test {
public static void main(String[] args) {
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}compile it.
javac Test.javause javap on it
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Difference between and != operators

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